I have form in 100.php with ajax call to 200.php.
<html>
<head>
<!-- include reCAPTCHA API JavaScript library given by Google -->
<script src='https://www.google.com/recaptcha/api.js'></script>
<script type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script>
$(document).ready(function() {
$("#btn").click(function(event){
event.preventDefault();
var myname = $("#name").val();
var myaddress = $("#address").val();
var yourData ='name='+myname+'&address='+myaddress; // php is expecting name and age
$.ajax({
type:'POST',
data:yourData,//Without serialized
url: '200.php',
success:function(data) {
if(data){
$('#testform')[0].reset();//reset the form
$('#result').html(data); // here html()
//alert('Submitted');
}else{
return false;
}
}
});
});
});
</script>
</head>
<body>
<form method="post" id="testform">
Name: <input type="text" name="name" value="" id="name"/> <br />
Address: <input type="text" name="address" value="" id="address"/>
<!--
place for the reCAPTCHA widget div with your site key
data-theme="dark" attribute - gives dark version
-->
<div class="g-recaptcha" data-sitekey="6LeJ8h8TAAAAAMS9nQX89XccpsC-SDeSycipiaHN"></div>
<input type="submit" name="ok" value="Send" id="btn"/>
</form>
<div id='result'></div>
</body>
200.php does validate captcha and diaplay name and adddress user entered. But my problem is that when I entered name and address, click on captcha. Captha is also validated and shows as in my screenshot. but name and address is not shown on the page. You can also check yourself here: http://raveen.comlu.com/100.php
I am new to Ajax call by PHP. I googled and I can troubleshoot by firebug. Can you say what I am doing wrong here? and steps to troubleshoot by firebug like to check if my ajax call is done, etc? thanks for your help.
Note: when I put all these code in one page without using ajax call. it works fine!!!!! I want this happens without page reload....
output
200.php
<?php
require_once('recaptchalib.php');
if( isset($_POST['ok']) ){
if( isset($_POST['g-recaptcha-response']) && !empty($_POST['g-recaptcha-response']) ){
$secret = "6LeJ8h8TAAAAAB3IFQVQEaoApFe6lvq4Wxlktvn1"; //your secret key
$response = null; //empty response
$reCaptcha = new ReCaptcha($secret); //check secret key is present
$response = $reCaptcha->verifyResponse( $_SERVER['REMOTE_ADDR'], $_POST['g-recaptcha-response'] );
//$response variable will report back with "success"
if( $response!=null && $response->success ){
echo "<h1>Hi ". $_POST['name']. " from ". $_POST['address']. ", thanks for submitting the form!</h1>";
}
}
else{
echo "<h1>Please click on the reCAPTCHA box.</h1>";
}
}
?>
There are few errors in your code, such as:
Look at the following two statements,
if( isset($_POST['ok']) ){...
and
var yourData ='name='+myname+'&address='+myaddress;
You're not sending any variable named ok to 200.php page, so the control won't even enter the if block.
You're validating reCaptcha in the wrong way. From the documentation:
If your website performs server side validation using an AJAX request, you should only verify the user’s reCAPTCHA response token (g-recaptcha-response) once. If a verify attempt has been made with a particular token, it cannot be used again. You will need to call grecaptcha.reset() to ask the end user to verify with reCAPTCHA again.
So you have to use grecaptcha.getResponse() to get the user's response.
And as a sidenote use grecaptcha.reset() to ask the end user to verify with reCAPTCHA again.
Your jQuery/AJAX script should be like this:
<script>
$(document).ready(function() {
$("#btn").click(function(event){
event.preventDefault();
var recaptchaResponse = grecaptcha.getResponse();
var myname = $("#name").val();
var myaddress = $("#address").val();
var yourData = {name: myname, address: myaddress, recaptchaResponse: recaptchaResponse};
$.ajax({
type: 'POST',
data: yourData,
dataType: 'html',
url: '200.php',
success: function(data) {
// reset form
$('#testform')[0].reset();
// display data
$('#result').html(data);
// reset the reCaptcha
grecaptcha.reset();
},
error: function(jqXHR, textStatus, errorThrown){
// error
}
});
});
});
</script>
And on 200.php page, process your AJAX data like this:
<?php
//your site secret key
$secret = '6LeJ8h8TAAAAAB3IFQVQEaoApFe6lvq4Wxlktvn1';
if(isset($_POST['recaptchaResponse']) && !empty($_POST['recaptchaResponse'])){
//get verified response data
$param = "https://www.google.com/recaptcha/api/siteverify?secret=".$secret."&response=".$_POST['recaptchaResponse'];
$verifyResponse = file_get_contents($param);
$responseData = json_decode($verifyResponse);
if($responseData->success){
// success
echo "<h1>Hi ". $_POST['name']. " from ". $_POST['address']. ", thanks for submitting the form!</h1>";
}else{
// failure
echo "<h1>You have incorrect captcha. Please try again.</h1>";
}
}else{
echo "<h1>Please click on the reCAPTCHA box.</h1>";
}
?>
Related
Please, can somebody publish a mistakes corrected and tested code for my problem?
Program does - 22.php has the form. When the user enter and click Submit button, the result should be taken from 23.php and displayed in div on 22.php
I already tried solutions below and none of them solve my problem;
1) I changed to: $("#testform").submit(function(event){
2) I included "return false;" at the end to prevent it to actually submit the form and reload the page.
3) clear my browser cache
I can see what happen the program with my computer;
1) I do not get error message after I click submit.
2) I can see the tab of the page reloads quickly and the entered text fields are cleared.
3) No error message or result shows.
<html>
<head>
<title>My first PHP page</title>
<script type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script>
$(document).ready(function() {
$("#btn").click(function(event){
event.preventDefault();
var myname = $("#name").val();
var myage = $("#age").val();
yourData ='myname='+myname+'&myage='+myage;
$.ajax({
type:'POST',
data:yourData,//Without serialized
url: '23.php',
success:function(data) {
if(data){
$('#testform')[0].reset();//reset the form
$('#result').val(data);
alert('Submitted');
}else{
return false;
}
};
});
});
});
</script>
</head>
<body>
<form method="post" id="testform">
Name:
<input type="text" name="name" id="name" />Age:
<input type="text" name="age" id="age" />
<input type="submit" name="submit" id="btn" />
</form>
<div id='result'></div>
</body>
</html>
<?php
if ( isset($_POST['name']) ) { // was the form submitted?
echo "Welcome ". $_POST["name"] . "<br>";
echo "You are ". $_POST["age"] . "years old<br>";
}
?>
you don't need to change your php code
try submit form with submit event ...
$("#testform").submit(function(event){
use `dataType:json`; in your ajax ..
yourData =$(this).serialize();
Your php
<?php
if ( isset($_POST['name']) ) { // was the form submitted?
$data['name']= 'welcome '.$name;
$data ['age']= 'you are '.$age;
print_r(json_encode($data));exit;
}
?>
Now In Your Success function
var message = data.name + ' ' + data.age;
$('#result').html(message );
You are sending myname and checking name(isset($_POST['name']) in php.
don't use .value() use .html() for data rendering. and console log the data and see whats request and response using firebug.
Can you try this one?
To be changed
var yourData ='name='+myname+'&age='+myage; // php is expecting name and age
and
$('#result').html(data); // here html()
the code becomes
$(document).ready(function() {
$("#btn").click(function(event){
event.preventDefault();
var myname = $("#name").val();
var myage = $("#age").val();
var yourData ='name='+myname+'&age='+myage; // php is expecting name and age
$.ajax({
type:'POST',
data:yourData,//Without serialized
url: '23.php',
success:function(data) {
if(data){
$('#testform')[0].reset();//reset the form
$('#result').html(data); // here html()
alert('Submitted');
}else{
return false;
}
}
});
});
});
Try formatting your post data like this inside your ajax function.
$.ajax({
type:'POST',
data : {
myname: myname
myage: myage
}
...
}
EDIT
Try removing the ; in
return false;
}
};
to
return false;
}
}
You can change at both end ajax and php:
#PHP:
You can check for correct posted data which is myname and myage not name and age.
<?php
if ( isset($_POST['myname'])) { // was the form submitted?
echo "Welcome ". $_POST["myname"] . "<br>";
echo "You are ". $_POST["myage"] . "years old<br>";
}
?>
or #Ajax:
yourData ='name='+myname+'&age='+myage;
//--------^^^^^^----------^^^^----change these to work without changing php
Just noticed the #result is an div element. So, you can't use .val() but use .html(), .append() etc:
$('#result').html(data);
I have a form with an input field for a userID. Based on the entered UID I want to load data on the same page related to that userID when the user clicks btnLoad. The data is stored in a MySQL database. I tried several approaches, but I can't manage to make it work. The problem is not fetching the data from the database, but getting the value from the input field into my php script to use in my statement/query.
What I did so far:
I have a form with input field txtTest and a button btnLoad to trigger an ajax call that launches the php script and pass the value of txtTest.
I have a div on the same page in which the result of the php script will be echoed.
When I click the button, nothing happens...
Test.html
<script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script>
<script type="text/javascript" src="http://ajax.microsoft.com/ajax/jquery.validate/1.7/jquery.validate.min.js"></script>
<script>
//AJAX CALL
function fireAjax(){
$.ajax({
url:"testpassvariable.php",
type:"POST",
data:{userID:$("#txtTest").val(),},
success: function (response){
$('#testDiv').html(response);
}
});
}
</script>
</head>
<body>
<form name="testForm" id="testForm" action="" method="post" enctype="application/x-www-form-urlencoded">
<input type="text" name="txtTest" id="txtTest"/>
<input type="button" id="btnLoad" name="btnLoad" onclick="fireAjax();"
<input type="submit" name="SubmitButton" id="SubmitButton" value="TEST"/>
</form>
<div id="testDiv" name="testDiv">
</div>
</body>
The submit button is to insert updated data into the DB. I know I have to add the "action". But I leave it out at this point to focus on my current problem.
testpassvariable.php
<?php
$player = $_POST['userID'];
echo $player;
?>
For the purpose of this script (testing if I can pass a value to php and return it in the current page), I left all script related to fetching data from the DB out.
As the documentation says 'A page can't be manipulated safely until the document is ready.' Try this:
<script>
$(document).ready(function(){
//AJAX CALL
function fireAjax(){
$.ajax({
url:"testpassvariable.php",
type:"POST",
data:{userID:$("#txtTest").val(),},
success: function (response){
$('#testDiv').html(response);
}
});
}
});
</script>
You need to correct two things:
1) Need to add $(document).ready().
When you include jQuery in your page, it automatically traverses through all HTML elements (forms, form elements, images, etc...) and binds them.
So that we can fire any event of them further.
If you do not include $(document).ready(), this traversing will not be done, thus no events will be fired.
Corrected Code:
<script>
$(document).ready(function(){
//AJAX CALL
function fireAjax(){
$.ajax({
url:"testpassvariable.php",
type:"POST",
data:{userID:$("#txtTest").val(),},
success: function (response){
$('#testDiv').html(response);
}
});
}
});
</script>
$(document).ready() can also be written as:
$(function(){
// Your code
});
2) The button's HTML is improper:
Change:
<input type="button" id="btnLoad" name="btnLoad" onclick="fireAjax();"
To:
<input type="button" id="btnLoad" name="btnLoad" onclick="fireAjax();"/>
$.ajax({
url: "testpassvariable.php",
type: "POST",
data: {
userID: $("#txtTest").val(),
},
dataType: text, //<-add
success: function (response) {
$('#testDiv').html(response);
}
});
add dataType:text, you should be ok.
You need to specify the response from the php page since you are returning a string you should expect a string. Adding dataType: text tells ajax that you are expecting text response from php
This is very basic but should see you through.
Change
<input type="button" id="btnLoad" name="btnLoad" onclick="fireAjax();"/>
Change AJAX to pass JSON Array.
data = $(this).serialize() + "&" + $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "action.php",
data: data,
....
// action.php
header('Content-type: application/json; charset=utf-8');
echo json_encode(array(
'a' => $b[5]
));
//Connect to DB
$db = mysql_connect("localhst","user","pass") or die("Database Error");
mysql_select_db("db_name",$db);
//Get ID from request
$id = isset($_GET['id']) ? (int)$_GET['id'] : 0;
//Check id is valid
if($id > 0)
{
//Query the DB
$resource = mysql_query("SELECT * FROM table WHERE id = " . $id);
if($resource === false)
{
die("Database Error");
}
if(mysql_num_rows($resource) == 0)
{
die("No User Exists");
}
$user = mysql_fetch_assoc($resource);
echo "Hello User, your number is" . $user['number'];
}
try this:- for more info go here
$(document).ready(function(){
$("#btnLoad").click(function(){
$.post({"testpassvariable.php",{{'userID':$("#txtTest").val()},function(response){
$('#testDiv').html(response);
}
});
});
});
and i think that the error is here:-(you wrote it like this)
data:{userID:$("#txtTest").val(),}
but it should be like this:-
data:{userID:$("#txtTest").val()}
happy coding :-)
I followed a tutorial to adapt the code. Here I am trying trying to auto-populate my form fields with AJAX when an 'ID' value is provided. I am new to Jquery and can't get to work this code.
Edit 1 : While testing the code, Jquery isn't preventing the form to submit and sending the AJAX request.
HTML form
<form id="form-ajax" action="form-ajax.php">
<label>ID:</label><input type="text" name="ID" /><br />
<label>Name:</label><input type="text" name="Name" /><br />
<label>Address:</label><input type="text" name="Address" /><br />
<label>Phone:</label><input type="text" name="Phone" /><br />
<label>Email:</label><input type="email" name="Email" /><br />
<input type="submit" value="fill from db" />
</form>
I tried changing Jquery code but still I couldn't get it to work. I think Jquery is creating a problem here. But I am unable to find the error or buggy code. Please it would be be very helpful if you put me in right direction.
Edit 2 : I tried using
return false;
instead of
event.preventDefault();
to prevent the form from submitting but still it isn't working. Any idea what I am doing wrong here ?
Jquery
jQuery(function($) {
// hook the submit action on the form
$("#form-ajax").submit(function(event) {
// stop the form submitting
event.preventDefault();
// grab the ID and send AJAX request if not (empty / only whitespace)
var IDval = this.elements.ID.value;
if (/\S/.test(IDval)) {
// using the ajax() method directly
$.ajax({
type : "GET",
url : ajax.php,
cache : false,
dataType : "json",
data : { ID : IDval },
success : process_response,
error: function(xhr) { alert("AJAX request failed: " + xhr.status); }
});
}
else {
alert("No ID supplied");
}
};
function process_response(response) {
var frm = $("#form-ajax");
var i;
console.dir(response); // for debug
for (i in response) {
frm.find('[name="' + i + '"]').val(response[i]);
}
}
});
Ajax.php
if (isset($_GET['action'])) {
if ($_GET['action'] == 'fetch') {
// tell the browser what's coming
header('Content-type: application/json');
// open database connection
$db = new PDO('mysql:dbname=test;host:localhost;', 'xyz', 'xyz');
// use prepared statements!
$query = $db->prepare('select * from form_ajax where ID = ?');
$query->execute(array($_GET['ID']));
$row = $query->fetch(PDO::FETCH_OBJ);
// send the data encoded as JSON
echo json_encode($row);
exit;
}
}
I don't see where you're parsing your json response into a javascript object (hash). This jQuery method should help. It also looks like you're not posting your form using jquery, but rather trying to make a get request. To properly submit the form using jquery, use something like this:
$.post( "form-ajax.php", $( "#form-ajax" ).serialize() );
Also, have you tried adding id attributes to your form elements?
<input type="text" id="name" name="name"/>
It would be easier to later reach them with
var element = $('#'+element_id);
If this is not a solution, can you post the json that is coming back from your request?
Replace the submit input with button:
<button type="button" id="submit">
Note the type="button".
It's mandatory to prevent form submition
Javascript:
$(document).ready(function() {
$("#submit").on("click", function(e) {
$.ajax({type:"get",
url: "ajax.php",
data: $("#form-ajax").serialize(),
dataType: "json",
success: process_response,
error: function(xhr) { alert("AJAX request failed: " + xhr.status); }
});
});
});
I am trying to create a simple webapp sort of thing that will send push notifications to my clients on button click. Here is a sample page that i have created
I have a file named as sendPush.php
On button click i want to send a push notification which will be echoed as
Notifications sent:
"Notification sent to userId : xxxX"
"Notification sent to userId : xxxX"
"Notification sent to userId : xxxX"
"Notification sent to userId : xxxX"
I want to send notifis to all 147 users. Now here is my php code for button click
<script type="text/javascript">
function sendNotif()
{
alert('ok');
}
</script>
<div class="content">
<input type="button" value="Click to Send" onClick="sendNotif();">
<br />
<br />
<label for="push">Notifications sent: </label>
</div>
The problem here i am facing is, i have php function in same app named as sendNotification() that will send notification and echo the result. But I am not sure how can i make a loop of this php function in javascript inside javascript function
function sendNotif()
{
// LOOP HERE
}
If $clients is the list of my clients, how can i send notif to all in a loop using php function in same page as sendNotification($client)
MOdified
<script type="text/javascript">
var lastIdCount = 0;
function sendNotif()
{
var clients = "<?php echo $clients; ?>";
var getPath = "push.php?clientId=".concat(clients['lastIdCount']);
$.ajax({
type: "POST",
url: getPath,
task: "save",
data: {
ajax: "true",
},
dataType : 'json'
}).done(function( msg )
{
alert('ok');
if( msg.status=="1")
{
alert('okasdf');
lastIdCount++;
sendNotif();
}
else
{
alert("Error : "+msg.error);
}
});
}
</script>
In push.php
sample
$resp = array();
$resp['error'] = 'Invalid Request';
$resp['status'] = '0';
$resp['data'] = '0';
You can try first to get all clients you want to send notification and use them ID's for setInterval or setTimeout functions which would repeat your queries. Probably you should
get_clients.php
<?php
$clients_array = array(1,2,6,15,29); /// let's say ID's you got from SQL or w/e you need.
echo json_encode($clients_array); // [1,2,6,15,29]
?>
send_for_client.php
<?php
$id = isset($_POST['id'])?$_POST['id']:false;
if($id){
// do some code you need
echo "Notification sent for id: ".$id;
}
?>
index.html
...
<head>
<script src="//code.jquery.com/jquery-1.11.0.min.js"></script>
<script>
$(window).load(function(){
$("#send").click(function(){
$.post('get_clients.php',{},function(cid){
obj = JSON.parse(cid);
var cids = obj;
/// cids is array of clients. so, you can do like:
var i = 0;
var interval = setInterval(function(){
if(cids.length > i){
$.post('send_for_client.php',{id:cids[i]},function(resp){
$("#result").append(resp+"<br />");
i++;
});
} else {
clearInterval(interval);
}
},100);
});
});
});
</script>
</head>
<body>
<input id="send" type="submit" name="button" value="Send notifications" />
<div id="result">
</div>
</body>
...
I'm not tested this think, however it should work or simply show idea how you could try to find a solution for your problem. Have in mind this code can have mistakes so.. don't be lazy to check them out, not even do copy/paste :)
I hope it helped even a bit.
javascript and php are run in 2 different places. Your javascript runs in a browser while your php runs on the server. You cant really mix those two.
The way you probably want to do this is, on button click capture the click with javascript and send ajax request to your php script sitting on the server. Than have the php perform push notifications. Once php script is done, return result back to javascript to show it to the user.
You should also use javascript library like jquery which makes things much easier (especially the ajax call).
Update 2: I found out what was wrong! There was a 301 redirect in the .htaccess file. I will post it as an answer once I am allowed to (users under 10 rep have to wait 8 hours).
Update: I have taken Barmar's suggestion and checked the network tab (a tab I'm not too familiar with) and noticed I am receiving a 301 from handle.php See screenshot. I am going to do some searching and post my results.
Original Post: I am using the JQuery validation plugin to validate and send form data via ajax. The problem isn't that the data is being sent, but the form handler is saying there are no elements in the $_POST array. I have tested a few different methods to send ajax, and the data sends, but the form handler does not see any $_POST[] values.
Note: I have to use the JQuery validation plugin so it has to be handled by .validate.submitHandler(). Any $(form).on() won't suffice.
html + js (index.php)
<form action="handle.php" class="sky-form sky-form-modal" id="sky-form-modal" method=
"post" name="sky-form-modal">
<label class="input">
<input name="name" placeholder="Name" type=
"text">
</label>
<label class="input"><input name="company" placeholder="Company" type=
"text">
</label>
<footer>
<button class="button" type="submit">Send request</button>
<div class="progress"></div>
</footer>
</form>
<script>
$("#sky-form-modal").validate({
submitHandler: function(form) {
var $form = $("#sky-form-modal"); //being explicit for testing
var $inputs = $form.find("input, select, button, textarea");
var serializedData = $form.serialize();
request = $.ajax({
url: "handle.php",
type: "POST",
data: serializedData
});
console.log('data: ' + serializedData);
request.done(function(response, textStatus, jqXHR) {
console.log("Response: " + response);
});
},
});
</script>
handle.php:
<?php
if(isset($_POST['name'])) {
echo 'we got it';
} else {
echo 'name not set';
}
?>
Okay, so it seems like everything works, check out the console.log after I fill in the username and leave the company blank:
data: name=testtest&company=
Response: name not set
As you can see, serialize works and grabs all the info, but when handled by handle.php it tells me that the $_POST[] is empty. Looping through it on handle.php proves it:
foreach($_POST as $key=>$value) {
echo "$key: $value
\n";
}
Which doesn't return at all.
I have also tried ajaxSubmit() and form.submit() but I get the same exact results.
This one looks right to me, because I have searched and searched stackoverflow and came across that most of the problems with this is including the 'name' attribute on the input tags, which is already done.
Thanks in advance!!
My issue was irrelevant to my code and ended being a few declarations in the .htaccess. It was redirecting me from a .php file to a directory (for prettier URLS). Now, this is a common technique so:
if you are working on someone else's project and your URL's aren't standard with a file extension, check the .htaccess!
Page.html or .php
<form action="/" id="sky-form-modal" method=
"post" name="sky-form-modal">
<input name="name" placeholder="Name" type="text">
<input name="company" placeholder="Company" type="text">
<button class="button" type="submit">Send request</button>
</form>
<div id="result"></div>
<script>
var request;
$("#sky-form-modal").submit(function(event){
// abort any pending request
if (request) {
request.abort();
}
var $form = $(this);
var $inputs = $form.find("input, input");
// serialize the data in the form
var serializedData = $form.serialize();
// let's disable the inputs for the duration of the ajax request
// Note: we disable elements AFTER the form data has been serialized.
// Disabled form elements will not be serialized.
$inputs.prop("disabled", true);
// fire off the request to /form.php
request = $.ajax({
url: "handle.php",
type: "post",
data: serializedData
});
// callback handler that will be called on success
request.done(function (response, textStatus, jqXHR){
// log a message to the console
console.log("Hooray, it worked!");
$("#result").html(response);
});
// callback handler that will be called on failure
request.fail(function (jqXHR, textStatus, errorThrown){
// log the error to the console
console.error(
"The following error occured: "+
textStatus, errorThrown
);
});
// callback handler that will be called regardless
// if the request failed or succeeded
request.always(function () {
// reenable the inputs
$inputs.prop("disabled", false);
});
// prevent default posting of form
event.preventDefault();
});
</script>
handle.php
<?php
foreach ($_POST as $key => $value) {
echo "POST Key: '$key', Value: '$value'<br>";
}
?>
I removed your labels and classes for the simple look of the form.
i Guess you missed '(' after validation
$("#sky-form-modal").validate {
$("#sky-form-modal").validate ({