Multiple products in one form - javascript

I would like to add a functionality in my form, in which a user can add as many entries before hitting submit button, like a 'add to cart' functionality, show the added entries in same page, in a separate div with submit button then save those multiple entry in database using that submit button(in a separate div that shows added entry).
So far my form allows only entries on per submit bases, meaning is if the user wants to add another entry, he/she has to go back to the form and add and click to submit again.
<form method="POST" name="myForm" action="saveto.php">
<label> Speed Rating:</label>
<select name="speed_rating" required class="form-control" id="speed_rating" ></select>
<div class="form-group col-sm-8">
<label> Description:</label>
<select name="description" required class="form-control" id="description" >
</select>
</div>
<div class="form-group col-sm-4">
<label> Load Index:</label>
<select name="load_index" required class="form-control" id="load_index" >
</select>
</div>
<div class="form-group col-sm-6">
<label> Vendor:</label>
<select name="vendor" required class="form-control" id="vendor" >
</select>
<div class="note"> Recommended Vendor : <span id="recomvend"> </span> </div>
</div>
<div class="form-group col-sm-6">
<label> Quantity:</label>
<input type="text" required name="qty" class="form-control" id="qty"></div>
<div style="clear:both"> </div>
<input type="submit" name="submit" class="btn btn-primary smp" value="Submit">
<button id="clear" type="button" class="btn btn-primary smp smp2" > Reset </button>
</div>
<input type="submit" value="submit" name="submit">
</form>
How would you achieved this? My saveto.php is just a normal script that will process the submitted data to database, one entry in a per submit bases.

I created this jsfiddle https://jsfiddle.net/jy6vh4rp/31/
If that's what you are looking for then you should add this to your front end:
<form action="validate.php" method="post">
<div style="padding: 30px 0; text-align: center;">
<button type="button" onclick="createDOM()">Add</button>
<input type="submit" value="submit" name="submit" />
</div>
<div class="productsContainer"></div>
</form>
<script>
$(document).ready(function() {
id = 0;
createDOM = function() {
$(".productsContainer").append('<input type="text" id="' + id + '" name="products[]" value="' + id + '" />');
id++;
};
});
</script>
And this to your validation backend :
foreach($_POST['products'] as $prodInput){
$product = filter_var($prodInput,FILTER_SANITIZE_NUMBER_INT);
if( is_numeric($product) ){
echo $product;
}
}

Related

ASP.net razor pages and multi-select, posting all items in select

I have a form which has two selects, one on the left, one on the right. One on the left to list the items to add, two buttons, one to add and one to remove items to another select using a bit of jQuery. Both selects have the multiple="multiple" attributes set.
The problem is, when I submit the form, only items selected in the right hand select are posted in the form data, which is expected. I have added the following bit of jQuery to select all of the items in the select list on submit, but it still only sends the data of the single selected item before the submit button is pressed:
$("#pageForm").submit(function (e) {
$("#controlGradesList option").prop("selected", "selected");
});
This is my form markup:
<form method="post" id="pageForm">
#Html.HiddenFor(x => x.Data.Ref)
<div class="row">
<div class="col-sm-5">
<h3>All grades</h3>
<div class="form-group">
<input type="text" id="filterBox" class="form-control" placeholder="Filter grades" />
</div>
<div class="form-group">
<select class="form-control" size="20" multiple="multiple" id="gradesList" asp-items="#(new SelectList(Model.Data.AvailableGrades, "Ref", "Display"))">
</select>
</div>
</div>
<div class="col-sm-2">
<div class="push-down-arrows">
<div class="form-group">
<input type="button" class="btn btn-primary btn-block" id="addButton" value=">>" title="Add grade to control group" />
</div>
<div class="form-group">
<input type="button" class="btn btn-primary btn-block" id="removeButton" value="<<" title="Remove grade from control group" />
</div>
</div>
</div>
<div class="col-sm-5">
<h3>Associated grades</h3>
<div class="grades-padding-top">
<div class="form-group">
<select class="form-control" size="20" multiple="multiple" id="controlGradesList" asp-for="Data.AssociatedGradeRefs" asp-items="#(new SelectList(Model.Data.AssociatedGrades, "Ref", "Display"))">
</select>
</div>
</div>
</div>
</div>
<hr />
<button class="btn btn-primary" type="submit"><i class="fa fa-save"> </i>Save</button>
| Back to previous page
</form>
What am I missing here?
I needed to use and onclick event on the button to select all of the options in the select, prevent default and submit the form:
<button class="btn btn-primary" type="submit" onclick="submitForm(event)"><i class="fa fa-save"> </i>Save</button>
and
function submitForm(e) {
$("#controlGradesList option").prop("selected", true);
e.preventDefault();
$('#pageForm')[0].submit();
}

jQuery and Ajax not working $.on

I want when I click on Clear button, all fields in the form to be cleared.
The ajax request is only replacing the form from the tag <form> to </form>.
When it is clicked on Clear button, the console output is working.
I have the following form:
<div class="col-lg-5 formWrapper">
<form data-th-fragment="layoutForm" id="layoutForm" class="form-horizontal" data-th-object="${layout}" data-th-action="#{/layouts/add}" method="POST" role="form">
<div class="row">
<input id="objectId" data-th-field="*{id}" type="hidden">
<input data-th-if="*{filePath} !=null" data-th-field="*{filePath}" type="text" hidden="hidden">
<label for="layoutName" >Layout name</label>
<input data-th-field="*{name}" id="layoutName" class="form-control" type="text">
</div>
<div class="row">
<div class="col-lg-4">
<label for="status">Status</label>
<select id="status" data-th-field="*{status}"class="form-control">
<option value="1">Active</option>
<option value="0">Blocked</option>
</select>
</div>
<div class="col-lg-6">
<label for="exhibitorName">Exhibitor</label>
<select data-th-field="*{exhibitor}" name="exhibitorName" id="exhibitorName" class="form-control">
<option data-th-each="exhibitor : ${exhibitorsList}" data-th-value="${exhibitor.id}" data-th-text="${exhibitor.exhibitorName}"></option>
</select>
</div>
</div>
<div class="row">
<div class=" col-lg-3">
<input id="clearForm" type="reset" value="Clear" class="form-control btn-lg btn btn-default">
</div>
<div class=" col-lg-3 col-lg-offset-4">
<input id="submitButton" type="submit" value="Add" class="form-control btn-lg btn btn-success">
</div>
</div>
</form>
</div>
The form looks something like this:
The jQuery is as follow:
$(document).ready(function() {
$('.formWrapper').on('click','#clearForm', function (event) {
$(this).closest('form').find("input[type=text]").val("");
console.log("ASD");
});
});
The snipped is how I replace the form:
$("body").on('click','#editLayout', function(event){
var ajax = $.ajax({
url : "/layouts/edit/" + $(this).data("id"),
dataType : "html",
success: function (data) {
$("#layoutForm").replaceWith(data);
$('#submitButton').val('Edit').addClass('btn-warning').removeClass('btn-success');
}
});
});
Try this,
$('#form_id').trigger("reset");
or
$('#form_id')[0].reset();
A reset button doesn't need any script at all (or name or id):
<input type="reset">
and you're done. But if you really must use a script, note that every form control has a form property that references the form it's in, so you could do:
<input type="button" onclick="this.form.reset();">
But a reset button is a far better choice.
Try to use $('#clearForm').reset(); or $('#clearForm')[0].reset();

how to get a dynamic form id generated by jsp in jquery

How to get a formId that is generated by using a jsp using jquery?
<c:url var="updateSubUserDetails" value="/employer/recruiters/updateSubUserDetails"/>
<form id="updateform${subUser.employerId}" action="${updateSubUserDetails}" method="post" >
<div class="modal-body">
<input type="hidden" name="subUserId" value="${subUser.employerId}"/>
<div class="form-group">
<input type="text" id="subUserName${subUser.employerId}" name="subUserName" class="form-control " value="${subUser.firstName}" placeholder="Edit Sub User Name"/>
</div>
<div class="form-group">
<input type="text" id="subUserEmail${subUser.employerId}" name="subUserEmail" class="form-control " value="${subUser.emailId}" onchange="checkMail(${subUser.employerId})" placeholder="Edit Email"/>
</div>
<span id="avialabilityMessage${subUser.employerId}"></span>
<div class="form-group">
<input type="text" id="subUserMobile${subUser.employerId}" name="subUserMobile" class="form-control " value="${subUser.mobileNumber}"placeholder="Edit Contact No"/>
</div>
<sec:csrfInput/>
<div class="modal-footer">
<input type="button" id="muEditButtonID" onclick="updateSubUserDetails(${subUser.employerId})" class="btn btn-warning btn-lg glyphicon glyphicon-ok-sign" value="Update"> 
</div>
</div>
</form>
How to get above dynamically generated form id in javascript jquery? Please assist me.
//if you sure there is only one form
document.forms[0]
//else
document.querySelector('[id^="updateform"]')
so, if you want to get id just add .id
//if you sure there is only one form
document.forms[0].id
//else
document.querySelector('[id^="updateform"]').id

Multiple forms with one submit button with edit and delete button

How to submit and "show"(in the same page) multiple form with one submit button with edit and delete button with php javascript?
This is my mockup
This is my code without php:
<div class="row">
<div class="col-md-6">
<div class="panel-body">
<form method="post">
<div class="form-group row">
<div class="col-md-3">
<label>Content number</label>
<input class="form-control" name="BranchName" type="text" />
</div>
<div class="col-md-4">
<label>Topic</label>
<input class="form-control" name="Tel" type="text">
</div>
</div>
<div class="form-group">
<label>Content</label>
<textarea class="form-control" name="Address" rows="3"></textarea>
</div>
<p id="submit">
<button type="submit" class="btn btn-info">Submit</button>
</p>
</form>
</div>
</div>
</div>
Please help. This is the final that what i expect. I want it to clear text area after click submit to be ready for the new form. But now i don't know how to show all form that submitted at the bottom of the page in list of item with edit and delete function.
As i'm assuming your getting your information via PHP, what you will need to do in the edit/ delete sections is add some form item id for the edit/delete functions something like. Alternatively you can do the same thing in JavaScript, and link the AJAX request to a .php file with the functions for handling the edit and delete functions.
<?php foreach($key as $data) { ?>
<form action="edit.php" method="post">
<input name="<?php echo $data[$key].formItemID ?>" type="submit" value="edit" />
</form>
<form action="delete.php" method="post">
<input name="<?php echo $data[$key].formItemID ?>" type="submit" value="delete" />
</form>
<?php } ?>

How to make a second submit button?

I have a classic form that submits data to a controller. Nothing special until here.
The thing is I want a second button, let's say "Save and Exit" that I want to also submit and redirect to home page.
How could I do that? I guess this includes a little javascript for checking?
I just can't wrap my head around it. Thank you!
<form method="POST" action="link/here" id="main_form" class="form-horizontal">
<input name="_token" value="JDtRMqc4aRFlK4QFzDPRTxKvNxIj5EnoLOceOUBT" type="hidden">
<div class="box-body">
<div class="form-group">
<label for="url" class="col-sm-3 control-label">Figura</label>
<div class="col-sm-9">
<input class="form-control" id="Figura" name="figura" placeholder="Figura" value="" type="text">
</div>
</div>
<div class="form-group">
<label for="url" class="col-sm-3 control-label">Parcela</label>
<div class="col-sm-9">
<input class="form-control" id="Parcela" name="parcela" placeholder="Parcela" value="" type="text">
</div>
</div>
<div class="form-group">
<label for="url" class="col-sm-3 control-label">Rand</label>
<div class="col-sm-9">
<input class="form-control" id="Rand" name="rand" placeholder="Rand" value="" type="text">
</div>
</div>
<div class="form-group">
<label for="url" class="col-sm-3 control-label">Nr. Locuri</label>
<div class="col-sm-9">
<input class="form-control" id="Locuri" name="locuri" placeholder="Locuri" value="" type="text">
</div>
</div>
<div id="locuri_div" class="col-sm-offset-1"></div>
<div class="pull-right">
<button type="submit" class="btn btn-success">Salveaza</button>
</div>
<div class="pull-left">
Inapoi
</div>
</div>
<!-- /.box-body -->
</form>
your current button :
<button type="submit" name="check" value="0" class="btn btn-success">Save</button>
add a new one:
<button type="submit" name="check" value="1" class="btn btn-success">Save and Exit</button>
then in your save.php do:
if($_POST['check'] == 0){
//redirect to page
}
else{
//redirect to home
}
Give each button a name and a value. In your controller (client-side JS is the wrong tool for this), test the name and then redirect based on that.
For example:
<button name="action" value="save">Save</button>
<button name="action" value="save_and_go_home">Save & Go Home</button>
And then (to use expressjs as an example):
app.post('/here', function (req, res) {
// Do everything else you want to do with the data
// Then
var action = req.body.action;
if (action === "save_and_go_home") {
res.redirect("/");
} else {
res.send('Whatever you were sending before')
}
});

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