I am currently bringing a form into a div like this:
$('#m').load('http://example.com/converter/index.php #converty');
I need the results to display in the #m div, currently it takes me to the converter/index.php page, any help appreciated! The form that is loaded:
<form action="/converter/index.php" method="post" id="conversionForm" style="display: block;">
**do stuff**
</form>
FYI: the page with the script is at the root domain, while the converter is in the folder example.com/converter directory.
Prevent the default behavior of the form submit by using the .submit method on the form element, then collect your form data by using .serializeArray and do what you need to do with it.
Here is an example.
$( "form" ).submit(function( event ) {
var formData = $( this ).serializeArray();
$.each(formData, function(i, item) {
var $p = $("<p>");
$p.text(item.name + ": " + item.value);
$("#output").append($p);
})
event.preventDefault();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="output"></div>
<form method="get" action="foo.php">
<div><input type="text" name="a" value="1" id="a"></div>
<div><input type="text" name="b" value="2" id="b"></div>
<div><input type="hidden" name="c" value="3" id="c"></div>
<div>
<textarea name="d" rows="8" cols="40">4</textarea>
</div>
<div><select name="e">
<option value="5" selected="selected">5</option>
<option value="6">6</option>
<option value="7">7</option>
</select></div>
<div>
<input type="checkbox" name="f" value="8" id="f">
</div>
<div>
<input type="submit" name="g" value="Submit" id="g">
</div>
</form>
Related
I have a form for a quiz that has 3 different inputs. Number of questions, and two types of tests. i am modifying existing code that works fine but we want the layout different which requires it to be coded differently. this is the version that isn't working. Basically I need the number of questions and category to be sent with the button clicked. For some reason it isn't sending either. Any help would be great, thanks!
<strong>Questions</strong>
<select name="num_questions">
{section name=foo start=10 loop=31}
<option value={$smarty.section.foo.index}>{$smarty.section.foo.index}</option>
{/section}
</select>
</div>
<select onchange="$('.questions_{$c.categorynum}').val(this.value);" name="category">
{foreach from=$categories item=c}
{if ($c.categorynum != 1 and $c.categorynum < 8)}
<div class="questiontitle" style="float:left;">
<option value={$c.categorynum}><strong>{$c.name}</strong></option>
</div>
{/if}
{/foreach}
</select>
<form action="test.php" method="post" style="float:left;">
<input type="submit" value="Create Exam" name="create" style="margin:0 3px;"/>
<input type="hidden" name="category" class="category" value="{$c.categorynum}"/>
<input type="hidden" class="questions_{$c.categorynum}" name="num_questions" value="10"/>
</form>
<form action="simulation.php" method="post" style="float:left;">
<input type="submit" name="flashcard" value="Flash Cards" style="margin:0 3px;"/>
<input type="hidden" name="create" value="1"/>
<input type="hidden" name="category" value="{$c.categorynum}"/>
<input type="hidden" class="questions_{$c.categorynum}" name="numquestions" value="10"/>
</form>
I want to clear all form input data after a submitting all input data to php file how can I clear this data by using jquery function?
You can listen to the submit event and then clear the values of each input like below:
$('#form').submit(function() {
$(this)[0].reset();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="form">
<input type="text" />
<input type="submit" />
</form>
This should work...
$('form').on('submit', function() {
var children = $(this).children()
children.each(function(i, el) {
if ($(el).attr('type') === 'checkbox') return $(el).removeAttr('checked')
$(el).val(null)
})
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<input type="text" />
<br>
<input type="text" />
<br>
<input type="checkbox" />iphone
<input type="checkbox" />Android
<br>
<input type="radio" name="gender" value="male" checked>Male
<br>
<input type="radio" name="gender" value="female">Female
<br>
<input type="radio" name="gender" value="other">Other
<br>
<select>
<option value="volvo">Volvo</option>
<option value="saab">Saab</option>
<option value="mercedes">Mercedes</option>
<option value="audi">Audi</option>
</select>
<br>
<button type="submit"> submit </button>
</form>
try this
$(document).ready(function(){
$('#submit').click(function(){
$('#my_form').find("input[type=text]").val("");
});
});
document.querySelector(".name").value = "";
<form class="form">
<input type="text" class="name"/>
<input type="submit" value="Send" class="submit"/>
</form>
Then the input value will be always empty
Goal:
When I clickon the clear all button and the data inside of the input box should be empthy and the dropdownlist should go back to default settings that is year 2009.
Problem:
I don't know how to do in order to make the dropdownlist to go back to default when you have pressed the button?
Info:
Please remember that I do not want to make any big changes in the current javascript/jquery sourcecode because it is used in production phase.
I would like to make a complementary to the current source code.
I tried using <input type="reset" value="Clear alll" name="clear_all"> but it doesn't work in long term with the current source code.
Thanks!
http://jsbin.com/qezesohake/edit?html,js,console,output
function df(data) {
$(data).find(':input').each(function () {
switch (this.type) {
case 'text':
case 'textarea':
$(this).val('');
break;
}
});
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<form action=""" method="post">
<fieldset>
<input id="aaa" type="text" value="" />
<input id="bbb" type="text" value="" />
<select id="year">
<option value="2010">2010</option>
<option value="2009" selected="selected">2009</option>
<option value="2008">2008</option>
</select>
</fieldset>
<input type="button" value="Clear alll" name="clear_all" onclick="df(this.form)" />
</form>
<form action="#" method="post">
<fieldset>
<input id="aaa" type="text" value="" />
<input id="bbb" type="text" value="" />
<select id="year">
<option value="2010">2010</option>
<option value="2009" selected="selected">2009</option>
<option value="2008">2008</option>
</select>
</fieldset>
<input type="reset" value="Clear alll" name="clear_all" onclick="doSomething()">
</form>
<script>
function doSomething(){
alert('Do something!');
}
</script>
You don't need any javascript to clear form instead just replace your input type to reset button
<input type="reset" value="Clear all" name="clear_all"/>
Reset button does not require any onClick event to be passed. It works automatically.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<form action=""" method="post">
<fieldset>
<input id="aaa" type="text" value="" />
<input id="bbb" type="text" value="" />
<select id="year">
<option value="2010">2010</option>
<option value="2009" selected="selected">2009</option>
<option value="2008">2008</option>
</select>
</fieldset>
<input type="reset" value="Clear alll" name="clear_all" />
</form>
When I load the page both forms are displayed. If I check and then uncheck "add" the second form disappears. How do I make this page load with form 2 hidden on load?
<html>
<title>Car Service</title>
<strong>Car Service:</strong><br><br>
<input type="submit" id="accountsearch" name="accountsearch" value="Select Customer" onclick="window.open('selectaccount.php');"><br><br>
<form name="newservicesetup" id="newservicesetup" action="" method="post">
<select name="ordertype" id="ordertype">
<option>(Select Service)</option>
<option value="Service">Service</option>
<option value="ServiceHardware">Service w/ Hardware</option>
</select>
<input type="text" name="qty1" id="qty1" value="Quantity" size="5" onclick="this.value=''">
<input type="checkbox" id="add" value="0" name="add" onclick="
if (this.checked) {
document.getElementById('newservicesetup1').style.display='inline';
} else {
document.getElementById('newservicesetup1').style.display='none'; } return true;" >
</form>
<form name="newservicesetup1" id="newservicesetup1" action="" method="post">
<select name="ordertype1" id="ordertype1">
<option>(Select Service)</option>
<option value="Service">Service</option>
<option value="ServiceHardware">Service w/ Hardware</option>
</select>
<input type="text" name="qty2" id="qty2" value="Quantity" size="5" onclick="this.value=''">
</form>
<br>
XX: <input type="file" name="sfa" id="sfa">
AA1: <input type="file" name="pbxws" id="pbxws"><br> <br>
<input type="submit" name="next" id="next" value="Next">
set the second forms css class to hidden or something like that and then define .hidden in your css to be display:none. Or put style='display:none' t ostart with on the second form
Change your second form tag to read this....
<form name="newservicesetup1" id="newservicesetup1" action="" method="post" style="display:none;">
I have regular form like this.
<form action="/domainchecker.php" method="post">
<input type="text" name="domain" size="20">
<fieldset>
<select name="ext">
<option>.com</option>
<option>.net</option>
<option>.org</option>
<option>.us</option>
<option>.info</option>
<option>.biz</option>
<option>.mobi</option>
<option>.name</option>
<option>.tv</option>
<option>.me</option>
</select>
</fieldset>
<input type="submit" value="Go">
</form>
This selectbox enables to select only one option.
What I want is Forced selection in hidden / backend for the first 5 options regardless user select it or not.
How can I achieve this using JavaScript OR JQuery ?
Thanks.
Since you are using PHP you can try this:
<form action="/domainchecker.php" method="post">
<input type="hidden" name="ext[]" value=".com">
<input type="hidden" name="ext[]" value=".net">
<input type="hidden" name="ext[]" value=".org">
<input type="hidden" name="ext[]" value=".us">
<input type="hidden" name="ext[]" value=".info">
<input type="text" name="domain" size="20">
<fieldset>
<select name="ext[]">
<option>.com</option>
<option>.net</option>
<option>.org</option>
<option>.us</option>
<option>.info</option>
<option>.biz</option>
<option>.mobi</option>
<option>.name</option>
<option>.tv</option>
<option>.me</option>
</select>
</fieldset>
<input type="submit" value="Go">
</form>
Note the brackets in the fields' names. In your PHP script you'll need something like:
$extensions = $_POST['ext'];
foreach ($extensions as $ext) {
#do something
}
Note that the $extensions array will contain duplicates if the user selected one of the first 5 entries in the dropdown.
You can also use checkboxes instead of a dropdown like this:
<form action="/domainchecker.php" method="post">
<input type="text" name="domain" size="20">
<fieldset>
<input type="checkbox" name="ext[]" value=".com" selected="true">
<input type="checkbox" name="ext[]" value=".net" selected="true">
<input type="checkbox" name="ext[]" value=".org" selected="true">
<input type="checkbox" name="ext[]" value=".us" selected="true">
<input type="checkbox" name="ext[]" value=".info" selected="true">
<input type="checkbox" name="ext[]" value=".biz">
<input type="checkbox" name="ext[]" value=".mobi">
<input type="checkbox" name="ext[]" value=".name">
<input type="checkbox" name="ext[]" value=".tv">
<input type="checkbox" name="ext[]" value=".me">
</select>
</fieldset>
<input type="submit" value="Go">
</form>
The PHP is the same, without the duplicate issue
Add them server-side.
you can't do multiple selection on your select if attribute multiple is not set
like this, then have default selection by setting the option's attribute selected="selected"
<fieldset>
<select name="ext" size="5" multiple="multiple" >
<option>.com</option>
<option>.net</option>
<option selected="selected">.org</option>
<option selected="selected">.us</option>
<option selected="selected">.info</option>
<option>.biz</option>
<option selected="selected">.mobi</option>
<option>.name</option>
<option>.tv</option>
<option>.me</option>
</select>
</fieldset>