I need a regular expression to allow a person to enter their height in the following format either
5'10 or 5'10" making the quotation marks optional for the inches. There also could be a space between the feet and inches like 5' 10 or 5' 10".
thanks for the help in advance.
You should be able to use /\d+'\s?\d+"?/ that will allow the numbers to be multiple digits long, requires the single quote after the first number, allows an optional space after the single quote and optionally selects the double quote.
The following will ensure that the number of feet is no greater than 9 and that the inches are between 0 and 11.
/^\d' ?(?:\d|1[0-1])"?$/
If you wanted to make sure the person is at least 2 feet tall, for example, you can just replace the initial \d with the appropriate range.
/^[2-9]' ?(?:\d|1[0-1])"?$/
For weight validation, you can do something like the following, which will ensure the user enters 2 or 3 digits followed by "kg", with an optional space in between. This can easily be adapted for "lbs", or the units can simply be omitted, depending on your requirements.
/^\d{2,3} ?kg$/
I think you might benefit from reading up on regular expressions and testing them out for yourself.
Related
I'm evaluating a phone number in js with this regex:
/[a-z]/i.test(this.state.phone)
Now I need to limit its length to 30 chars.
I tried so many times but basically I know I need to specify max lenght in curly braces like this:
/[a-z]{30}/i.test(this.state.phone)
But this way the check about letters doesn't work anymore.
I've spended too much time on it I need some help!
EDIT: to clarify I need to avoid any letter (upper or lowercase) or special char but round brackets, space, dot, minus and plus sign.
So this is ok:
+001.333 123456
this not
+001 333 123456v
Now I need to limit its length to 30 chars
/[a-z]{30}/i will check for exact 30 characters, you need to specify minimum length as well.
/\d{1,30}/i
{1,30} will check for min 1 and max 30 characters.
Also, if there no other characters allowed in this.state.phone, then asset start of string ^ and end of string $ as well.
/^(\+)?[0-9\s]{1,30}$/
I am trying to figure out how to create a regex that will let me search for not only one or double digits, but also have a limit from 1-60. I want double digits to be applicable as well so for example, 01-09 works just as well as 1-9.
^([1,2,3,4,5]\d{0,1}|(60))
is what I have so far in terms of setting up the the double digits, but I then can't get 7, 8, 9 to pass as either single or double digits. Any idea on how to solve this problem or do I need to do a case by case approach?
try this;
^0*([1-9]$|^[1-5][0-9]$|^60$)
from this generator
ie, can either be just 1-9, or 1-5 followed by 1-9, or 60 itself.
Edit amended to force begining and end of string and allows leading zeros
i'm trying to find an expression that matches a phone number in the format of (0[2,3,6,7,8,or 9]) XXXXXXXX where X is a digit, the space must be matched and so must the parentheses
My current expression is:
/\b\(0[236789]\)\s(\d){8}\b/g
but it's not picking up any test numbers such as
(02) 12345678
I know regex phone number questions get spammed on SO. I have been reading through all the ones I can find which is how I've made it to this point but I can't for the life of me figure this out.
Just remove the \b on either end, and it should work
/\(0[236789]\)\s(\d){8}/g
This will match multiple phone numbers, not sure if that is what you want. If you want to make sure the entire string from start to finish is the full phone number, you can do this
/^\(0[236789]\)\s(\d){8}$/
This will match (02) 12345678, and won't work if there are any characters around the string.
Well, this is the best I can come up with.
/^[+]?(1\-|1\s|1|\d{3}\-|\d{3}\s|\d{2}\-|\d{2}\s|)?((\(\d{3}\))|\d{3})(\-|\s)?(\d{3})
(\-|\s)?(\d{4})$/g
This should support all combinations like
(541) 754-3010
+1-541-754-3010
1-541-754-3010
001-541-754-3010
191 541 754 3010
+91 541 754 3010
and so on.
I need regex to validate a number that could contain thousand separators or decimals using javascript.
Max value being 9,999,999.99
Min value 0.01
Other valid values:
11,111
11.1
1,111.11
INVALID values:
1111
1111,11
,111
111,
I've searched all over with no joy.
/^\d{1,3}(,\d{3})*(\.\d+)?$/
About the minimum and maximum values... Well, I wouldn't do it with a regex, but you can add lookaheads at the beginning:
/^(?!0+\.00)(?=.{1,9}(\.|$))\d{1,3}(,\d{3})*(\.\d+)?$/
Note: this allows 0,999.00, so you may want to change it to:
/^(?!0+\.00)(?=.{1,9}(\.|$))(?!0(?!\.))\d{1,3}(,\d{3})*(\.\d+)?$/
which would not allow a leading 0.
Edit:
Tests: http://jsfiddle.net/pKsYq/2/
((\d){1,3})+([,][\d]{3})*([.](\d)*)?
It worked on a few, but I'm still learning regex as well.
The logic should be 1-3 digits 0-1 times, 1 comma followed by 3 digits any number of times, and a single . followed by any number of digits 0-1 times
First, I want to point out that if you own the form the data is coming from, the best way to restrict the input is to use the proper form elements (aka, number field)
<input type="number" name="size" min="0.01" max="9,999,999.99" step="0.01">
Whether "," can be entered will be based on the browser, but the browser will always give you the value as an actual number. (Remember that all form data must be validated/sanitized server side as well. Never trust the client)
Second, I'd like to expand on the other answers to a more robust (platform independent)/modifiable regex.
You should surround the regex with ^ and $ to make sure you are matching against the whole number, not just a subset of it. ex ^<my_regex>$
The right side of the decimal is optional, so we can put it in an optional group (<regex>)?
Matching a literal period and than any chain of numbers is simply \.\d+
If you want to insist the last number after the decimal isn't a 0, you can use [1-9] for "a non-zero number" so \.\d+[1-9]
For the left side of the decimal, the leading number will be non-zero, or the number is zero. So ([1-9]<rest-of-number-regex>|0)
The first group of numbers will be 1-3 digits so [1-9]\d{0,2}
After that, we have to add digits in 3s so (,\d{3})*
Remember ? means optional, so to make the , optional is just (,?\d{3})*
Putting it all together
^([1-9]\d{0,2}(,?\d{3})*|0)(\.\d+[1-9])?$
Tezra's formula fails for '1.' or '1.0'. For my purposes, I allow leading and trailing zeros, as well as a leading + or - sign, like so:
^[-+]?((\d{1,3}(,\d{3})*)|(\d*))(\.|\.\d*)?$
In a recent project we needed to alter this version in order to meet international requirements.
This is what we used: ^-?(\d{1,3}(?<tt>\.|\,| ))((\d{3}\k<tt>)*(\d{3}(?!\k<tt>)[\.|\,]))?\d*$
Creating a named group (?<tt>\.|\,| ) allowed us to use the negative look ahead (?!\k<tt>)[\.|\,]) later to ensure the thousands separator and the decimal point are in fact different.
I have used below regrex for following retrictions -
^(?!0|\.00)[0-9]+(,\d{3})*(.[0-9]{0,2})$
Not allow 0 and .00.
','(thousand seperator) after 3 digits.
'.' (decimal upto 2 decimal places).
I am looking to create a regular expression in javascript that does the following:
Allows for 1 or more numbers
Then has an optional period (".")
Then has an optional number of digits up to 6
The context is that i need people to enter in numeric values in the millions and i want them to at least include a 0 if they are entering thousands... so they could enter the following:
1 (would be one million)
0.725 (would be 725k)
10.5 (would be 10M 500K)
I also need to ensure that the value doesn't reach over 725.00 (or 725 million).
Thanks in advance.
That sounds like:
/^(?!\d{4})(?![89]\d\d)(?!7[3-9]\d)(?!72[6-9])(?!725\.0*[1-9])(0|[1-9]\d*)(\.\d{1,6})$/
which means:
doesn't start with four digits (i.e., is less than 1000)
doesn't start with 8 or 9 followed by two digits (i.e., is less than 800)
doesn't start with 73-79 followed by a digit (i.e., is less than 730)
doesn't start with 726-729 (i.e., is less than 726)
doesn't start with 725. followed by zero or more zeroes followed by a nonzero digit (i.e., is less than or equal to 725.00).
starts either with 0, or with 1-9 followed by zero or more digits
after that, optionally a decimal point followed by between one and six digits
That said, I'd actually recommend implementing the above as several separate checks, rather than cramming it all into one regex like the above. In particular, the "is less than or equal to 725.00" check is probably better implemented using numeric comparison; and even if you do want to use a regex for that, you probably want to detect it as a separate error from 0.1asefawe so you can give a more precise error-message.
So basically you want a number that would be multiplied by 10^6 to get the true value.
This sounds like a two-stepper; First, verify that the input string is in a format you expect (you can use a regex for this very easily). Then, parse the string into a number variable and test the actual value. The regex pattern for that would look like "[0-9]{1,3}(\.[0-9]{1,6})?", basically matching a number with up to 3 whole digits and 6 fractional digits, the decimal place and fractional digits being optional. If it matches this pattern, then it's parsable into a number, and you can then perform a quick check that your number <= 725.
I honestly don't think it's feasible to create a single Regex that can validate a proper numeric format AND an inclusive maximum range, but here's a start:
"^(725(\.0{1,6})|(([7][2][0-4]|[7][0-1][0-9]|[1-6][0-9]{2}|[1-9][0-9]|[0-9])(\.[0-9]{1,6})?)$"
This will allow any natural whole number from zero to 724, with any fractional part up to six digits from ".000001" to ".999999". It does this in stages; it will match 720-724, or 700-719, or any three-digit number up to 699, or any two-digit number, or any one-digit number. Then, it will also match the quantity "725" explicitly, with an optional decimal point and up to 6 zeroes.
EDIT: While your comment states that you used this pattern, and it does produce the correct result, I had intended it as a "what not to do"; this pattern will be far more costly to evaluate than the first solution, just to avoid a server-side rule check. And you will have to perform a server-side validation anyway; anything done within the confines of the user's browser should be suspect because the user can disable JavaScript or can even use browser plug-ins like FireBug to make your HTML page behave the way he wants, instead of the way you designed it.