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Get value from radio button

I'm trying to make a multiple select radio but the output to the console is console=on.
That doesnt help at all. I need to know which (none,t,i or ti) that is selected.
Any idea how to do this?
$('#btnSubmit').click(function() {
var data = $('#containerCreationForm').serialize();
console.log(data);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="containerCreationForm" method="post">
<div class="content-form">
<label class="col-sm-2 control-label">Console</label>
<div class="col-sm-10">
<div class="col-sm-5">
<div class="radio radio-info">
<input name="console" id="it" class="form-control" type="radio">
<label for="it">Interactive & TTY
<span class="text-blue">(-i -t)</span>
</label>
</div>
<div class="radio radio-info">
<input name="console" id="tty" class="form-control" type="radio">
<label for="tty">TTY
<span class="text-blue">(-t)</span>
</label>
</div>
</div>
<div class="col-sm-5">
<div class="radio radio-info">
<input name="console" id="interactive" class="form-control" type="radio">
<label for="interactive">Interactive
<span class="text-blue">(-i)</span>
</label>
</div>
<div class="radio radio-info">
<input name="console" id="none" class="form-control" type="radio" checked="">
<label for="none">None</label>
</div>
</div>
</div>
<button type="button" id="#btnSubmit">Submit</button>
</div>

Add value attribute in radio button.
Example:
Since,you are using Jquery in your code. I'm using it here:
$(document).ready(function(){
$("input[type='button']").click(function(){
var radioValue = $("input[name='gender']:checked").val();
if(radioValue){
alert("Your are a - " + radioValue);
}
});
});
In HTML:
<label><input type="radio" name="gender" value="male">Male</label>
<label><input type="radio" name="gender" value="female">Female</label>
<p><input type="button" value="Radio Value"></p>
Hope it helps..!

You need to use names and values to identify what your radios mean
eg
$(function() {
$("form").submit(
function(args) {
args.preventDefault();
console.log($(this).serialize());
}
);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<fieldset>
<legend>Gender:</legend>
Male: <input type="radio" name=gender value=m> Female: <input type="radio" name=gender value=f> Other <input type="radio" name=gender value=o>
</fieldset>
<input type=submit>
</form>
this will result in a form value of gender= m | f | o
also note you should be using the forms submit event as this will invoke the forms validation logic which your current code is bypassing

can not get value from radio button using jquery

I try to get value from radio button, here's my code:
var isactive = result.IsActive;
$("input[name='RadioActive']").each(function () {
if ($(this).val() == isactive) {
$(this).attr("checked", "checked");
}
});
and the html :
<section class="col col-lg-2">
<label class="label">Active</label>
<div class="inline-group">
<label class="radio">
<input type="radio" name="RadioActive" class="RadioActive" value="T" />
<i></i>
Yes
</label>
<label class="radio">
<input type="radio" name="RadioActive" class="RadioActive" value="F" />
<i></i>
No
</label>
</div>
</section>
Doesn't work. Do you have any Idea ? What am I Missing ?

To select a radio button using jquery use prop.
In the below snippet expecting the value of result.IsActive to be F & assigning it to isactive
var isactive = "F";
$("input[name='RadioActive']").each(function() {
if ($(this).val() == isactive) {
$(this).prop("checked", "checked");
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<section class="col col-lg-2">
<label class="label">Active</label>
<div class="inline-group">
<label class="radio">
<input type="radio" name="RadioActive" class="RadioActive" value="T" />
<i></i>
Yes
</label>
<label class="radio">
<input type="radio" name="RadioActive" class="RadioActive" value="F" />
<i></i>
No
</label>
</div>
</section>

var isActive='F';
$("input[name='RadioActive']").each(function (index,value) {
if( $(value).val()==isActive)
$(value).attr('checked','checked');
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<section class="col col-lg-2">
<label class="label">Active</label>
<div class="inline-group">
<label class="radio">
<input type="radio" name="RadioActive" class="RadioActive" value="T" />
<i></i>
Yes
</label>
<label class="radio">
<input type="radio" name="RadioActive" class="RadioActive" value="F" />
<i></i>
No
</label>
</div>
</section>

The problem is that result.IsActive isn't resolving. Simply setting isactive to either T or F will check the radio button for you:
var isactive = "T";
$("input[name='RadioActive']").each(function() {
if ($(this).val() == isactive) {
$(this).attr("checked", "checked");
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<section class="col col-lg-2">
<label class="label">Active</label>
<div class="inline-group">
<label class="radio">
<input type="radio" name="RadioActive" class="RadioActive" value="T" />
Yes
</label>
<label class="radio">
<input type="radio" name="RadioActive" class="RadioActive" value="F" />
No
</label>
</div>
</section>
Note that setting it to true or false will not trigger the checked attribute; it needs to equal the value of the radio button exactly (which are T and F respectively).
Ensure that your result.IsActive returns either T or F, and it will work correctly for you.
Hope this helps! :)

You can use something like below
$("input[name='RadioActive']:checked").val()

Here is your JavaScript code:
$(document).ready(function () {
$('#myForm').on('click', function () {
var value = $("[name=RadioActive]:checked").val();
alert("Selected Radio Value is : " + value);
})
});
HTML code:
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="style.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="script.js"></script>
</head>
<body>
<form id="myForm">
<section class="col col-lg-2">
<label class="label">Active</label>
<div class="inline-group">
<label class="radio">
<input type="radio" name="RadioActive" class="RadioActive" value="T" />
<i></i>
Yes
</label>
<label class="radio">
<input type="radio" name="RadioActive" class="RadioActive" value="F" />
<i></i>
No
</label>
</div>
</section>
</form>
</body>
</html>
and here is a working plunker for the code:
https://plnkr.co/edit/D9UaU43OxHGUg80xxsiS?p=preview

update field on radio select

In a form I have a set of radio buttons with fixed donation amount and another field when a user can enter an amount of choice. For simplicity whilst processing the form I want a functionality where whatever is selected populates in the other field. I have the HTML/JS below:
$("input[id^='radio']").click(function() {
$("input[name='otheramount']").val(jQuery(this).val());
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="radio-select">
<input type="radio" name="selamount" id="amount-1" value="10.00">
<label for="amount-1">$10</label>
</div>
<div class="radio-select">
<input type="radio" name="selamount" id="amount-2" value="15.00">
<label for="amount-2">$15</label>
</div>
<div class="radio-select">
<input type="radio" name="selamount" id="amount-3" value="20.00">
<label for="amount-3">$20</label>
</div>
<div class="radio-select">
<input type="radio" name="selamount" id="amount-3" value="20.00">
<label for="amount-4">$25</label>
</div>
<div class="form-group other-amount col-lg-3 col-md-8 col-xs-12 padd-top-10"></div>
<input type="text" id="otheramount" name="otheramount" value="" placeholder="Or Other Amount">
I have also tried
<input type="radio" name="selamount" id="amount-3" value="20.00" onclick="document.getElementById('otheramount').value = this.value">
But when the first one changes it does not change anymore on subsequent clicks.

None of your IDs begin with "radio," which is what your [id^='radio'] selector is trying to match.
They begin with "amount" instead, so you should use:
$("input[id^='amount']").click(...
Also, here's a trick you can use with labels.
Instead of doing:
<input type="radio" name="selamount" id="amount-1" value="10.00">
<label for="amount-1">$10</label>
… you can put the input inside the label and avoid using the for attribute altogether:
<label>
<input type="radio" name="selamount" id="amount-1" value="10.00">
$10
</label>
Working Snippet
$("input[id^='amount']").click(function() { //CHANGE THIS
$("input[name='otheramount']").val(jQuery(this).val());
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="radio-select">
<label>
<input type="radio" name="selamount" id="amount-1" value="10.00">
$10
</label>
</div>
<div class="radio-select">
<label>
<input type="radio" name="selamount" id="amount-2" value="15.00">
$15
</label>
</div>
<div class="radio-select">
<label>
<input type="radio" name="selamount" id="amount-3" value="20.00">
$20
</label>
</div>
<div class="radio-select">
<label>
<input type="radio" name="selamount" id="amount-3" value="20.00">
$25
</label>
</div>
<div class="form-group other-amount col-lg-3 col-md-8 col-xs-12 padd-top-10">
<input type="text" id="otheramount" name="otheramount" value="" placeholder="Or Other Amount">

Change alphabet when select radio button

When I click one of the alphabet, the selected one shall be displayed and the rest should be hidden.
Somehow, the code doesn't work. I'm using jQuery.
$("#r-learn-more").click(function() {
alert("Handler for .click() called.");
});
$("#r-book-viewing").click(function() {
$("#bb").attr("display", "block");
});
$("#r-closing-price").click(function() {
alert("Handler for .click() called.");
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<div class="fieldset-content">
<div class="radio">
<input type="radio" value="one" name="radiogroup1" id="r-learn-more" checked="">
<label for="r-learn-more">a</label>
</div>
<div class="radio">
<input type="radio" value="two" name="radiogroup1" id="r-book-viewing">
<label for="r-book-viewing">b</label>
</div>
<div class="radio">
<input type="radio" value="three" name="radiogroup1" id="r-closing-price">
<label for="r-closing-price">c</label>
</div>
</div>
<div id="aa" style="display: block;">a</div>
<div id="bb" style="display: none;">b</div>
<div style="display: none;">c</div>

In general you tried with $("#bb").attr('display','block'), must be $("#bb").css("display","block");
Maybe the better way is to use something like:
<div class="fieldset-content">
<div class="radio">
<input type="radio" data-show="aa" value="one" name="radiogroup1" id="r-learn-more" checked="">
<label for="r-learn-more">a</label>
</div>
<div class="radio">
<input type="radio" data-show="bb" value="two" name="radiogroup1" id="r-book-viewing">
<label for="r-book-viewing">b</label>
</div>
<div class="radio">
<input type="radio" data-show="cc" value="three" name="radiogroup1" id="r-closing-price">
<label for="r-closing-price">c</label>
</div>
</div>
<div id="aa" class='item' style="display: block;">a</div>
<div id="bb" class='item' style="display: none;">b</div>
<div id="cc" class='item' style="display: none;">c</div>
And JS
var $items = $('.item');
$(':radio').on('change', function () {
var $item = $('#' + this.dataset.show);
$items.not($item).css('display', 'none');
$item.css('display', 'block');
});

Try this
$('.radio input').change(function(event){
$('.alphabet-letter').hide();
$('#'+$(this).data('id')).show();
}).first().prop('checked', true).trigger('change');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<div class="fieldset-content">
<div class="radio">
<input type="radio" value="one" name="radiogroup1" id="r-learn-more" data-id="aa">
<label for="r-learn-more">a</label>
</div>
<div class="radio">
<input type="radio" value="two" name="radiogroup1" id="r-book-viewing" data-id="bb">
<label for="r-book-viewing">b</label>
</div>
<div class="radio">
<input type="radio" value="three" name="radiogroup1" id="r-closing-price" data-id="cc">
<label for="r-closing-price">c</label>
</div>
</div>
<div id="aa" class="alphabet-letter">
a
</div>
<div id="bb" class="alphabet-letter">
b
</div>
<div id="cc" class="alphabet-letter">
c
</div>

Wouldn't even be easier just to have one "result" div?
Something like this
EDIT: For displaying the "a" as default either you just put "a" in the result div, or maybe on load you get the text (in this case you are not using the value) of the radio button option selected as per the edit in the snippet
$('#result').text($('input:radio[name=radiogroup1]:checked').parent().text());
$( ".radio input" ).click(function() {
var label = $("label[for='"+$(this).attr('id')+"']");
console.log(label);
console.log(label.html());
$('#result').text(label.html());
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<div class="fieldset-content">
<div class="radio">
<input type="radio" value="one" name="radiogroup1" id="r-learn-more" checked="">
<label for="r-learn-more">a</label>
</div>
<div class="radio">
<input type="radio" value="two" name="radiogroup1" id="r-book-viewing">
<label for="r-book-viewing">b</label>
</div>
<div class="radio">
<input type="radio" value="three" name="radiogroup1" id="r-closing-price">
<label for="r-closing-price">c</label>
</div>
</div>
<div id="result" style="display: block;">
<!--Alernative to load the text by jquery you could just put here "a"-->
</div>

How to change the checked value using javascript

I am trying to change the radio button that is checked by default and I cannot access the html to do so, but I can use javascript. Here is the html
<div class="row" id="courseSearchAvailability">
<div class="col-xs-12">
<fieldset class="accessibility">
<legend>
Filter By Course Availability
</legend>
<div class="radio">
<label>
<input type="radio" name="courseSearch.filterString" value="availforreg" id="searchAvailable">
Search scheduled courses
</label>
</div>
<div class="radio">
<label>
<input type="radio" name="courseSearch.filterString" value="all" checked="checked" id="searchAll">
Search all courses
</label>
</div>
</fieldset>
</div>
</div>
I want to make the searchAvailable the default and here is the javascript that I'm using and it doesn't seem to work. I'm new to this so be nice lol.
var sel = document.getElementById('searchAvailable');
sel.searchALL.removeAttribute('checked');
sel.searchAvailable.setAttribute('checked', 'checked');
document.forms[0].reset();

Just these two lines should be enough:
var sel = document.getElementById('searchAvailable');
sel.checked = true;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="row" id="courseSearchAvailability">
<div class="col-xs-12">
<fieldset class="accessibility">
<legend>Filter By Course Availability</legend>
<div class="radio">
<label>
<input type="radio" name="courseSearch.filterString" value="availforreg" id="searchAvailable">Search scheduled courses</label>
</div>
<div class="radio">
<label>
<input type="radio" name="courseSearch.filterString" value="all" checked="checked" id="searchAll">Search all courses</label>
</div>
</fieldset>
</div>
</div>