We Keep Coding

How do I display external API search results in a table?

I am a final year student and am creating a food log web application for my major project. I have created a search function that allows me to search and display external API results, but now I wish to display them in a table, can anyone help please?
I would prefer if it would be a table that can be filtered, eg, the columns ordered ascending/descending?
Thanks
function get foodItem(userInput) {
var storedSearchItem;
$('.resultContainer').html('');
$.ajax({
type: 'GET',
async: false,
url: 'https://api.nutritionix.com/v1_1/search/'+userInput+'?'+
'fields=item_name%2Citem_id%2Cbrand_name%2Cnf_calories%2Cnf_total_fat&appId=325062a4&appKey=bf1a30b2066602dc6f33db888cd53bd3',
success: function(d) {
storedSearchItem = d.hits;
}
});
storedSearchItem.map(function(item) {
var x = item.fields
$('.resultContainer').append(
'<div class="itemBar">'+
'<h2>' + x.item_name + '<h2>' +
'<h3>Calories: ' + x.nf_calories + '<h3>' +
'<h3>Serving Size: ' + x.nf_serving_size_qty + ' ' + x.nf_serving_size_unit +'<h3>' +
'<h3>Total Fat: ' + x.nf_total_fat + '<h3>' +
'</div>'
);
});
}//ends get result function
function searchValue() {
var formVal = document.getElementById('itemSearch').value; //value from search bar
getFoodItem(formVal);
}
$('#searchForm').submit(function(e) {
e.preventDefault();
});`

You need to append your table in the success function
your code will look like something like this
success: function(d) {
storedSearchItem = d.hits;
storedSearchItem.map(function(item) {
var x = item.fields
$('.resultContainer').append(
'<div class="itemBar">'+
'<h2>' + x.item_name + '<h2>' +
'<h3>Calories: ' + x.nf_calories + '<h3>' +
'<h3>Serving Size: ' + x.nf_serving_size_qty + ' ' + x.nf_serving_size_unit +'<h3>' +
'<h3>Total Fat: ' + x.nf_total_fat + '<h3>' +
'</div>'
);
});
}

using javascript how do i put rss feed into a list and show only 4 of them

I have the rss titles going into a dropdown box and they change when each one is clicked on but i want about 4 rss feeds showing on the page so i dont need the dropdown box.
$(document).ready(function()
{
$.ajax({
type: "GET",
url: "rss_warriors.php",
dataType: "xml",
cache: false,
success: parse_rss
});
function parse_rss(rss_feed)
{
console.log(rss_feed);
$('#output').append('<select>');
$(rss_feed).find("item").each(function()
{
$('select').append('<option value="' +
$(this).find('title').text() + '">' +
$(this).find('title').text() + '</option>');
});
line_record(0,rss_feed);
$("select").on("change", function(evt)
{
line_record( $("select option:selected").index(),rss_feed)
});
}
function line_record(sel_index,rss_feed)
{
var local_index = sel_index;
var image_url;
var item_title;
var item_description;
var item_pubDate;
image_url = $(rss_feed).find("item").eq(local_index).find("thumbnail").last().attr("url");
item_title = $(rss_feed).find("item").eq(local_index).find("title").text();
item_description = $(rss_feed).find("item").eq(local_index).find("description").text();
item_pubDate = $(rss_feed).find("item").eq(local_index).find("pubDate").text();
$("#img_warriors").empty();
$("#txt_warriors").empty();
$("#img_warriors").append("<img src='" + image_url + "'>");
$("#txt_warriors").append("<span class='title_large'>" + item_title + "</span>");
$("#txt_warriors").append("<p>" + item_description + "</p>");
$("#txt_warriors").append("<p>" + item_pubDate + "</p>");
}
});

Not sure if it is what you mean, but what about :
$(rss_feed).find("item").each(function(i) {
if (i <=3) {
$('select').append('<option value="' +
$(this).find('title').text() + '">' +
$(this).find('title').text() + '</option>');
}
});

Display php data json_encoded with ajax

I convert my php code to json with json_encoded function.
After I write ajax code to display my data in ajax but when running don't display my data.
My json code:
[
{"Name":"fasher","Description":"2500 kg","Namyandegi":"20,500,000","Bazar":"22,410,000"}
,
{"Name":"shob","Description":"1000 kg","Namyandegi":"10,400,000","Bazar":"12,220,000"}
]
and ajax file:
<script type='text/javascript'>
$(document).ready(function(){
$.getJSON('saipa.php', function(data) {
$.each(data, function(key, val) {
$('ul').append('<li id="shoker">' + val.Name + ' ' + val.Description + ' ' + val.Namyandegi + ' ' + val.Bazar + '</li>');
});
});
});
</script>
<body>
<ul><li id="shoker"></li></ul>
</body>

Use the index overload $.each()
$.each(data, function(index) {
$('ul').append('<li id="shoker">' + data[index].Name + ' ' +
data[index].Description + ' ' +
data[index].Namyandegi + ' ' +
data[index].Bazar + '</li>'
);
});

Error in the Javascript Jquery code

There is an error showing on this code, I have looked through it for hours and cannot find it, could anyone assist please
$(document).ready(function () {
$('#show-records').click(function () {
$.post('./includes/processes.php', function (data) {
var pushedData = jQuery.parseJSON - (DATA);
var htmldata = " ";
$.each(pushedData, function (i, serverData) {
htmldata = htmldata, +'- ' + serverData.Style + ', ' + serverData.Brand + ', ' + serverData.Model + ', ' + serverData.January Registrations + ', ' + serverData.February Registrations + ', ' + serverData.March Registrations + '<br>';
$('#show-list').html(htmldata);
});
});
});
});

htmldata = htmldata, + '
is invalid syntax, try
htmldata = htmldata + '

There is an extra comma after html data on that line. When appending to variables you should try and use this syntax too, enclosing all other strings in "string" .
Change that line of code to:
htmldata += ', - ' + serverDat...
The += is the same as writing htmldata = htmldata + ', -' + .. which is easier to read and maintain.

Handling JSON Object With jQuery?

I'm having trouble handling a JSON object that I'm getting back from an AJAX request.
It's a simple flat JSON object, and all I want to do is write the responses back onto the page.
Can anyone point out how to loop over these objects and output the values? I just keep getting [undefined] or [object] written
Code here:
$.ajax({
type: "POST",
url: "func/chatResponse.php",
data: dataString,
success: function() {
$.getJSON('func/chatResponse.php?a=jsonLatest', function(data) {
$.each(data, function(index) {
//items.push('<li id="' + key + '">' + val + '</li>');
$('body').append('<li id="' + data.user + '">' + data.user + '</li>');
alert(data);
});
});
alert("done");
}
});
JSON sample here
[
{"user":"someguy","message":"my message","timestamp":"2011-04-19 17:26:09"},
{"user":"Cheyne","message":"Hey There ... Nice site","timestamp":"2011-04-19 17:26:09"}
]

data is the array, while you want the items inside the array.
$.each doesn't change data to become the items, instead it passes individual items as the second parameter to the function you supply:
$.each(data, function (index, item) {
// Use item in here
$('body').append('<li id="' + item.user + '">' + item.user + '</li>');
});
Alternatively, you can use data[index]:
$.each(data, function (index) {
// use data[index] in here
$('body').append('<li id="' + data[index].user + '">' + data[index].user + '</li>');
});
By the way, avoid ugly string concatenation with:
$('<li>', {id: item.user, text: item.user}).appendTo('body');

What you want is
$.each(data, function(index) {
//items.push('<li id="' + key + '">' + val + '</li>');
$('body').append('<li id="' + data[index].user + '">' + data[index].user + '</li>');
alert(data);
});