We Keep Coding

Can't delete on Angular

I'm trying to delete one line from a table, however and even following the examples on stackoverflow, I can't reach a solution.
One of the Important things before start, is that I have the url's hidden, so I don't see the Get url, even the splice don't delete the right line on the table.
HTML:
<button id="{{value.username}}" type='button' type="button" ng-click="delete(value.username, $index)" class="btn btn-primary">Delete</button></td>
JS
$scope.delete = function(deletingId, index){
console.log(deletingId);
$http.get("../admin/deleted.php?username=" + deletingId)
.success(function(data){
$scope.data.splice(index, 1);
console.log('dadasdas');
})
}
PHP
$id = $_GET ['username'];
$sql = "SELECT * FROM members";
$records = mysql_query($sql);
if(isset($_GET['username'])){
$id = $_GET ['username'];
$delete = "DELETE FROM members WHERE username= '$id'";
$res = mysql_query($delete) or die ("FAILED" .mysql_error());
}
Am I doing anything wrong ( the scope is working, the php src is correct, but even doing an echo on php it doesn't fulfill nothing) since I've the url's hidden is there anyway to make it as a post?
Thanks in advance

Try this (I will use Mysqli, because I don't use Mysql);
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
$conn = new mysqli($servername, $username, $password, $dbname);
$id = $_GET['username'];
$sql = "SELECT * FROM users";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
if (strtolower($id) == strtolower($row['username'])) {
$sql = "DELETE FROM users WHERE id=".row['id'];
$conn->query($sql);
}
}
} else {
echo "No accounts registered!";
}
So, deleting stuff with SQL, is case sensitive. So, I hope/think you have a auto increment id in your database. Then this will 100% surely work!

PHP Coding to Connect MYSQL Issues

I am creating a database to make my 'PHP' website but I couldn't do this. My website is cruzapp that is related to rideshare companies and changing it in to php to get details about our users. But I can't connect MYSQL by using the following PHP code:
?php
$username = "name";
$password = "password";
$hostname = "host";
//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password)
or die("Not connected to MySQL");
echo "Connected to MySQL<br>";
//select a database to work with
$selected = mysql_select_db("examples",$dbhandle)
or die("Could not select examples");
//execute the SQL query and return records
$result = mysql_query("SELECT id, model,year FROM cars");
//fetch tha data from the database
while ($row = mysql_fetch_array($result)) {
echo "ID:"$row{'id'}." Name:".$row{'model'}."Year: ". //display the results
$row{'year'}.<br>";
}
//close the connection
mysql_close($dbhandle)
?>
Can anyone help me to debug this code?
I will be very thankful to you.

Try this one out. It uses MySQLi with error echoing.
<?php
$username = "name";
$password = "password";
$hostname = "host";
$database = "examples";
$con = mysqli_connect($hostname, $username, $password, $database);
if (!$con) {
exit("Connection failed: " . mysqli_connect_error());
}
$result = mysqli_query($con, "SELECT id, model,year FROM cars");
if (mysqli_error($con)) {
exit("Error: " . mysqli_error($con));
}
while ($row = mysqli_fetch_array($result)) {
echo "ID:" . $row['id'] . " Name:" . $row['model'] . "Year: " . $row['year'] . "<br>";
}
mysqli_close($con);

First of all you should not use mysql because with PHP 7 mysql extension does not work anymore. so you must consider to change it to mysqli or PDO. PDO is recommended. Any how for a quick fix $selected = mysql_select_db($dbhandle,"examples") do this and also check all your values like hostname database name table name and make sure there are no mistakes.

i am developing a website using php and mysql,in this website

i want to fetch data from my database which is linked to the website,i have created a search box,whenever i enter a particular value in search box,it should display all the related content from the database.i have done the following code,it is not fetching the data from the database,it just shows a blank screen.
<?php
define('db_name','njgh');
define('db_user','root');
define('db_password','');
define('db_host','localhost');
session_start();
$link=mysql_connect(db_host,db_user,db_password);
if(!$link)
{
die('couldnot connetc:'.mysql_error());
}
$db_selected=mysql_select_db(db_name,$link);
if(!$db_selected)
{
die('cant connect to db');
}
function clean($str) {
$str = #trim($str);
if(get_magic_quotes_gpc()) {
$str = stripslashes($str);
}
return mysql_real_escape_string($str);
}
$value = clean($_POST['searchtext']);
$qry = "SELECT * FROM database WHERE Site_ID = '$value'";
$result = mysql_query($qry);
print_r($result);

mysql_query function return resource ID not your data , use mysql_fetch_array, mysql_fetch_object to get data
$value = ($_POST['searchtext']);
$result = mysql_query("SELECT * FROM database WHERE Site_ID = '$value'");
while ($row = mysql_fetch_array($result, MYSQL_NUM)) {
printf("ID: %s Name: %s", $row[0], $row[1]);
}

mysql_* has been removed entirely as of PHP 7.0. Prevent SQL injection and use the mysqli statement class.
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "njgh";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$value = $_POST['searchtext'];
/* create a prepared statement */
if($stmt = $conn->prepare("SELECT * FROM database WHERE Site_ID =?")) {
/* bind parameters for markers */
$stmt->bind_param("s", $value);
/* execute query */
$stmt->execute();
$result = $stmt->get_result();
if($result->num_rows > 0) {
while ($row = $result->fetch_assoc()) {
echo $row['db_table_field_name'];
}
//or
$row = $result->fetch_assoc();
print_r($row);
} else {
}
/* close statement */
$stmt->close();
}
/* close connection */
$con->close();
?>

The original MySQL extension is now deprecated, and will generate E_DEPRECATED errors when connecting to a database. Instead, use the MySQLi or PDO_MySQL extensions.
Hope this will work for you......
<?php
define('db_name','sports');
define('db_user','root');
define('db_password','');
define('db_host','localhost');
$link=mysqli_connect(db_host,db_user,db_password,db_name);
if(!$link)
{
die('couldnot connect:'.mysql_error());
}
function clean($str) {
$link=mysqli_connect(db_host,db_user,db_password,db_name);
$str = #trim($str);
if(get_magic_quotes_gpc())
$str = stripslashes($str);
return mysqli_real_escape_string($link, $str);
}
if(isset($_POST['searchtext'])){
$value = clean($_POST['searchtext']);
$qry = "SELECT * FROM cricket WHERE id = '$value'";
$qrydb = mysqli_query($link, $qry);
while($row=mysqli_fetch_array($qrydb)){
$name = $row['name'];
}
echo $name ;
}
?>
<body>
<form method="post">
<input type="text" name="searchtext">
<input type="submit" name="submit">
</form>
</body>

Php error on ajax call script

Well For Start I Want To Tank You All For The Help
The Script now it create a table but send empty info
so i have try to do like this:
http://mediaads.eu/villageop/back/savepoints.php?user_id=abcdefghijklm
Now The script wen i call it give me this error:
So I Have Edit The Script code to clean it
so now my code is:
<?php
header('Access-Control-Allow-Origin: *');
error_reporting(E_ALL);
ini_set('display_errors',1);
$servername = "localhost";
$username = "publiadd_publix";
$password = "1a3g7893fsh";
try {
$conn = new PDO("mysql:host=$servername;dbname=publiadd_registervillageop", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
echo "Connected successfully";
}
catch(PDOException $e){
echo "Connection failed: " . $e->getMessage();
}
if(isset($_GET['user_id'])){
//$user_id = intval($_GET['user_id']);
//Lightly sanitize the GET's to prevent SQL injections and possible XSS attacks
try {
$dbh = new PDO("mysql:host=$servername;dbname=publiadd_registervillageop", $username, $password);
$user_id = #$_GET['user_id'];
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); // <== add this line
$sql = "INSERT INTO users (user_id) VALUES ('".$_POST["user_id"]."')";
if ($dbh->query($sql)) {
echo "<script type= 'text/javascript'>alert('New Record Inserted Successfully');</script>";
}
else{
echo "<script type= 'text/javascript'>alert('Data not successfully Inserted.');</script>";
}
$dbh = null;
}
catch(PDOException $e){
echo $e->getMessage();
}
}
?>
$sql->execute(array($user_Id));
if($sql){
//The query returned true - now do whatever you like here.
echo 'Your ID was saved. Congrats!';
}else{
//The query returned false - you might want to put some sort of error reporting here. Even logging the error to a text file is fine.
echo 'There was a problem saving your points. Please try again later.';
}
}else{
echo 'Your id wasnt passed in the request.';
}
// close MySQL connection
$conn = null;
?>
<html>
<head>
</head>
<body>
<body bgcolor="#ffffff">
</body>
</html>

The method you are using in your forms is GET so use $_GET not $_POST as it goes in your if condition. So replace $_POST with $_GET and second error is your table name it is users table not publiadd_registervillageop so your sql query looks like,
$sql = "INSERT INTO users (user_id) VALUES ('".$_GET["user_id"]."')";

Jquery ajax call not working if using connection in include file

I can't figure out why jquery ajax post call not working if I used connection on include php file though I'm getting right response from php. Kindly tell me what's the explanation behind this
This is on my DB file
<?php
$host = "mysql2.000webhost.com";
$username = "a212_mt5199";
$password = "secret";
$db = "a211_mydb";
$con = new mysqli ($host, $username, $password, $db);
GLOBAL $con;
if ($con->connect_error) {
die ("Error:" . $con->connect_error);
}
?>
This including the above is not working
<?php
include("db.php");
// set parameters and execute
$myusername=$_POST['name'];
$mypassword=$_POST['pwd'];
// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$stmt = $con->prepare("SELECT username, password FROM members WHERE username=? and password=?");
$stmt->bind_param("ss", $myusername, $mypassword);
$stmt->execute();
$stmt->bind_result($username, $password);
$stmt->store_result();
// Mysql_num_row is counting table row
$count=$stmt->num_rows;
// If result matched $myusername and $mypassword, table row must be 1 row
if($count==1){
// Register $myusername, $mypassword and redirect to file "login_success.php"
session_register("myusername");
session_register("mypassword");
echo 'true';
$_SESSION['user_name']= $username;
} else {
echo "Wrong Username or Password";
}
$stmt->close();
$con->close();
?>
This is working
<?php
$host = "mysql2.000webhost.com";
$username = "a212_mt5199";
$password = "secret";
$db = "a211_mydb";
$con = new mysqli ($host, $username, $password, $db);
if ($con->connect_error) {
die ("Error:" . $con->connect_error);
}
// set parameters and execute
$myusername=$_POST['name'];
$mypassword=$_POST['pwd'];
// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$stmt = $con->prepare("SELECT username, password FROM members WHERE username=? and password=?");
$stmt->bind_param("ss", $myusername, $mypassword);
$stmt->execute();
$stmt->bind_result($username, $password);
$stmt->store_result();
// Mysql_num_row is counting table row
$count=$stmt->num_rows;
// If result matched $myusername and $mypassword, table row must be 1 row
if($count==1){
// Register $myusername, $mypassword and redirect to file "login_success.php"
session_register("myusername");
session_register("mypassword");
echo 'true';
$_SESSION['user_name']= $username;
} else {
echo "Wrong Username or Password";
}
$stmt->close();
$con->close();
?>

Able to solve issue by using DEFINE variable.