The AJAX post works when passing the predefined data as follow:
//var data = {"name" : "Testing", "email" : "testing#gmail.com", "cpf" : "9876543210"};
But I am unable to pass the data dynamically from the form.
Please help me figure this out.
POST function
$.fn.serializeObject = function()
{
var o = {};
var a = this.serializeArray();
$.each(a, function() {
if (o[this.name] !== undefined) {
if (!o[this.name].push) {
o[this.name] = [o[this.name]];
}
o[this.name].push(this.value || '');
} else {
o[this.name] = this.value || '';
}
});
return o;
};
$(function() {
$("#post").click(function() {
$("#dataIn").text(JSON.stringify($("form").serializeObject()));
$(function() {
//var data = {"name" : "Testing", "email" : "testing#gmail.com", "cpf" : "9876543210"};
var data = ("#dataIn");
$.ajax({
type: "POST",
url: "http://myhost:8080/mypath-rs/rest/beneficiaries",
//data: JSON.stringify(data),
contentType: "application/json",
});
});
});
});
The Form
<form action="" method="post" class="form-inline">
<label class="sr-only">Name</label>
<input type="text" name="name" class="form-control" id="name" placeholder="Name">
<label class="sr-only">Email</label>
<input type="text" name="email" class="form-control" id="email" placeholder="Email">
<label class="sr-only">CPF</label>
<input type="text" name="cpf" class="form-control" id="cpf" placeholder="CPF">
<button id="post" type="submit" type="button">Add </button>
</form>
<p >Json Result</p>
<pre id="dataIn" ></pre>
I am not sure if I have to serialize the form or if the JSON.stringify(data) can already do this.
Below code works perfectly:
Non dynamically, But working
$("#post1").click(function(){
var data = {"name" : "Testing", "email" : "testing#gmail.com", "cpf" : "9876543210"};
$.ajax({
type: "POST",
url: "http://myhost:8080/mypath-rs/rest/beneficiaries",
data: JSON.stringify(data),
contentType: "application/json",
});
console.log("Loaded");
});
Thank you.
The best solution I could think of at the moment:
$(function() {
$("#post").click(function() {
var data = JSON.stringify($("form").serializeObject());
$("#dataIn").text(data);
$(function() {
$.ajax({
type: "POST",
url: "http://myhost:8080/mypath-rs/rest/beneficiaries",
data: data,
contentType: "application/json",
});
});
});
});
You don't need to use JSON.stringify() twice, because you already did it on .serializeObject() returned value. Next you print it to your #dataIn container and send it via ajax request.
You can try this https://jsfiddle.net/sjc79b55/2/
Please update <button id="post" type="button">Add </button> line also
<form action="" method="post" class="form-inline">
<label class="sr-only">Name</label>
<input type="text" name="name" class="form-control" id="name" placeholder="Name">
<label class="sr-only">Email</label>
<input type="text" name="email" class="form-control" id="email" placeholder="Email">
<label class="sr-only">CPF</label>
<input type="text" name="cpf" class="form-control" id="cpf" placeholder="CPF">
<button id="post" type="button">Add </button>
</form>
<p >Json Result</p>
<pre id="dataIn" ></pre>
JS.......
$.fn.serializeObject = function()
{
var o = {};
var a = this.serializeArray();
$.each(a, function() {
if (o[this.name] !== undefined) {
if (!o[this.name].push) {
o[this.name] = [o[this.name]];
}
o[this.name].push(this.value || '');
} else {
o[this.name] = this.value || '';
}
});
return o;
};
$(function() {
$("#post").click(function() {
var jsonData = JSON.stringify($(".form-inline").serializeObject());
$("#dataIn").text(jsonData);
$(function() {
//var data = {"name" : "Testing", "email" : "testing#gmail.com", "cpf" : "9876543210"};
// var data = $("#dataIn").text();
//alert(jsonData);
$.ajax({
type: "POST",
url: "http://myhost:8080/mypath-rs/rest/beneficiaries",
data: jsonData,
contentType: "application/json",
});
});
});
});
Related
I have two forms one with product details like price, description and name. And the other with images, they both have different Ajax but they send data to the same route. I want to submit them with one button. So if I click a submit button it should submit all data at once which are price, name, image etc. How can I do this if possible?
Blade file
//Form1
<form id="form1">
<input type="hidden" value="{{csrf_token()}}" id="token"/>
<label for="name">Name</label>
<input type="text" class="form-control" name="name" id="name"
placeholder="Enter product name">
<label for="price">Price</label>
<input type="text" class="form-control" name="price" id="price"
placeholder="Enter product price">
</form>
//Form2
<form id="file_form" method="post" enctype="multipart/form-data">
<input type="hidden" value="{{csrf_token()}}" id="token"/>
<label for="images">Choose Images</label>
<input id="files" type="file" class="" name="files[]" multiple />
</form>
//Submit Button
<input type='button' class="btn btn-primary" value="Submit" id="btn"/>
Javascript
//Form1 javascript
var token = $("#token").val();
$(document).ready(function(){
$("#btn").click(function(){
var url = '{{ route('product.store') }}';
var form = $('form')[0];
var formData = new FormData(form);
formData.append('_token', token);
$.ajax({
url: url,
data: formData,
type: 'POST',
cache: false,
contentType: false,
processData: false,
success:function(data){
if($.isEmptyObject(data.error)){
$("#msg").html("Product has been added successfull");
$("#msg").fadeOut(3000);
}
}
});
});
//Form 2 Javascript
$("#btn").click(function (e) {
e.preventDefault();
file_area = $('.file-area');
progressbar = $('.progress-bar');
status_bar = $('#status');
image_list = $(".image-list");
status_bar.css('display', 'block');
status_bar.html('<div class="fa-3x">' +
'<i class="fas fa-spinner fa-pulse"></i>' +
'</div>');
if (selected_files.length < 1) {
status_bar.html('<li class="error">Please select file</li>')
} else {
var data = new FormData();
data.append('_token', token);
for (var i = 0, len = selected_files.length; i < len; i++) {
data.append('files[]', selected_files[i]);
}
fiel_feild = $('#files');
$.ajax({
url: '{{ route('product.store') }}',
type: 'POST',
data: data,
contentType: false,
cache: false,
processData: false,
success: function (response) {
result = JSON.parse(response);
if (result['status'] == 'error') {
status_bar.html(result['error']);
} else if (result['status'] == 'success') {
selected_files = [];
image_list.html('');
file_area.css('display', 'none');
status_bar.html('<li class="success">File uploaded successfully.</li>');
}
}
});
return false;
}
});
I'm trying to insert data to database using ajax with Jquery. My data is inserted without ajax perfectly but when i use ajax, there is something wrong with image. it get the file null in the controller in post method.
This is my Form in the View.
<form id="InsertForm" name="InsertForm" enctype="multipart/form-data">
<div class="form-group">
<label for="Name">Name</label>
<input type="text" class="form-control" name="StudentName" id="name" />
</div>
<div class="form-group">
<label for="LastName">Last Name</label>
<input type="text" class="form-control" name="StudentLastName" id="last" />
</div>
<div class="form-group">
<label for="Address">Address</label>
<input type="text" class="form-control" name="StudentAddress" id="address" />
</div>
<div class="form-group">
<label for="Gender">Gender</label>
<input type="text" class="form-control" name="Gender" id="gender" />
</div>
<div class="form-group">
<label for="Image">Image</label>
<input type="file" class="form-control" id="StudentImage" name="StudentImage" />
</div>
<button id="saveclick" type="submit" name="save">Save</button>
</form>
This is my Script in the View for inserting data with image.
<script>
$(document).ready(function () {
$("#saveclick").click(function (e) {
var student = {
StudentName: $("#name").val(),
StudentLastName: $("#last").val(),
StudentAddress: $("#address").val(),
Gender: $("#gender").val(),
StudentImage: $("#StudentImage").val().split('\\').pop()
};
//var formdata = new FormData($('InsertForm').get(0));
//var Student= $("#InsertForm").serialize();
var jsonData = JSON.stringify(student);
alert(jsonData);
$.ajax({
type: "POST",
url: '#Url.Action("Insert", "Student", null)',// Insert Action Method in Student Controller.
contentType: "application/json; charset=utf-8",
dataType: "json",
enctype: 'multipart/form-data',
data: jsonData,
success: function (data) {
if (data.success) {
alert(data.message);
}
},
error: function (xhr) {
alert('error');
}
});
return false;
});
});
</script>
This is my Controller action Method in Student Controller.
[HttpPost]
public JsonResult Insert(Student student)
{
if (ModelState.IsValid)
{
Student stu = new Student();
stu.StudentName = student.StudentName;
stu.StudentLastName = student.StudentLastName;
stu.StudentAddress = student.StudentAddress;
stu.Gender = student.Gender;
HttpPostedFileBase file = Request.Files["StudentImage"];
file.SaveAs(HttpContext.Server.MapPath("~/Images/") + file.FileName);
stu.StudentImage = file.FileName;
db.Students.Add(stu);
db.SaveChanges();
return Json(student);
}
else
{
ModelState.AddModelError("", "Inavlid Data Inserted");
}
return Json(student);
}
Thanks if you solve my this problem.
try following
<script type="text/javascript">
$(document).ready(function () {
$("#saveclick").click(function (e) {
var data = new FormData();
var files = fileUpload.files;
fileData.append("StudentImage", files[0]);
fileData.append("StudentName",$("#name").val());
/* add all values as above one by one for LastName,Gender,Address*/
$.ajax({
type: "POST",
url: '#Url.Action("Insert", "Student", null)',// Insert Action Method in Student Controller.
contentType: "application/json; charset=utf-8",
processdata: false,
data: data,
type:"POST"
success: function (data) {
if (data.success) {
alert(data.message);
}
},
error: function (xhr) {
alert('error');
}
});
return false;
});
});
</script>
Here is the solution that solve my great problem. We need to append the ForamData in any variable.
<script>
$(document).ready(function () {
$("#saveclick").click(function (e) {
// Create FormData object
var fileData = new FormData();
var fileUpload = $("#StudentImage").get(0);
var files = fileUpload.files;
// Looping over all files and add it to FormData object
//for (var i = 0; i < files.length; i++) {
// fileData.append(files[i].name, files[i]);
//}
fileData.append("StudentImage", files[0]);
fileData.append("StudentName", $("#name").val());
fileData.append("StudentLastName", $("#last").val());
fileData.append("StudentAddress", $("#address").val());
fileData.append("Gender", $("#gender").val());
$.ajax({
type: "POST",
url: '#Url.Action("Insert", "Student", null)',
data: fileData,
processData: false,
contentType: false,
success: function (data) {
if (data.success) {
alert(data.message);
}
},
error: function (xhr) {
alert('error');
}
});
return false;
});
});
</script>
I submit a form data using $.ajax() method, data contains image files.
while submitting I encountered with below issues:
form is not getting submitted in IE10,11
though it is submitting in chrome and FF, ajax() executing both success and error methods
I am able to submit the data in chrome and FF but it is displaying only error message
data is submitted to DB from Chrome and FF
Below is the code I am using to submit the data
$.fn.serializeObject = function()
{
var o = {};
var a = this.serializeArray();
$.each(a, function() {
if (o[this.name] !== undefined) {
if (!o[this.name].push) {
o[this.name] = [o[this.name]];
}
o[this.name].push(this.value || '');
} else {
o[this.name] = this.value || '';
}
});
return o;
};
$(function() {
$('form').submit(function() {
var senddata = JSON.stringify($('form').serializeObject());
$('#result').text(senddata);
var form_data = new FormData($(this)[0]);
form_data.append('jsonString', senddata);
var settings = {
"async": true,
"crossDomain": true,
"url": "google.com",//sample url
"method": "POST",
"processData": false,
"contentType": false,
"headers": {
"Access-Control-Allow-Origin": "*",
"cache-control": "no-cache"
},
"mimeType": "multipart/form-data",
"cache": false,
"data": form_data//,
//"dataType": "jsonp"
};
$.ajax(settings).done(function (data) {
console.log(data);
})
.success(function (data) {
alert("submitted");
})
.error(function (data){
alert("failed");
console.log(data);
});
return false;
});
});
<!-- language: lang-html -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<form action="">
<input type="hidden" name="profileTypeId" value="112" maxlength="36" size="12"/>
First Name:<input type="text" name="firstName" value="Hydtest" maxlength="12" size="12"/> <br/>
Last Name:<input type="text" name="lastName" value="3SparrowTest" maxlength="36" size="12"/> <br/>
email:<input type="text" name="emailId" value="jackSparrow#testmail.com" maxlength="36" size="12"/> <br/>
Address1:<input type="text" name="address1" value="PiratesTest" maxlength="36" size="12"/> <br/>
<input type="hidden" name="address2" value="PiratesTest" maxlength="36" size="12"/>
<input type="hidden" name="city" value="caribbean" maxlength="36" size="12"/>
Profile Image: <input name="file" type="file" /><br />
<p><input type="submit" /></p>
</form>
<!-- end snippet -->
I think the form is not submitting because of images. Could you try base64 encoding the images before submitting them to the server.
Here is a reference to base64 encode images using javascript:
https://davidwalsh.name/convert-image-data-uri-javascript
Hello everyone I am newbie in java-script so i hope you can help me with my issue. So I have the form, it look something like this:
<form method="post">
Field1: <input type="text" name="field1"><br>
Field2: <input type="text" name="field2"><br>
<input type="submit" value="Submit">
</form>
I need to take data from the form and make xml request, the xml request should look like this
<root>
<header section>
<section>data</section>
</header section>
<data section>
<field1>data</field2>
<field2>data</field2>
</data section>
</root>
After that i have to display xml response on the page.
I made xml request
<script>
$('.button').click( function() {
$(".results").append("<ul></ul>");
$.ajax({
type: "GET",
dataType: 'xml',
url: 'response.xml',
success: function(xml) {
$(xml).find('root').each(function(){
var sField1 = $(this).find('field1').text();
var sField2 = $(this).find('field2').text();
$("<li></li>").html(sTitle + ", " + sPublisher).appendTo(".results ul");
});
},
error: function() {
alert("An error occurred while processing XML file.");
}
});
});
</script>
But I don't know how to take data from the form and make request. Can you help me with it? Thanks a lot.
// You can use jQuery to build XML document:
function buildXmlFromForm(form) {
var xml = $('<XMLDocument />');
xml.append (
$('<header-section />').append(
$('<section />').text('data')
)
).append (
$('<data-section />').append(
$('<field1 />').text(form.find("input[name='field1']").val())
).append(
$('<field2 />').text(form.find("input[name='field2']").val())
)
);
return xml.html();
}
// you should use POST or PUT method (not GET) to post xml-data to server side
$( "#form1" ).submit(function(event) {
event.preventDefault();
$("#results").append("<ul></ul>");
var xmlString = buildXmlFromForm($(this));
$("#xmlSrc").val(xmlString);
$.ajax({
type: "POST",
dataType: 'xml',
url: 'response.xml',
data: xmlString,
success: function(respData) {
$("<li></li>").html("ok: "+respData).appendTo("#results ul");
console.log(respData);
},
error: function(errorData) {
$("<li></li>").html("error: "+errorData.statusText).appendTo("#results ul");
console.log(errorData);
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form method="post" id="form1">
Field1: <input type="text" name="field1" value="***v1***"><br/>
Field2: <input type="text" name="field2" value="***v2***"><br/><br/>
<input type="submit" value="Submit">
</form>
<hr/>
<textarea id="xmlSrc" cols="70" rows="5"></textarea>
<div id="results"/>
Try this:
serialize will return formData of current form
You must have unique identifier for your form to be used as querySelector
$('#myForm').on('submit', function(e) {
e.preventDefault();
var formData = $(this).serialize();
$(".results").append("<ul></ul>");
$.ajax({
type: "GET",
dataType: 'xml',
url: 'response.xml',
data: formData,
success: function(xml) {
$(xml).find('root').each(function() {
var sField1 = $(this).find('field1').text();
var sField2 = $(this).find('field2').text();
$("<li></li>").html(sTitle + ", " + sPublisher).appendTo(".results ul");
});
},
error: function() {
alert("An error occurred while processing XML file.");
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form method="post" id="myForm">
Field1:
<input type="text" name="field1">
<br>Field2:
<input type="text" name="field2">
<br>
<input type="submit" value="Submit">
</form>
<form method="POST" class="userform" id="loginForm">
<div data-role="content">
<h2> Login:</h2>
<div data-role="fieldcontain">
<input name="email" placeholder="put your name" type="email" data-mini="true">
</div>
<div data-role="fieldcontain">
<input name="password" placeholder="enter your password" type="password" data-mini="true">
</div>
<input type="submit" data-theme="a" value="submit" id="submitButton">
<h5 align="center">
Forget password?
</h5>
</div>
</form>
this is my login.js
$.fn.serializeObject = function()
{
var o = {};
var a = this.serializeArray();
$.each(a, function() {
if (o[this.name]) {
if (!o[this.name].push) {
o[this.name] = [o[this.name]];
}
o[this.name].push(this.value || '');
} else {
o[this.name] = this.value || '';
}
});
return o;
};
var $bro = $('#loginForm');
$('#submitButton').click(function(e) {
//console.log("submit button has been clicked");
e.preventDefault(); //cancel form submit
var jsObj = $bro.serializeObject()
, ajaxObj = {};
//console.log(jsObj);
ajaxObj = {
type: "POST",
url: "http://192.168.0.100:8080/AdvancedLibrarySystem/api/v1/login",
data: JSON.stringify(jsObj),
contentType:"application/json",
error: function(jqXHR, textStatus, errorThrown) {
console.log("Error " + jqXHR.getAllResponseHeaders() + " " + errorThrown);
},
success: function(data) {
console.log(data);
if(data[0].status == '200') {
alert("Welcome!!!")
$('#div_ajaxResponse').text( data[0] );
$.mobile.changePage('home.html');
}
else{
alert("Incorret Username or Password!!!")
}
},
complete: function(XMLHttpRequest) {
//console.log( XMLHttpRequest.getAllResponseHeaders() );
},
dataType: "json" //request JSON
};
$.ajax(ajaxObj);
});
I'm trying to use an authentification in phonegap via ajax but if i'm trying to run that code in chrome console it works fine but when i'm using it in my phonegap application it's not giving response in the server... Anyone can help me out please...
I am not sure what you mean by 'not giving response in the server', but one thing worth checking out is the cross-domain options in the config.xml of your phonegap project. There should be an "access" tag in there that specifies what domains can be accessed. Try setting it to "*" and try again.