Javascript Circular reference exception - javascript

I am trying to update the description field for a record in a database using a JQuery.change for the input on the view. However, after wiring up my clientside code I am now getting a circular reference exception when trying to stringify the JSON in order to make the ajax call. Any help would be greatly appreciated.
Here's the code:
<div class="divTableCell">
<label for="CheckRunDescription" id="checkRunDescriptionLabel">Description:</label>
<input type="text" id="CheckRunDescription" style="width: 270px;" />
</div>
The JQuery:
$('#CheckRunDescription')
.change(function() {
$(this).data("old", $(this).data("new") || "");
var newDetails = $(this).data("new", $(this).val());
updateCheckRunDetails(newDetails);
});
function updateCheckRunDetails(newDetails) {
var checkRunID = $('#checkRunID').val();
var js = JSON.stringify({ checkRunDetails:newDetails, checkRunID:checkRunID });
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: './PayInvoicesWS.asmx/UpdateCheckRunDetails',
data: js,
dataType: "json",
success: function (data) {
},
error: function (data) {
}
});
}

You are trying to stringify a jQuery object.
var newDetails = $(this).data("new", $(this).val());// returns `$(this)`
I am guessing you want the input value passed to the function
Try
$('#CheckRunDescription')
.change(function() {
var newDetails = $(this).val();
$(this).data("old", $(this).data("new") || "").data("new", newDetails );
updateCheckRunDetails(newDetails);
});

Related

Can't get jQuery var to PHP

I am trying to get a jQuery var into PHP so I can use it with mysql. I have searched everywhere but nothing seemed to solve it.
I have the following jQuery code:
$('.eventRow').click(function(){
var eventID = this.id;
$.ajax(
{
url: "index.php",
type: "POST",
data: { phpEventId: eventID},
success: function (result) {
console.log('success');
}
});
$('#hiddenBox').html(eventID);
console.log(eventID);
});
If I run this, the ID is shown in both #hiddenBox and in the console.log. The console also says "Succes" from the Ajax.
I am trying to get it in the php file:
$value = $_POST['phpEventId'];
echo "<div class = 'showNumber'>"."Nummer: ".$value."</div>";
It just says: Nummer:
It also gives no error whatsoever.
Thanks for your help!
Try
var eventID = $(this).attr('id');
Where this id comes from in your code ?
Passing it as JSON often gets the results I'm looking for. The server will interpret the JSON object as POST variables:
$.ajax({
url: "index.php",
type: "POST",
data: JSON.stringify({phpEventId: eventID}),
contentType: "application/json; charset=utf-8",
success: function (result) {
console.log(result);
}
});

Passing a form array to Javascript via PHP using jQuery AJAX

I'm submitting a form via AJAX and utilising jQuery and I need to find out how I cna pass form arrays to it.
For example, my html would be something like:
<input id="standard_field" type="text" name="standard_name">
<input id="some_id_1" type="text" name="my_array[my_name_1]">
<input id="some_id_2" type="text" name="my_array[my_name_2]">
<input id="some_id_3" type="text" name="my_array[my_name_3]">
Now I know you can easily get the name of the standard field in jQuery using something like:
var foo = $('standard_field').val();
But I'm not sure how to get the array data? Also, it needs to be passed to the PHP script from ajax in exactly the same way the PHP script would get it as if the form was submitted without ajax.
So an example of how I would normally pass data:
var foo = $('standard_field').val();
var loadUrl = "some_script.php";
var dataObject = { foo: foo };
getAjaxData(loadUrl, dataObject, 'POST', 'json')
.done(function(response) {
//..........
})
.fail(function() {
//......
});
// End
function getAjaxData(loadUrl, dataObject, action, type) {
return jQuery.ajax({
type: action,
url: loadUrl,
data: dataObject,
dataType: type
});
}
So firstly how can I get the data to pass from the form and secondly how can I pass it from jQuery to the PHP script so PHP get's it as an array like it would if it was POST'ed straight to the PHP script?
You should use serialize
HTML:
<form id="form1" action="" method="post">
<input id="standard_field" type="text" name="standard_name">
<input id="some_id_1" type="text" name="my_array[my_name_1]">
<input id="some_id_2" type="text" name="my_array[my_name_2]">
<input id="some_id_3" type="text" name="my_array[my_name_3]">
</form>
JS:
var dataObject = $('#form1').serialize();
var loadUrl = "some_script.php";
getAjaxData(loadUrl, dataObject, 'POST', 'json')
.done(function(response) {
//..........
})
.fail(function() {
//......
});
// End
function getAjaxData(loadUrl, dataObject, action, type) {
return jQuery.ajax({
type: action,
url: loadUrl,
data: dataObject,
dataType: type
});
}
You can use this plugin http://malsup.com/jquery/form/
Example code:
JS:
$('#your_button').change(function() {
var options = {
url: 'your_url',
type: 'POST',
dataType: 'json',
beforeSubmit: function() {
// Callback function to be invoked before the form is submitted
},
success: function(data) {
// Callback function to be invoked after the form has been submitted
},
error: function() {
// Callback function to be invoked upon error
}
};
// do something
});
PHP:
var_dump($_POST);
You can use the String.slice method to extract the label name.
var input = $('#myform input');
var data = [];
var name, label, value = '';
for(var i in input) {
name = input.eq(i).attr('name');
label = name.splice(9, -1);
value = input.eq(i).val();
data[label] = value;
}
data = JSON.stringify(data);
And for detect when it's an array you can user String.indexOf('[') like
For an unknown array structure :
array_name = name.splice(0, name.indexOf('['));
label = name.splice(name.indexOf('['), name.indexOf(']'));

Suppressing and adding parameters for ajax call

I am trying to make an ajax call for two separate click events. The difference is for the second click event the variable testOne should not be part of the call and instead there would be a new variable. How should I approach this?
var varOne = '';
var varTwo = '';
var varThree = '';
function testAjax(){
$.ajax({
type: "POST",
dataType: 'html',
url: "http://someblabla.php",
data: {
testOne: varOne,
testTwo: varOne
}
}).done(function(data) {
$('.result').html(data);
});
}
$('.clickOne').click(function(){
varOne = 'xyz123';
varTwo = '123hbz';
testAjax();
});
$('.clickTwo').click(function(){
//varOne = 'xyz123'; // I dont need this for this click
varTwo = '123hbz';
varThree = 'kjsddfag'; // this gets added
testAjax();
});
<div class="clickOne"></div>
<div class="clickTwo"></div>
Make some like this
function testAjax(data){
$.ajax({
type: "POST",
dataType: 'html',
url: "http://someblabla.php",
data: data,
}).done(function(data) {
$('.result').html(data);
});
}
$('.clickOne').click(function(){
var data= {
varOne: 'xyz123',
varTwo: '123hbz',
}
testAjax(data);
});
$('.clickTwo').click(function(){
var data= {
varThree : 'kjsddfag',
varTwo: '123hbz',
}
testAjax(data);
});
<div class="clickOne"></div>
<div class="clickTwo"></div>
You can also do the same in other way with minimum line of code, you can call the ajax on click event and pass the data based on the element triggered the click event.
like this:
$('.ajax').click(function(e){
if($(this).hasClass('clickOne')){
var data= { varOne: 'xyz123'; varTwo: '123hbz'; }
}else{
var data= { varThree : 'kjsddfag'; varTwo: '123hbz'; }
}
$.ajax({
type: "POST",
dataType: 'json',
url: "http://someblabla.php",
data: data,
}).done(function(data) {
$('.result').html(data);
});
e.preventDefault();
});
<div class="ajax clickOne"></div>
<div class="ajax clickTwo"></div>
In this way you can put as many conditions for different data variable.
You should be doing it like this:
function testAjax(data){
$.ajax({
type: "POST",
dataType: 'html',
url: "http://someblabla.php",
data: data
}).done(function(data) {
$('.result').html(data);
});
}
$('.clickOne').click(function(){
var data {
varOne = 'xyz123',
varTwo = '123hbz'
}
testAjax(data);
});
$('.clickTwo').click(function(){
var data = {
varTwo = '123hbz',
varThree = 'kjsddfag'
}
testAjax(data);
});
<div class="clickOne"></div>
<div class="clickTwo"></div>
This way you absolute control over which variables are added to which ajax call. You should not use global variables unless you really need them to be global, which doesn't seem to be the case.
You can pass whatever JavaScript object to the data parameter of the ajax method.
I just wanted to add something. I often hide value inside the value attribute of the button tags to produce something like this.
I haven't been able to test this of course but I thought it was worth mentioning.
jquery:
var fields = '';
function testAjax(){
$.ajax({
type: "POST",
dataType: 'html',
url: "http://someblabla.php",
data: fields
}).done(function(data) {
$('.result').html(data);
});
}
$('#btn').click(function(){
var varCount = 0;
var vars = $(this).val().split('|');
$.each( vars, function( key, value ) {
varCount++;
fields = fields + 'var' + varCount + '=' + value + '&';
});
fields = fields.slice(0,-1);
$(this).val('123hbz|kjsddfag');
testAjax();
});
html:
<button id="btn" value="xyz123|123hbz"></button>
A more optimized and cleaner version -
var varTwo='junk1'
var varOne='junk2'
var varThree='junk3'
function testAjax(data){
$.ajax({
type: "POST",
dataType: 'html',
url: "http://someblabla.php",
data: data,
}).done(function(data) {
$('.result').html(data);
});
}
$('.ajaxClick').click(function(){
var data={};
if(this.classList.contains('clickOne')){
data.varOne=varOne;
data.varTwo=varTwo;
}else{
data.varThree=varThree;
data.varTwo=varTwo;
}
testAjax(data);
});
<div class="ajaxClick clickOne"></div>
<div class="ajaxClick clickTwo"></div>

How to pass extra parameter in jquery post request from outside click event?

Hi i have jquery request like below ,
$('#filterForm').submit(function(e){
e.preventDefault();
var dataString = $('#filterForm').serialize();
var class2011 = document.getElementById("2011").className;
//var validate = validateFilter();
alert(dataString);
if(class2011=='yearOn')
{
dataString+='&year=2011';
document.getElementById("2011").className='yearOff';
}
else
{
document.getElementById("2011").className='yearOn';
}
alert (dataString);
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
});
and my Form is like ,
<form method="post" name="filterForm" id="filterForm">
<!-- some input elements -->
</form>
Well, I am triggering jquery submit on submit event of a form ,(it's working fine)
I want pass one extra parameter inside form which is not in above form content but it's outside in page
it's like below
[Check this image link for code preview][1]
So how can i trigger above event , on click of , element with class yearOn ( check above html snippet ) and class yearOff , with additional parameter of year set to either 2011 or 2010
$(document).ready(function () {
$('#filterForm').submit(function (e) {
e.preventDefault();
var dataString = $('#filterForm').serialize();
if ($("#2011").hasClass('yearOn')) {
dataString += '&year=2011';
$("#2011").removeClass('yearOn').addClass('yearOff');
}
else {
$("#2011").removeClass('yearOff').addClass('yearOn');
}
$.ajax({
url: "/myServlet",
type: "POST",
data: dataString,
success: function (data) {
/*var a = data;
alert(data);*/
}
});
});
});
1.) If you are using jQuery already, you can use the $.post() function provided by jquery. It will make your life easier in most cases.
2.) I have always had a successful post with extra parameters this way:
Build you extra parameters here
commands={
year:'2011'
};
Combine it with your form serialize
var dataString=$.param(commands)+'&'+$("#filterForm").serialize();
Perform your post here
$.post("myServlet",data,
function(data) {
/*var a = data;
alert(data);*/
}
);
OR use $.ajax if you really love it
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
In the end, here is the full code the way you are doing it now
$('#filterForm').submit(function(e){
e.preventDefault();
var class2011 = document.getElementById("2011").className;
//var validate = validateFilter();
alert(dataString);
if(class2011=='yearOn') {
dataString+='&year=2011';
document.getElementById("2011").className='yearOff';
} else {
document.getElementById("2011").className='yearOn';
}
commands={
year:'2011'
};
var dataString=$.param(commands)+'&'+$("#filterForm").serialize();
alert (dataString);
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
});

Data variable in jquery ajax function

I'm trying to use the code below, but it's not working:
UPDATED WORKING:
$(document).ready(function() {
$('.infor').click(function () {
var datasend = $(this).html();
$.ajax({
type: 'POST',
url: 'http://domain.com/page.php',
data: 'im_id='+datasend',
success: function(data){
$('#test_holder').html(data);
}
});
});
});
As you can see I used $datasend as the var to send but it doesn't return the value of it, only its name.
I would change
$datasend = $(this).html;
to
var datasend = $(this).html();
Next I would change
data: 'im_id=$datasend',
to
data: 'im_id='+datasend,

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