I am using jqueryfiletree to display a folder of files on the web server. I also have php to parse the csv and display it on the page. How can I pass the selected jqueryfiletree file to the php in the page so it displays the selected csv? Here's what I have so far:
Javscript:
<script src="jquery.js" type="text/javascript"></script>
<script src="jquery.easing.js" type="text/javascript"></script>
<script src="jqueryFileTree.js" type="text/javascript"></script>
<link href="jqueryFileTree.css" rel="stylesheet" type="text/css"
media="screen" />
<script type="text/javascript">
$(document).ready( function() {
$('#fileTreeDemo_1').fileTree({ root: '../data/', script:
'connectors/jqueryFileTree.php' }, function(file) {
alert(file);
var file = "<?php echo $file;?>";
});
});
</script>
</head>
<body>
<h1>Select a file to view</h1>
<div class="menuleftcontent">
<div id="fileTreeDemo_1" class="demo"></div>
</div>
</td><td>
PHP
<div class="maincontent">
<?php
$row = 1;
if (($handle = fopen($file, "r")) !== FALSE) {
echo '<table border="1">';
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
$num = count($data);
if ($row == 1) {
echo '<thead><tr>';
}else{
echo '<tr>';
}
for ($c=0; $c < $num; $c++) {
//echo $data[$c] . "<br />\n";
if(empty($data[$c])) {
$value = " ";
}else{
$value = $data[$c];
}
if ($row == 1) {
echo '<th>'.$value.'</th>';
}else{
echo '<td>'.$value.'</td>';
}
}
if ($row == 1) {
echo '</tr></thead><tbody>';
}else{
echo '</tr>';
}
$row++;
}
echo '</tbody></table>';
fclose($handle);
}
?>
</div>
I can see two problems so far. Firstly, you do not have a semi-colon to end the line on this line:
var file = "<?php echo $file;?>";
(i've added it).
Also, $file is not defined in your php. And you can not try and define it in javascript (I fear that is what you are trying to do maybe?).
Best options is to make an AJAX request so you can send it to the server side and use it there (which is what you want?). And of course, you can then respond data back to the front end.
THis is a rough idea:
$('#fileTreeDemo_1').fileTree({ root: '../data/', script:
'connectors/jqueryFileTree.php' }, function(file) {
$.post('myphpfile.php', {file:file}, function(response){
// handle response
});
});
and then in php, check for the post with if(isset($_POST['file'])) ,etc etc
Related
I’m trying to make a user input by reading the contents of my server directory with php. So the user can select a file, in my case a CSV file which gets saved into a variable and then gets processed further down in my JavaScript code that should make a chart from it. All it does now is output the path string of the selected file. I tried using the json_encode function but it still doesn’t seem to work.
<?php
$dir = '/var/www/html/';
$graphen = '';
if (!isset($_POST['submit'])) {
if ($dp = opendir($dir)) {
$files = array();
while (($file = readdir($dp)) !== false) {
if (!is_dir($dir . $file)) {
$files[] = $file;
}
}
closedir($dp);
} else {
exit('Directory not opened.');
}
if ($files) {
echo '<form action="' . $_SERVER['PHP_SELF'] . '" method="post">';
foreach ($files as $file) {
echo '<input type="checkbox" name="files[]" value="' . $file . '" /> ' .
$file . '<br />';
}
echo '<input type="submit" name="submit" value="submit" />' .
'</form>';
} else {
exit('No files found.');
}
} else {
if (isset($_POST['files'])) {
foreach ($_POST['files'] as $value) {
$graphen .= $dir . $value . '<br />';
}
} else {
exit('No files selected');
}
}
echo $graphen;
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<script src="highcharts.js"></script>
<script src="data.js"></script>
<script src="exporting.js"></script>
<script src="export-data.js"></script>
<script src="accessibility.js"></script>
<script src="jquery-3.5.1.min.js"></script>
</head>
<body>
<div id="container1"></div>
<script type="text/javascript">
var fileName = <?php echo json_encode($graphen); ?>; //doesn't work
$.ajax({
type: "GET",
url: fileName,
success: function (data) {
drawChart(data)
}
});
function drawChart(raw_data) {
//my code to draw chart is here and working
}
If you assign a String to a variable in JavaScript, use " or ':
var x = "Hello";
Your current code results in
var fileName = <?php echo json_encode($graphen); ?>; => var fileName = variable;
Add quotes and it should work:
var fileName = '<?php echo json_encode($graphen); ?>'; => var fileName = 'variable';
I have some code where I need to update a column of a table (MySQL) calling another php file without leaving the page where some tables might allow inline editing.
I have a point in the php echoing of the page, where an icon can be clicked to save input. The code at that point is:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<?php
$sql = "SELECT * FROM table WHERE a_column='certain_value'";
if (mysqli_query($conn, $sql)) {
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
$note = $row["note"];
$code = $row["code"];
}
}
}
// some tabled elements not relevant for the issue
echo "<input type='text' id='note_1' name='note_1' value=$note readonly>";
echo "<input type='text' id='new_note' name='new_note'>";
echo "<img src='icon_to_click.png' id='icon_to_click' name='icon_to_click' >";
?>
<script type="text/javascript">
$(document).ready(function() {
$('#icon_to_click').click(function() {
var note_orig = document.getElementById('note_1').value;
var code_val = '<?php echo "$code" ?>';
var note_new = document.getElementById('new_note').value;
if (note_new != note_orig) {
$.ajax({
type: 'POST',
url: 'update_notes.php',
data: {'code': code_val, 'note': note_new},
success: function(response){
document.getElementById('note_1').value = note_new;
}
});
}
});
});
The relevant code of update_notes.php is:
<?php
// connection
$unsafe_note = $_POST["note"];
$code = $_POST["code"];
require "safetize.php"; // the user input is made safe
$note = $safetized_note; // get the output of safetize.php
$sqlupdate = "UPDATE table SET note='$note' WHERE code='$code'";
if (mysqli_query($conn, $sqlupdate)) {
echo "Note updated";
} else {
echo "Problem in updating";
}
// close connection
?>
Now when I run the code and look at the tool, it gives me the error: Uncaught ReferenceError: $ is not defined, linking the error to this line of the previous js code:
$(document).ready(function() {
So, how can I fix that?
It means that you tried to use Jquery in your Javascript Code without calling Jquery Library or the code is called without the library was fully loaded.
I notice :
That you haven't closed your script tag
You use Jquery so you can use $('#id_name') to select element by Id instead of document.getElementById('note_1')
Get element value by using Element.val() instead of Element.value
Try to edit your code like this
<?php
$sql = "SELECT * FROM table WHERE a_column='certain_value'";
if (mysqli_query($conn, $sql)) {
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
$note = $row["note"];
$code = $row["code"];
}
}
}
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Some title</title>
</head>
<body>
<form method="post" accept-charset="UTF-8">
<input type='text' id='note_1' name='note_1' value=<?= $code ?> readonly>";
<input type='text' id='new_note' name='new_note'>";
<img src='icon_to_click.png' id='icon_to_click' name='icon_to_click' >";
</form>
<script>
$(document).ready(function() {
$('#icon_to_click').click(function() {
var note_orig = $('#note_1').val();
var code_val = '<?= $code ?>';
var note_new = $('#new_note').val();
if (note_new != note_orig) {
$.ajax({
type: 'POST',
url: 'update_notes.php',
data: {'code': code_val, 'note': note_new},
success: function(response){
$('#note_1').val() = note_new;
}
});
}
});
});
</script>
</body>
</html>
Hey I have faced same error a day before,this is because you have missed using a jquery library script that is needed. please try using some Updated Jquery CDN . :) It will definitely help
OR
include the jquery.js file before any jquery plugin files.
This postprovides sample code using obtaining a server file list as an example. Here is the code I have used:
<html lang="en-US">
<head>
<meta charset="UTF-8">
<title>How to create form using jQuery UI</title>
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.10.3/themes/pepper-grinder/jquery-ui.css" media="screen" rel="stylesheet" type="text/css">
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.0/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.10.2/jquery-ui.min.js" type="text/javascript"></script>
<script type="text/javascript">
$(function() {
$.get('getfilename.php', { dir : '/ajax1/' }, function(data) {
// you should now have a json encoded PHP array
$.each(data, function(key, val) {
alert('index ' + key + ' points to file ' + val);
});
}, 'json');
alert ("ok");
});
</script>
</head>
<body>
<h1>Get file names... </h1>
</body>
</html>
getfilename.php
$dir = $_REQUEST['dir'] ;
$dir = $_SERVER['DOCUMENT_ROOT'] . $dir;
$filesArray = array();
$Counter = 0;
$files = scandir($dir);
foreach ($files as &$file) {
if ($file!='.' && $file!='..' ) {
$filesArray[$Counter] = $file;
echo $filesArray[$Counter].'';
$Counter++;
}
}
echo json_encode($filesArray);
My problem is that the javascript alert alert('index ' + key + ' points to file ' + val); fails to display anything on the page. The script is working because I get a response in the Firebug console log.
ajax.jsajax.phpindex.html["ajax.js","ajax.php","index.html"]
What I need to change on the script to return this information to the html page so that I can use the JSON for further processing ?
Thanks.
With your debug you broke the JSON output in PHP. So, remove:
echo $filesArray[$Counter].'';
Also, before any output, you should add JSON header:
header('Content-Type: application/json');
At the end, your PHP file should look like this:
$dir = $_REQUEST['dir'] ;
$dir = $_SERVER['DOCUMENT_ROOT'] . $dir;
$filesArray = array();
$files = scandir($dir);
foreach ($files as &$file) {
if ($file!='.' && $file!='..' ) {
$filesArray[] = $file;
}
}
header('Content-Type: application/json');
echo json_encode($filesArray);
can some one help me out in updating edited value in mysql db using jquery/php.
I have three buttons edit/save/cancel
when i click on edit button span data pushed into input text and edit button replaced with save button!!
when i click on edit button i'll get span data in my text box with save and cancel button but when i try to update using save button its not updating in my db and in UI
Code
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script type="text/javascript">
function showdata()
{
$.ajax({
url:"pages/feeds.php",
type:'post',
async:false,
data:{
showtable:1
},
success:function(re){
$('#showdata').html(re);
}
});
}
$('#orders').delegate('.editOrder','click',function(e){
e.preventDefault(e);
var $li = $(this).closest('li'); $li.find('input.name').val($li.find('span.name').html());
$li.addClass('edit');
});
$('#orders').delegate('.cancelEdit','click',function(e){
e.preventDefault(e);
$(this).closest('li').removeClass('edit');
});
//Edit Code
$('body').delegate('.edit','click',function(){
var IdEdit = $(this).attr('ide');
$.ajax({
url:"pages/feeds.php",
type:"post",
data:{
editvalue:1,
id:IdEdit
},
success:function(show)
{
$('#id').val(show.id);
$('#url1').val(show.url);
}
});
});
//Ends
//Update Starts
$('.update').click(function(){
var id = $('#id').val()-0;
var urls = $('#url1').val();
$.ajax({
url:"pages/feeds.php",
type:"post",
async:false,
data:{
update:1,
id:id,
upurls:urls
},
success:function(up)
{
$('input[type=text]').val('');
showdata();
},
error:function(){
alert('error in updating');
}
});
});
//UPdate Ends
</script>
<style type="text/css">
ul li .edit{
display:none;
}
ul li.edit .edit{
display:initial;
}
ul li.edit .noedit{
display:none;
}
</style>
</head>
<body>
<ul id="orders">
<?php
$sql = "select * from demo";
$result = mysql_query($sql);
while($row = mysql_fetch_object($result))
{
?>
<li>
<span class="noedit name" value='<?php echo $row->id;?>'><?php echo $row->url;?></span>
<input id="url1" class="form-control edit name" value="<?php echo $row->id;?>"/>
<a ide='<?php echo $row->id;?>' id="edit" class='editOrder' href="#" style="display:block-inline;">EDIT</a>
<a idu='<?php echo $row->id;?>' id="update" class='update saveEdit' href='#' style='display:none;'>SAVE</a>
<a idd='<?php echo $row->id;?>' id="delete" class='delete' href="#" style="display:block-inline;">DELETE</a>
<a idc='<?php echo $row->id;?>' id="cancel" class='cancelEdit edit' href='#' style='display:none;'>CANCEL</a>
</li>
<?php } ?>
</ul>
</body>
</html>
<?php
//Edit Starts
if(isset($_POST['editvalue']))
{
$sql = "select * from deccan where id='{$_POST['id']}'";
$row = mysql_query($sql);
$rows = mysql_fetch_object($row);
header("Content-type:text/x-json");
echo json_encode($rows);
exit();
}
//Ends
//UPdate Starts
if(isset($_POST['update']))
{
$sql = "
update deccan
set
url='{$_POST['upurls']}'
where id='{$_POST['id']}'
";
$result = mysql_query($sql);
if($result)
{
//alert('success');
echo 'updated successfully';
}
else
{
//alert('failed');
echo 'failed to update';
}
}
?>
Alright. I was still missing the following code from you, so you'll have to add these yourself:
The HTML element with parameter id="id" needed for $('#id').val(text.id);
The HTML element with parameter id="url1" needed for $('#url1').val(text.url);
The PHP response code for JS function showdata(); inside feeds.php
Since I don't have your database here, I was unable to test the code. It should work fine, but if anything is wrong, just let me know:
PHP file: index.php
<?php
// Include PDO class
include_once("pdo.class.php");
// Database connection settings
define("DB_HOST", "localhost");
define("DB_USER", "username");
define("DB_PASS", "password");
define("DB_NAME", "database");
?>
<!DOCTYPE HTML>
<html lang="en">
<head>
<meta charset="UTF-8">
<!-- CSS resources -->
<link rel="stylesheet" type="text/css" href="style.css">
<!-- Javascript resources -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script src="main.js"></script>
<title>Update Script</title>
</head>
<body>
<ul id="orders">
<?php
// Instantiate database
$db = new Database;
// Try getting data from database
Try {
// Query
$db->query("SELECT * FROM demo");
// Get results
$data = $db->resultset();
// Echo reults
foreach($data as $row){ ?>
<li>
<span class="noedit name" value="<?php echo $row['id']; ?>"><?php echo $row['url']; ?></span>
<input id="url1" class="form-control edit name" value="<?php echo $row['id']; ?>" />
<a data-ide="<?php echo $row['id']; ?>" class='editOrder' href="#" style="display:block-inline;">EDIT</a>
<a data-idu="<?php echo $row['id']; ?>" class='update saveEdit' href='#' style='display:none;'>SAVE</a>
<a data-idd="<?php echo $row['id']; ?>" class='delete' href="#" style="display:block-inline;">DELETE</a>
<a data-idc="<?php echo $row['id']; ?>" class='cancelEdit edit' href='#' style='display:none;'>CANCEL</a>
</li>
<?php }
//Catch any database errors
} Catch(PDOException $e){
echo "Database error:". $e->getMessage();
}
?>
</ul>
</body>
</html>
Javascript file: main.js
$('#orders').delegate('.editOrder','click',function(e){
e.preventDefault();
var $li = $(this).closest('li');
$li.find('input.name').val($li.find('span.name').html());
$li.addClass('edit');
});
$('#orders').delegate('.cancelEdit','click',function(e){
e.preventDefault();
$(this).closest('li').removeClass('edit');
});
//Edit Code
$('body').delegate('.edit','click',function(){
var IdEdit = $(this).attr('data-ide');
$.ajax({
url: "pages/feeds.php",
type: "POST",
data: 'editvalue=1&id='+IdEdit,
success: function(text){
$('#id').val(text.id);
$('#url1').val(text.url);
}
});
});
//Update Code
$('.update').click(function(){
var id = $('#id').val()-0;
var urls = $('#url1').val();
$.ajax({
url: "pages/feeds.php",
type: "POST",
async: false,
data: 'update=1&id='+id+'&upurls='+urls,
success: function(text){
$('input[type=text]').val('');
showdata();
},
error:function(){
alert('Error in updating');
}
});
});
function showdata(){
$.ajax({
url: "pages/feeds.php",
type: "POST",
async: false,
data: 'showtable=1',
success:function(text){
$('#showdata').html(text);
}
});
}
CSS file: style.css
ul li .edit{
display:none;
}
ul li.edit .edit{
display:initial;
}
ul li.edit .noedit{
display:none;
}
PHP file: feeds.php
<?php
// Include PDO class
include_once("pdo.class.php");
// Database connection settings
define("DB_HOST", "localhost");
define("DB_USER", "username");
define("DB_PASS", "password");
define("DB_NAME", "database");
// Instantiate database
$db = new Database;
// Edit
if(isset($_POST['editvalue']) && $_POST['editvalue'] == 1){
// Try getting data from database
Try {
// Query
$db->query("SELECT * FROM deccan WHERE id = :id");
// Prepare POST data (to prevent SQL injection)
$db->bind(":id", $_POST['id']);
// Get result
$data = $db->single();
// Set header JSON
header("Content-type:text/x-json");
// Return result
echo json_encode($rows);
} Catch(PDOException $e){
echo "Database error:". $e->getMessage();
}
} else if(isset($_POST['update']) && $_POST['update'] == 1){
// Try updating data in database
Try {
// Query
$db->query("UPDATE deccan SET url = :url WHERE id = :id");
// Prepare POST data (to prevent SQL injection)
$db->bind(":url", $_POST['upurls']);
$db->bind(":id", $_POST['id']);
// Execute Query
$db->execute();
// Return succes
echo 'updated successfully';
} Catch(PDOException $e){
echo "Database error:". $e->getMessage();
}
} else if(isset($_POST['showtable']) && $_POST['showtable'] == 1){
/*
This part was not included in your code, so write it
yourself using above data as examples
*/
}
?>
PHP file: pdo.class.php
<?php
Class Database {
private $host = DB_HOST;
private $user = DB_USER;
private $pass = DB_PASS;
private $dbname = DB_NAME;
private $dbh;
private $error;
private $stmt;
public function __construct(){
// Set DSN
$dsn = 'mysql:host=' . $this->host . ';dbname=' . $this->dbname;
// Set options
$options = array(
PDO::ATTR_PERSISTENT => true,
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION
);
// Create a new PDO instanace
try{
$this->dbh = new PDO($dsn, $this->user, $this->pass, $options);
}
// Catch any errors
catch(PDOException $e){
$this->error = $e->getMessage();
return $this->error;
}
}
public function query($query){
$this->stmt = $this->dbh->prepare($query);
}
public function bind($param, $value, $type = null){
if (is_null($type)) {
switch (true) {
case is_int($value):
$type = PDO::PARAM_INT;
break;
case is_bool($value):
$type = PDO::PARAM_BOOL;
break;
case is_null($value):
$type = PDO::PARAM_NULL;
break;
default:
$type = PDO::PARAM_STR;
}
}
$this->stmt->bindValue($param, $value, $type);
}
public function execute(){
return $this->stmt->execute();
}
public function column(){
$this->execute();
return $this->stmt->fetchAll(PDO::FETCH_COLUMN);
}
public function resultset(){
$this->execute();
return $this->stmt->fetchAll(PDO::FETCH_ASSOC);
}
public function single(){
$this->execute();
return $this->stmt->fetch(PDO::FETCH_ASSOC);
}
public function rowCount(){
return $this->stmt->rowCount();
}
public function lastInsertId(){
return $this->dbh->lastInsertId();
}
public function beginTransaction(){
return $this->dbh->beginTransaction();
}
public function endTransaction(){
return $this->dbh->commit();
}
public function cancelTransaction(){
return $this->dbh->rollBack();
}
public function debugDumpParams(){
return $this->stmt->debugDumpParams();
}
}
?>
I would normally have two scripts (.php) files.
One to display the form and one to catch the submission (possibly via ajax)
You can have both in the same .php file but then you'd want to check before outputting any text whether you have any POST data to process.
If you go with two files
view file:
<html>
<body>
<form method="POST" action="path/to/formname_submit.php">
your form fields go here
<input name="somefield"/>
...
</form>
<script>
//your jquery code
....
</script>
<body>
</html>
submit file
<?php
if (empty($_POST['id'])){
die("no ID");
};
if (empty($_POST['editvalue'])){
die("no editvalue");
}
//get a database connection
$db = mysqli(DBHOST,DBUSER,DBPASS,DBNAME);
$db->set_charset("utf8");
// read in the POST data
//should do some more validation / anti SQL injection
$editvalue = $db->escape_string($_POST['editvalue']);
$id = intval($_POST['id']);
$sql = "UPDATE sometable SET `field` = '$editvalue' WHERE id=$id";
if ($db->query($sql)){
echo 'Success';
}
else {
echo 'UPDATE ERROR:'.$db->errno.': '.$db->error;
}
your jquery can now send the data to the second script and see if the data coming back from the call is 'Success' and display an error if it's not.
Im trying to get my PHP script called from AJAX (that is in my main php file).
Here's an example of what it is supposed to do: http://jsfiddle.net/xfuddzen/
The HTML source code shows only desk_box DIV being created (which is in my main.php). station_info DIV (being created in the display_station.php) is not there. How can I fix this? thanks in advance
Problem: DIVs from my display_stationinfo.php are not being created by using the AJAX call.
main.php with JQuery/AJAX part:
<div id="map_size" align="center">
<?php
//didsplay Desk stations in the map
while($row = mysqli_fetch_assoc($desk_coord_result)){
//naming X,Y values
$id = $row['coordinate_id'];
$x_pos = $row['x_coord'];
$y_pos = $row['y_coord'];
//draw a box with a DIV at its X,Y coord
echo "<div class='desk_box' data='".$id."' style='position:absolute;left:".$x_pos."px;top:".$y_pos."px;'>id:".$id."</div>";
} //end while loop for desk_coord_result
?>
<script type="text/javascript">
//Display station information in a hidden DIV that is toggled
//And call the php script that queries and returns the results LIVE
$(document).ready(function() {
$('.desk_box').each((function(){(this).click(function() {
var id = $(this).attr("data")
$("#station_info_"+id).toggle();
$.ajax({
url: 'station_info.php',
data: { 'id': id },
type: 'POST',
dataType: 'json',
success: function(json) {
$("#station_info_"+id).css({'left':json.x_pos ,'top': json.y_pos}).append('<p>Hello the id is:'+ json.id +'</br>Section:'+ json.sec_name +'</p>');
}//end success
});//end ajax
});//end click
});//end ready
</script>
</div> <!-- end map_size -->
display_station.php (script that I want to call):
<?php
include 'db_conn.php';
//query to show workstation/desks information from DB for the DESKS
$station_sql = "SELECT coordinate_id, x_coord, y_coord, section_name FROM coordinates";
$station_result = mysqli_query($conn,$station_sql);
//see if query is good
if ($station_result === false) {
die(mysqli_error());
}
//Display workstations information in a hidden DIV that is toggled
$html = '';
if($station_result->num_rows > 0){
while($row = $station_result->fetch_object()) {
$id = $row->coordinate_id;
$html .= "<div class='station_info_' id='station_info_$id' style='position:absolute;left:{$row->x_coord}px;top:{$row->y_coord}px;'>Hello the id is:$id</br>Section:{$row->section_name}</br></div>";
}
}
else{
// no results - may want to do something with $html
$html = "no result given";
}
$station_result->free();
$conn->close();
echo $html;
?>
Why dont you filter the coordinate in the query? Like this:
$station_sql = "SELECT coordinate_id, x_coord, y_coord, section_name FROM coordinates WHERE coordinate_id = " . $_GET['coordinate_id'];
And in jquery code:
url: 'display_stationinfo.php?coordinate_id=' + id,
Let's start with your database connection, which should be on a separate secure page.
connect.php:
<?php
function db(){
return new mysqli('host', 'username', 'password', 'database');
}
?>
Obviously, your host will not be 'host'.
Now main.php:
<?php
// only use for PHP on this page for initial page load - target other pages with AJAX
?>
<!DOCTYPE html>
<html xmlns='http://www.w3.org/1999/xhtml' xml:lang='en' lang='en'>
<head>
<meta http-equiv='content-type' content='text/html;charset=utf-8' />
<title>This is Where Your Title Goes</title>
<script type='text/javascript' src='//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js'></script>
<script type='text/javascript' src='main.js'></script>
<link rel='stylesheet' type='text/css' href='main.css' />
</head>
<body>
<div id='map_container'>
<div id='map_size'>
</div>
</div>
</body>
</html>
Now for main.js:
//<![CDATA[
$(function(){
var ms = $('#map_size');
$.post('main_init.php', {init:'1'}, function(d){
for(var i in d){
var di = d[i], x = di.x, y = di.y;
var sti = $("<div class='station_info_' id='station_info_"+i+"'></div>").css({
left:x,
top:y
});
// HTML id, class, and name attributes cannot start with a number
$("<div class='desk_box' data='"+i+"'>id:"+i+'</div>').css({
left:x,
top:y
}).appendTo(ms).append(sti).click(function(){
var info = $(this).next();
$.post('live_info.php', {station_id:info.attr('id').replace(/^station_info_/, '')}, function(r){
// do stuff with r
info.html('love:'+r.love+'<br />hate:'+r.hate).toggle();
}, 'json');
});
}
}, 'json');
});
// use CSS to do `.desk_box,.station_info_{position:absolute;}`
//]]>
Now for main_init.php:
<?php
if(isset($_POST['init']) && $_POST['init'] === '1'){
include_once 'connect.php'; $db = db(); $json = array();
$q = $db->query("SELECT * FROM table WHERE"); // example only
if($q->num_rows > 0){
while($r = $q->fetch_object()){
$json[strval($r->coordinate_id)] = array('x' => $r->x_coord, 'y' => $r->y_coord);
}
}
else{
// no results
}
$q->free(); $db->close();
echo json_encode($json);
}
else{
// could be a hack
}
?>
Here's what live_info.php might look like:
<?php
if(isset($_POST['station_id'])){
include_once 'connect.php'; $db = db(); $json = array();
// example only - you will only get one `$row` if query is done specific, so while loop is not needed
$q = $db->query("SELECT love,hate FROM some_table WHERE id='{$_POST['station_id']}'");
if($q->num_rows > 0){
$row = $q->fetch_object();
// it's okay to overwrite array in this case
$json = array('love' => $row->love, 'hate' => $row->hate);
}
else{
// no results
}
$q->free(); $db->close();
echo json_encode($json);
}
else{
// may be a hack
}
?>