I have an array currently only with names because I cannot figure out how to add more information but not make the script sort that data. For every entry in the array I wish to add a number between 1-20 for each, and also a count of how many is named that name. So it would something like 1. Nielsen (100,000). It's only a problem with my second function because I need to sort it by length.
<script>
var arr = []
arr[0] = " Nielsen"
arr[1] = " Jensen"
arr[2] = " Hansen"
arr[3] = " Pedersen"
arr[4] = " Andersen"
arr[5] = " Christensen"
arr[6] = " Larsen"
arr[7] = " Sørensen"
arr[8] = " Rasmussen"
arr[9] = " Jørgensen"
arr[10] = " Petersen"
arr[11] = " Madsen"
arr[12] = " Kristensen"
arr[13] = " Olsen"
arr[14] = " Thomsen"
arr[15] = " Christiansen"
arr[16] = " Poulsen"
arr[17] = " Johansen"
arr[18] = " Møller"
arr[19] = " Mortensen"
document.getElementById("liste").innerHTML = arr; // Skriver den oprindelige rækkefølge
function Sorter1() {
arr.sort(); // Sorter efter aflabetisk rækkefølge
document.getElementById("liste").innerHTML = arr; // Skriver rækkefølgen
}
function Sorter2() {
arr.sort(function (a, b) {
return b.length - a.length || // sorter efter længde
a.localeCompare(b); // Sorter efter aflabetisk rækkefølge
});
document.getElementById("liste").innerHTML = arr; // Skriver rækkefølgen
}
</script>
If I understand you correct you would like to create a multidimensional array and then sort it on the name alphabetically and on character count. If that is correct I would suggest you to create an multidimensional object with the data needed. Then you will be able to sort on the name key and preserve the other information correctly.
Check this out, it may get you in the right direction
var arr = [
{
name: 'Nielsen',
num: 1,
count: 100
},
{
name: 'Jensenlongest',
num: 15,
count: 230
},
{
name: 'Jensenlong',
num: 13,
count: 500
},
{
name: 'Jensen',
num: 2,
count: 300
},
{
name: 'Hansen',
num: 5,
count: 400
}
]
// Just adds the unsorted arr to the list for demo purpose
updateList(arr)
// On "Sort by length" button click
document.getElementById('sort-by-length').addEventListener('click', function (event) {
arr.sort(sortNameByLength);
updateList(arr);
})
// On "Sort alphabetically" button click
document.getElementById('sort-alphabetically').addEventListener('click', function (event) {
arr.sort(sortNameAlphabetically);
updateList(arr);
})
// Sort by name alphabetically
function sortNameAlphabetically(a, b) {
return a.name > b.name
}
// Sort by name length
function sortNameByLength(a, b) {
return a.name.length - b.name.length
}
// Updates the list according to the current sorting of the arr
function updateList(names) {
var listHtml = ''
names.forEach(function (item, index) {
listHtml += item.name + ', ' + item.num + ' (' + item.count + ')<br>'
})
document.getElementById("liste").innerHTML = listHtml
}
https://jsfiddle.net/sbe8yzv0/4/
This will result in a list like this.
Hansen, 5 (400)
Jensen, 2 (300)
Jensenlong, 13 (500)
Jensenlongest, 15 (230)
Nielsen, 1 (100)
You can use an array of complex objects with the data structure you like (just be consistent). Then define your own sort() method that will compare only the name parameter of your objects. Here's a simple example:
var arr = [];
arr[0] = {ID: 1, Name: "Nielsen", Value: "100"};
arr[0] = {ID: 2, Name: "Jensen", Value: "200"};
// Sort based on the second column, 'Name'.
function sortByName(){
arr.sort(
function(x, y){
return x.Name > y.Name; // Compare and sort based on the 'Name' column only.
}
);
console.log(arr[0]); // If results are correct this is 'Jensen'.
console.log(arr[1]); // If results are correct this is 'Nielsen'.
}
Adapt this to your needs (add the proper columns and data, add the proper variables, make it so that it shows in your page's HTML) and it will do what you want.
Related
I have an array of objects. These objects have a property id. I need a function which returns the next available id (which is not used by an object).
array = [
{
id: 1
},
{
id: 2
},
{
id: 5
},
{
id: 3
}
]
I would like to have a function which takes an array as an input and returns a number (which is the next free id).
In the example case:
findFreeId(array){
magic happens
}
result --> 4
How about something like this?
function findFreeId (array) {
const sortedArray = array
.slice() // Make a copy of the array.
.sort(function (a, b) {return a.id - b.id}); // Sort it.
let previousId = 0;
for (let element of sortedArray) {
if (element.id != (previousId + 1)) {
// Found a gap.
return previousId + 1;
}
previousId = element.id;
}
// Found no gaps.
return previousId + 1;
}
// Tests.
let withGap = [{id: 1}, {id: 2}, {id: 5}, {id: 3}];
let noGap = [{id: 1}, {id: 2}];
let empty = [];
console.log(findFreeId(withGap)); // 4
console.log(findFreeId(noGap)); // 3
console.log(findFreeId(empty)); // 1
A simple approach is to get all the ID values, sort them, then starting at 0 look for the first missing number in the sequence. That may be OK where efficiency doesn't matter, but a more efficient method is to:
Get the IDs
Sort them
Step through the values to get the next available number
Insert the value in the list of IDs
Store the value so next time it starts at #3 from the previous value + 1
E.g.
class IDStore {
constructor(dataArray) {
if (!Array.isArray(dataArray)) {
return null;
}
this.previousIndex = 0;
this.indexes = dataArray.map(obj => obj.id).sort();
}
get nextIndex() {
while (this.indexes[this.previousIndex] == this.previousIndex) {
this.previousIndex++;
}
return this.previousIndex;
}
addIndex(index) {
if (!Number.isInteger(index) || this.indexes.find[index]) {
return null;
}
this.indexes.push(index);
this.indexes.sort();
return index;
}
}
var data = [ { id: 1 }, { id: 2 }, { id: 5 }, { id: 3 } ];
// Create an ID store
var idStore = new IDStore(data);
// Insert more objects in the array with unique IDs
for (var i=0, next; i<4; i++) {
// Current list of indexes
console.log('Indexes: ' + idStore.indexes);
// Get the next available index
next = idStore.nextIndex;
console.log('Next available: ' + next);
// Calling nextIndex doesn't affect next index
next = idStore.nextIndex;
console.log('Next available: ' + next);
// Use next index
data.push({id: next});
// Adding next index is manual
idStore.addIndex(next);
console.log('Added: ' + next);
}
// Data structure is independent
console.log('End: ' + JSON.stringify(data));
This is somewhat simplistic in that it assumes the IDs are sequential integers starting at 0 and doesn't have much validation or error handling.
Maintaining the id is separate from adding new members to the data array. It would be much better to combine the operations, so an "add object" method gets the next available ID, adds it to the object, adds the object to the array, updates the index and returns the new ID.
const findFreeId = (ids) => {
let id = 0;
for (id; ; id++) {
let isFree = true;
for (let i = 0; i < array.length; i++) {
const e = ids[i];
if (e === id) {
isFree = false;
break;
}
}
if (isFree) break;
}
return id;
}
In NodeJS I have a string like this
"Package=Package&Qty=1&Price=123?Package=Package Two&Qty=3&Price=702?Package=Package Three&Qty=1&Price=199?Package=Package One&Qty=4&Price=852?"
In the string you can see there are multiple Package, Qty and Price. Now I want to send email for each Qty and Package. So if you see Package Two it has Qty 3. So in that case there it will send 3 emails with Package and Price. So basically it will send email for each Qty with corresponding Package and Price.
So for now I have my code like this
var string = "Package=Package&Qty=1&Price=123?Package=Package Two&Qty=3&Price=702?Package=Package Three&Qty=1&Price=199?Package=Package One&Qty=4&Price=852?";
var packArr = string.split('?');
var PackageName;
var PackagePrice;
for (var i = 0; i < packArr.length; i++) {
if( packArr[i].length > 0 ) {
let packageQty = packArr[i].split('&');
for (var j = 0; j < packageQty.length; j++) {
if( packageQty[j].match(/Package=/i) ) {
PackageName = packageQty[j].replace(/Package=/g,'');
console.log(PackageName);
}
if( packageQty[j].match(/Price=/i) ) {
PackagePrice = packageQty[j].replace(/Price=/g,'');
console.log(PackagePrice);
}
if (packageQty[j].match(/Qty=/i)) {
var ret = packageQty[j].replace(/Qty=/g,'');
var Pck = Number(ret);
for (var k = 1; k <= Pck; k++) {
console.log(k);
console.log('Package Name ' + PackageName);
console.log('Package Price ' + PackagePrice);
//send email with Package Name, Package Price
if( k == Pck ) {
break;
}
}
}
}
}
}
The above code actually not working properly. It is not getting the Package and Price properly for each loop. So can someone tell me how to do this in a easy way? Any help and suggestions will be really appreciable.
Here's a much cleaner way using querystring package
const string = "Package=Package&Qty=1&Price=123?Package=Package Two&Qty=3&Price=702?Package=Package Three&Qty=1&Price=199?Package=Package One&Qty=4&Price=852?";
const qs = require('querystring');
// We split the string into multiple valid query strings.
// We strip the empty item due to the '?' at the end using .filter(Boolean)
const items = string.split('?').filter(Boolean);
// We loop through each group
for(const query of items) {
// Parse the query string of each group
const { Package, Qty, Price } = qs.parse(query);
for(let i = 0; i < Number(Qty); i++) {
// We send the email here <Qty> times.
console.log('Package Name ' + Package);
console.log('Package Price ' + Price);
}
}
I don't know how you feel about libraries, but Ramda (disclaimer: I'm one of the authors) is well-suited to data-transformations. And this screams for some straightforward data transformation.
I might use it to write a conversion function that changes your initial data into something like:
[
{Package: "Package", Price: 123, Qty: 1},
{Package: "Package Two", Price: 702, Qty: 3},
{Package: "Package Three", Price: 199, Qty: 1},
{Package: "Package One", Price: 852, Qty: 4}
]
This new format should then be easy to work with.
Here is a implementation that does this:
const {pipe, split, filter, map, fromPairs, evolve} = R;
const str = "Package=Package&Qty=1&Price=123?Package=Package Two&Qty=3&Price=702?Package=Package Three&Qty=1&Price=199?Package=Package One&Qty=4&Price=852?";
const convertToObjects = pipe(
split('?'),
filter(Boolean),
map(split('&')),
map(map(split('='))),
map(fromPairs),
map(evolve({Price: Number, Qty: Number}))
);
console.log(convertToObjects(str))
<script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.25.0/ramda.js"></script>
map, split, and filter should be obvious.
fromPairs turns [['a', 1], ['b', 2]] into {a: 1, b: 2}.
evolve takes a specification mapping property names to transformation functions, and transforms an object by applying those functions to the relevant properties, keeping all other properties intact. Here we use it with the JS Number function to convert {Package: 'Foo', Qty: '2', Price: '456'} into {Package: 'Foo', Qty: 2, Price: 456}.
and pipe creates a pipeline of functions in which the output of one function becomes the input to the next. Values supplied to the resulting function are sent to the first one and the result of the last one is returned.
Extending #Marcos-casagrande example here without external dependency using plain javascript
const string = "Package=Package&Qty=1&Price=123?Package=Package Two&Qty=3&Price=702?Package=Package Three&Qty=1&Price=199?Package=Package One&Qty=4&Price=852?";
// We split the string into multiple valid query strings.
// We strip the empty item due to the '?' at the end using .filter(Boolean)
const items = string.split('?').filter(Boolean);
// We loop through each group
items.map(query => {
// Parse the query string of each group
const {
Package,
Qty,
Price
} = query.split('&').reduce((acc, cur) => {
let arr = cur.split('=');
return {
...acc,
[arr[0]]: arr[1]
};
}, {});
for (let i = 0; i < Number(Qty); i++) {
// We send the email here <Qty> times.
console.log('Package Name ' + Package);
console.log('Package Price ' + Price);
}
})
Another way using only regexes and a few array methods, not requiring nested loops
var input = "Package=Package&Qty=1&Price=123?Package=Package Two&Qty=3&Price=702?Package=Package Three&Qty=1&Price=199?Package=Package One&Qty=4&Price=852?"
var results = input
.split('?')
.map(s => /^Package=(.*?)&Qty=(.*?)&Price=(.*?)$/.exec(s))
.filter(s => s)
.map(s => ({
package: s[1],
qty: parseFloat(s[2]),
price: parseFloat(s[3])
}))
console.log(JSON.stringify(results, null, 4))
Here is a pure JS alternative, please take a look.
function extract(name, string) {
name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
var regexS = "[\\?&]" + name + "=([^&#]*)";
var regex = new RegExp(regexS);
var results = regex.exec(string);
return results == null ? null : results[1];
}
function parse(string) {
items = string.split('?');
results = [];
for (var i in items) {
if (items[i].length == 0) continue;
var item = '?' + items[i];
results.push({
package: extract("Package", item),
qty: extract("Qty", item),
price: extract("Price", item)
})
}
return results;
}
str = "Package=Package&Qty=1&Price=123?Package=Package Two&Qty=3&Price=702?Package=Package Three&Qty=1&Price=199?Package=Package One&Qty=4&Price=852?";
document.getElementById('output').innerText = JSON.stringify(parse(str));
<div id='output'></div>
I have an array containing objects with this structure:
var results = [{
AuthorId: 2,
Id: 89,
caseId: 33 //some key
},...];
Now, I want to check if the objects in this array exist 2 or more times and log them in the console.
My approach:
$.each(results, function (i, result) {
var stringRes = result.AuthorId + ";" + result.caseId;
$.each(results, function (j, toTest) {
if (j <= results.length - 2) {
var stringToTest = results[j + 1].AuthorId + ";" + results[j + 1].caseId;
if (stringToTest == stringRes) {
console.log(result.Id);
//some function to do something with duplicates
}
}
});
});
Firstly, I know making strings and comparing them isn't really good. Secondly, this will log every item at least once, because every item compares to each other (= the item compares itself to itself).
Is this fixable with a (more or less) fast and reliable way?
You could use a hash table or a map for counting. If the count is 2 or greater make something. As key, I suggest to use the stringified object, if the object has always the same structure.
var results = [{ AuthorId: 2, Id: 89, caseId: 33 }, { AuthorId: 2, Id: 89, caseId: 33 }],
hash = Object.create(null);
results.forEach(function (a) {
var key = JSON.stringify(a);
hash[key] = (hash[key] || 0) + 1;
if (hash[key] >= 2) {
console.log('count of 2 or more of ' + key);
}
});
Let's says I've an array['Alex', 'Sam', 'Robert']
I'd like to combine them something like:
Take first array[0] and append with array[2] which will be AlexRobert
first letter of array[0] which is A and append with array[2] that is Robert which will be ARobert
Take array[0] which is Alex and append with first letter of array[2] that is R which will be AlexR
Take first array[0] append with first letter of array[1] along with array[2] which will become AlexSRobert.
Basically the whole idea is when someone enter first name, middle name & last name I should be able to make combination and guess email ids. For example- Juan F. Nathaniel the array form will be like ['Juan', 'F', 'Nathaniel']
I want the combination of first, middle and last name like jaunn, jnathaniel, jaunfnathaniel
I'm beginner and here is what I've written:
var nameCombination = function(name){
var counting = name.split(" ");
for (var i=0; i<counting.length; i++){
console.log(counting[i] + counting[i+1]);
console.log(counting[i].split("",1) + counting[i+1]);
}
}
nameCombination('Alex Sam Robert');
I'm assuming you needed a function to do this? Here is a function to handle grabbing pieces of each index of the array. I'll leave it up to you to figure out what type of data you need...
var test = function() {
var array = ['Alex', 'Sam', 'Robert'];
var conditions = [{
index: 0,
length: array[0].length
},
{
index: 1,
length: 1
},
{
index: 2,
length: array[2].length
}]
alert(combine(array, conditions));
}
var combine = function(array, conditions) {
var output = "";
for(index in conditions) {
var condition = conditions[index];
var index = condition['index'];
var length = condition['length'];
output += array[index].substring(0, length);
}
return output;
}
test();
You could use an iterative and recursive approach for variable length of parts an their length.
function combine(array) {
function c(part, index) {
array[index].forEach(function (a) {
var p = part.concat(a);
if (p.length === array.length) {
r.push(p.join(''));
return;
}
c(p, index + 1);
});
}
var r = [];
c([], 0);
return r;
}
var input= ['Johann', 'Sebastian', 'Bach'],
array = input.map(function (a) { return ['', a[0], a]; });
result = combine(array);
console.log(result);
This problem can be solved using recursive approach.
var combinations = function(names, i, n){
if(i == n){
return [];
}
last_names = combinations(names, i + 1, n);
name_combinations = last_names.map(function(last_name){
return [
last_name,
names[i] + last_name,
names[i] + last_name[0],
names[i][0] + last_name,
names[i][0] + last_name[0]
]
});
name_combinations = [].concat.apply([], name_combinations);
name_combinations.push(names[i]);
return name_combinations;
};
var nameCombinations = function(name){
var name_array = name.split(' ');
return Array.from(new Set(combinations(name_array, 0, name_array.length)));
};
nameCombinations('first last');
above function can generate all the desired combinations for a given name.
for example: nameCombinations('first last') will return ["last", "firstlast", "firstl", "flast", "fl", "first"].
Ok without writing out every combination I will do the first few to give you the idea:
assuming
array[0] is the person's first name
array[1] is the person's middle name
array[2] is the person's last name
Firstname+Lastname:
var output = array[0] + array [2];
Firstname+Middlename:
var output1 = array[0] + array[1];
then then you could display the output using innerHTML:
Javascript:
document.getElementById("output").innerHTML = output + '<br>' + output1;
HTML:
<div id="output"></div>
Keep in mind you would need to keep doing that for the rest of the combinations.
Now for the combinations where you need to get the first letter of the variable you need to use charAt which I found from this stack overflow answer.
You would do the same thing as before, except instead you need to use charAt and do something like so:
Firstname+FirstLetterOfLastName:
var output2 = array[0] + array[2].charAt(0);
And you can output it using the same method as before.
If your still confused leave a comment and I will try and answer your questions.
My code:
var company=new Array("Kestrel Moon:","BB:");
var basicPri=new Array(1165,1231);
for(var i=0;i<15;i++){
var companyTotal=company[i].concat(basicPri[…
document.write(""+companyTotal+"")
It shows on the screen:
Kestrel Moon: 1165
BB: 1231
I want to sort the array so that it goes ascending order of highest value of price so it should display it as:
BB: 1231
Kestrel Moon: 1165
A normal sort would not do it as it would sort the prices but the company names stay where they are, how do I sort both arrays so it would display what I want to display?
Thank You
typically, you would group the name with number:
function sortNumber(a,b)
{
return b[1] - a[1]; // comparing using 2nd element
}
var n = [["ccc", 10.23], ["www", 23.12], ["mmm", 0.56]];
document.write(n.sort(sortNumber));
output:
www,23.12,ccc,10.23,mmm,0.56
and if you use jQuery, you can create a table from the result:
function sortNumber(a,b)
{
return b[1] - a[1]; // comparing using 2nd element
}
var n = [["ccc", 10.23], ["www", 23.12], ["mmm", 0.56]];
sorted = n.sort(sortNumber);
$('body').append('<table id="thetable"></table>');
$('#thetable').css({borderCollapse: 'collapse'})
for (i = 0; i < sorted.length; i++) {
$('#thetable').append('<tr><td>' + sorted[i][0] + '</td><td>' + sorted[i][1] + '</td></tr>')
}
$('td').css({ border: '1px solid #ccc', padding: '0.2em 1em' });
Here's a possibility using your code as base (i.e. 2 arrays):
// comparaison functor
function sorter(a, b) {
return a.name.localeCompare(b.name);
}
// build a sorted array of object like
// [ { "name": "foo", price: 123 }, ... ]
// sorted by company name (Locale aware order)
function mysort(comp, prices) {
var res = [];
for (var i = 0; i < comp.length; i++) {
res.push({"name": comp[i], "price": prices[i]});
}
return res.sort(sorter);
}
var company = ["Kestrel Moon:", "BB:"];
var basicPri = [1165, 1231];
var companyTotal = "";
var arr = mysort(company, basicPri);
for (var i in arr) {
companyTotal += arr[i].name + " " + arr[i].price + "<br/>";
}
document.write(companyTotal);
Tested on chrome 6.0.427.0 dev
A normal sort would not do it as it would sort the prices but the company names stay where they are ...
In this case, an array of objects would probably be a better data structure for your data. Consider the example below:
var dict = [
{company: 'Kestrel Moon:', basicPri: '1165'},
{company: 'BB:', basicPri: '1231'}
];
var sorted = dict.sort(function(a, b) {
return a.company.localeCompare(b.company);
});
console.log(sorted[0].company + ' ' + sorted[0].basicPri);
console.log(sorted[1].company + ' ' + sorted[1].basicPri);
// Prints:
// ------------------
// BB: 1231
// Kestrel Moon: 1165