I'm trying to update the two locked textboxes with information that I get from my database. I enter a phone number in the "Telefon" checkbox, and I want it to get the firstname and lasttname for that phone number. Which works by the way, but it's not the way I want it. I want the information to be automatically put into the textboxes without refreshing the page. and for some odd reason my code got split in two here. I've tried to look for a solution for hours. I'm very new to coding, and I would love some help!
<?php
SESSION_START();
$output = NULL;
if(isset($_POST['btn_checkTelefon'])) {
require 'connectdb.php';
$telefon_Search = $connect_DB->real_escape_string($_POST['telefon_Search']);
$sql = "SELECT * FROM elever WHERE Telefon = '$telefon_Search'";
$resultSet = $connect_DB->query($sql);
if($resultSet->num_rows > 0) {
while($rows = $resultSet->fetch_assoc()) {
$fornavnoutput_Database = $rows['Fornavn'];
$etternavnoutput_Database = $rows['Etternavn'];
}
echo '<script type = "text/javascript">';
echo 'function sayHi() {';
echo 'val1 = document.getElementById("telefon_Input").value;';
echo 'if(val1 == "") {';
echo ' alert("Vennligst skriv inn ditt telefon nummer!");';
echo '}';
echo 'if(val1 !== "") { ';
echo ' document.getElementById("check_Fornavn").value = "<?php echo $fornavnoutput_Database?>";';
echo ' document.getElementById("check_Etternavn").value = "<?php echo $etternavnoutput_Database?>";';
echo '}';
echo '}';
echo '</script>';
} else {
$output = "No results";
}
}
$fornavnoutput_Database2 = "Fornavn";
$etternavnoutput_Database2 = "Etternavn";
?>
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" type="text/css" href="style2.css?<?php echo time(); ?>" />
</script>
<script type = "text/javascript"></script>
<title></title>
</head>
<body>
<?php
include 'connectdb.php';
?>
<form name="form1" action="">
<table id="valgt_skap_tabell" class="bokssvartabell">
<tr>
<td>Valgt skap</td>
</tr>
<tr>
<td>
<input class="bokssvarskjema" type="text" name="Valgt skap" disabled value= <?php
if(isset($_POST["radios"])){
echo $_POST["radios"];
} else {
//header('location: index.php');
} ?>>
</td>
</tr>
</table>
<table id="telefon_tabell" class="bokssvar_tabell">
<tr>
<td>Telefon:</td>
</tr>
<tr>
<td><input type="text" name="telefon_Search" id="telefon_Input" maxlength=8"><br></td>
</tr>
<tr>
<td><button type="button" name ="btn_checkTelefon" id="sjekkTelefon" onclick = "sayHi()">Sjekk</button></td>
</tr>
<div id="d1"></div>
</table>
<table id="opplysninger_tabell" class="bokssvartabell">
<tr>
<td>Fornavn:</td>
<td>Etternavn:</td>
</tr>
<tr>
<td><input type="text" name="Fornavn" disabled id="check_Fornavn"></td>
<td><input type="text" name="Etternavn" disabled id="check_Etternavn"></td>
</tr>
</table>
</form>
<?php echo $output; ?>
</body>
You need to use AJAX for this. Example $.ajax() -> shortcuts $.post(), $("id").load("url"), ... Look it up a lot in depth explanation about these on stackoverflow.
Please never mix JavaScript with php.
Use it in separate file.
Edit: So have you fixed it yet?
The easier way to load paged dynamicaly is with load method + actions. $.post is used if you need to do something with returned data from php. I will give you example of load.
I will give a proper example how to code.
Universal function for a link that look at href value and load HTML parts (form in this case) from PHP dynamicaly to your page, you do need to implement actions or just call your ordinary page if you have only one default action there. I use jQuery library here. This script must be in separate file else it will work but you will get a sync warning in your console.
$(function() {
$('a').on("click", function(e) {
e.preventDefault();
e.stopPropagation();
var URL = $(this).attr('href');
$('body').load(URL, 'form');
})
})
php example
prefered showsomethingfunction in separate file like showfunctions.php
function myLinks() {
echo "<a href='index.php?action=showsomething'>showsomething</a>"
}
index.php + included showfunctions.php
<?php
myLinks();
if(isset($_GET["action"]){
// do your ordinary thing like open connection with database.
switch($_GET["action"]))
{
case "showsomething":
//show showsomething() function with html
break;
//further you can add more action instead of showsomething if you have several links
}
//close database.
}
?>
You need to separate your code else it will be a mess if it gets even more complicated. HTML code must be ONLY in showfunctions.php for example in function to call for actions.
Code is not tested but I think it will work. This code will also work without javascript but then it will just reload pages.
You have to use jQuery $.post() for that.
first You have to create php file which will process Your data.
For example lets create file query.php with the following content:
<?php
if(isset($_POST['telefon_Search'])) {
require 'connectdb.php';
$telefon_Search = $connect_DB->real_escape_string($_POST['telefon_Search']);
$sql = "SELECT * FROM elever WHERE Telefon = '$telefon_Search'";
$resultSet = $connect_DB->query($sql);
if($resultSet->num_rows > 0) {
$row = $resultSet->fetch_assoc();
echo json_encode($row);
}
}
next on Your page You have to create function which will send phone number to our query.php file and which will return Name and Surname if they exist.
$('#sjekkTelefon').click(function (){
$.post('query.php', { telefon_Search : $('#telefon_Input').val() }, function (data){
var user = $.parseJSON(data);
$('#check_Fornavn').val(user.Fornavn);
$('#check_Etternavn').val(user.Etternavn);
});
});
and complete html will looks like:
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" type="text/css" href="style2.css?<?php echo time(); ?>" />
<title></title>
</head>
<body>
<table id="telefon_tabell" class="bokssvar_tabell">
<tr>
<td>Telefon:</td>
</tr>
<tr>
<td><input type="text" name="telefon_Search" id="telefon_Input" maxlength=8"><br></td>
</tr>
<tr>
<td><button name ="btn_checkTelefon" id="sjekkTelefon">Sjekk</button></td>
</tr>
<div id="d1"></div>
</table>
<table id="opplysninger_tabell" class="bokssvartabell">
<tr>
<td>Fornavn:</td>
<td>Etternavn:</td>
</tr>
<tr>
<td><input type="text" name="Fornavn" disabled id="check_Fornavn"></td>
<td><input type="text" name="Etternavn" disabled id="check_Etternavn"></td>
</tr>
</table>
<script src="https://code.jquery.com/jquery-1.11.3.min.js"></script>
<script>
$('#sjekkTelefon').click(function (){
$.post('query.php', { telefon_Search : $('#telefon_Input').val() }, function (data){
$('#check_Fornavn').val(data.Fornavn);
$('#check_Etternavn').val(data.Etternavn);
});
});
</script>
</body>
</html>
Related
I'd like to get an interactive block in my page that onchange of one of the 3 search fields only reloads the div 'mydata' and reruns the query with a new filter. I know it probably can be done with ajax but i'm stuck in finding the right piece of code.
Here's my testcode
Main php file users2.php:
<head>
<title>Test</title>
<script src="../jquery-ui-1.12.1.custom/external/jquery/jquery.js"></script>
<script src="../jquery-ui-1.12.1.custom/jquery-ui.js"></script>
<script>
$.ready(function() {
// create the on change event
$('#search_name').on('change', function() {
// get the new information from the server
$.ajax({
url: 'users_functions2.php?id=' + $('#search_name').val(),
success: function(data){
// this code is run when you get the reply;
$('#mydata').html(data);
}
});
});
});
</script>
</head>
<body>
<?PHP
include '../conf/config.inc.php';
include 'users_functions2.php';
?>
</body>
And here the include file users_functions2.php:
<?php
echo "<div id='mydata'>";
echo "<table><tr><th>ID</th><th>Name</th><th>City</th></tr>";
echo "<tr>";
echo "<td><input type=text placeholder='search' name=search_id</td>";
echo "<td><input type=text placeholder='search' name=search_name</td>";
echo "<td><input type=text placeholder='search' name=search_city</td>";
echo "</tr>";
$sql="select id, name, city from users;";
if (isset($_GET['search_name'])) { $sql .= "WHERE vo_name LIKE \"%".$_GET['search_name']."%\""; }
$res = my_query($sql);
while($row = mysqli_fetch_array($res)) {
echo "<tr><td>".$row['id']."</td>";
echo "<td>".$row['name']."</td>";
echo "<td>".$row['city']."</td></tr>";
}
echo "</table>";
echo "</div>";
?>
Hope Chris is ok with this, i'd like my question being answered with a working example:
File 1:
<!DOCTYPE html>
<head>
<meta charset="utf-8">
<title>Test</title>
<script src="https://code.jquery.com/jquery-1.12.4.min.js" integrity="sha256-ZosEbRLbNQzLpnKIkEdrPv7lOy9C27hHQ+Xp8a4MxAQ=" crossorigin="anonymous"></script>
<script src="https://code.jquery.com/ui/1.12.0/jquery-ui.min.js" integrity="sha256-eGE6blurk5sHj+rmkfsGYeKyZx3M4bG+ZlFyA7Kns7E=" crossorigin="anonymous"></script>
<script>
$(document).ready(function() {
// create the on change event
$('#search_name').on('change', function() {
// get the new information from the server
$.ajax({
url: 'users_functions2.php?search_name=' + $('#search_name').val(),
success: function(data){
// this code is run when you get the reply;
$('#mydata').html(data);
}
});
});
});
</script>
</head>
<body>
<table>
<thead>
<tr>
<th>ID</th><th>Name</th><th>City</th>
</tr>
<tr>
<th><input type=text placeholder='search' name=search_id></th>
<th><input type=text placeholder='search' id='search_name' name=search_name></th>
<th><input type=text placeholder='search' name=search_city></th>
</tr>
</thead>
<tbody id="mydata">
<?PHP
include 'users_functions2.php';
?>
</tbody>
</table>
</div>
</body>
File 2:
<?php
include '../conf/config.inc.php';
$sql="SELECT id, `name`, city FROM users";
$search_name = filter_input(INPUT_GET, 'search_name');
if ($search_name) {
$sql .= " WHERE vo_name LIKE \"%$search_name%\"";
}
$res = my_query($sql);
while($row = mysqli_fetch_array($res)) {
extract($row);
echo "<tr><td>$id</td><td>$name</td><td>$city</td></tr>";
}
?>
I am not really good in coding, I need a help with my code. I have a code to search in a database. Now it's showing all the data on the database, when somebody search, it will filter out and show me result on the same table.I only want to show the result, when somebody search on the search bar, it should show me the filtered data. otherwise, my table should be hidden.
Can anybody please tell me how to do that. Thank you so much for your time.
<?php
if(isset($_POST['search']))
{
$valueToSearch = $_POST['valueToSearch'];
// search in all table columns
// using concat mysql function
$query = "SELECT * FROM `ADDRESS` WHERE CONCAT(`ID`, `STATE`) LIKE '%".$valueToSearch."%'";
$search_result = filterTable($query);
}
else {
$query = "SELECT * FROM `ADDRESS`";
$search_result = filterTable($query);
}
// function to connect and execute the query
function filterTable($query)
{
$connect = mysqli_connect("localhost:3306", "root", "dbadmin", "simplymac");
$filter_Result = mysqli_query($connect, $query);
return $filter_Result;
}
?>
<!DOCTYPE html>
<html>
<head>
<title>SimplyMac PO Tracking Tool</title>
<link rel="stylesheet" type="text/css" href="stylesheet.css">
<style>
</style>
</head>
<body>
<div class="images-wrapper">
<img class="Large" src="/dbadmin/Images/simplymac_logo.png" width="320" height="140" />
</div>
<form action="index.php" method="post">
<div class="wrap">
<center><h3>PO TRACKING TOOL</h3></center>
<center><table>
<tr>
<td><input type="text" name="valueToSearch" placeholder="Enter Purchase Order (PO#) Number" size="100" class="searchbar"></td>
<td><input type="submit" name="search" value="SEARCH" class="Button"></td>
</tr>
</table></center>
</div>
<table class="resultdata">
<tr>
<th>ID</th>
<th>ADDRESS_LINE_1</th>
<th>ADDRESS_LINE_2</th>
<th>CITY</th>
<th>STATE</th>
<th>ZIP</th>
</tr>
<?php while($row = mysqli_fetch_array($search_result)):?>
<tr>
<td><?php echo $row['ID'];?></td>
<td><?php echo $row['ADDRESS_LINE_1'];?></td>
<td><?php echo $row['ADDRESS_LINE_2'];?></td>
<td><?php echo $row['CITY'];?></td>
<td><?php echo $row['STATE'];?></td>
<td><?php echo $row['ZIP'];?></td>
</tr>
<?php endwhile;?>
</table>
</form>
</body>
</html>
You can use ajax for your problem.
When customer type in text box at that time call one java script function, in this function get text box value and call ajax for result table.
function getResult(search)
{
var file_path = '';//your php file path
$.ajax({
type: "POST",
url: file_path,
data: search,
cache: false,
success: function(result){
//print result in one div
}
});
}
<input type="submit" name="search" value="SEARCH" class="Button" onClick="getResult(this.value);">
My script fetchs and insert some data from db and displays to the user then I decied to slightly change my code and add some functionality.For example what if any of textbox is empty so that I have added a java script file that controls this sitituation.Bu I cant get the value of textboxes values from index .php file
this is index.php file
<?php
$records = array();
$db = new mysqli("localhost", "root", "", "app");
if (!empty($_POST)) {
$first = $_POST["first"];
$last = $_POST["last"];
$bio = $_POST["bio"];
$insert = $db->prepare("Insert into people (first,last,bio,created) values(?,?,?,NOW())");
$insert->bind_param("sss", $first, $last, $bio);
if ($insert->execute()) {
header("location: index.php");
}
}
if ($result = $db->query("select * from people")) {
if ($result->num_rows) {
while ($row = $result->fetch_object()) {
$records[] = $row;
}
$result->free();
}
} else {
$db->error;
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<script type="text/javascript" src="http://code.jquery.com/jquery-1.10.2.min.js"></script>
<script type="text/javascript" src="sites.js"></script>
<title>Title</title>
</head>
<body>
<?php
if (!count($records)) {
echo "no";
} else {
?>
<table>
<tr>
<td>First</td>
<td>Last</td>
<td>Bio</td>
<td>Created</td>
</tr>
<?php
foreach ($records as $r) {
?>
<tr>
<td><?php echo $r->first; ?></td>
<td><?php echo $r->last; ?></td>
<td><?php echo $r->bio; ?></td>
<td><?php echo $r->created; ?></td>
</tr>
<?php
}
?>
</table>
<?php
}
?>
and this is the html markup
<form action="" method="post">
First <input type="text" id="first"><br>
last <input type="text" id="last"><br>
Bio <input type="text" id="bio"><br>
<button id="submit" value="click me!!"></button>
</form>
</body>
</html>
I am trying to get inputs values from index file like this below But it doesnt work this way It returns object
$(document).ready(function () {
$('#submit').click(function () {
var name=$('#last');
alert(name);
});
});
thank in advance
When selecting an element with
$('#last')
you are getting the entire element in return. With that, you can use the val() method to retrieve the elements value:
var name = $('#last').val();
This will not return the value of name field:
var name=$('#last');
You can use like:
var name=$('#last').val();
Also note that, you are missing the name attribute in input fields. Without name attribute you can't get the value in $_POST.
You are referring to the object so you will get the object.
var name=$('#last');
If you need the value you have to ask for it:
var name=$('#last').val();
How Delete row in table html using ajax and php,
I need delete row in html table select row and click button delete make delete using ajax Currentally can make delete without ajax but I need delete row and stay on page without make submit on other page
code javaScript
function getDelete()
{
$.ajax({
type:"post",
//dataType:"json",
data:"id="+id,
url:"delete_address.php?id=$id", // url of php page where you are writing the query
success:function(json)
{
},
error:function(){
}
});
}
code html and php
<?php
$resualt=mssql_query("SELECT * FROM Address where user_id='$UserId' ") ;
echo "<table border='1' class='imagetable' id='imagetable'
width='400px' >\n";
echo '<thead>'.'<tr>';
echo '<th>Street</th>'.'<th>Quarter</th>'.
'<th>From</th>'.'<th>To</th>'.'<th>Notes</th>';
echo '</tr>'.'</thead>';
echo '<tbody>';
while ($row = mssql_fetch_assoc($resualt)) {
$fromDate=$row['from_date'];
$toDate=$row['to_date'];
echo " <tr onClick='myPopup($row[id])'".
( $_GET['id'] == $row['id'] ?
"style='background-color: green;'":"").">\n"."<td >
{$row['street']} </td>\n".
"<td>{$row['quarter']}</td>\n"."<td>$fdate2</td>\n".
"<td>$tdate2</td>\n"."<td>{$row['other_info']}</td>\n";
}
echo '</tbody>';
echo "</table>\n";
?>
<?php
echo"<a class='button-link' onClick='getDelete()'>delete</a>";
?>
code sql query
<?php
$idEmploye=$_GET['id'];
$userId=$_GET['user_id'];
$db_host = 'MOHAMMAD-PC\SQL2005';
$db_username = 'sa';
$db_password = '123321';
$db_name = 'db_test';
mssql_connect($db_host, $db_username, $db_password);
mssql_select_db($db_name);
mssql_query("DELETE FROM Address
WHERE id='$idEmploye' ; ") or die(mssql_error()) ;
echo '<script language="javascript">';
echo 'alert("successfully deleted ")';
echo '</script>';
echo "<script>setTimeout(\"location.href ='address.php';\",10); </script>";
?>
Any Help Very Thanks
Try this solution
HTML:
<table>
<tr>
<td>Username</td>
<td>Email</td>
<td>Action</td>
</tr>
<tr>
<td>TheHalfheart</td>
<td>TheHalfheart#gmail.com</td>
<td>
<input type="button" class="delete-btn" data-id="1" value="Delete"/>
</td>
</tr>
<tr>
<td>freetuts.net</td>
<td>freetuts.net#gmail.com</td>
<td>
<input type="button" class="delete-btn" data-id="2" value="Delete"/>
</td>
</tr>
</table>
We have two button's properties call data-id and class delete-btn
AJAX jQuery:
<script language="javascript">
$(document).ready(function(){
$('.delete-btn').click(function(){
// Confirm
if ( ! confirm('Are you sure want to delete this row?')){
return false;
}
// id need to delete
var id = $(this).attr('data-id');
// Current button
var obj = this;
// Delete by ajax request
$.ajax({
type : "post",
dataType : "text",
data : {
id : id
},
success : function(result){
result = $.trim(result);
if (result == 'OK'){
// Remove HTML row
$(obj).parent().parent().remove();
}
else{
alert('request fails');
}
}
});
});
});
</script>
In PHP:
Get the ID and delete
Reponse OK if success
Sorry i'm learning English, please fix if its bad
Im using ajax to load the testNew.php file into the Cart.html file. It loads the testNew.php file but when i click on the button add which is in the testNew.php, 0 is being entered in the database and as soon as i click on the add button the page refresh by itself. My problem is that i dont want the page to refresh and want the add button to do the same action as in the testNew.php file(which works correctly).
<script type='text/javascript' src='http://code.jquery.com/jquery-1.6.2.js'>
</script>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js">
</script>
<script>
$(document).ready(function() {
$("#product").click(function() {
$.ajax({ //create an ajax request to load_page.php
type: "GET",
url: "testNew.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
//alert(response);
}
});
});
});
</script>
</head>
<body>
<table border="1">
<tr>
<td>
<input type="button" id="product" name="product"value="View all products"/>
</td>
</tr>
</table>
<div id="responsecontainer"></div>
Here is the testNew.php which works correctly.
<?php
include'connect.php';
$image = isset($_REQUEST['image']) ? $_REQUEST['image'] : "";
$id = isset($_REQUEST['id']) ? $_REQUEST['id'] : "";
$name = isset($_REQUEST['name']) ? $_REQUEST['name'] : "";
$price= isset($_REQUEST['price']) ? $_REQUEST['price'] : "";
$sql="SELECT * FROM product";
$result = mysql_query($sql);
if($result>0){
?>
<table border='1'>
<tr>
<th>Id</th>
<th>Image</th>
<th>Name</th>
<th>Price MUR</th>
</tr>
<?php
while ($row = mysql_fetch_array($result)){
?>
<tr>
<td><?php echo ($row['id']); ?></td>
<td><img src=<?php echo $row['image'] ?> width='120'
height='100'/></td>
<td><?php echo htmlspecialchars($row['name']); ?></td>
<td><?php echo htmlspecialchars($row['price']); ?></td>
<td>
<form method="POST" action="" >
<input type="hidden" name="id" value="<?php echo $row['id']; ?>" />
<input type="hidden" name="name" value="<?php echo $row['name']; ?>" />
<input type="hidden" name="image" value="<?php echo $row['image']; ?>" />
<input type="hidden" name="price" value="<?php echo $row['price']; ?>" />
<input id="submit" type="submit" name="submit" value='Add to cart'
onclick="add()"/>
</form>
</td>
</tr>
<?php
}
?>
</table>
<?php
}
$insert = "INSERT INTO product_add(id, name, price) VALUES ('$id', '$name','$price')";
$insertQuery=mysql_query($insert);
?>
Your error in thought is actually that you are including a form through AJAX of which the HTML is then loaded into your page after which the action attribute on the form refers to the page itself (loading HTML into your page with AJAX does not work the same as an iframe) which does not have the relevant code to actually parse and insert the database.
You need to make a separate page that only accepts a few parameters and inserts those into the database. However, before you do that you need to read this:
I'm going to go off on the safety of your code for a tad.
$_REQUEST refers to both $_GET and $_POST, you really want only $_POST as you just want to deal with what gets submitted through a form.
You never sanitize your input, this way a person could craft an URL with say phpNew.php?id='; DROP TABLE wooptiedoo. This is a simplified example but nevertheless you should take a closer look at the mysql_real_escape_string documentation and possibly some guides on "sql injection".
After that those same variables can be used for XSS which means someone can use your page to serve random HTML to people visiting that site and trusting your domain. I suggest you look up the htmlentities function and/or read up on "cross-site scripting" attacks.
And to end it all, the mysql_* functions are deprecated and you should probably be using mysqli_* functions.