es6 call class methods from within same class - javascript

I'm trying to call a class method in my class form a neighboring method as shown in the example below.
import blah from './blaha';
export default class myclass{
constructor(con) {
this.config = con;
}
async meth1(paramA) {
//do_stuff...
}
meth2(paramB) {
//attempt to call meth1()
}
}
I would like to call a method from within a different method using es6 class styles.

Use this
import blah from './blaha';
export default class myclass{
constructor(con) {
this.config = con;
}
async meth1(paramA) {
//do_stuff...
}
meth2(paramB) {
this.meth1()
}
}

Related

Should I new a utils class in es6?

I have declared a class, like:
export default class Utils {
static deepClone(): object {
return {}
}
}
so when I want to use deepClone, I can:
// First One
import Utils from './Utils';
export default class Element {
constructor(){
this.utils = new Utils()
}
create(){
return this.utils.deepClone()
}
}
or:
// Second One
import Utils from './Utils';
export default class Element {
constructor(){
this.utils = Utils
// this is an optional
// in my child class I need't to import Utils
// I can use this.utils.deepClone() directly
}
create(){
return Utils.deepClone()
}
}
I wonder which is a better way to imply Element class
Looking forward to your reply, I can’t thank you enough
The second way is more correct but it has a problem that you should create an instance of Utils class to use each property which isn't a static method.
The output of a class that you didn't create an instance is a function instead of an object of prototypes.
./Utils.js
export default class Utils {
static deepClone(): object {
return {}
}
public deepExtend() {
// deepClone code
}
}
Use in another file:
import Utils from './Utils';
export default class Element {
constructor(){
this.utils = new Utils();
}
create(){
return Utils.deepClone()
}
extend(){
return this.utils.deepExtend()
}
}
I would return export new of the Utils and I will pass it in the constructor of your Element as an Instance, something like:
IUtils = someInterface;
export default class Element {
constructor(utils: IUtils){
this.utils = utils;
}
create(){
return this.utils.deepClone()
}
}
In these way it:
Doesn't create new instances for nothing
Uses other instances that you can pass to your Element class
Is testable

How to have a Class.SubClass.SomeMethod structure?

This is my main class (it uses a subclass:)
import SubClass from './SubClass'
class MainClass extends classes(SubClass) {
constructor () {
// some code
}
}
window.MainClass = new MainClass()
export default MainClass
This is the subclass:
class SubClass {
constructor () {
this.someMethod = function () {
// some code
}
}
}
export default SubClass
If I want to use a method from the SubClass I can write: MainClass.someMethod.
How to modify this code so I write: MainClass.SubClass.someMethod instead?
So I can write:
MainClass.SubClass.someMethod
MainClass.SubClass2.someMethod
In case I need another SubClass?
I think you need to call super(). And classes() seem doen't need to be added.
When used in a constructor, the super keyword appears alone and must be used before the this keyword is used.
See document
import SubClass from './SubClass'
class MainClass extends SubClass {
constructor () {
super();
console.log(this.someMethod)
}
}
Hope this help

How to extend the two classes in Typescript

I need to extend the two classes from the same namespace.
for ex:
declare namespace myNameSpace{
class class1{
///some methods will be here
}
class class3 extends class1{
//some method wil be here
}
class class2 extends myNameSpace. class3 {
//some methods will be here
}
export namespace class2 {
//declaration will be here
}
}
i need to extend the 'myNameSpace.class1' class as well as 'class2' namespace.
class newClass extends myNameSpace.class1, myNameSpace.class2 {
constructor() {
super();
}
}
If i call the both the classes, i got an error message
classes can only extend a single class
Is there any other way to fix this issue in typescript.
Is there any other way to fix this issue in typescript.
TypeScript is single inheritance by design.
You can use mixins but you can't override methods (unless you write a custom applyMixins methods)
Using the method:
function applyMixins(derivedCtor: any, baseCtors: any[]) {
baseCtors.forEach(baseCtor => {
Object.getOwnPropertyNames(baseCtor.prototype).forEach(name => {
derivedCtor.prototype[name] = baseCtor.prototype[name];
});
});
}
You have to implement (on empty way)
class NewClass implements myNameSpace.class1, myNameSpace.class2 {
// empty implementation
public methodFrom1 : ()=>void;
public methodFrom2 : ()=>number;
constructor() {
// no super()
}
}
now use mixing to actually make it multi extend classes:
applyMixins(NewClass, [myNameSpace.class1, myNameSpace.class2]);
and now you can create the class
const foo = new NewClass()
foo.methodFrom1() // actually calls nameSpace.class1.prototype.methodFrom1

Typescript - Calling a class exported from another file.

I have a file called searchBar.ts in which contains a init() function that I wish to call in a file called index.ts.
My searchBar.ts file looks like this:
class searchBar {
init() {
console.log('work you C*&*T')
}
}
export let searchBarClass = new searchBar;
I then want to be able to call this function in index.ts. I am currently trying to do this with the below code but init is never found with my intellisense:
import { searchBarClass } from './modules/searchBar';
class Main {
searchBarClass.init()
}
let main = new Main();
export {main}
Later on I then want to wrap the function in a global function that I'll call in the HTML file.
Let me know your thoughts
If you want to export a class and call the init() method on the object instance:
export class SearchBar {
init() {
console.log('work you C*&*T')
}
}
Then accessing it from another file:
import { SearchBar } from './modules/searchBar';
export class Main {
constructor() {
let searchBar = new SearchBar();
searchBar.init();
}
}
let main = new Main();
If you want to access the init() function statically:
export class SearchBar {
static init() {
console.log('work you C*&*T')
}
}
Then accessing it from another file:
import { SearchBar } from './modules/searchBar';
export class Main {
constructor() {
SearchBar.init();
}
}
let main = new Main();

How to inherit from existing AMD js class in TypeScript compilng to AMD module?

I did try the following:
class Child {
public func() {
alert("hello");
}
constructor() {
Parent.apply(this, arguments);
}
}
Child["prototype"] = Object.create(Parent.prototype)
Child["prototype"].constructor = Child;
but the instance of the Child class doesn't have func() method.
How to do inheritance from js class?
General case
Just use declare in order to declare an existing class.
declare class Parent { // produces no JS code
constructor(val);
}
class Child extends Parent {
constructor(val) {
super(val);
}
}
Case of an external module (AMD)
The external module has to be described in a definition file .d.ts.
File ContainerSurface.d.ts:
declare class ContainerSurface {
constructor(options);
}
export = ContainerSurface;
How to use it:
import ContainerSurface = require('ContainerSurface');
class Child extends ContainerSurface {
constructor(options) {
super(options);
}
}

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