jQuery: Multiple draggables and droppables? - javascript

I'm trying to use jquery draggable and droppable.
I have multiple draggables and multiple droppables on my page.
The drga and drop works fine but the issue is that when I drag and drop a div onto 1 droppable, it will get cloned in other droppables on my page as well... also, when I move the draggables inside the droppables, they get multiplied again.
To explain this issue, I've created this FIDDLE
and this is my entire code:
(function ($) {
$.fn.liveDraggable = function (opts) {
this.live("mouseover", function() {
if (!$(this).data("init")) {
$(this).data("init", true).draggable(opts);
}
});
return this;
};
}(jQuery));
$('.drag').liveDraggable({
helper: 'clone',
cursor: 'move'
});
var x = null;
$(".droppable").droppable({
drop: function(e, ui) {
var parent = $(".droppable");
var x = ui.helper.clone();
var img = $(x)
var leftAdj = (ui.position.left - parent.offset().left);
var topAdj = (ui.position.top - parent.offset().top);
if (x.hasClass("outside")) {
x.css({
left: leftAdj,
top: topAdj
});
x.removeClass("outside");
}
x.draggable({
helper: 'original'
});
x.find('.ui-resizable-handle').remove();
x.resizable();
x.appendTo('.droppable');
ui.helper.remove();
}
});
Drag the red divs onto the black divs and you should see the issue.
Could someone please advise on this issue?
Any help would be appreciated.
EDIT:
Getting close but still not quite there: https://jsfiddle.net/qkhunz8k/2/

Edit: Apparently I'm not communicating very well. Let me try this again. All of your droppables have the class droppable. As you say, of course they do. That is the purpose of the class.
However, in your code, when you say x.appendTo('.droppable'), this is the source of your duplicates. It is appending to every element which has the droppable class.
I'm not suggesting that you change or remove the droppable class. I'm not suggesting that you change all of your jquery selectors. I'm only suggesting that when you do your .appendTo, perhaps you should only be appending it to the droppable which is the target. Not all of them. Does that make sense? You can do this by doing x.appendTo(this). Just change that one line, and see if the duplicate problem goes away.
$(".droppable").droppable({
...
x.appendTo(this);
The only thing this change will do is change the number of elements your draggable gets appended to. It wouldn't cause any other changes. But I think it will solve your original problem.
As an aside, might I suggest that you would get better results by changing one other line? If you were to use the ui.draggable instead of the ui.helper, you might find that the css positioning would be a little easier to manage, and that you wouldn't need to manipulate the top and left properties so much. Just a thought.
var x = ui.draggable.clone();
updated modification of your fiddle here

Related

Jquery UI. Droppable after element

I have an issue regarding jquery Ui droppable.
I need to drop an element before or after the element it's dragged over. Is there anyway to detect which element it's over, and then append/prepend it in the parent container.
Right now, I just drops in the end of the div, because of append, I'm a little clueless.
I made a fiddle to hopefully better illustrate my issue:
http://jsfiddle.net/tsxzf80u/
$('section').droppable({
accept:'.dragme',
drop:function(event, ui){
var div = $("<div />").addClass('full').html('test');
$(this).append(div);
}
});
Thanks in advance
If you make each of the divs inside of the section individually droppable, then use after(), seems to do what you want.
$('#fullId1, #fullId2').droppable({
accept: '.dragme',
drop: function (event, ui) {
var div = $("<div />").addClass('full').html('test');
$(this).after(div);
}
});
http://jsfiddle.net/tsxzf80u/2/

JQuery UI droppable accept and drop not working

I am using the JQuery UI draggable and droppable. But it looks like ui.droppable is undefined. Can someone help me please?
Here is my code:
$(".droppable").droppable({
tolerance : "pointer",
accept : ".acceptable",
drop : function(event, ui) {
ui.draggable.hide(500, function() {
var position = ui.droppable.attr("id");
built(position.replace("position", ""),
ui.draggable.attr("id"));
ui.draggable.remove();
});
}
});
i found the solution somehow i missed it, i also was trying $(this).droppable.attr("id"); wich was undefined aswell somehow i missed that i use $(this) inside of the hide, callback function where $(this) is the draggable object it worked by moving the line code out of the hide function.

jQuery UI - dropped element -> from which div was it dragged

I have a problem with jQuery UI and get some information of a dropped item.
I have three areas on the screen:
<div id="area1"></div>
<div id="area2"></div>
<div id="area3"></div>
In these areas, I put elements which are draggable with jQuery UI.
Now if an element is dropped from one to another area, I will not only get the area number in which the element is dropped to, I also want the area number where the element was dropped before the new drop.
I created a full working example: http://jsbin.com/iyaya3/
There is a blue draggable element and if I drag it from area1 to area2, I want to have the alert message with "dragged from area1 - dropped to area2".
How can this be done?
Best Regards, Tim-.
Hey, I updated your jsbin - http://jsbin.com/iyaya3/3
It works like this:
Take initial parent element's id and save it on draggable using jQuery.data
When dropping it on droppable, update data
I've got two ideas:
1) You can put a class or ID on the elements in each div:
<div id="area1"><node class="from1"></node></div>
<div id="area2"><node class="from2"></node></div>
<div id="area2"><node class="from2"></node></div>
And then test for that when you have the item
2) Write a function to do the clone instead of relying on the drag and drop to do it for you (http://ui-dev.jquery.com/demos/draggable/#option-helper) and then test for the parent and store that (in a singleton outside the scope of the dragger) where you can get it later.
I think I would prefer the first (even if you don't have html access to add these classes, just add it with javascript)
In your draggable setup, add this:
start: function(event,ui){
ui.helper.data('from-id', $(this).parent().attr('id') );
}
This will attach, as data, the ID of the container from which the element is being dragged.
Then, in the droppable, you can have:
alert( 'I was dragged from ' + ui.draggable.data('from-id') );
Here's the updated jsBin.
Edit: The start function creates a closure, so $(this).parent().attr('id') continues to point to the original parent. One solution to this problem (if you wish to keep a start function) is to clear start when the drag stops:
stop: function(event,ui){
ui.helper.draggable({ start: null });
}
This will allow the data methods in the droppable handlers to update the from-id without being immediately reverted to the original value by the start function.
Here's a revised jsBin example.
$(element.draggable).parent().attr('id')) works for me
I removed the duplicated code and solved the problem by saving the previous element id by the data() function.
JS Bin
<script type="text/javascript">
$(document).ready(function() {
$('#area1').append('<div class="shoulddraggable" style="width:100px;height:100px;top:0px;left:0px;background-color:blue;" data-elementid="100"></div>');
$(".shoulddraggable").draggable({
scroll: false,
revert: "invalid",
scope: "items",
});
$(".shoulddraggable").data('previousId', 'area1');
$('.droppable').droppable({
scope: "items",
drop: function(event, ui) {
alert('Previous container id: ' + ui.draggable.data('previousId'));
alert("Element: "+ui.draggable.data("elementid")+" dragged into" + $(this).attr('id'));
ui.draggable.data('previousId', $(this).attr('id'));
}
});
});
</script>
</body>
</html>

Change dragging object and restore it after dropping it

please help me, I know in general how to use the draggable and droppable classes, but I can not find a way to achieve this:
I have a large-sized image that I need to drag and drop into a div.
1) while dragging, instead of moving around the large-sized image, I want to use a small-sized image (I already have it, just need to change the src).
2) Once it reaches the target div, I would like to hide that dragged image and show again the large-sized image in its original place.
The only restriction is: "revert: invalid" must apply.
This is my code:
$("#big_img").draggable({
revert: 'invalid',
drag : function(e, ui){
//Change big image with a small version of it
$(this).attr("src").replace("/Large/","/Small/"); //<--this do nothing
}
});
$("#target").droppable({
drop: function(e, ui) {
alert("was added"); //<-- no problem here.
//Restore the big_img
}
});
Thank you.
I think I solved it:
Using "helper", I can achieve to use other image instead, like this:
$("#big_img").draggable({
helper: return $("<img src='"+$(this).attr("src").replace("/Large/","/Small/")+"' />");
});
I just need to center it to the mouse cursor, but that I think won't be a problem. Then,
removing the dropped element won't be a problem either. So, I won't need to restore the image as it is not really moving. :)
If you have another alternative, I will be pleased to read it.
String.prototype.replace() does not modify the source string, but returns a new, modified string. Try the following:
$("#big_img").draggable({
revert: 'invalid',
drag : function(e, ui) {
$this = $(this);
$this.attr("src", $this.attr("src").replace("/Large/","/Small/"));
}
});

jQuery: How to stop a helper from being removed if it wasn't successfully dropped

I have a draggable with a custom helper. Sometimes the helper is a clone and sometimes it is the original element.
The problem is that when the helper is the original element and is not dropped on a valid droppable it gets removed. My solution looks like this so far:
in my on_dropped callback I set ui.helper.dropped_on_droppable to true;
In the stop callback of the draggable, I check for that variable and then ... what do I do?
$('.my_draggable').draggable({
stop : function(e, ui) {
if (!ui.helper.dropped_on_droppable) {
/* what do I do here? */
}
},
Is this even the right approach?
Ok, I found a solution! It's ugly and it breaks the 'rules of encapsulation,' but at least it does the job.
Remember this is just for special cases! jQuery can handle its own helper removal just fine. In my case I had a helper that was sometimes the original element and sometimes a clone, so it wasn't always appropriate to delete the helper after reverting.
element.draggable({
stop : function(e, ui) {
/* "dropped_on_droppable" is custom and set in my custom drop method
".moved_draggable" is custom and set in my custom drag method,
to differentiate between the two types of draggables
*/
if (!ui.helper.dropped_on_droppable & ui.helper.hasClass('moved_draggable')) {
/* this is the big hack that breaks encapsulation */
$.ui.ddmanager.current.cancelHelperRemoval = true;
}
},
Warning: this breaks encapsulation and may not be forwards compatible
I might be missing something here, but is it not simply a case of adding
revert: "invalid"
to the options of the draggable if the draggable is of an original element, not a clone?
I use a custom helper that aggregates multiple-selection draggables into a single div. This does not seem to jive with the revert functionality so I came up with this scheme. The elements are manually appended back to the original parent which I keep track of via .data().
.draggable({
helper: function() {
var div = $(document.createElement('div'))
.data('lastParent', $(this).parent());
return div;
},
start: function() {
//... add multiple selection items to the helper..
},
stop: function(event,ui) {
$( $(ui.helper).data('lastParent') ).append( $(ui.helper).children() );
}
}
This approach does lose out on the pretty animation, but it may be useful to you or someone else with this issue.

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