I have this code in view:
<?php foreach ($display as $disp): ?>
<td><a href="#" id="name" data-type="text" data-pk="<?php echo $disp->id;?>" data-url="<?php echo Yii::$app->request->baseUrl;?>/product/update" ><?=$disp->name?></a></td>
<?php endforeach;?>
This shows all the names but only first name is editable with x-editable.
here is the javascripts used:
$.fn.editable.defaults.mode = 'inline';
$(document).ready(function() {
$('#name').editable();
});
The ID must be unique. this could have done with class.
<?php foreach ($display as $disp): ?>
<td><a href="#" class="name" data-type="text" data-pk="<?php echo $disp->id;?>" data-url="<?php echo Yii::$app->request->baseUrl;?>/product/update" ><?=$disp->name?></a></td>
<?php endforeach;?>
and,
$('.name').editable();
Related
I'm trying to add a row in a table from a data from another table. it says uncaught reference error.
here's the function
function addItem(id, name){
bootbox.confirm("Are you sure?", function(result) {
if (result) {
$('#ingredients_table').append("<tr><td>"+name+"</td></tr>");
}
});
}
here's the table where I'm calling the js function
<?php foreach($inventory as $row): ?>
<tr style="cursor: pointer;" data-toggle="tooltip" data-placement="top" title="Add ingredient" onclick="javascript:addItem(<?php echo $row->inventory_id; ?>, <?php echo $row->name; ?>)">
<td><?php echo $row->name; ?></td>
</tr>
<?php endforeach; ?>
The ID is showing in the table when I switch them, but the name is not.
Hope this will help you :
use '' (quotes) for javascript function arguments
<?php foreach($inventory as $row): ?>
<tr style="cursor: pointer;" data-toggle="tooltip" data-placement="top"
title="Add ingredient"
onclick="javascript:addItem('<?php echo $row->inventory_id; ?>', '<?php echo $row->name; ?>')">
<td><?php echo $row->name; ?></td>
Hi guys I have a table created by php in this way:
foreach ($query as $row): ?>
<tr id="<?php echo $row->aic;?>" >
<td><?php echo $row->aic; ?></td>
<td><?php echo $row->denominazione ?></td>
<td><?php echo $row->quantita; ?></td>
<td><?php echo $row->alert; ?></td>
<td>
<a id="bt_modifica"
class="btn btn-default btn-xs"
data-toggle="tooltip"
data-placement="top"
title=""
data-original-title="Modifica">
<img src="<?php echo base_url(); ?>template/images/Modifica.png">
</a>
<a id="bt_elimina>"
class="btn btn-default btn-xs"
data-toggle="tooltip"
data-placement="top"
title=""
data-original-title="Elimina"
onclick="deleteRow(<?php echo $row->aic ?>))">
<img src="<?php echo base_url(); ?>template/images/Elimina.png">
</a>
</td>
</tr>
<?php
endforeach; ?>
</tbody>
I need to delete row by rowId. This table has the dynamics id.
The columns ids are the same id of the sql table; in effect aic is id of sql table! In this way I are sure that the HTML row id is unique.
This is script
function deleteRow(rowID)
{ var row = document.getElementById(rowID);
row.parentElement.removeChild(row);
alert(rowID);
}
}
this code don't delete row.
Change this:
onclick="deleteRow(deleteRow(<?php echo $row->aic ?>))">
to
onclick="deleteRow(<?php echo $row->aic ?>)">
Another potential issue is that this:
<?php echo $row->aic ?>
may not be a number. So, you need to quote it. That is, change:
onclick="deleteRow(<?php echo $row->aic ?>)">
to:
onclick="deleteRow(\"<?php echo $row->aic ?>\")">
2 issues -
The one that might be causing issue - Incorrect Function Name
Other one - Calling deleteRow() twice - within each other (this should not cause any issue though)
So, just change -
function eliminaProdotto(rowID)
to -
function deleteRow(rowID)
Edit:
Based on modified question -
Is $row->aic a string? If yes, then add quotes around it...
onclick="deleteRow('<?php echo $row->aic ?>')"
I am having a table from where i am fetching activities and displaying in a table ...like this
<table width="1000px;" style="border:0px;" >
<tr>
<?php
$sql_activities="select * from tb_activities";
$query_activities=mysql_query($sql_activities);
while($row_activities=mysql_fetch_array($query_activities))
{
?>
<td width="50">
<input type="radio" value="<?php echo $row_activities['activity_name']; ?>" name="activities" onclick="hi() " id="activities" /><?php echo " ".$row_activities["activity_name"]; ?></td>
<?php
}
?>
</tr>
</table>
Now i have applied it in an onlick event of a radio button and the script for the function is:
<script type="text/javascript">
function hi()
{
a = document.getElementById("activities").value;
alert(a);
}
</script>
i want to alert the name of the activity chosen but when i click on any activity, it shows the same. The first activity.ven if i have clicked on any other activity...can anyone help me ??
what you should do is change this:
onclick="hi()"
to this:
onclick="hi(this);
then your function would be:
function hi(who) {
var a = who.value;
alert(a);
}
In PHP side of things change:
<td width="50"><input type="radio" value="<?php echo $row_activities['activity_name']; ?>" name="activities" onclick="hi() " id="activities" /><?php echo " ".$row_activities["activity_name"]; ?></td>
To: ( YOU NEED Unique IDs on Input/ Radio Buttons to be generated dynamically & Sent to JS)
<?php $i = 1; ?>
<td width="50"><input type="radio" value="<?php echo $row_activities['activity_name']; ?>" name="<?php echo $row_activities['activity_name'].$i; ?>" id ="<?php echo $row_activities['activity_name'].$i; ?>" onclick="hi("<?php echo $row_activities['activity_name'].$i; ?> ")" /></td>
<?php $i++; ?>
In Javascript Change to This:
function hi(elementID) {
var value = document.getElementById(elementID).value;
alert(value);
}
Code may have some escape errors, but logically this should give you idea how to do it, Hope that helps.
i have this form, when user clicks on the submit button, a script open a popup where i need to print the radio button value. My problem is the printed value on the popup window: "on" but the result should be a number (selected person's id)
My PHP Code:
<form method="post" action="edit.php" onsubmit="target_popup(this,'edit.php')"><input type="submit" value="Modifica Giocatore" /><br /><br /><br />
<?php
//my queries (work)
?>
<table cellspacing="2" cellpadding="2">
<tr>
<th></th>
<th>Name</th>
<th>Surname</th>
</tr>
<?php
$i=0;
while ($i < $num) {
$id=mysql_result($results,$i,"ID");
$name=mysql_result($results,$i,"Name");
$surname=mysql_result($results,$i,"Surname");
?>
<tr>
<td><input type="radio" name="radioEdit" value"<?= $id; ?>" /><?= $id; ?></td>
<td><?=$name?></td>
<td><?=$surname?></td>
</tr>
<?php
$i++;
}
?>
<?php
echo "</table></form>"
?>
And this is my script:
function target_popup(form,page)
{
window.open(page, 'formpopup', 'left=100,top=100,width=600,height=400,menubar,toolbar,resizable');
form.target = 'formpopup';
}
edit.php file:
<?php
$prova = $_POST['radioEdit'];
echo $prova;
?>
Thanks.
The only way I could get this to work was to use sessions.
Here is what I could test without setting up an entire DB.
PHP
<?php
session_start();
$id="12345"; // test ID number
// works with sessions
$prova = $_POST['radioEdit'] = $_SESSION['id'] = $id;
echo $prova;
?>
<form method="post" action="edit.php" onsubmit="target_popup(this,'edit.php')">
<td><input type="radio" name="radioEdit" value"<?php echo $id; ?>" /><?= $id; ?></td>
<input type="submit" value="Modifica Giocatore" />
</form>
<script>
function target_popup(form,page)
{
window.open(page, 'formpopup', 'left=100,top=100,width=600,height=400,menubar,toolbar,resizable');
form.target = 'formpopup';
}
</script>
edit.php
<?php
session_start();
echo $_SESSION['id'];
echo $id;
echo "<br>";
var_dump($_SESSION['id']);
?>
What happens when you echo $id? Are you sure that it returns a value? Also isn't <?= ;?> considered really old and deprecated PHP? You should be using <?php echo ;?>
I am working on Updating Codeigntier Cart with Jquery using Ajax call to update. Here is my jquery function
$(function() {
$('.cart_form select').on('change', function(ev) {
var rowid = $(this).attr('class');
var qty = $(this).val();
var postData_updatecart = {
'rowid' : rowid,
'qty' : qty
};
//posting data to update cart
$.ajax({
url : base_url + 'bookings/update_booking_cart',
type : 'post',
data : postData_updatecart,
beforeSend : function() {
$('#cart_content').html('Updating...');
},
success : function(html) {
//window.location.href = "postproperty.php?type="+suffix+'&page=page1';
$('#cart_content').html(html);
}
});
});
});
I have cart view file as
<div class="cart_form">
<?php echo form_open(base_url().'index.php/bookings/customerdetails', array('class' => 'bookings_form_customer', 'id' => 'bookings_form_customer')); ?>
<table cellpadding="6" cellspacing="1" style="width:100%" border="0">
<tr>
<th style="text-align:left">Item Description</th>
<th style="text-align:left">QTY</th>
<th style="text-align:right">Item Price</th>
<th style="text-align:right">Sub-Total</th>
</tr>
<?php $i = 1; ?>
<?php foreach ($this->cart->contents() as $items): ?>
<?php echo form_hidden($i.'[rowid]', $items['rowid']); ?>
<tr>
<td>
<?php echo $items['name']; ?>
<?php if ($this->cart->has_options($items['rowid']) == TRUE): ?>
<p>
<?php foreach ($this->cart->product_options($items['rowid']) as $option_name => $option_value): ?>
<strong><?php echo $option_name; ?>:</strong> <?php echo $option_value; ?><br />
<?php endforeach; ?>
</p>
<?php endif; ?>
</td>
<td>
<select name="<?php echo $i.'[qty]'; ?>" class="<?php echo $items['rowid']; ?>">
<?php
for($tt=0; $tt<=10; $tt++)
{
?>
<option value="<?php echo $tt; ?>" <?php if($tt==$items['qty']) echo 'selected="selected"'; ?>><?php echo $tt; ?></option>
<?php
}
?>
</select>
</td>
<td style="text-align:right"><?php echo $this->cart->format_number($items['price']); ?></td>
<td style="text-align:right">$<?php echo $this->cart->format_number($items['subtotal']); ?></td>
</tr>
<?php $i++; ?>
<?php endforeach; ?>
<tr>
<td colspan="2"> </td>
<td class="right"><strong>Total</strong></td>
<td class="right">$<?php echo $this->cart->format_number($this->cart->total()); ?></td>
</tr>
</table>
<p><?php echo form_submit('update_cart', 'Update your Cart'); ?></p>
</form>
</div>
Things are working Nice. But, lets say if I have 2 products, if i select one item's qty from 1 to 2, cart is updated and updated cart is shown using AJAX. But, if I immediately change another item's qty then it doesnt work.
The cart view file is inside class 'cart_form'.
Helping hands are appreciated.
I got an answer. You can refer below link
Ajax Request works only once
OR
Directly follow this
REPLACE jquery code part by
$(function() {
$(document).on( "change", "#bookings_form_customer select", function(ev) {
// your code goes here
});
});