My HTML Code is :
<!DOCTYPE html>
<html>
<head>
<title>Furry Friends Campaign</title>
<link rel="stylesheet" type="text/css" href="styles/my_style.css">
</head>
<body>
<div id="clickMe">Show me the the Furry Friend of the Day</div>
<div id="picframe">
<img src="images/furry_friend.jpg" alt="Our Furry Friend">
</div>
<script type="text/javascript" src="scripts/jquery-3.1.0.min.js"></script>
<script type="text/javascript">
$(document).ready(function()
{
$("#clickMe").click(function()
{
$("img").fadeIn(1000);
$("#picframe").slideToggle("slow");
});
});
</script>
</body>
</html>
The accompanying CSS looks like:
#clickMe {
background: #D8B36E;
padding: 20px;
text-align: center;
width: 205px;
display: block;
border: 2px solid #000;
}
#picframe {
background: #D8B36E;
padding: 20px;
width: 205px;
display: none;
border: 2px solid #000;
}
The slideToggle works perfectly, but for some reason, the image doesn't fade in. I've tried setting the duration to longer periods, but that yields the same results. Can someone point out what's wrong with this code? I'm using the latest version of Chrome.
UPDATE: I tried running the example code of the book I was using, which uses jquery-1.6.2.min.js and using that version of jQuery, the code works perfectly. Is this some error on jQuery's part? Or is the new way that things will be done now?
Since jQuery 1.8, fadeIn no longer initially hides the image, so trying to fade in an image which is visible or doesn't have display set to none won't lead to anything.
To fade in, you should hide it first. Initially it's not hidden, since children don't inherit display CSS property, and you have set it to none only on #picframe, the parent of img. Just add $("img").hide(); on ready. This will make it work.
Since it looks like you need to fade it in / out with each click, you could do the following instead of $("img").fadeIn(1000):
if($("img").is(":hidden")) $("img").fadeIn(1000);
else $("img").fadeOut(1000);
Demo below.
#clickMe {
background: #D8B36E;
padding: 20px;
text-align: center;
width: 205px;
display: block;
border: 2px solid #000;
}
#picframe {
background: #D8B36E;
padding: 20px;
width: 205px;
display: none;
border: 2px solid #000;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js"></script>
<div id="clickMe">Show me the the Furry Friend of the Day</div>
<div id="picframe">
<img src="images/furry_friend.jpg" alt="Our Furry Friend">
</div>
<script type="text/javascript" src="scripts/jquery-3.1.0.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
//$("img").hide();
$("#clickMe").click(function() {
$("img").fadeIn(1000);
$("#picframe").slideToggle("slow");
});
});
</script>
Somehow, img didn't inherit the display:none in #picframe div. Here's the fix: https://jsfiddle.net/69rLha7e/1/
There is a "timing" consideration while playing with multiple animations a time.
In this CodePen, I used diferent timing for fadeIn, fadeOut and toggleSlide.
And you have to check the display state in order to decide to fade in or out.
$(document).ready(function(){
$("#clickMe").click(function(){
console.log( $("img").css("display") ) ;
if( $("img").css("display")=="inline" ){
$("img").fadeOut(400);
}else{
$("img").fadeIn(800);
}
$("#picframe").slideToggle(400);
});
});
Related
I've been sitting with this problem for like 2 hours. What I'm trying to make is a website where you push a button and it changes color. I know this can be done with CSS, but I'm not interested in that.
The main problem is that when I push the button, nothing happens.. However, if I remove the ' #sug from the css' everything works perfectly... So what I want to do, is to make the layout very basic at the beginning, so there's nothing to it, except like the black background, and when I push the buttons it should switch..
Also, I know you can implement onclick in the button tag, but that's not what I'm going for either. I want to know WHY this happens and how I can resolve this problem.
Here's my javascript, CSS and HTML code:
window.onload = setUp;
function setUp() {
document.getElementById("normal").onclick = setNormalStyle;
document.getElementById("crazy").onclick = setCoolStyle;
document.getElementById("insane").onclick = setInsaneStyle;
}
function setNormalStyle() {
var messageBox = document.getElementById("sug");
messageBox.className = "normal";
}
function setCoolStyle() {
var savingTheSecondVar = document.getElementById("sug");
savingTheSecondVar.className = "cool";
}
function setInsaneStyle() {
var savingTheThirdVar = document.getElementById("sug");
savingTheThirdVar.className = "insane";
}
#sug {
background-color: black;
}
.normal {
height: 500px;
background-color: blue;
color: white;
padding: 30px;
margin: auto;
width: 500px;
}
.insane {
height: 500px;
background-color: green;
padding: 30px;
margin: auto;
width: 500px;
color: white;
}
.cool {
height: 500px;
background-color: red;
padding: 30px;
margin: auto;
width: 500px;
color: white;
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<link type="text/css" rel="stylesheet" href="Struktur.css" />
<script type="text/javascript" src="struktur.js"></script>
<title>My first Javascript project</title>
</head>
<body>
<div id="sug" class="cool insane normal">
<header>
<h1> Welcome to this Javascript site! </h1>
</header>
<section>
<p>
text
</p>
</section>
<button type="button" id="normal">First style</button>
<button type="button" id="crazy">Second style</button>
<button type="button" id="insane">Third style</button>
</div>
</body>
</html>
The problem is your CSS.
#sug{
background-color: black;
}
Overrides the background-color of your classes because it is a more specific selector (i.e. an id selector).
change the rest of your classes in the css to include the id like
#sug.normal, #sug.insane, #sug.cool etc.
Here is a nice article on CSS specificity to help you understand more: https://css-tricks.com/specifics-on-css-specificity/
That's because an id has preference over a class. You will need to specify it like this:
#sug.cool { background: red; }
etc.
You are not removing the background-color provided by the #sug id in CSS onClick() events of the buttons.
Id has more preference over classes
It is a good habit to use below code as classes has spaces between them and it can be used if you want to add more than one class.
messageBox.className += " " + "normal";
I'm using JQuery UI to toggle the div with effect .toggle('blind', 250).
I have tackled the .stop() method but it was not my goal in toggling the div, because when I want to toggle the div #clContainer even clicking multiple times the other div #ccConatiner can only be toggled next when it is done...
Here's my Code
$(function(){
$("#clContainer").on('click', function(){
$("#ccContainer").toggle('blind', 350);
});
});
#ccContainer,
#clContainer{
margin: 10px;
height: 100px;
width: 100px;
background-color: #333;
cursor: pointer;
color: #fff;
}
#ccContainer{
display: none;
}
<html>
<head>
<script src="http://code.jquery.com/jquery-1.12.0.min.js"></script>
<script src="http://code.jquery.com/ui/1.11.4/jquery-ui.js"></script>
</head>
<div>
<div id="clContainer">
Click me
</div>
<div id="ccContainer"></div>
</div>
</html>
Please help.
You need to set a flag each time your animation starts, and clear it when it finishes. and on each click check for the flag to see if there is an ongoing animation and only animate again if there isn't any ongoing animation.
you can use .promise().done() to set a callback function that will run as soon as all animations on your cube finish, and in this callback clear the animation_ongoing flag:
var animation_ongoing=0;
$(function() {
$("#clContainer").on('click', function() {
if(!animation_ongoing){
animation_ongoing=1;
$("#ccContainer").toggle('blind', 350).promise().done(function(){
animation_ongoing=0;
});
}
});
});
#ccContainer,
#clContainer {
margin: 10px;
height: 100px;
width: 100px;
background-color: #333;
cursor: pointer;
color: #fff;
}
#ccContainer {
display: none;
}
<html>
<head>
<script src="http://code.jquery.com/jquery-1.12.0.min.js"></script>
<script src="http://code.jquery.com/ui/1.11.4/jquery-ui.js"></script>
</head>
<div>
<div id="clContainer">
Click me
</div>
<div id="ccContainer"></div>
</div>
</html>
So I'm trying to use bPopup as a modal window, but I can't see to get the actual modal window to pop up. I followed the instructions on the documentation (see http://dinbror.dk/bpopup/), but I can't seem to get it appear. Am I missing something?
<html>
<script type = "text/javascript" src = "jquery-1.11.3.min.js"></script>
<script type = "text/javascript" src = "jquery.bpopup.min.js"></script>
<p> Some text </p>
<div style="display:none" id='popup'>
Why is there no modal body???
</div>
<script type = "text/javascript">
$(document).ready(
function(){
$('p').click(function(){
$('#popup').bPopup();
})
})
</script>
</html>
The resulting script looks like this:
After clicking, the result is this:
However, on the documentation, the modal is as follows:
I'm really not sure what I'm missing. I'm probably just blind to something really obvious, any ideas?
Have you read this?
What is bPopup? bPopup is a lightweight jQuery modal popup plugin
(only 1.49KB gzipped). It doesn't create or style your popup but
provides you with all the logic like centering, modal overlay, events
and more. It gives you a lot of opportunities to customize so it will
fit your needs.
So you need to write your own styles for the modal window.
Do not give inline style style="display:none". Inline style will have highest priority and hence bpopup does not/cannot change that property.
Style it in css instead like this
#popup {
background-color:#fff;
border-radius:15px;
color:#000;
display:none;
padding:20px;
min-width:400px;
min-height: 180px;
}
$(document).ready(function() {
$('p').click(function() {
$('#popup').bPopup();
});
});
#popup {
background-color: #fff;
border-radius: 15px;
color: #000;
display: none;
padding: 20px;
min-width: 400px;
min-height: 180px;
}
.bClose {
cursor: pointer;
position: absolute;
right: 10px;
top: 5px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://rawgit.com/dinbror/bpopup/master/jquery.bpopup.min.js"></script>
<p>Some text</p>
<div id='popup'>Why is there no modal body???
<span class="bClose">x</span>
</div>
I am trying to build a simple web page for my website using HTML, CSS, JavaScript and JQuery. What I want is to display a slideshow of a few of my images at the top of the page. I just want the pictures to fade out and fade in after one another forever until the user closes the browser. I want each picture to be displayed for a certain amount of time, after which it will fade out and another picture would fade in.
I referred to this as well as this post on SO but couldn't find a solution. I got some idea from this page and tried to develop some code.
The overall layout of the website is as follows:
For this, my index.html page looks like this:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
<head>
<title>Home Page</title>
<link rel="stylesheet" href="css/style.css" />
<script language="javascript" src="js/jquery-1.10.2.min.js"></script>
<script language="javascript" src="js/common.js"></script>
<script language="javascript" src="js/banner_rotator.js"></script>
</head>
<body onload="loadBody();">
<div id="wrapper">
<img id="headerlogo" />
<div id="nav">
Home
About
Weddings
Portraiture
Landscapes
Products
Miscellaneous
Services
Contact
</div>
<div id="container">
<div id="content">
<!-- Main content starts here -->
<p>
Welcome to the world of The Siblings' photography.
</p>
imgpos = <span id="imgposspan"></span>
<!-- Main content ends here -->
</div>
</div>
</div>
</body>
</html>
The CSS is like this:
body {
background-color: transparent; color: #d0d0d0;
font: normal normal 11px verdana; margin: 0 auto;
}
#wrapper {
background-color: transparent; width: 960px; margin: 0 auto;
}
#headerlogo {
border-radius: 0px 0px 5px 5px; display: block;
width: 960px; height: 350px;
background-color: #d0d0d0;
}
#container {
width: 100%; margin-top: -35px;
}
#nav {
background-color: transparent;
color: #888888; border-radius: 5px; padding: 10px;
width: 100%; position: relative; top: -40px;
}
#nav>a {
border-radius: 5px; display: inline-block; padding: 5px 19px;
font-weight: bold; border: 1px solid transparent;
color: #888888; background: none none transparent no-repeat;
}
#nav>a:link {
text-decoration: none; border-color: transparent; background-image: none;
}
#nav>a:visited {
text-decoration: none; border-color: transparent; background-image: none;
}
#nav>a:hover{
text-decoration: none; border-color: #ffa500; background-image: url("/img/1x30_ffa500.gif");
background-repeat: repeat-x; box-shadow: 0px 0px 5px #ffd700;
}
#nav>a:active {
text-decoration: underline; border-color: transparent;
background-image: none;
}
#content {
background-color: #f0f0f0; color: #202020;
padding: 5px; border-radius: 5px;
}
The common.js file is like this:
$(document).ready(function (){
var images = new Array();
images[0] = new Image();
images[0].src = "img/coverpics/sea_link.jpg";
images[1] = new Image();
images[1].src = "img/coverpics/marine_drive.jpg";
images[2] = new Image();
images[2].src = "img/coverpics/backbay.jpg"
banner_rotator("headerlogo", images, 0);
});
And, the banner_rotator.js file is like this:
function banner_rotator(imgid, imgarray, imgpos) {
setInterval(function() {
if (imgpos >= imgarray.length || imgpos == undefined)
imgpos = 0;
$("#"+imgid).attr({ "src" : imgarray[imgpos].src });
$("#"+imgid).fadeIn(1000, "linear");
$("#"+imgid).delay(6500);
$("#"+imgid).fadeOut(500);
// $("#imgposspan").html(imgpos);
imgpos++;
}, 8000);
}
Now, my problem description is as follows:
For the first few seconds the top portion is blank. The image is not showed, even though I am developing and having all the files on my local machine itself.
This first image directly pops up on the screen, instead of fading in.
After this image fades out, the image block vanishes, as if it is set to display: none; for a second. The entire page that follows the image shifts up. Then, the next image fades in and so forth everything runs normal.
Hence, in short, I have problems with the starting of this slideshow. Can anybody please help?
Also please tell me where can I put my code so everybody here can access and see for themselves how it runs?
JSFIDDLE
<img id="headerlogo" />
Don't do that (an image tag with no src attribute)
Put a div that will hold the space (set position:relative with width & height in css)
Then the problem is that you are changing your src attribute in your time loop, this ain't smooth
In your CSS, suppose you name your slider wrapper headerlogo_wrapper
div.headerlogo_wrapper > img {position:absolute;display:none;left:0;top:0}
Then you append your images to the space holder you have created (they will not show obviously)
Then you fadeIn your first image then you launch your setInterval :
//after having appended the images to the slider wrapper :
var $img = $("div.headerlogo_wrapper > img");
$img.eq(0).fadeIn(1000, "linear");
var ivisible = 0;
setInterval( function() {
$img.eq(ivisible).fadeOut(500);
++ivisible;
if (ivisible>$img.length-1) ivisible = 0;
$img.eq(ivisible).stop().fadeIn(1000, "linear");
}, 8000);
(If you want an image to be shown during load, some simple changes shall do; also if the first interval start immediately you obviously don't need to fadeIn "manually" the first image)
Try this: http://jsfiddle.net/3XV5M/
Your problem is the first time you run the timer function it won't run straight away. It will be run after 8000ms. The way this fiddle works is it will execute the function immediately and the run itself again after 8 seconds. Note I'm using setTimeout instead of setInterval.
function banner_rotator(imgid, imgarray, imgpos) {
if (imgpos >= imgarray.length || imgpos == undefined) imgpos = 0;
$("#"+imgid).attr({ "src" : imgarray[imgpos].src })
.fadeIn(1000, "linear")
.delay(6500)
.fadeOut(500);
imgpos++;
setTimeout(function() {banner_rotator(imgid, imgarray, imgpos) }, 8000);
}
The other problem is you need to hide the images first, so they can fade in. They wont fade in if they are already visible.
#headerlogo {
border-radius: 0px 0px 5px 5px;
width: 960px; height: 350px;
background-color: #d0d0d0;
display: none; /* Add this */
}
Then to prevent the other elements jumping up when you fade the images out, wrap the image element inside a div and set it's height. I used a div with a class of banner and added this style:
.banner {
height: 350px;
}
Hope that helps.
The problem is that you are fading out at the end of your interval. So replace this:
$("#"+imgid).attr({ "src" : imgarray[imgpos].src });
$("#"+imgid).fadeIn(1000, "linear");
$("#"+imgid).delay(6500);
$("#"+imgid).fadeOut(500);
with this:
$("#"+imgid).fadeOut(500)
$("#"+imgid).queue(function(){
$("#"+imgid).attr({ "src" : imgarray[imgpos].src });
$("#"+imgid).fadeIn(1000);
$("#imgposspan").html(imgpos);
imgpos++;
$(this).dequeue();
});
JSFIDDLE demo
The website i am currently working on has a pop out div with a map of locations on it, my problem is once the pop up div has been closed i then have to refresh the page to open the div again
It is running jquery - here is the code
<script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('#view_map_of_stocklists_link').click(function() {
//$('#popupdiv').show('slow');
$("#popupdiv").css('visibility', 'visible');
$("#mappy").css('opacity', '1');
});
$('.closepopup').click(function() {
$('#popupdiv').hide('slow');
});
});
</script>
The styling
<style>
#popupdiv
{
position: absolute;
left: 50%;
top: 50%;
background-color: white;
z-index: 100;
height: 600px;
margin-top: -200px;
width: 960px;
margin-left: -500px;
padding: 20px;
}
#view_map_of_stocklists_link:hover {
cursor:pointer;
}
.closepopup {
margin-top: 60px;
border: 1px solid #ccc;
background-color: #000;
color: white;
cursor: pointer;
}
</style>
and then the HTML itself
<div id="popupdiv" style="visibility:hidden;">
<center>
<iframe style="opacity:0;" id="mappy" src="http://mapsengine.google.com/map/embed?mid=zNedxWZ7lai0.krRxVqZZmyns" width="900" height="500"></iframe>
<div class="closepopup" style="width:200px">Close</div>
</center>
</div>
<h2 class="bold skin-font-color1">Our Beloved Stockists</h2>
<h5 class="skin-font-color1 p-wrapper"><!-- client txt --> <div id="view_map_of_stocklists_link" class="skin-font-color4">
<h4>View map of stockists</h4>
</div>
The website is http://www.tee-ze.co.uk/sosmoothies/
Cheers
You are setting 'visibility' to 'visible' instead of 'display' to 'block'.
When jQuery .hide() is called it ultimately saves the previous display value and sets it to display:none; So you should be doing something like:
$('#view_map_of_stocklists_link').click(function() {
$('#popupdiv').hide('slow');
});
Which I just realized you have commented out in your code. I wish I could leave a comment but I need more rep.
Edit:
Sorry for complaining in may previous answer.
I just tried uncommenting the existing code and removing the visibilty stuff and that works just fine in your site. Try it.
The way you're showing the popup map doesn't match the way you're hiding it.
You show it with:
$("#popupdiv").css('visibility', 'visible');
But you hide it with:
$('#popupdiv').hide('slow');
That fades it out but ultimately sets the CSS style display: none on the #popupdiv element.
When you try to show it again, it still has display: none on it. Setting the visibility doesn't affect the display style.
You need to make the hide and show match up. Either use the visibility style, or the display style, but use the same one for both hiding and showing (and jQuery's .show() method uses display).
For example, you might create the <div> with display: none instead of visibility: hidden, and then you can use jQuery's .show() and .hide() consistently.