I figured out how to change image on mouseover through javascript. But unable to figure how to add description below the image on mouseover/mouseclick on respective image. I'm not good at jQuery. Please help me in solving the problem in javascript only.
<html>
<head>
<style>
.imgStyle {
height: 100px;
width: 100px;
border: 3px solid grey;
}
</style>
</head>
<body>
<img src="img/img_01.jpg" id="mainImage" />
<div id="describ01" style="display:none">Description 01</div>
<div id="describ02" style="display:none">Description 02</div>
<div id="describ03" style="display:none">Description 03</div>
<div id="describ04" style="display:none">Description 04</div>
<br />
<div id="myDiv" onmouseover="changeImage(event)">
<img src="img/img_02.jpg" class="imgStyle" />
<img src="img/img_03.jpg" class="imgStyle" />
<img src="img/img_04.jpg" class="imgStyle" />
<img src="img/img_05.jpg" class="imgStyle" />
</div>
<script type="text/javascript">
function changeImage(event) {
event = event || window.event;
var targetElement = event.target || event.srcElement;
if(targetElement.tagName == "IMG") {
document.getElementById("mainImage").src = targetElement.getAttribute("src");
}
}
</script>
</body>
</html>
If you want to use javascript then the answer will be
document.getElementById("description").innerHTML = 'Hello World';
and if you want to use JQuery then
$("#description").html("Hello World");
Hopefully it will help you
Give each of your images a data attribute:
<img src="img/img_02.jpg" class="imgStyle" data-text='text goes here' />
Then use this on hover:
if(targetElement.tagName == "IMG") {
document.getElementById("mainImage").src = targetElement.getAttribute("src");
document.getElementById("description").innerHTML = this.getAttribute("data-text");
};
Now you only need one description div as before.
Related
I have a series of images with the class of .piece in a div called #pieces. Only the first image #piece0 is shown initially, and as you click on #piece0, #piece1 appears on top of #piece0. And then when you click on #piece1, #piece2 appears on top. My current code doesn't do that. How do I fix that?
<div id="pieces">
<img class="piece" id="piece0" style="display:block;"/>
<img class="piece" id="piece1" style="display:none;"/>
<img class="piece" id="piece2" style="display:none;"/>
<img class="piece" id="piece3" style="display:none;"/>
</div>
<script>
var pieceNum = $("#pieces").children().size();
var i = 0;
if (i < pieceNum) {
$("#piece" + i).click(function({
i++;
$("piece" + i).css("display", "block");
}));
}
</script>
If you want to get element children size(length) , use $("#pieces img").length . But for your problem that is not necessary .
You can catch image click by $("pieces img").on("click".. and get next element by .next() then the last element have no next , for that case you can check by next().length . 0 will return if next element have no exist
$("#pieces img").on("click",function() {
$(this).next().show();
$("#pieces").append($(this));
});
#pieces {
display: flex;
flex-direction: column;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="pieces">
<img class="piece" id="piece0" style="display:block;" alt="one"/>
<img class="piece" id="piece1" style="display:none;" alt="two"/>
<img class="piece" id="piece2" style="display:none;" alt="three"/>
<img class="piece" id="piece3" style="display:none;" alt="four"/>
</div>
$(document).ready(function(){
var pieceNum = $("#pieces").children();
var i = 0;
if (i < pieceNum.length) {
$("#piece" + i).click(function(){
$("#piece" + i).css("display", "none");
i++;
$("#piece" + i).css("display", "block");
});
}
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="pieces">
<img class="piece" id="piece0" style="display:block;" src="http://placekitten.com/g/200/300"/>
<img class="piece" id="piece1" style="display:none;" src="http://placekitten.com/g/200/400"/>
<img class="piece" id="piece2" style="display:none;" src="http://placekitten.com/g/200/300"/>
<img class="piece" id="piece3" style="display:none;" src="http://placekitten.com/g/200/100"/>
</div>
Try this:
var pieceNum = $("#pieces").children().size();
var i = 0;
if (i < pieceNum) {
$("#piece" + i).click(function({
$("piece" + i).css("display", "none");
i++;
$("piece" + i).css("display", "block");
}));
}
You don't need to write multiple click events, You can have single click event attached to all elements and do traversing using .next() to show next element :
$(".piece").click(function({
var $nextPiece = $(this).next();
if($nextPiece.length > 0)
$nextPiece.css("display", "block");
}));
You can use the next() to access next child and show() to display the img. Also, you will need to add position: absolute; to make images overlap each other.
$(document).ready(function() {
$('.piece').on('click', function() {
$(this).next().show();
});
});
img {
max-width: 100px;
margin-right: 1em;
position: absolute;
}
<script src="https://code.jquery.com/jquery-3.4.1.min.js" integrity="sha256-CSXorXvZcTkaix6Yvo6HppcZGetbYMGWSFlBw8HfCJo=" crossorigin="anonymous"></script>
<div id="pieces">
<img class="piece" src="https://res.cloudinary.com/demo/image/upload/w_250,h_250,c_mfit/w_700/sample.jpg" />
<img class="piece" src="https://res.cloudinary.com/demo/image/upload/w_300,h_200,c_crop/sample.jpg" style="display:none;" />
<img class="piece" src="https://res.cloudinary.com/demo/image/upload/w_250,h_250,c_mfit/w_700/sample.jpg" style="display:none;" />
<img class="piece" src="https://res.cloudinary.com/demo/image/upload/w_300,h_200,c_crop/sample.jpg" style="display:none;" />
</div>
Try this
$(".piece").on('click', function(){
$(".piece").hide();
let id = (parseInt(this.id.slice(-1)) +1)%4;
$("#piece" +id).show();
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="pieces">
<img class="piece" id="piece0" style="display:block;" alt="piece 0"/>
<img class="piece" id="piece1" style="display:none;" alt="piece 1"/>
<img class="piece" id="piece2" style="display:none;" alt="piece 2"/>
<img class="piece" id="piece3" style="display:none;" alt="piece 3"/>
</div>
I'm trying to implement a function like Google Image Search, which is that when you click a picture, a subpage appears in the screen below the picture. And it takes a whole line. The screenshot is showing below.
http://www.wy19900814fun.com/thumbnails/test.png
Here's my code. Is there anyone helping me to implement or at least give me some advise? I'm trying to do a function like when you click a picture, the second div class shows below the picture you click. It needs to take a whole line.
<html>
<head>
<style>
.container {
text-align: center;
}
.container img {
display:inline-block;
}
.subpage {
display:none;
}
</style>
<script type="text/javascript">
</script>
</head>
<body>
<div class="container">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/20964301401_5d9fdf5c0d_o_large_958fe482-f2e7-4120-b4fe-016fcf612bf5_large.jpeg?v=1440873580">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/20770321799_5c81882577_o_large_c4c19c91-0532-422f-99d0-297b2731c4e3_large.jpeg?v=1440873580">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/17108089939_8d4cefd10a_o_large_3dc1d49b-cb59-432a-a8d7-b118cfd61314_large.jpeg?v=1440873578">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/17950190230_114070818c_o_large_60ce5c71-7575-49ab-be75-ed2cfed6768d_large.jpeg?v=1440873577">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15175737319_c0db73446f_o_zps867eecb9_large_858814b0-6a80-4a34-b55d-97acc179cc91_large.jpeg?v=1440873576">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15085342999_b8878e538e_o_zps54a2d381_large_f731cd55-f8d0-4e9a-8ba5-c254b4b8241d_large.jpeg?v=1440873575">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15085523427_bacc983407_o_zps2c262937_large.jpeg?v=1440873574">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15268975561_ed3f9f5c0b_o_zpsd4857119_large.jpeg?v=1440873573">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15339485796_bed118ac3c_o_zpsf0927ac3_large.jpeg?v=1440873572">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/IMG_9092_zpsc38bd27c_large.jpeg?v=1440873571">
</div>
<div class="subpage">
<p>This is </br>just</br> a test.</br> Please show</br> subpage</p>
</div>
</body>
</html>
$('img').click(function() {
var $img = $(this),
offset = $img.offset(),
subPage = $('#subPage').hide().insertAfter('.container'),
nextImage = $img.next(),
finalImage = $img;
if (!$img.is(':last-child')) {
while (offset.top == nextImage.offset().top) {
nextImage = nextImage.next();
}
finalImage = nextImage.prev();
}
subPage.html('').append($img.clone()).insertAfter(finalImage).slideDown();
});
.container {
text-align: center;
}
.container img {
display:inline-block;
width:32%;
vertical-align:top;
}
#subPage {
background:#222;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/20964301401_5d9fdf5c0d_o_large_958fe482-f2e7-4120-b4fe-016fcf612bf5_large.jpeg?v=1440873580">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/20770321799_5c81882577_o_large_c4c19c91-0532-422f-99d0-297b2731c4e3_large.jpeg?v=1440873580">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/17108089939_8d4cefd10a_o_large_3dc1d49b-cb59-432a-a8d7-b118cfd61314_large.jpeg?v=1440873578">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/17950190230_114070818c_o_large_60ce5c71-7575-49ab-be75-ed2cfed6768d_large.jpeg?v=1440873577">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15175737319_c0db73446f_o_zps867eecb9_large_858814b0-6a80-4a34-b55d-97acc179cc91_large.jpeg?v=1440873576">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15085342999_b8878e538e_o_zps54a2d381_large_f731cd55-f8d0-4e9a-8ba5-c254b4b8241d_large.jpeg?v=1440873575">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15085523427_bacc983407_o_zps2c262937_large.jpeg?v=1440873574">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15268975561_ed3f9f5c0b_o_zpsd4857119_large.jpeg?v=1440873573">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15339485796_bed118ac3c_o_zpsf0927ac3_large.jpeg?v=1440873572">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/IMG_9092_zpsc38bd27c_large.jpeg?v=1440873571">
</div>
<div id="subPage"></div>
You could do like that :
JS :
$(document).ready(function () {
$('.container img').click(function () {
var src = $(this).attr('src');
var subpage = $('.subpage');
subpage.hide().empty().fadeIn(250);
$('<img>', {'src' : src}).hide(250).appendTo(subpage).fadeIn(250);
});
});
Jsfiddle
I've a next button and back button. I want to show one question div at a time. Then I want next button to change the div to the next div question and the back button should change the div back to the previous div. Only one div should be seen at a time.
<input type="image" src="forward.gif" alt="Next">
<input type="image" src="back.gif" alt="Back">
<div class="question_one">
<img src ="images/green_question1.png" width="100%" height="100%"></img>
</div>
<div class="question_two">
<img src ="images/green_question2.png" width="100%" height="100%"></img>
</div>
<div class="question_three">
<img src ="images/green_question3.png" width="100%" height="100%"></img>
</div>
<div class="question_four">
<img src ="images/green_question4.png" width="100%" height="100%"></img>
</div>
Here's a simple JavaScript which solves this kind of problem:
<script>
var next = document.getElementById('next'),
back = document.getElementById('back'),
questions = document.getElementsByTagName('div'),
current = 0;
next.onclick = function showNext() {
if (questions[current+1]) {
questions[current].style.display = 'none';
questions[current+1].style.display = 'block';
current++;
} else {
return false;
}
}
back.onclick = function showPrev() {
if (questions[current-1]) {
questions[current].style.display = 'none';
questions[current-1].style.display = 'block';
current--;
} else {
return false;
}
}
</script>
And at first you should hide the questions with CSS (except the first one):
<style>
div:not(:first-of-type) {
display: none;
}
</style>
EDIT: here is your HTML...
<input type="image" src="forward.gif" alt="Next" id="next">
<input type="image" src="back.gif" alt="Back" id="back">
<div class="question_one">
<img src ="images/green_question1.png" width="100%" height="100%"></img>
</div>
<div class="question_two">
<img src ="images/green_question2.png" width="100%" height="100%"></img>
</div>
<div class="question_three">
<img src ="images/green_question3.png" width="100%" height="100%"></img>
</div>
<div class="question_four">
<img src ="images/green_question4.png" width="100%" height="100%"></img>
</div>
First, regroup your class with unique name and add id to your back and forward button (To apply clicks events). Example :
<input type="image" src="forward.gif" alt="Next" id="forwardQ">
<input type="image" src="back.gif" alt="Back" id="nextQ">
<div class="question">
<img src ="images/green_question1.png" width="100%" height="100%"></img>
</div>
<div class="question">
<img src ="images/green_question2.png" width="100%" height="100%"></img>
</div>
<div class="question">
<img src ="images/green_question3.png" width="100%" height="100%"></img>
</div>
<div class="question">
<img src ="images/green_question4.png" width="100%" height="100%"></img>
</div>
With JQuery:
var actual = 0; // select by default the first question
$(document).ready(function() {
var number_of_question = $('.question').length; // get number of questions
$('.question:gt(' + actual + ')').hide(); // Hide unselect question
$('#nextQ').click(function() {
if(actual < number_of_question - 1 ) {
changeQuestion(actual + 1); // display select question
}
});
$('#forwardQ').click(function() {
if(actual) {
changeQuestion(actual - 1); // display select question
}
});
});
function changeQuestion( newQuestion ) {
$('.question:eq(' + actual +')').hide(); // hide current question
$('.question:eq(' + newQuestion +')').show(); // show new question
actual = newQuestion; // memorize actual selection
}
You can achieve this by combining HTML, CSS and jQuery.
In the below example I am displaying only the div elements with class active and hiding the other divs. And adding the class active to appropriate divs when ever the user clicks on the Next or Previous button.
HTML Code
<input type="button" value="Next" id="next_qs">
<input type="button" value="Back" id="prev_qs">
<div class="question_one">
QS1
</div>
<div class="question_two">
QS2
</div>
<div class="question_three">
QS3
</div>
<div class="question_four">
QS4
</div>
CSS Code
div {
width: 300px; height: 200px; border: 1px solid #333; clear: both; display: none;
}
div.active {
display: block;
}
jQuery Code
$("div:first").addClass('active')
$("#next_qs").click(function() {
$("div.active").removeClass('active').next().addClass('active');
});
$("#prev_qs").click(function() {
$("div.active").removeClass('active').prev().addClass('active');
});
http://jsfiddle.net/27gwy14f/
HTML
<div id="container">
<input type="image" src="back.gif" alt="Back">
<input type="image" src="forward.gif" alt="Next">
<div class="question_one question active">
1
<img src ="images/green_question1.png" width="100%" height="100%"></img>
</div>
<div class="question_two question">
2
<img src ="images/green_question2.png" width="100%" height="100%"></img>
</div>
<div class="question_three question ">
3
<img src ="images/green_question3.png" width="100%" height="100%"></img>
</div>
<div class="question_four question">
4
<img src ="images/green_question4.png" width="100%" height="100%"></img>
</div>
</div>
Jquery
<script>
var $container = $("#container") // caches the jquery object
$container.find('input[alt="Next"]').on("click",function(){
var active = $container.find(".active")
if(active.next(".question").length === 0){
return false
}else{
active.removeClass("active")
active.next(".question").addClass("active")
}
})
$container.find('input[alt="Back"]').on("click",function(){
var active = $container.find(".active")
if(active.prev(".question").length === 0){
return false
}else{
active.removeClass("active")
active.prev(".question").addClass("active")
}
})
</script>
CSS
<style>
#container .question{
display:none
}
#container .active{
display:inline-block;
}
</style>
JS FIDDLE
http://jsfiddle.net/vrnxL9n8/
edit: added js fiddle link
HTML :
<html>
<head>
<script>pushImages();</script>
<title>Float Image Gallery</title>
</head>
<body>
<button onclick="showAllGalleries();">Show gallery</button>
<div class="gallery">
<div class="gallery-close">
<a href=#><img class="gallery-close-button" src="http://bit.do/closeicon" onclick="hideAllGalleries();" /></a>
</div>
<div class="gallery-content">
<!-- Whenever need to add a image, add this code :
<div class="gallery-image-cell">
<img class="gallery-content-image" src="" alt="Please add image here" />
<img class="gallery-content-image" src="" alt="Please add image here" />
<img class="gallery-content-image" src="" alt="Please add image here" />
<img class="gallery-content-image" src="" alt="Please add image here" />
</div>
-->
<!--
Information :
When adding photo that is not 1:1, it will force shrink to 1:1.
-->
<div class="gallery-image-cell">
<img class="gallery-content-image" src="" alt="Please add image here" />
<img class="gallery-content-image" src="" alt="Please add image here" />
<img class="gallery-content-image" src="" alt="Please add image here" />
<img class="gallery-content-image" src="" alt="Please add image here" />
</div>
<div class="gallery-image-cell">
<img class="gallery-content-image" src="" alt="Please add image here" />
<img class="gallery-content-image" src="" alt="Please add image here" />
<img class="gallery-content-image" src="" alt="Please add image here" />
<img class="gallery-content-image" src="" alt="Please add image here" />
</div>
</div>
</div>
</body>
</html>
CSS :
<style>
.gallery {
display:none;
width:100%;
height:100%;
left:0;
bottom:0;
top:auto;
right:auto;
position:fixed;
background-color:#cccccc;
opacity:50%;
overflow-y: scroll;
}
.gallery-close {
width:auto;
height:auto;
margin-top:10px;
margin-left:10px;
}
.gallery-close-button {
width:30px;
height:30px;
}
.gallery-content {
width:100%;
height:auto;
text-align:center;
}
.gallery-content-image {
width:20%;
height:100%;
opacity:0.6;
filter:alpha(opacity=60);
}
.gallery-content-image:hover {
background-color:#ffffff;
opacity:1.0;
filter:alpha(opacity=100);
}
.gallery-image-cell {
width: 100%;
height: 0;
padding-bottom: 20%;
margin-left: auto;
margin-right: auto;
}
</style>
Javascript :
<script tyep="text/javascript">
function showAllGalleries(){
var adsArray = document.getElementsByClassName("gallery");
for (var i = 0; i<adsArray.length; i++){
adsArray[i].style.display='inline';
}
}
function hideAllGalleries(){
var adsArray = document.getElementsByClassName("gallery");
for (var i = 0; i<adsArray.length; i++){
adsArray[i].style.display='none';
}
}
function pushImages(){
var imageArray = document.getElementsByClassName("gallery-content-image")
var imageLinkArray[];
imageLinkArray.push("http://www.catchannel.com/images/feral-cats-birds.jpg");
imageLinkArray.push("http://www.catchannel.com/images/orange-tabbies.jpg");
imageLinkArray.push("http://thenypost.files.wordpress.com/2013/08/tiger132056-300x300.jpg");
imageLinkArray.push("http://bioexpedition.com/wp-content/uploads/2012/06/Indochinese-Tiger-picture.jpg");
imageLinkArray.push("http://www.east-northamptonshire.gov.uk/images/Dog_2.jpg");
imageLinkArray.push("http://www.pet365.co.uk/product_images/r/008/dd_black_with_dog__41452_zoom.jpg");
imageLinkArray.push("http://www.texasbirds.info/backyard/images/mountain_bluebird2_male.jpg");
imageLinkArray.push("http://www.honolulumagazine.com/images/2013/Oct13/Print/Bird_Fairy.jpg");
/*Use imageLinkArray.push("") to add a image; Add enough image.*/
for (var i=0; i<imageArray.length; i++){
imageArray[i].src = imageLinkArray[i];
}
}
</script>
I'm not sure where the problem is, but after clicking the button nothing happened.
Please help. Any help will be appreciated. Thank you.
<script>pushImages();</script>
This is calling a function before the DOM is even loaded, which should throw an error in your console. Place it at the bottom of your code or wrap it in window.onload = function() { .... }.
You're also missing an equal sign in this line: var imageLinkArray[]; (should be var imageLinkArray = [];.
I also suggest not practicing inline scripting. It's bad practice to do so. Try adding an event handler to the body (onclick only supports one event handler).
document.getElementsByTagName("body")[0].addEventListener("load", showAllGalleries, false);
I have the following code which displays an image onmouseover and sets back the default image active onmouseout.
<img src="image1.jpg" onmouseover="this.src='image2.jp'" onmouseout="this.src='image1.jpg'" />
I want to be able to display multiple images onmouseover event; each displaying after a set time. Can anyone help me out on this?
HTML
<div id="container">
<img id="initialIMG" src="http://icons.iconarchive.com/icons/jamespeng/construction/128/bonecrusher-icon.png" />
</div>
<img src="http://icons.iconarchive.com/icons/jamespeng/construction/128/bonecrusher-icon.png" onmouseover="this.src='http://icons.iconarchive.com/icons/jamespeng/construction/128/longhaul-icon.png'" onmouseout="this.src='http://icons.iconarchive.com/icons/jamespeng/construction/128/bonecrusher-icon.png'" />
JavaScript
$(document).ready(function(){
$("#container").mouseenter(function() {
var t = setTimeout(function(){
$("#initialIMG").hide();
$("#initialIMG").attr("src", "http://icons.iconarchive.com/icons/jamespeng/construction/128/longhaul-icon.png" )
$("#initialIMG").fadeIn(50);
$("#container").append( '<img id="addedIMG" src="http://icons.iconarchive.com/icons/jamespeng/construction/128/mixmaster-icon.png" style="display:none;"/>' );
$("#addedIMG").fadeIn(50);
},500);
});
$("#container").mouseleave(function() {
var t = setTimeout(function(){
$("#initialIMG").hide();
$("#initialIMG").attr("src", "http://icons.iconarchive.com/icons/jamespeng/construction/128/bonecrusher-icon.png" )
$("#initialIMG").fadeIn(50);
$("#addedIMG").remove();
},500);
});
});
FIDDLE
Try this:
function showImage() {
//Your code here
}
function hideImage() {
//Your code here
}
<img src="image1.jpg" onmouseover="showImage();" onmouseout="hideImage();" />
Is there any specific reason you don't want to use jQuery?
in css:
#my-pics .default{
display: inline;
}
in html:
<div id="my-pics">
<img src="image1.jpg" class="default" />
<img src="image2.jpg" style="display:none;" />
<img src="image3.jpg" style="display:none;" />
</div>
in js:
$("#my-pics").mouseenter(function(){
$(this).find(".default").hide();
$(this).find(":not(.default)").show();
}).mouseleave(function(){
$(this).find(".default").show();
$(this).find(":not(.default)").hide();
});
Of course you need to import jquery first. Haven't tested this myself, any errors?
CSS solution?
in html:
<div id="my-pics">
<img src="image1.jpg" class="default" />
<img src="image2.jpg"/>
<img src="image3.jpg"/>
</div>
in css:
#my-pics img{
display: none;
}
#my-pics img.default{
display: inline;
}
#my-pics:hover img{
display: inline;
}
#my-pics:hover img.default{
display: none;
}
A quick solution, maybe not the most beautiful one, but it works.
HTML:
<img id="image1" src="image1.jpg" onmouseover="showImages()" onmouseout="hideImages()" />
<img id="image2" src="image2.jpg" style="display:none;" />
<img id="image3" src="image3.jpg" style="display:none;" />
Javascript:
function showImages(){
document.getElementById('image2').style = '';
document.getElementById('image3').style = '';
}
function hideImages(){
document.getElementById('image2').style = 'display: none;';
document.getElementById('image3').style = 'display: none;';
}
Of course you should solve this with classes to clean up your code. This is just a basic example that works.
If you are using jQuery then when your document is ready:
<img class="main-image" data-target=".images-set1" src="mainImage1.jpg">
secondary images:
<div class="images-set1">
<img src="secondary1-1.jpg" style="display:none">
<img src="secondary1-2.jpg" style="display:none">
<img src="secondary1-2.jpg" style="display:none">
....
</div>
with jQuery:
$('main-image').on('mouseover', function (event) {
$($(event.target).attr('data-target') + ' img').show();
})
.on('mouseout', function (event) {
$($(event.target).attr('data-target') + ' img').hide();
});
this will just hide/show the secondary image element related to the main image,
tell me if this is not exactly the behaviour you want.