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Passing js variable to php using ajax does not work

I want to get variable rating_idex in my php file so if is user click button #add-review it should pass in ajax variable and it will get array in php file and send review to the database, but it is not working and I don't see solution
$('#add-review').click(function(){
var user_name = $('#reviewer-name').val();
var user_review = $('#review').val();
console.log(user_name);
console.log(rating_index);
console.log(user_review);
if(user_name == '' || user_review == '')
{
alert("Please Fill Both Field");
return false;
}
else
{
$.ajax({
url:"rating-data.php",
method:"GET",
data:{
rating_index: rating_index,
user_name: user_name,
user_review: user_review
},
success:function(data)
{
$('#review_modal').modal('hide');
load_rating_data();
console.log(data);
}
})
}
});
This is my php code when I can get the variable and send them to the database:
<?php
include 'connection.php';
echo ($rating_index);
if(isset($_GET["rating_index"]))
{
$data = array(
':user_name' => $_GET["user_name"],
':user_rating' => $_GET["rating_index"],
':user_review' => $_GET["user_review"],
':datetime' => time()
);
$query = "
INSERT INTO review_table
(user_name, user_rating, user_review, datetime)
VALUES (:user_name, :user_rating, :user_review, :datetime)
";
$query_run = mysqli_query($conn, $query);
if($query_run){
echo "Your Review & Rating Successfully Submitted";
} else{
echo '<script type="text/javascript"> alert("Something went wrong") </script>';
echo mysqli_error($conn);
}
}
?>
When I am trying to echo ($rating_index) it give me feedback that variable does not exist so it is something with ajax but can't find solution, thanks in advance for any solutions

Instead of echo ($rating_index); try echo ($_GET["rating_index"]); reason being you didn't actually declared $rating_index

if I'm not wrong you want to pass the PHP variable in javascript?
if yes you cant pass the PHP variable in js like this.
var x = " < ? php echo"$name" ? >";
you can pass your PHP variable like this but in only the .php file not in the .js

How to convert Ajax response to string to compare with JS string

How do I convert Ajax response into plain text string?I have global variable and I store the ajax response to it but when I'm going to compare it with javascript string when even they are equal It returns false.
Here is my code:
function checkUsn(){
var usn = document.getElementById("usn").value;
if(usn){
$.ajax({
type: 'post',
url: 'checkdata.php',
data: {
emp_username: usn,
},
success: function(response){
console.log(response);
myGlobalContainer.usn = response; //convert it to compare with string
$('#status').html(response);
}
});
}
}
in console when I type the existing username in database it logs OK. This OK stores in myGlobalContainer.usn, but when I do comparison like code below it return false.
if(myGlobalContainer.usn == "OK"){
return true;
}else{
return false;
}
I will add php file.
<?php
header("Content-Type: text/plain");
include 'db_config.php';
$conn = new mysqli($db_servername, $db_username, $db_password, $db_name);
if(isset($_POST['emp_username'])){
$usn = $_POST['emp_username'];
$checkdata = "SELECT emp_username FROM emp_details where emp_username='$usn'";
$query = mysqli_query($conn, $checkdata);
if(mysqli_num_rows($query) > 0){
echo "OK";
}else{
echo "Your Username not exist";
}
exit();
}
if(isset($_POST['emp_pw']) && isset($_POST['emp_usn'])){
$pw = $_POST['emp_pw'];
$usn = $_POST['emp_usn'];
$get_pw = "SELECT emp_password FROM emp_details where emp_username='$usn'";
$query = mysqli_query($conn, $get_pw);
//$get_num_rows = mysqli_num_rows($query);
//echo $get_num_rows;
$row = mysqli_fetch_assoc($query);
//echo $row["emp_password"];
// check if password is match with username
if($pw == $row["emp_password"]){
echo "MATCH";
}else{
echo "Wrong password";
}
exit();
}
?>
Please help Thanks!

By default, jQuery's ajax function will determine the type of data it is receiving from the Content-Type response header.
You can override that with the dataType parameter.
$.ajax({
dataType: "text",
// etc etc
});
… however, since the response seems to be "OK" and not HTML, it is likely that your PHP should be adjusted so it outputs the correct Content-Type:
<?php
header("Content-Type: text/plain"); # Override the default (text/html)
echo "OK";
So also make sure that the response is really simply "OK" and that you are not outputting (for example) "OK" followed by a new line.

I've change my code to
success: function(response){
console.log(response);
myGlobalContainer.usn = response.trim(); //convert it to compare with string
$('#status').html(response);
and It works but Guys thanks for your help very appreciated!
also thanks to this question
Ajax response doesn't equal what I think it should

i seem you should use a function in ajax success.
var myGlobalContainer.usn = "";
function signAndCompare(str)
{
myGlobalContainer.usn = str
if(myGlobalContainer.usn == "OK")
{
console.log("true");
return true;
}
console.log("false");
return false;
}
function checkUsn(){
var usn = document.getElementById("usn").value;
if(usn){
$.ajax({
type: 'post',
url: 'checkdata.php',
data: {
emp_username: usn,
},
success: function(response){
console.log(response);
signAndCompare(response);//this line: **compare** and sign response
$('#status').html(response);
}
});
}

Ajax call to php, get mysql data as array and use in JS function

I'm looking to make an ajax call to a PHP script to get data from MySQL, create a json array and pass it back to the success function of the ajax call, where i will then use it as parameters for a JavaScript function.
This is my ajax call,
$('button[name="message"]').click(function() {
var $row = $(this).closest("tr"); // Find the row
var $tenant_id = $row.find(".col-md-1 id").text(); // Find the tenants ID
var $landlord_id = "<?php echo $id; ?>"
$.ajax({
url : "./message.php",
type : "POST",
async : false,
data: {
landlord_id: $landlord_id,
tenant_id : $tenant_id
},
success: function(data){
console.log(data);
var messages = data;
insertChat(messages.sender_id, messages.body, messages.timestamp);
}
})
});
And this is my PHP file,
<?php
session_start();
require_once('../dbconnect.php');
// update tenants table to show deposit returned
if(isset($_POST['tenant_id'])){
$tenant_id = $_POST['tenant_id'];
$landlord_id = $_POST['landlord_id'];
$sql = "SELECT * from messages WHERE messages.sender_id OR messages.receiver_id = '$tenant_id' AND messages.sender_id OR messages.receiver_id = '$landlord_id'";
$result = mysqli_query($conn, $sql) or die("Error in Selecting " . mysqli_error($conn));
//create an array
$messages = array();
while($row =mysqli_fetch_assoc($result))
{
$messages[] = $row;
}
echo json_encode($messages);
}
?>
If anybody has a link to a tutorial or the individual parts that would be fantastic. I don't even know if the process i have outlined above is correct.
If anybody could tell me the correct way to go about this that would be of great help!
Thanks

Just a few things to adjust your javascript side (I won't explain the php sql injection issue you have... but please research prepare, bind_param and execute):
Since you are returning an ARRAY of $messages from php (json_encoded), you need to loop on those in your success handler.
Add dataType: 'JSON' to your options, so it explicitly expects json returned from php.
And you were missing a couple semicolons ;)
Adjustments added to your code:
$('button[name="message"]').click(function() {
var $row = $(this).closest("tr");
var tenant_id = $row.find(".col-md-1 id").text();
var landlord_id = "<?php echo $id; ?>";
$.ajax({
url : "./message.php",
type : "POST",
data: {
landlord_id: landlord_id,
tenant_id : tenant_id
},
dataType: 'JSON',
success: function(data){
console.log(data);
if (typeof data !== undefined) {
for(var i = 0; i < data.length; i++) {
insertChat(data[i].sender_id, data[i].body, data[i].timestamp);
}
}
}
});
});

Undefined index in php when getting value passed from AJAX

I'm trying to get the value that I passed in AJAX to PHP. It shows an alert that says, "Success!" however it when I try to display the value in PHP, it says undefined index. Also I am passing it in the same page.
Whenever I click a button, it opens a modal and I also passing values from that button to the modal. This is evident in my JS code.
<script>
$(document).ready(function(){
$('#editModal').on('show.bs.modal', function (e) {
var id = $(e.relatedTarget).data('id'); //im trying to pass this value to php, e.g. 5
var time = $(e.relatedTarget).data('time');
var name = $(e.relatedTarget).data('name');
var stat = $(e.relatedTarget).data('stat');
var desc = $(e.relatedTarget).data('desc');
alert(id);
$("#task_id_edit").val(id);
$("#new-taskID").val(id);
$("#allotted_time_edit").val(time);
$("#task_name_edit").val(name);
$("#task_status_edit").val(stat);
$("#task_desc_edit").val(desc);
$("#task_id_ref2").val(id);
//AJAX CODE HERE
$(function() {
$.ajax({
type: "POST",
url: 'tasks.php?id='<?php $id = isset($_GET['id']) ? $_GET['id'] : ""; echo $id; ?>,
data: { "userID" : id },
success: function(data)
{
alert("success!"); //this display
}
});
});
}); // line 1131
});
</script>
PHP CODE:
<?php
$uid = $_POST['userID'];
echo $uid." is the value";
?>
It keeps getting an error that says, undefined index: userID. I am confused. Please help me how to fix this. Your help will be much appreciated! Thank you!

Echo the number in the javascript string.
Currently you will get:
url:'tasks.php?id='1,
The 1 should be concatenated or inside the quote. Try:
url: 'tasks.php?id=<?php $id = isset($_GET['id']) ? $_GET['id'] : ""; echo $id; ?>',
or take that parameter out since it doesn't appear to be being used.

Just put the $_POST['userID'] in a if statement
Undefined index: UserID is not a error it is a warning
<?php
if(isset($_POST['userID'])
{
$uid = $_POST['userID'];
echo $uid." is the value";
}
else
{
echo "Sorry Value cant be printed";
}
?>

How can i add a variable in AJAX URL

I have a function in php that need an id and i need to add a variable in my ajax url the id
PHP Code:
function get_json_selected($purpose)
{
//echo $this->input->post("ids");
$ids = explode(",", $this->input->post("ids"));
$site_url = site_url($this->router->class);
if ($purpose == "EQUIPEMENT"){
$this->db->select(
'a.id,
a.manufacturer,
a.description,
a.serial_no,
a.part_no,
a.status,
a.availability,
getReturnStatus(a.id) as return_status',
FALSE
);
$this->db->where_in('a.id', array_unique($ids));
$result = $this->db->get("equipments a")->result_array();
echo json_encode(array("spares" => $result));
} else {
$this->db->select(
'a.id,
a.manufacturer,
a.description,
a.serial_no,
a.part_no,
a.status,
a.availability,
getReturnStatus(a.id) as return_status',
FALSE
);
$this->db->where_in('a.id', array_unique($ids));
$result = $this->db->get($this->active_table." a")->result_array();
echo json_encode(array("spares" => $result));
}
}
Ajax Code:
this is just example of the variable of id.
$purpose = "EQUIPMENT"; // how can i add this php variable to ajax url
url: "<?=site_url('equip_request/get_json_selected');?>", // this is the current code how can i add id in this url
or is this code right?
url: "<?=site_url('equip_request/get_json_selected/'.$purpose);?>"

var purpose = '<?php echo json_encode($purpose); ?>';
url: 'example.php?=' + purpose;
+ is the concatenator in javascript. hope this helps. spend plenty of time and add plenty of security to echoing that var into javascript. else you could find yourself viction of xss.