We Keep Coding

I want to make a cart with php and js with the js sending a post request

<script>
function cart(func,id){
let url = "<?= SITEURL ?>Home/cart/" + func;
var xhr = new XMLHttpRequest();
xhr.open("POST", url, true);
xhr.setRequestHeader('Content-Type', 'application/json');
xhr.send(JSON.stringify({
"value": id
}));
}
</script>
case 'cart':
require_once "modelProduct.php";
$model = new Product();
$idItem = $_POST['value'];
if($aParam[2] == 'add'){
if(isset($_SESSION['cart'])){
array_push($_SESSION['cart'],$idItem);
} else {
$_SESSION['cart'] = array();
array_push($_SESSION['cart'],$idItem);
}
} else if($aParam[2] == 'remove'){
if (($key = array_search($idItem, $_SESSION['cart'])) !== false) {
unset($_SESSION['cart'][$key]);
}
}
$category= $model->getById($idItem);
$aData['data'] = $products->getListaWhere("product_id = {$idItem}");
require_once "site/productsView.php";
break;
From what I saw this should send post request to site/Home/cart/func and there what would happened would be the ID would be added to the session['cart'] and the page would refresh but instead nothing seams to be happening

pass two different variables in javascript?

this is my javascript of first page
<script>
function MessageDetailsById(id)
{
$("#active"+id).css({"color":"red"});
var http = new XMLHttpRequest();
var url = "Ajax.php";
var adm = "<?php echo $admno; ?>";
var params = "Id="+id;"adm="+adm;
http.open("POST", url, true);
http.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
http.onreadystatechange = function() {
if(http.readyState == 4 && http.status == 200) {
//alert(http.responseText);
}
}
http.send(params);
window.location.href="#";
}
</script>
this is the coding of ajax.php
<?php
include("model.php");
$DB=new database;
if(isset($_POST["Id"]))
{
$DB->updateMassageTitleStauts($_POST["Id"],$_POST["adm"]);
}
else
{
header("Location:index.php?ajaxmas=wHgfghks^^%&fnjfskjdfb");
}
?>
i want to send one variable of php and another is id of a div... how to send two parameters and recieves them on other side ??? please correct this code in details i am not expert ???

For the post data encoding:
var params = "Id=" + id + "&adm=" + adm;
Use & for separator.

How do I echo multiple values from a PHP file to a Javascript Ajax call?

With reference to the code attached below, I wish to reference variables which have been initialized in my processUsersAnswers.php, in my index.php file.
Code snippet in index.php
<script type="text/javascript">
function checkAnswers(){
var xhr = new XMLHttpRequest();
/* code */
xhr.open("POST", "processUsersAnswers.php", true);
xhr.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xhr.onreadystatechange = function() {
if(xhr.readyState == 4 && xhr.status == 200) {
/* code */
}
}
xhr.send(vars); //
}
Code snippet in processUsersAnswers.php
<?php
$score = 403;
$userAnswers = array();
$userAnswers[0] = "bla bla";
$userAnswers[1] = "asfasfaeg";
$userAnswers[2] = "erhehdfh";
/*How can I retrieve $userAnswers in my index.php file? */
?>
For instance, how can I retrieve the value for $score in my index.php file?

Try this :
Your new processUsersAnswers.php file
<?php
$score = 403;
$userAnswers = array();
$userAnswers[0] = "bla bla";
$userAnswers[1] = "asfasfaeg";
$userAnswers[2] = "erhehdfh";
echo json_encode('score' => $score);
exit;
And in your JS :
<script type="text/javascript">
function checkAnswers(){
var xhr = new XMLHttpRequest();
/* code */
xhr.open("POST", "processUsersAnswers.php", true);
xhr.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xhr.onreadystatechange = function() {
if(xhr.readyState == 4 && xhr.status == 200) {
var json = JSON.parse(xhr.responseText);
alert(json.score);
}
}
xhr.send(vars); //
}
This is not mandatory to use JSON, but this way you can easily add more info from the server.

How can I pass data from client to server use raw AJAX?

Hello I have already search but they often use jquery ajax to pass data from js to PHP(server-side). but for my project it has a bunch of pure js code so I should use raw AJAX to pass data.
For example, if I want to send a variable "Imgname" that value = 13 and want to echo in php page.
this is my try
<script>
if(window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = function() {
if(xmlhttp.readyState === 4 && xmlhttp.status === 200) {
alert('send to server successfully');
}
};
xmlhttp.open("POST", "test2.php", true);
xmlhttp.send("Imgname=13");
}
</script>
in test2.php
<?php
$temp = $_POST['Imgname'];
echo $temp; /////output should be 13
?>
but error Undefined index: Imgname in C:\xampp\htdocs\test2.php on line 2

You need to make sure that you're sending the correct content-type:
xmlhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");

Try sending the header:
var http = new XMLHttpRequest();
var url = "test2.php";
var params = "Imgname=13";
http.open("POST", url, true);
http.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
http.onreadystatechange = function() {//Call a function when the state changes.
if(http.readyState == 4 && http.status == 200) {
alert(http.responseText);
}
}
http.send(params);

Post data using XMLHttpRequest to laravel 5.2 controller as request

I have done posting/updating successfully with javascript XMLHttpRequest() to php $_REQUEST like:
function ajax_edit(e_id){
var edit_form = document.getElementById('edit_form'+e_id);
var e_name = document.getElementById('name'+e_id).value,
e_email = document.getElementById('email'+e_id).value,
e_contact = document.getElementById('contact'+e_id).value,
e_status = document.getElementById('status'+e_id).value;
xmlhttp.open('GET', 'hello-world.php?edit=yes&id='+e_id+'&name='+e_name+'&email='+e_email+'&contact='+e_contact+'&status='+e_status, true);
xmlhttp.send();
$('#edit'+e_id).modal('hide');
return false;
edit_form.reset();
}
And my php work was like:
if(isset($_REQUEST['edit'])){
$name = mysqli_real_escape_string($conn, strip_tags($_REQUEST['name']));
$email = mysqli_real_escape_string($conn, strip_tags($_REQUEST['email']));
$contact = mysqli_real_escape_string($conn, strip_tags($_REQUEST['contact']));
$status = mysqli_real_escape_string($conn, strip_tags($_REQUEST['status']));
$edit_sql = "UPDATE users SET name = '$name', email = '$email', contact = '$contact', status = '$status' WHERE id = '$_REQUEST[id]'";
$run_edit = mysqli_query($conn, $edit_sql);
}
Now I am trying to apply the same process to another Laravel 5.2 project but don't know how to do, specially the url (hello-world.php?edit=yes) part from where I will send data to my controller as request.
So far I have done with this:
function submit_form(edit_id){
xmlhttp = new XMLHttpRequest();
var edit_form = document.getElementById('edit_form'+edit_id);
var url = "{{ URL::to('updatelabdetails'); }}";
var edit_labname = document.getElementById('labname'+edit_id).value,
edit_pcname = document.getElementById('pcname'+edit_id).value;
alert(edit_pcname);
var params = "labname='+edit_labname+'&pcname='+edit_pcname";
alert(params);
xmlhttp.open('GET', url+"?"+params, true);
xmlhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xmlhttp.onreadystatechange = function() {
if(xmlhttp.readyState == 4 && http.status == 200) {
alert(xmlhttp.responseText);
}
}
xmlhttp.send();
return false;
}
But only able to output till alert(edit_pcname); part.
My Route:
Route::post('updatelabdetails', 'LoginController#updateLabDetails');
My Controller:
public function updateLabDetails(Request $request){
$post = $request->all();
var_dump($post);
die();
}
After submitting its going to some url like /showlabdetails? with MethodNotAllowedHttpException error.
Thanks in advance.

Please update your submit_form function like this
function submit_form(edit_id){
var edit_labname = document.getElementById('labname'+edit_id).value,
edit_pcname = document.getElementById('pcname'+edit_id).value;
var http = new XMLHttpRequest();
var url = "updatelabdetails";
var params = "labname='+edit_labname+'&pcname='+edit_pcname";
http.open("POST", url, true);
http.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
http.onreadystatechange = function() {
if(http.readyState == 4 && http.status == 200) {
alert(http.responseText);
}
}
http.send(params);
}

Your laravel roure isn't correct you've registered POST route and accessing the GET one.
Change Route::post('updatelabdetails', 'LoginController#updateLabDetails'); to Route::get('updatelabdetails', 'LoginController#updateLabDetails');

you need to add token in your request as said in the laravel documentation. see this link https://laravel.com/docs/5.4/csrf