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Only last value from JavaScript in while loop is displayed

I'm working on the code displaying in the while loop data received from the database. Within that code there is a form in which I added a hidden input (name="position"). I'd like to use that input to store number of pixels from the top of the window. Unfortunately, the javascript added by me, changes the value of the hidden input only in the last table in the loop. In the first tables the hidden input named "position" remains unchanged (remains empty). Could anyone please help me?
<?php
while ($row = $wynik->fetch_assoc()) {
?>
<form method="post" style="margin-bottom: 0px;" onsubmit="poz()">
<input type="hidden" name="edition" value="<?php echo $row["id"]; ?>">
<input type="hidden" id="<?php echo $row["id"]; ?>" name="position" value="">
<input type="submit" value="Edytuj" class="edytuj">
</form>
<script>
function poz() {
var position = window.pageYOffset;
document.getElementById(<?php echo $row["id"]; ?>).value = position;
}
</script>

You need to add an event listener to know what is clicked
window.addEventListener("load",function() {
[...document.querySelectorAll(".edytuj")].forEach(function(elem) {
elem.addEventListener("click",function (e) {
var tgt = e.target;
tgt.previousElementSibling.value=tgt.offsetTop;
})
});
})
<input type="hidden" name="edition" value="<?php echo $row["id"]; ?>">
<input type="hidden" id="<?php echo $row["id"]; ?>" name="position" value="">
<input type="button" value="Edytuj" class="edytuj">

Get the values of while loop using button with js

How can I get the values in the while loop using button with js?
<?php
while ($row = mysqli_fetch_array($query))
{
echo '<input type="text" name="sample" value="'.$row['sample'].'">';
}
?>
Thanks

You can get the value of textbox when you click on a button.
<input type="text" name="sample[]" value="abc" class="valueInput">
<input type="text" name="sample[]" value="xyz" class="valueInput">
<input type="text" name="sample[]" value="pqr" class="valueInput">
<input type="button" class="getValue" value="Get Value">
Note: I have set the static input box you can make it dynamic but make sure please add the class as valueInput.
Jquery Code.
$(document).on('click','.getValue',function(){
var valArr = [];
$(".valueInput").each(function(){
valArr.push($(this).val());
});
console.log(valArr);
})

The name of the input field should indicate an array with [].
<form action="action.php" method="POST">
<?php
while ($row = mysqli_fetch_array($query)){
echo '<input type="text" name="sample[]" value="'.$row['sample'].'">';
}
?><input type="submit">
</form>
action.php: (Processes the data on submit)
<?php
echo "<pre>";
print_r($_POST['sample']);
echo "</pre>";

Set value of input element using javascript and get the value using php

Here I have a form and input element:
cart.php
<form id="cartform" action="cart.php?action=update&pd=<?php echo $row['product_id'] ?>" name="form1" method="post">
<?php
$query = "select * from cart where customer_id='$user' ";
$result = mysqli_query($con,$query);$payableamount = 0;$totalsavings = 0;
while($row = mysqli_fetch_array($result))
{
$productid = $row['product_id'];
$query2 = "select * from product where product_id='$productid'";
$result2 = mysqli_query($con,$query2);
while($row2=mysqli_fetch_array($result2))
{
?>
<input tpe="text" name="quantxt[]" id="quantxt" value="<?php echo $qty = $row['quantity']; ?>" onkeyup="showsubmit(<?php echo $row['cart_id'] ?>,<?php echo $row['product_id'] ?>)">
<input type="text" name="s1" id="s1" value=""/>
<input style="visibility:hidden;width:80px;border-radius:10px;background-color:green;border:none;padding:5px;color:white;"
type="submit"
name="sub_<?php echo $row['cart_id'] ?>"
id="sub_<?php echo $row['cart_id'] ?>"
value="UPDATE">
</table>
</form>
and the javascript is:
<script>
function showsubmit(id,prodid)
{
alert(id);
alert(prodid);
document.getElementById("sub_"+id).style.visibility ="visible";
document.getElementById("s1").value = prodid;
f = document.getElementById("s1").value;
alert("product id is:"+f);
}
</script>
when i am accessign the value of s1 element in cart2.php it gives nothing.
on next page s1 has no value,while i am expecting the value that is updated using javascript
$prod_id = $_POST['s1'];
echo "product id of clickable product is:".$prod_id."<br>";

this line:
<input type="text" name="s1" id="s1" value=""/>
is inside a loop. can you make sure that the loop only has one row returning? because if not, then you're creating multiple elements with same id which javascript can not catch properly. id is supposed to be unique. in the case of multiple same ids it'll catch the first match and stop.

Can only post first result of while loop

I am using a while loop to display results from a query. The while loop is working fine. In hidden fields I would like to post the values of userID and accessID to the user details page. I am submitting the form using javascript to submit from a link. My problem is that regardless of the username I click I can only post the values for the first displayed record. What am I doing wrong?
The code:
<?php
while($row = $result->fetch_array()) { ?>
<form method="post" action="edit_user.php" id="userForm">
<tr>
<td>
<?php echo $row['firstname'].' '.$row['surname']; ?>
<input type="hidden" name="userID" value="<?php echo $row['userID']; ?>" />
<input type="hidden" name="accessID" value="<?php echo $row['accessID']; ?>" />
</td>
</tr>
</form>
<?php } ?>
The javascript used for submitting the form:
function submitForm() {
var form = document.getElementById("userForm");
form.submit();
}
Thank you.
EDIT - I don't want to pass the values in the url.

you are generating multiple <form>s inside loop, move your <form> outside while loop, like:
<form method="post" action="edit_user.php" id="userForm">
<?php
while($row = $result->fetch_array()) { ?>
<tr>
<td>
<?php echo $row['firstname'].' '.$row['surname']; ?>
<input type="hidden" name="userID[]" value="<?php echo $row['userID']; ?>" />
<input type="hidden" name="accessID[]" value="<?php echo $row['accessID']; ?>" />
</td>
</tr>
<?php } ?>
Submit
</form>

You're running into trouble because of this line
var form = document.getElementById("userForm");
In Javascript and HTML, an ID is supposed to be unique to a certain DOM element. In this case, you've got a whole load of form tags that have the same ID. You need to give each form a different ID, and then pass that ID to the submitForm function.
For example:
<?php
$id = 0;
while($row = $result->fetch_array()) { ?>
$id++;
<form method="post" action="edit_user.php" id="<?php echo "userForm".$id ?>">
<tr>
<td>
<?php echo $row['firstname'].' '.$row['surname']; ?>
<input type="hidden" name="userID" value="<?php echo $row['userID']; ?>" />
<input type="hidden" name="accessID" value="<?php echo $row['accessID']; ?>" />
</td>
</tr>
</form>
<?php } ?>
and then
function submitForm(id) {
var form = document.getElementById(id);
form.submit();
}
edit: how do I php? :D

Multiple forms onclick event only working for first form

I'm sure this has been asked befor but I can't seem to find it in a search
I have multiple forms on a page generated by php all with onCick event
The problem is it only picks up the first event after that any other clicks produce same result from first click
Here is javascript
function CompareScores(form)
{
var scoreA = document.getElementById("score_A").value;
var scoreB = document.getElementById("score_B").value;
if(scoreA > scoreB){
alert('Score A is Larger ' + scoreA)
}else{
alert('Score B is Larger ' + scoreB)
}
}
And the php generating forms
<?php
while($i<=$numPrelimTeams) {
if($i!=$e) {
?>
<form action="processScores.php" method="post"><p><u><?php echo $prelimTeam[$i]; ?> --> SCORE : <input type="text" class="small" id="score_A" name="score_A" size="1"></u></p>
<input type="hidden" name="team_A" value="<?php echo $prelimTeam[$i]; ?>">
<input type="hidden" name="game" value="<?php echo $game_num; ?>">
<p class="right">Game # <?php echo $game_num; ?> ) <input type="button" value="Enter Scores" onClick="CompareScores(this.form)"></p>
<?php
}else{
?>
<p><u><?php echo $prelimTeam[$i]; ?> --> SCORE : <input type="text" class="small" id="score_B" name="score_B" size="1"></u></p>
<input type="hidden" name="team_B" value="<?php echo $prelimTeam[$i]; ?>">
</form><br><br><br>
<?php
$game_num++;
$e=$e+2;
}
$i++;
}
?>

Without knowing the inputs or seeing the result, it's hard to tell for sure, but it looks like you might be generating multiple instances of this form on the same page, giving you multiple page elements named "score_A" and "score_B". document.getElementById will then become a bit ambiguous.
Since you're already sending the form object, use that instead:
var scoreA = form.score_A.value;
...

There is essentially a single problem with your code. You have multiple instances of the same ID.
To fix it, try something like this.
<input type="text" class="small score_A" name="score_A" size="1" />
Similarly
<input type="text" class="small score_B" name="score_B" size="1" />
Now, you can write a querySelector in your JS
function CompareScores(form) {
var a = form.querySelector('.score_A').value;
var b = form.querySelector('.score_B').value;
//do something
}