Use ajax to display a form depending on an input - javascript

I've designed a website using wordpress, - On my site I want to show a booking system which is organised by postcode (So I stay in the same area on the various days).
I've written some php code which allows me to input a postcode, it then removes any whitespace and removes the last 3 characters. Whats left is checked against a list of postcodes and depending on what the postcode is, it displays different forms...
this is the code:
<?php
$postcode = $_POST['postcode'];
$postcode = preg_replace('/\s+/', '', $postcode);
$postcode = substr($postcode, 0, -3);
if(in_array($postcode, array("NR1", "NR2", "NR3", "NR4", "NR5", "NR6", "NR7", "NR8", "NR9", "NR19", "NR20"))){
?>
[bookly-form staff_member_id="2" hide="staff_members,date,week_days,time_range"]
<?php
} elseif(in_array($postcode, array("NR10", "NR11", "NR12", "NR26", "NR27", "NR28"))) {
?>
[bookly-form staff_member_id="3" hide="staff_members,date,week_days,time_range"]
<?php
} elseif(in_array($postcode, array("NR13", "NR14", "NR15", "NR29", "NR30", "NR31", "NR32", "NR33", "NR34", "NR35", "IP18", "IP19", "IP20", "IP21", "IP22"))) {
?>
[bookly-form staff_member_id="4" hide="staff_members,date,week_days,time_range"]
<?php
} else {
?>
Thank you for enquiring about our microchipping services. Unfortunatly we don't cover your postcode at the moment.
If you'd like to know when we do cover your area simply fill out the form below or feel free to call our offices to register your details
[ccf_form id="57"]
<?php
}
?>
Considering this is in wordpress, I can use a php plugin to either call the code etc and manually code the form in html - but how would I get this to run through ajax so that I do not need to submit the page etc... I don't want the page to refresh - I just want the content to swap.

Initial form for postcode in your html file:
<form id="form" action="" method="post">
<input type="text" id="postcode" name="postcode" value="" />
<button type="submit">Submit</button>
</form>;
<div id="return-wrap"></div>
On submit serialize data for sending. ( console.log(); is for debugging and you can see result in browsers console )
jQuery(document).ready(function ($) {
$('#form').on('submit', function (e) {
e.preventDefault();
$.ajax({
url: 'ajax.php',
type: 'POST',
data: $(this).serialize(),
dataType: 'json',
beforeSend: function () {
},
success: function (data, textStatus, xhr) {
console.log(data);
console.log(data.status);
$('#return-wrap').html(data.result);
},
error: function (xhr, textStatus, errorThrown) {
console.log(textStatus);
console.log(errorThrown);
console.log(data.status);
}
});
});
});
And then access data in php like you would access any other post data
if($_POST){
$template = $_POST['postcode'];
/** Do whatever with this data */
$form = '';
echo json_encode(array('status' => 'ok', 'result' => $form));
} else {
echo json_encode(array('status' => 'error'));
}

Related

How to obtain response from form submitted by AJAX?

I want to use Acymailing Joomla! component installed at example.com/mailer to manage subscriptions from non Joomla site on example.com
In that case I have simple script
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'https://example.com/mailer/index.php?option=com_acymailing&ctrl=sub',
data: $('form').serialize(),
success: function () {
swal('Great success!');
}
});
});
});
and form
<form class="form-inline" action="https://example.com/mailer/index.php?option=com_acymailing&ctrl=sub" method="post">
<div class="form-group">
<label class="sr-only" for="user_name">Email address</label>
<input id="user_name" type="text" name="user[name]" value="" class="form-control" placeholder="Email">
</div>
<div class="form-group">
<label class="sr-only" for="user_email">Password</label>
<input id="user_email" type="text" name="user[email]" value="" class="form-control" placeholder="Password">
</div>
<button type="submit" class="btn btn-default">Sign Up!</button>
<input type="hidden" name="user[html]" value="1" />
<input type="hidden" name="acyformname" value="formAcymailing1" />
<input type="hidden" name="ctrl" value="sub"/>
<input type="hidden" name="task" value="optin"/>
<input type="hidden" name="redirect" value="https://example.com"/>
<input type="hidden" name="option" value="com_acymailing"/>
<input type="hidden" name="visiblelists" value=""/>
<input type="hidden" name="hiddenlists" value="1"/>
</form>
Everything works fine except success, error states...
Joomla Acymailing have sub.php file to handle ajax responses
if($config->get('subscription_message',1) || $ajax){
if($allowSubscriptionModifications){
if($statusAdd == 2){
if($userClass->confirmationSentSuccess){
$msg = 'CONFIRMATION_SENT';
$code = 2;
$msgtype = 'success';
}else{
$msg = $userClass->confirmationSentError;
$code = 7;
$msgtype = 'error';
}
}else{
if($insertMessage){
$msg = 'SUBSCRIPTION_OK';
$code = 3;
$msgtype = 'success';
}elseif($updateMessage){
$msg = 'SUBSCRIPTION_UPDATED_OK';
$code = 4;
$msgtype = 'success';
}else{
$msg = 'ALREADY_SUBSCRIBED';
$code = 5;
$msgtype = 'success';
}
}
}else{
if($modifySubscriptionSuccess){
$msg = 'IDENTIFICATION_SENT';
$code = 6;
$msgtype = 'warning';
}else{
$msg = $modifySubscriptionError;
$code = 8;
$msgtype = 'error';
}
}
if($msg == strtoupper($msg)){
$source = acymailing_getVar('cmd', 'acy_source');
if(strpos($source, 'module_') !== false){
$moduleId = '_'.strtoupper($source);
if(acymailing_translation($msg.$moduleId) != $msg.$moduleId) $msg = $msg.$moduleId;
}
$msg = acymailing_translation($msg);
}
$replace = array();
$replace['{list:name}'] = '';
foreach($myuser as $oneProp => $oneVal){
$replace['{user:'.$oneProp.'}'] = $oneVal;
}
$msg = str_replace(array_keys($replace),$replace,$msg);
if($config->get('redirect_tags', 0) == 1) $redirectUrl = str_replace(array_keys($replace),$replace,$redirectUrl);
if($ajax){
$msg = str_replace(array("\n","\r",'"','\\'),array(' ',' ',"'",'\\\\'),$msg);
echo '{"message":"'.$msg.'","type":"'.($msgtype == 'warning' ? 'success' : $msgtype).'","code":"'.$code.'"}';
}elseif(empty($redirectUrl)){
acymailing_enqueueMessage($msg,$msgtype == 'success' ? 'info' : $msgtype);
}else{
if(strlen($msg)>0){
if($msgtype == 'success') acymailing_enqueueMessage($msg);
elseif($msgtype == 'warning') acymailing_enqueueMessage($msg,'notice');
else acymailing_enqueueMessage($msg,'error');
}
}
}
And JSON looks like on Joomla side registration to the same form by index.php?option=com_acymailing&ctrl=sub
message Subscribe confirmed
type success
code 3
{"message":"Subscribe confirmed","type":"success","code":"3"}
The question is: how to obtain that submission statuses success, error, already submbited etc on external submission form (at example.com page)?
this simple change may do it for you:
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'https://example.com/mailer/index.php?option=com_acymailing&ctrl=sub',
data: $('form').serialize()
}
}).done(function (data) {
swal('Great success!');
});
});
});
I personally like:
$.post("https://example.com...", {
data: $('form').serialize()
}, function(data) {
swal('Great success!');
});
since your result is in JSON, that should be more like:
$.post("https://example.com...", {
data: $('form').serialize()
}, function(data) {
console.log(data); // shows full return object in console
swal('Great success!');
}, "json");
Try the following, I have explained the changes inside comments:
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
var formdata = $(this).serializeArray(); //i really prefer serializeArray better than serialize (up2u)
$.ajax({
type: 'post',
dataType: 'json', //because your data is json
url: 'https://example.com/mailer/index.php?option=com_acymailing&ctrl=sub',
data: formdata,
success: function (d) {//d is the return/response of your url (your question answer)
swal(
d.type+': '+d.code ,
d.message,
d.type
);
},
error: function(d){
swal(
'Oops..' ,
'Something went wrong!', //your json must be in trouble
'error'
);
console.log(d); //delete this in production stage
console.log(d.responseText); //i add this so you will know what happenned exactly when you get this error. delete this too in production stage
}
});
});
});
I don't feel your ajax had issues, what i can see from the Joomla php code, everytime when you request that joomla URL you will always get a response header status code as 200, so your javascript will always land on success block of ajax code, returning with some json based message, when i checked the joomla acymaling (version 5.8.1 for joomla 3.8.3) code for that controller, i saw on line number 74 they are checking if the request is made using ajax, but missing Access-Control-Allow-Origin in php header which will restrict your outside call so you can replace this if condition from :
if($ajax){
#ob_end_clean();
header("Content-type:text/html; charset=utf-8");
}
to
if($ajax){
#ob_end_clean();
header("Content-type:text/html; charset=utf-8");
header("Access-Control-Allow-Origin: *");
}
so to allow calls from any other domain as well, but do remember this can also cause vulnerabilities to you joomla code. also you need to change your HTML form as well add one more hidden field in your HTML :
<input type="hidden" name="ajax" value="1" />
so to allow ajax request by your joomla controller file.
now in your success block of ajax you can make a check something like this :
success:function(data, status, xhr){
var json = $.parseJSON(data);
swal(json.message, json.type);
}
I hope this will help you in acomplishing what you want to, Happy coding.
I also face this type of problem.for solving this type of problem i Put a variable in the success as argument html.
e.g. success(html)
and
console.log(html)
this shows all errors including notices and all. turn on errore_reporting['E_ALL'];. and do not set dataType to 'json' .
Simple solution to your question is :
success: function (data) {
$("#<id_of_tag>").html(data);
}
data : Response returned from the server to your AJAX call
id_of_tag : where you want to display your returned output.
Its just an example, you can decide, what kind of data you want to return and what you want to do with your response.
To answer your question: On Success parameter in function will contain your response.
As in my case, i am returning another JSP page, which i want to display in div tag.
Also check below link : I think it might help you
Best way to check if AJAX request was successful in jQuery

Get and display results of PHP using jQuery/AJAX

I have a Leaflet map, and a text input. I want to take the address from the textbox, run it through a PHP script, and get the result all through jQuery.
Here is my form:
<form id="mapcheck" method="POST" action="geo.php">
<input id="largetxt" type="text" name="checkAddress">
<input id="button" type="submit" name="submit" value="Check">
</form>
Here is part of the PHP:
<?php
if (isset($_POST["checkAddress"])) { //Checks if action value exists
$checkAddress = $_POST["checkAddress"];
$plus = str_replace(" ", "+", $checkAddress);
$json = file_get_contents('https://maps.googleapis.com/maps/api/geocode/json?address=' . $plus . '&key=GMAPSKEY');
$obj = json_decode($json);
$mapLat = $obj->results[0]->geometry->location->lat;
$mapLng = $obj->results[0]->geometry->location->lng;
$coords = ('' . $mapLat . ', ' . $mapLng . '');
return $coords;
}
?>
And the jQuery:
$(document).ready(function() {
$("#button").click(function(){
$.ajax({
url: "geo.php",
method: "POST",
data: {
checkAddress: $("#largetxt").val()
},
success: function(response){
console.log(response);
}
});
});
});
I need to listen on submit of the form via jQuery (NOT PHP), run it through a geocode script, then take that result and put it through regular JavaScript (Leaflet map.) I have played around with the AJAX feature of jQuery to no avail. There is a very simple solution to this, but I have not figured it out.
UPDATE: Problem resolved, thanks Vic.
You would need AJAX. Remove the form element but keep the inputs.
$("#button").click(function(){
$.ajax({
url: "geo.php",
method: "POST",
data: {
checkAddress: $("#largeText").val()
},
success: function(response){
console.log(response);
//your script
}
})
});

run full php-script in ajax/jquery

Sorry for my bad english. I'm trying to run a PHP function through an ajax script. The PHP script should run as a FULL NORMAL php script. My idea is to run a recaptcha by a Submit button WITHOUT refreshing the page. That is working, but I found no way to run a normal php script after that. Here is the part of my script.
php:
if( isset( $_REQUEST['startattack'] )){
$secret="********************";
$response=$_POST["g-recaptcha-response"];
$verify=file_get_contents("https://www.google.com/recaptcha/api/siteverify?secret={$secret}&response={$response}");
$captcha_success=json_decode($verify);
if ($captcha_success->success==false) {
echo "<script type='text/javascript'>alert('failed!')</script>";
} else if ($captcha_success->success==true) {
echo "<script type='text/javascript'>alert('success!')</script>";
}
}
html:
<form method='post' id="myform">
<center>
<div class="g-recaptcha" data-sitekey="6LfETygTAAAAAMC7bQu5A3ZhlPv2KBrh8zIo_Nwa"></div>
</center>
<button type="submit" id="startattack" name="startattack" onclick="mycall()" class="btn btn-attack">Start Attack</button>
</form>
ajax:
<script>
$(function () {
$('button').bind('click', function (event) {
$.ajax({
type: 'POST',
url: 'post.php',
data: $('button').serialize(),
success: function () {
alert('button was submitted');
type: 'post';
url: 'post.php';
}
});
event.preventDefault();// using this page stop being refreshing
});
});
</script>
I want to check the recaptcha here. If correct, it should echo correct in PHP and I want to add feature later. The same with the false captcha.
I think you can simplify things a bit. You don't return the response in the Ajax is your main problem.
PHP:
Just echo the returned json from the recaptcha (although I have no idea where you get the g-recaptcha-response key/value, you are not sending it anywhere).
if(isset( $_POST['startattack'] )){
$secret = "********************";
// I have added a key/value in the ajax called "sitekey",
// this might be what you are trying to retrieve?
$response = $_POST["g-recaptcha-response"];
echo file_get_contents("https://www.google.com/recaptcha/api/siteverify?secret={$secret}&response={$response}");
exit;
}
AJAX:
I think since the return from the recaptcha is json anyway, just echo it and pick it up on this side:
$(function () {
$('button').bind('click', function (event) {
var statusBlock = $('#status');
statusBlock.text('button was submitted');
$.ajax({
type: 'POST',
url: 'post.php',
data: {
// Not sure if you are trying to pass this key or not...
"sitekey":$('.g-recaptcha').data('sitekey'),
"startattack":true
},
success: function (response) {
var decode = JSON.parse(response);
var alertMsg = (decode.success)? 'Success' : 'Failed';
statusBlock.text('');
alert(alertMsg);
}
});
// using this page stop being refreshing
event.preventDefault();
});
});
Form:
Leave a spot to post the submit status so it doesn't interfere with the return alert dialog window.
<form method='post' id="myform">
<div id="status"></div>
<center>
<div class="g-recaptcha" data-sitekey="6LfETygTAAAAAMC7bQu5A3ZhlPv2KBrh8zIo_Nwa"></div>
</center>
<button type="submit" id="startattack" name="startattack" onclick="mycall()" class="btn btn-attack">Start Attack</button>
</form>

Retrieving data value from database from ajax function

I have a ajax function that would retrieve data from my database and display it in my textbox. I am using a JQuery Form Plugin to shorten the ajax process a little bit. Now what I want to do is to get the data back from the php script that I called from the ajax function.
The form markup is:
<form action="searchFunction.php" method="post" id="searchForm">
<input type="text" name="searchStudent" id="searchStudent" class="searchTextbox" />
<input type="submit" name="Search" id="Search" value="Search" class="searchButton" />
</form>
Server code in searchFunction.php
$cardid = $_POST['searchStudent'] ;
$cardid = mysql_real_escape_string($cardid);
$sql = mysql_query("SELECT * FROM `users` WHERE `card_id` = '$cardid'") or trigger_error(mysql_error().$sql);
$row = mysql_fetch_assoc($sql);
return $row;
The ajax script that processes the php is
$(document).ready(function() {
$('#searchForm').ajaxForm({
dataType: 'json',
success: processSearch
});
});
function processSearch(data) {
alert(data['username']); //Am I doing it right here?
}
In PHP, if I want to call the data, I would just simply create a function for the database and just for example echo $row['username'] it. But how do I do this with ajax? I'm fairly new to this so, please explain the process.
$('#Search').click(function (e) {
e.preventDefault(); // <------------------ stop default behaviour of button
var element = this;
$.ajax({
url: "/<SolutionName>/<MethodName>",
type: "POST",
data: JSON.stringify({ 'Options': someData}),
dataType: "json",
traditional: true,
contentType: "application/json; charset=utf-8",
error: function () {
alert('Unable to load feed, Incorrect path or invalid feed');
},
success: processSearch,
});
});
function processSearch(data) {
var username= ($(data).find('#username'));
}
Change the input type submit to button. Submit will trigger the action in the form so the form will get reloaded. if you are performing an ajax call change it into button.
Everything seems to be fine, except this bit -
function processSearch(data) {
alert(data['username']); //Am I doing it right here?
}
You need to change it to -
function processSearch(data) {
// data is a JSON object. Need to access it with dot notation
alert(data.username);
}
UPDATE
You also need to return a JSON response from your PHP file. Something like -
// Set the Content Type to JSON
header('Content-Type: application/json');
$data = [
"key" => "value"
];
return json_encode($data);
In your case you can directly encode the $row like so -
return json_encode($row);

Enter ID in html form and load related data from MySQL database in same page

I have a form with an input field for a userID. Based on the entered UID I want to load data on the same page related to that userID when the user clicks btnLoad. The data is stored in a MySQL database. I tried several approaches, but I can't manage to make it work. The problem is not fetching the data from the database, but getting the value from the input field into my php script to use in my statement/query.
What I did so far:
I have a form with input field txtTest and a button btnLoad to trigger an ajax call that launches the php script and pass the value of txtTest.
I have a div on the same page in which the result of the php script will be echoed.
When I click the button, nothing happens...
Test.html
<script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script>
<script type="text/javascript" src="http://ajax.microsoft.com/ajax/jquery.validate/1.7/jquery.validate.min.js"></script>
<script>
//AJAX CALL
function fireAjax(){
$.ajax({
url:"testpassvariable.php",
type:"POST",
data:{userID:$("#txtTest").val(),},
success: function (response){
$('#testDiv').html(response);
}
});
}
</script>
</head>
<body>
<form name="testForm" id="testForm" action="" method="post" enctype="application/x-www-form-urlencoded">
<input type="text" name="txtTest" id="txtTest"/>
<input type="button" id="btnLoad" name="btnLoad" onclick="fireAjax();"
<input type="submit" name="SubmitButton" id="SubmitButton" value="TEST"/>
</form>
<div id="testDiv" name="testDiv">
</div>
</body>
The submit button is to insert updated data into the DB. I know I have to add the "action". But I leave it out at this point to focus on my current problem.
testpassvariable.php
<?php
$player = $_POST['userID'];
echo $player;
?>
For the purpose of this script (testing if I can pass a value to php and return it in the current page), I left all script related to fetching data from the DB out.
As the documentation says 'A page can't be manipulated safely until the document is ready.' Try this:
<script>
$(document).ready(function(){
//AJAX CALL
function fireAjax(){
$.ajax({
url:"testpassvariable.php",
type:"POST",
data:{userID:$("#txtTest").val(),},
success: function (response){
$('#testDiv').html(response);
}
});
}
});
</script>
You need to correct two things:
1) Need to add $(document).ready().
When you include jQuery in your page, it automatically traverses through all HTML elements (forms, form elements, images, etc...) and binds them.
So that we can fire any event of them further.
If you do not include $(document).ready(), this traversing will not be done, thus no events will be fired.
Corrected Code:
<script>
$(document).ready(function(){
//AJAX CALL
function fireAjax(){
$.ajax({
url:"testpassvariable.php",
type:"POST",
data:{userID:$("#txtTest").val(),},
success: function (response){
$('#testDiv').html(response);
}
});
}
});
</script>
$(document).ready() can also be written as:
$(function(){
// Your code
});
2) The button's HTML is improper:
Change:
<input type="button" id="btnLoad" name="btnLoad" onclick="fireAjax();"
To:
<input type="button" id="btnLoad" name="btnLoad" onclick="fireAjax();"/>
$.ajax({
url: "testpassvariable.php",
type: "POST",
data: {
userID: $("#txtTest").val(),
},
dataType: text, //<-add
success: function (response) {
$('#testDiv').html(response);
}
});
add dataType:text, you should be ok.
You need to specify the response from the php page since you are returning a string you should expect a string. Adding dataType: text tells ajax that you are expecting text response from php
This is very basic but should see you through.
Change
<input type="button" id="btnLoad" name="btnLoad" onclick="fireAjax();"/>
Change AJAX to pass JSON Array.
data = $(this).serialize() + "&" + $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "action.php",
data: data,
....
// action.php
header('Content-type: application/json; charset=utf-8');
echo json_encode(array(
'a' => $b[5]
));
//Connect to DB
$db = mysql_connect("localhst","user","pass") or die("Database Error");
mysql_select_db("db_name",$db);
//Get ID from request
$id = isset($_GET['id']) ? (int)$_GET['id'] : 0;
//Check id is valid
if($id > 0)
{
//Query the DB
$resource = mysql_query("SELECT * FROM table WHERE id = " . $id);
if($resource === false)
{
die("Database Error");
}
if(mysql_num_rows($resource) == 0)
{
die("No User Exists");
}
$user = mysql_fetch_assoc($resource);
echo "Hello User, your number is" . $user['number'];
}
try this:- for more info go here
$(document).ready(function(){
$("#btnLoad").click(function(){
$.post({"testpassvariable.php",{{'userID':$("#txtTest").val()},function(response){
$('#testDiv').html(response);
}
});
});
});
and i think that the error is here:-(you wrote it like this)
data:{userID:$("#txtTest").val(),}
but it should be like this:-
data:{userID:$("#txtTest").val()}
happy coding :-)

Categories