How to make the progress bar Like the image below
I think the easiest way would be to use something like:
css:
.progress
{
position:relative;
width: 100px;
height: 100px;
}
.progressUnder
{
position: absolute;
width: 100%;
height: 100%;
background-image: url('backgroundUnder.jpg');
}
.progressOver
{
position: absolute;
width: 100%;
height: 0%;
background-image: url('backgroundOver.jpg');
}
.progressPercent
{
position:absolute;
top: 40px;
width: 100%;
text-align: center;
}
and html:
<div class='progress'>
<div class='progressUnder'/>
<div class='progressOver' />
<div class='progressPercent'>0%</div>
</div>
and then use javascript to animate the percent height of div.progressOver, as well as the .progressPercent counter.
You need to use a animation I think.
Aswell as The Molecule says. You need to use height for that color. I guess you know how an normal one works. First try to out create a circle, use the height as The Molecule explained, then you need to make the inside of the circle transparent/unneeded. As that is done the heights will be displayed in the circle. That how you do it, never done it myself tho since i dont use custom loading bars.
Related
I would like to do something pretty standard in HTML/CSS/javascript I think but somehow I didn't find any solution for now: I want to have multiple images on each other with some of them being clickable. For example:
submarine with red circle button as window in this case the submarine is one img and the red circle is an input type="image" working as a button.
I want those multiple images to behave "as one" in term of responsivness and scaling so that I still see the same overall image independantly of the size of my window.
If I use this trick here: How do I position one image on top of another in HTML? and make both images responsive then the circle is not scaling down simultanuously with the submarine. Moreover, since the red circle is positioned in an absolute way it is not staying at the same place relative to the submarine.
here is my current code:
.div{
position: relative;
}
.responsive {
max-width: 100%;
}
#test2 {
width: 12.3%;
position:absolute;
z-index: 2;
left: 73%;
top: 62%;
}
#test
{
width: 100%;
position:relative;
z-index: 1;
}
<div>
<img src="/submarine.png" id="test" class="responsive" />
<input type="image" src="/red_circle.png" id="test2" class="responsive" />
</div>
In order to achive that, you can work with percentages, so if you reduce the scale of the window the size of the images reduce as well.
CSS:
.submarine {
width: 30%;
height: 55%;
position: relative;
}
.redDot {
width: 2%;
position: absolute;
}
HTML:
<div>
<img src="submarine.jpg" clas="submarine">
<img src="redDot.png" class="redDot">
</div>
Then play with the margins in orther to position the red dot in the submarine.
Dimensions and positions in percentages relate to the dimensions of the parent element. In your case the window of the submarine should be positioned as a percentage of the submarines dimensions. What you should do to make this is work is to put the window as a child in the submarine. Easiest would be to work with divs with background-images and use background-size: 100% to make the background-images scale with the elements.
Also you could use the "padding-bottom trick" to set the "height" of the div to a percentage of the parent's width.
#submarine {
background: yellow;
width: 30%;
padding-bottom: 20%;
position: absolute;
left: 20%;
top: 20%;
}
#window{
position: absolute;
background: red;
width: 20%;
padding-bottom: 20%;
right: 5%;
top: 40%;
background: red;
}
<div id="submarine">
<div id="window"></div>
</div>
I would like to get a circle to expand from itself, while keeping the original circle. What I want is something like when you hover over the circles (e.g. water) on this page (click lets get started to see the circles). I'm not sure how to do this. Note that my knowledge of jQuery is quite small, so if you find a way to do this with jQuery, can you try to keep it simple? Thanks in advance. The earlier the better, as this is for a school project.
I tried to make the div have a function for onmouseover, but then I don't know how to get the rest. I was thinking about while the div animates from a smaller width and height, to move the circle, but the circle will still expand from the middle, and not the old circle.
Start with a CSS-only setup, then see if you actually need Javascript at all. This will generally always be more responsive/faster-loading. However, if you're already loading a JS library and it has functions built for this (like jQuery), then sure make use of them. There are plenty of tutorials for animating elements, CSS or JS.
Play around with numbers and styling as you wish.
Codepen
#container {
width: 100%;
height: 100vh;
display: flex;
justify-content: center;
align-items: center;
}
.circle {
width: 200px;
height: 200px;
background-color: red;
border-radius: 50%;
}
.circle:before {
content: "";
width: 200px;
height: 200px;
border-radius: 50%;
position: absolute;
z-index: -1;
display: inline-block;
top: 50%;
left: 50%;
transform: translate(-50%,-50%);
transition: 0.5s ease-in-out;
}
.circle:hover:before {
transform: scale(1.7) translate(-20%,-30%);
background-color: pink;
}
<div id="container">
<div class="circle red"> </div>
</div>
I have 2x Divs and 1x Img with the following CSS
#StageDiv {
position: absolute;
left: 50%;
margin-left: -200px;
}
#LogoDiv {
position: absolute;
margin-top: 135px;
left: 50%;
margin-left: -500px;
}
#logoimg {
/* max-width: 75%; /* */
width: 1000px; /* */
}
inside of #logoimg, I would like to use max-width: 75%; and then have margin-left: of both #LogoDiv and #StageDiv be a function of #logoimg as it changes
http://jsfiddle.net/3KLUW/1/
Is this possible in pure CSS or will I have to do this in javascript in a on resize event? (not sure what the actual function call is currently but im sure my buddy google will know) I think in the long run, I will most likely have to use a javascript event to scale my kineticjs stage anyway but I am curious to know if there is some CSS wizardry to do the first part.
Thoughts?
Edit:
window.onresize=function(){
var img = document.getElementById('logoimg');
var width = img.offsetWidth;
var div = document.getElementById('LogoDiv');
div.style.marginLeft= "-" + width/2 + "px";
};
still would be interested in a CSS solution
If you can get away with a wrapper div for the whole logo:
<div id="logo">
<div id="StageDiv">...</div>
<div id="LogoDiv">
<img id="logoimg" src="..." />
</div>
</div>
Then you can set the width and max-width on it, and use margin: auto to center it on the page:
#logo {
width: 1000px;
max-width: 75%;
margin: auto;
position: relative;
}
And positioning the other elements become much easier:
#LogoDiv {
top: 135px;
position: absolute;
}
#StageDiv {
text-align: center;
}
#logoimg {
width: 100%;
}
The margin: auto and text-align: center together give us the automatic margin you wanted.
Updated fiddle: http://jsfiddle.net/3KLUW/2/
The canvas will need to be scaled though, as you said on the question.
I've been experimenting with a way to get a page element to overlap the elements on either side of it and stay perfectly centered between them. My solution was to declare position:relative and set negative margin values roughly equal to 50% of the element's width, but the closest I've been able to come is to half the element's percentage of its parent's width:
<!DOCTYPE html>
<html>
<head>
<style>
.clap {
position:relative;
margin:auto -16.66%; // This element's share of the entire parent's width = 33.33%
color:#f00
}
</style>
</head>
<body>
<center>
<span style="display:inline-block">1234567890<span class="clap">1234567890</span>1234567890</span>
</center>
</body>
</html>
I'm trying to find a CSS-only solution that will use the width of the element itself, not the width of the container. I can't use JavaScript to do this because I plan to use it as a MathJaX fix by embedding it in a \style command. (As far as I know, MathJaX does not provide for embedded HTML or JavaScript code within its formulas, so you see why this must be CSS-only. I know it's possible with scripting. Is it possible with CSS, or is my endeavor hopeless?
Update: Thanks to a suggestion from #Daiwei, I think I'm on the road to the right solution. Thanks for all your answers. Here is the revised code:
.clap {
position:absolute;
display:inline-block;
transform: translate(-50%,0);
color:#f00 // for contrast
}
I'd love to show you the results, but I can't upload a picture. Sorry.
Another update: The solution I presented above works best in an HTML/CSS context, but it breaks in a MathJaX array, matrix, or similar tabular environment. Specifically, if the element is too long, it clips on the left side. Relative positioning moves the element halfway to the left but leaves a gaping space where it used to be! Any ideas for patching it up?
One pure CSS solution is to use transform.
element
{
position: relative;
top: 50%;
transform: translateY(-50%);
}
Notes:
You can use top: 50%; for vertical and left: 50%; for horizontal.
You would then use translateY(-50%) for vertical and translateX(-50%) for horizontal centering.
You can also use this trick to align elements to the bottom or right of it's parent, like in a table-cell by using 100% instead of 50% in the css.
If you want to support older browsers, then you'll need to use prefixes for transform. I highly recommend autoprefixer in your workflow.
As the size of the element is only known after it has been styled, how should the style be able to use it? Imagine this: Some element has a width of 200% of it's own width (=double size than "normal") set in CSS. One of it's children has its width set to 100% of the parent (=our element). The default width of an element is determined by its content. Content's of our element are as width as the element itself. Our element has no width yet however, as we're waiting for it to get some default, so we can double that one. Result: Nothing will ever get any width.
Therefore: What you're trying to do is not possible. But CSS3 has its calc, maybe you can get closer to what you want to acheive using it?
I don't know if this is what you wanted to do, but here is a demo: http://cdpn.io/bgkDf
HTML
<div class="container">
<div id="box-left"></div>
<div id="box-overlap">
<div id="box-overlap-inner"></div>
</div>
<div id="box-right"></div>
</div>
CSS
.container > div {
height: 50px;
float: left;
}
#box-left {
width: 40%;
background-color: red;
}
#box-right {
width: 60%;
background-color: green;
}
#box-overlap {
width: 0;
}
#box-overlap-inner {
position: relative;
z-index: 10;
height: 50px;
width: 50px;
transform: translate(-50%,0);
background-color: rgba(0,0,255,.5);
}
"Using element's own width for calculation or percentage" In general:
(Maybe not the best solution for your issue, but an answer to your question)
At the moment,the attr function doesn't work in Chrome. That would have been nice.
But you can use variables, if you either set the parent attribute yourself, or are able to use a predefined one. That way you can use the calc() function to calculate your child attribute.
Here is an example, using the browser defined viewport size, to calculate the width of an element:
<!DOCTYPE html>
<html>
<head>
<style>
:root {
--module-size: 33vw;
}
.clap {
display:inline-block;
width: calc(var(--module-size) / 2);
color:#f00;
border: 1px solid;
}
</style>
</head>
<body>
<center>
<span style="display:inline-block">1234567890
<span class="clap">1234567890</span>
1234567890</span>
</center>
</body>
This can be used in many interesting ways, to streamline your CSS. For instance with the #media style...
And if someone (like me) was trying to center the element by its parent, use this simple style:
.clap {
position:absolute;
left: 50%;
transform: translate(-50%,0);
}
What about converting the content to divs and enclose each within another div to use
margin: auto
?
Example (each super div within its own colour and shifted a little in height for clarity):
<html>
<head>
<style>
.dl
{
position: absolute;
left: 0px;
top: 0px;
max-width: 50%;
width: 50%;
text-align: left;
background: red;
opacity: 0.5;
}
.dls
{
margin: auto;
}
.dc
{
position: absolute;
left: 25%;
top: 10px;
max-width: 50%;
width: 50%;
text-align: center;
background: green;
opacity: 0.5;
color: white;
}
.dcs
{
margin: auto;
}
.dr
{
position: absolute;
right: 0px;
top: 20px;
max-width: 50%;
width: 50%;
text-align: right;
background: blue;
opacity: 0.5;
color: white;
}
.drs
{
margin: auto;
}
.overall-width
{
position: absolute;
left: 0%;
width:100%;
height: 20px;
margin: auto;
}
</style>
</head>
<body>
<div class="overall-width">
<div class="dl">
<div class="dls">
1234567890
</div>
</div>
<div class="dc">
<div class="dcs">
1234567890
</div>
</div>
<div class="dr">
<div class="drs">
1234567890
</div>
</div>
</div>
</body>
</html>
http://jsfiddle.net/3qMnM/1/
HTML:
<div class="info-panel"></div>
<div class="image">
<img src="http://placehold.it/960x1400">
</div>
CSS:
.image {
height: 100%;
width: auto;
margin-right: 200px;
}
.info-panel {
position: fixed;
width: 200px;
height: 100%;
background-color: red;
right: 0px;
}
I'm trying to scale images down (never up) dynamically to fit into the image-div (without cropping), which is variable in height (100%) and width (set to auto). The image also needs to be centered (vertically and horizontally) and have equal padding of a few pixels top and bottom.
There is an info panel next to the image container as you can see in the fiddle, but I'm not sure if this is relevant.
Do my statements make sense?
Thanks, I have spent way too much time experimenting with this already! :/
If I understand correctly, you want something like this.
It scales down if the image is too large, but keeps the original size when it fits inside the window. In other words, it never scales up - only down.
It is a combination of CSS and some jQuery:
This short JS centers the image vertically:
function verticallyCenterImage(){
var $img = $('.image img'),
windowHeight = $(window).outerHeight();
if($img.height() < windowHeight){
var delta = windowHeight - $img.height();
$img.css('margin-top', (delta / 2) + 'px');
}else{
$img.attr('style', '');
}
}
And this line of CSS keeps the image centered horizontally:
.image {
padding-right: 200px;
text-align: center; /* <- this one */
max-height: 100%;
overflow: hidden;
}
And to keep the original size of the image, I just set the max height and width on the img inside the .image class, like so:
.image img {
max-width: 96%;
max-height: 96%;
margin: 2%;
}
You can adjust the size and margins to your needs, just remember to keep them in relation too each other :)
Some of the techniques discussed here could work for you:
http://css-tricks.com/centering-in-the-unknown/
The trick there is to use table elements, or CSS 2.1 table display.
Edit: More approaches here: http://www.vanseodesign.com/css/vertical-centering/
You are mixing px with %. If you want to achieve that only by CSS, you need to use % for both widths:
.image {
width: 85%;
}
.image img {
width: 100%;
}
.info-panel {
position: fixed;
width: 15%;
height: 100%;
background-color: red;
right: 0px;
}
... otherwise, you have to use JS to calculate the current available width on the left side and assing it the .image div:
HTML
<div class="info-panel"></div>
<div class="image">
<img src="http://placehold.it/960x1400" />
</div>
CSS
.image {
min-height: 600px;
width: auto;
}
.image img {
width: 100%;
}
.info-panel {
position: fixed;
width: 200px;
height: 100%;
background-color: red;
right: 0px;
}
JS (jQuery)
$(document).ready(function() {
$('.image')
.css('min-height', 'auto')
.height($(window).height())
.width($(window).width() - $('.info-panel').width())
;
});