Post on native php (without framework) Into Code Igniter using AJAX - javascript

I'm trying to post data on my HTML code to CI with Ajax. But I got no response?
Here is my JS Code
$(document).ready(function(){
$("#simpan").click(function(){
nama_pelanggan = $("#nama_pelanggan").val();
telp = $("#telp").val();
jQuery.ajax({
type: "POST",
url: "http://192.168.100.100/booking_dev/booking/addBookingViaWeb/",
dataType: 'json',
data : {
"nama_pelanggan":nama_pelanggan,
"telp":telp,
},
success: function(res) {
if (res){
alert(msg);
}
}
});
});
});
And here is my form
<form>
Nama Pelanggan <br>
<input type="text" name="nama_pelanggan" id="nama_pelanggan"><br>
Telepon<br>
<input type="text" name="telp" id="telp"><br>
<input type="button" name="simpan" id="submit" value="Simpan">
</form>
and here is my contoller function code
public function addBookingViaWeb(){
$data = array(
'nama_pelanggan' => $this->input->post('nama_pelanggan'),
'telp'=>$this->input->post('telp')
);
echo json_encode($data);
}
Here is my post param
But I got no response
any idea?

add method in from if you use post then
<form method="post" action ="" >

Try using JQuery form serialize() to declare which data you want to post. It automatically put your form input into ajax data. Example :
first set ID to your form tag
<form id="form">
then
$.ajax({
type:'POST',
url : 'http://192.168.100.100/booking_dev/booking/addBookingViaWeb/',
data:$('#form').serialize(),
dataType:'JSON',
success:function(data){
console.log(data);
}
});

First problem I see is in your ajax submission code. Change
$("#simpan").click(function(){
to
$("#submit").click(function(event){
Notice that I added the event parameter. You now need to prevent the default submission behavior. On the first line of your click method add
event.preventDefault();
Now I'm assuming that your url endpoint http://192.168.100.100/booking_dev/booking/addBookingViaWeb/ can handle POST requests. Usually this is done with something like PHP or Ruby on Rails. If I was doing this in PHP I would write something like the following:
<?php
$arg1 = $_POST["nama_pelanggan"];
$arg2 = $_POST["telp"];
// do something with the arguments
$response = array("a" => $a, "b" => $b);
echo json_encode($response);
?>
I personally don't know anything about handling POST requests with js (as a backend) but what I've given you should get the data over there correctly.

I got solution for my problem from my friend xD
just add header("Access-Control-Allow-Origin: *"); on controller function
Thank you for helping answer my problem.

Related

Trying to send js variables to a php file

I am trying to send js variables from my js file to another php file when the user hits "FINISH" on the main php page. Here is my code so far:
map.php
<form action="./finalmap.php">
<input class="finish-button" type="submit" value="FINISH" onclick="sendData();" />
</form>
map.js
function sendData() {
$.ajax({
method: "POST",
url: "../finalmap.php",
data: {
selectedLoc: selectionArray,
startLoc: start,
endLoc: end,
dist: distance,
locTypes: allLocations
},
beforeSend : function(http) { },
success : function(response,status,http) {
alert(response);
},
error : function(http,status,error) {
$('.response').html("<span class='error'>Something went wrong</span>");
$(".response").slideDown();
}
});
}
finalmap.php
<?php
$data = $_POST['data'];
echo $data;
?>
Post is successful and I'm able to see the contents(my code) in my finalmap.php from the alert command. When I try to console.log $data in finalmap.php, it is empty/null.
My goal is to send the data to finalmap.php and redirect to it.
To solve this problem, you must reduce what you're testing to one thing at a time. Your code has errors and is incomplete. So let's start with the errors first: If you're using AJAX, you don't want HTML to submit the form in the regular way. If you get a page refresh, your AJAX didn't work.
<button type="button" id="submit-button">FINISH</button>
Note, no <form> is needed; you're submitting through AJAX.
Next, you need to be sure that your ajax function is being executed (since you're using $.ajax, I presume you have JQuery loaded):
<button type="button" id="submit-button">FINISH</button>
<script>
// all listener functions need to wait until DOM is loaded
$(document).ready(function() {
// this is the same idea as your onclick="sendData();
// but this separates the javascript from the html
$('#submit-button').on('click', function() {
console.log('hello world');
});
});
</script>
You use your web console to see the console.log message.
Now, try out the ajax command with a simple post:
<button type="button" id="submit-button">FINISH</button>
<script>
// all listener functions need to wait until DOM is loaded
$(document).ready(function() {
$('#submit-button').on('click', function() {
$.ajax({
method: "POST",
// "./finalmap.php" or "../finalmap.php"?
url: "../finalmap.php",
data: {foo: 'bar'},
success: function(response){
console.log('response is: ');
console.log(response);
}
});
});
});
</script>
finalmap.php
<?php echo 'This is finalmap.php';
If you see This is finalmap.php in the web console after pressing the button, then you can try sending data.
finalmap.php
<?php
echo 'You sent the following data: ';
print_r($_POST);
See where we're going with this? The way to eat an elephant is one bite at a time.
./finalmap.php is not a thing.
Instead the code must look like this:
<form action="/finalmap.php">
<input class="finish-button" type="submit" value="FINISH" onclick="sendData();" />
</form>
Try using this instead.
EDIT: OOPS SORRY, I JUST CPED AND PASTED.

Execute PHP code on form submit without text input

I just want to know if it is possible to execute a PHP post request with ajax by click on a form submit button that does not have any text input. Say i have a form
<form action="connecting.php" id="connect" method="post" enctype="multipart/form-data">
<input type="submit" name="userconnect" id="userconnect" value="connect">
</form>
And i want to execute this block of php code on submit button
connecting.php
<?php
require_once ("db.php");
$db = new MyDB();
session_start();
if (isset($_POST['userconnect']))
{
$my_id = htmlspecialchars($_SESSION['log_id'], ENT_QUOTES, 'UTF-8');
$user_id = (int) htmlspecialchars($_SESSION['userid'], ENT_QUOTES, 'UTF-8');
$rand_num = rand();
$hsql =<<<EOF
SELECT COUNT(hash) as count FROM connect WHERE (user_one = '$my_id' AND user_two = '$user_id') OR (user_two = '$my_id' AND user_one = '$user_id');
EOF;
$hret = $db->querySingle($hsql);
if ($hret == 1)
{
echo "<script>alert('You are already connected to this user')</script>";
}
else
{
$usql = $db->prepare("INSERT INTO connect (user_one, user_two, hash) VALUES (:my_id, :user_id, :rand_num)");
$usql->bindValue(':my_id', $my_id, SQLITE3_INTEGER);
$usql->bindValue(':user_id', $user_id, SQLITE3_INTEGER);
$usql->bindValue(':rand_num', $rand_num, SQLITE3_TEXT);
$uret = $usql->execute();
if (!$uret)
{
echo "Error connecting";
}
else
{
echo "Connection Sucessful";
}
}
}
This is the ajax request i am trying to use
$("#connect").submit(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "connecting.php",
data: $(this).serializeArray(), //the data is an issue cause of no text input in for
dataType: "json",
success: function(response) {
console.log(response);
},
error: function(response) {
}
});
});
This doesn't work because there is no data in the form for ajax to send but all data are in the PHP file. How do i execute the php file with ajax. Is there any way?
You dont have to send a POST request to a PHP script in order for it to execute. You can send a normal GET to a URL that executes a PHP script and send you back the JSON data you are looking for. That way, you dont have to send data with the post request and you can still run your PHP script.
Edit*
Another thing you can do is add a hidden ID field or some random text and send that with the POST as data. You dont have to do anything with it, it could just be a time stamp, but it will send the POST request. This is of course overhead and not my kind of programming, but an option nonetheless.
Yes it is possible.... you need to harness a click event...
for example if you had a div element like so:
<div id='mybutton'>click me</div>
then you could use code like this to do literally whatever you want when the button is clicked.:
$('#mybutton').on('click',function(){
$.post...
});
BONUS INFO:
You could also hijack the form submit event like so:
$('#form#myform').on('submit',function(e){
e.preventDefault(); //stop before page is reloaded with post headers
$.post...
});
You don't actually need a form event though, you can just $.get to a php url and return the html or json it generates. just check out the jquery documentation on $.get()

Retrieving data value from database from ajax function

I have a ajax function that would retrieve data from my database and display it in my textbox. I am using a JQuery Form Plugin to shorten the ajax process a little bit. Now what I want to do is to get the data back from the php script that I called from the ajax function.
The form markup is:
<form action="searchFunction.php" method="post" id="searchForm">
<input type="text" name="searchStudent" id="searchStudent" class="searchTextbox" />
<input type="submit" name="Search" id="Search" value="Search" class="searchButton" />
</form>
Server code in searchFunction.php
$cardid = $_POST['searchStudent'] ;
$cardid = mysql_real_escape_string($cardid);
$sql = mysql_query("SELECT * FROM `users` WHERE `card_id` = '$cardid'") or trigger_error(mysql_error().$sql);
$row = mysql_fetch_assoc($sql);
return $row;
The ajax script that processes the php is
$(document).ready(function() {
$('#searchForm').ajaxForm({
dataType: 'json',
success: processSearch
});
});
function processSearch(data) {
alert(data['username']); //Am I doing it right here?
}
In PHP, if I want to call the data, I would just simply create a function for the database and just for example echo $row['username'] it. But how do I do this with ajax? I'm fairly new to this so, please explain the process.
$('#Search').click(function (e) {
e.preventDefault(); // <------------------ stop default behaviour of button
var element = this;
$.ajax({
url: "/<SolutionName>/<MethodName>",
type: "POST",
data: JSON.stringify({ 'Options': someData}),
dataType: "json",
traditional: true,
contentType: "application/json; charset=utf-8",
error: function () {
alert('Unable to load feed, Incorrect path or invalid feed');
},
success: processSearch,
});
});
function processSearch(data) {
var username= ($(data).find('#username'));
}
Change the input type submit to button. Submit will trigger the action in the form so the form will get reloaded. if you are performing an ajax call change it into button.
Everything seems to be fine, except this bit -
function processSearch(data) {
alert(data['username']); //Am I doing it right here?
}
You need to change it to -
function processSearch(data) {
// data is a JSON object. Need to access it with dot notation
alert(data.username);
}
UPDATE
You also need to return a JSON response from your PHP file. Something like -
// Set the Content Type to JSON
header('Content-Type: application/json');
$data = [
"key" => "value"
];
return json_encode($data);
In your case you can directly encode the $row like so -
return json_encode($row);

How do i submit a hidden form using ajax when the page loads?

How can i submit a hidden form to php using ajax when the page loads?
I have a form with one hidden value which i want to submit without refreshing the page or any response message from the server. How can implement this in ajax? This is my form. I also have another form in the same page.
<form id = "ID_form" action = "validate.php" method = "post">
<input type = "hidden" name = "task_id" id = "task_id" value = <?php echo $_GET['task_id'];?>>
</form>
similar to Zafar's answer using jQuery
actually one of the examples on the jquery site https://api.jquery.com/jquery.post/
$(document).ready(function() {
$.post("validate.php", $("#ID_form").serialize());
});
you can .done(), .fail(), and .always() if you want to do anything with the response which you said you did not want.
in pure javascript
body.onload = function() {
var xmlhttp = new XMLHttpRequest();
xmlhttp.open("POST","validate.php",true);
xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xmlhttp.send("task_id=" + document.getElementById("task_id").value);
};
I think you have doubts invoking ajax submit at page load. Try doing this -
<script type="text/javascript">
$(document).ready(function(){
$.ajax({
"url": "validate.php",
"type": "post"
"data": {"task_id": $("#task_id").val();},
"success": function(){
// do some action here
}
})
})
</script>
If you're using jQuery you should be able to get the form and then call submit() on it.
E.g.:
var $idForm = $('#ID_form');
$idForm.submit();
Simple solution - jQuery AJAX post the value as others have suggested, but embed the PHP value directly. If you have multiple forms, you can add more key:value pairs as needed. Add a success/error handler if needed.
<script type="text/javascript">
$(document).ready(function(){
$.post( "validate.php", { task_id: "<?=$_GET['task_id']?>" } );
})
</script>
As others have said, no need for a form if you want to send the data in the background.
validate.php
<?php
$task_id = $_POST['task_id'];
//perform tasks//
$send = ['received:' => $task_id]; //json format//
echo json_encode($send);
JQuery/AJAX:
$(function() { //execute code when DOM is ready (page load)//
var $task = $("#task_id").val(); //store hidden value//
$.ajax({
url: "validate.php", //location to send data//
type: "post",
data: {task_id: $task},
dataType: "json", //specify json format//
success: function(data){
console.log(data.received); //use data received from PHP//
}
});
});
HTML:
<input type="hidden" name="task_id" id="task_id" value=<?= $_GET['task_id'] ?>>

How do i send parameter in ajax function call in jquery

I'm creating an online exam application in PHP and am having trouble with the AJAX calls.
I want the questions to be fetched (and used to populate a div) using an AJAX call when one of the buttons on the right are clicked. These buttons are not static; they are generated on the server (using PHP).
I'm looking for an AJAX call to be something like this:
functionname=myfunction(some_id){
ajax code
success:
html to question output div
}
and the button should call a function like this:
<button class="abc" onclick="myfunction(<?php echo $question->q_id ?>)">
Please suggest an AJAX call that would make this work
HTML
<button class="abc" questionId="<?php echo $question->q_id ?>">
Script
$('.abc').click(function () {
var qID = $(this).attr('questionId');
$.ajax({
type: "POST",
url: "questions.php", //Your required php page
data: "id=" + qID, //pass your required data here
success: function (response) { //You obtain the response that you echo from your controller
$('#Listbox').html(response); //The response is being printed inside the Listbox div that should have in your html page. Here you will have the content of $questions variable available
},
error: function () {
alert("Failed to get the members");
}
});
})
The type variable tells the browser the type of call you want to make to your PHP document. You can choose GET or POST here just as if you were working with a form.
data is the information that will get passed onto your form.
success is what jQuery will do if the call to the PHP file is successful.
More on ajax here
PHP
$id = gethostbyname($_POST['id']);
//$questions= query to get the data from the database based on id
return $questions;
You are doing it the wrong way. jQuery has in-built operators for stuff like this.
Firstly, when you generate the buttons, I'd suggest you create them like this:
<button id="abc" data-question-id="<?php echo $question->q_id; ?>">
Now create a listener/bind on the button:
jQuery(document).on('click', 'button#abc', function(e){
e.preventDefault();
var q_id = jQuery(this).data('question-id'); // the id
// run the ajax here.
});
I would suggest you have something like this to generate the buttons:
<button class="question" data-qid="<?php echo $question->q_id ?>">
And your event listener would be something like the following:
$( "button.question" ).click(function(e) {
var button = $(e.target);
var questionID = button.data('qid');
var url = "http://somewhere.com";
$.ajax({ method: "GET", url: url, success: function(data) {
$("div#question-container").html(data);
});
});

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