Don't print root element of ng-repeat [closed] - javascript

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HTML:
<div ng-repeat="bill in data.budget.bills" class="ngDailyAmount"></div>
How do I suppress the div tag from outputting to the browser. I only want my directive html to show - not the parent div.

As others pointed out, you can use replace: true to achieve what you spect. But it is a deprecated feature and might cause some issues in newer versions of angular, as a deprecated feature there is no support for it. Just try to adjust your code to the no replacing way.

To substitute the root element on the directive you can use replace:true option

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Change Text in IFrame without JQuery [closed]

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Weave: http://kodeweave.sourceforge.net/editor/#f6d9a54288f17fb68a8b234ec364dc41
I love JQuery, I do, but just for fun I'd like to learn how to write the following in pure/vanilla JS.
$("iframe").contents().find("<style>").html(cssEditor.value))
Something like this should work:
document
.getElementsByTagName('iframe')[0]
.contentDocument
.getElementsByTagName('style')[0]
.innerHTML = cssEditor.value;
Use the contentDocument property of the <iframe> DOM object to get the inner document.
You can then call normal methods on it like querySelector.

Invert everything on page except imges [closed]

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Hi I'm trying to invert everything on the page except for images? Any help will be appreciated. Thanks.
http://jsfiddle.net/nikita_turing/jVKw6/3/
Bookmarklet
If you can use jQuery, use the pseudo selector :not(img) to select all the elements except images, then set the CSS you want.
Something like
$(":not(img)").css({"-webkit-filter": "invert(100%)","-moz-filter": "invert(100%)","-o-filter": "invert(100%)","-ms-filter": "invert(100%)"});
There are can be two different solutions. Maybe not the best.
The first, Find all images
Then invert elements and invert images back to the first condition.
The second, using jQuery get all img elements and do the same work as in the previous idea.

how can position element like this? [closed]

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in the link below in the bottom of page we see some box that aligned with the javascript or jquery,and they are not in the same row. this can't be done with css.
and when the page width change they realigned with smomth animation.
any body know how to do that? is there any video to teach this technic?
http://esam.ir/itemView.aspx/562755/%D9%81%D8%B1%D9%88%D8%B4-%DA%AF%DB%8C%D8%AA%D8%A7%D8%B1-%DA%A9%D9%84%D8%A7%D8%B3%DB%8C%DA%A9-%D8%A7%DB%8C%D8%B1%D8%A7%D9%86%DB%8C.htm
thanks
There is an easy library called Masonry, have a look at that, they have some decent documentation and it works exactly like you want it. But going into the details of how its done is beyond the scope of a stack overflow post.
http://masonry.desandro.com

Using CSS in JS [closed]

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I am trying to change CSS elements depending on situations used in javascript.
an example I had tried was:
if ('image'=="clicked")
{blahblahblah}
'image' would be my div id or div tag in CSS.
I know in Jquery I can use $('#image').click, but I don't think it Jquery will be good for my situation.
Consider document.querySelector. It's powerful, accepting any valid CSS selector. You can even start from another element, such as myElement.querySelector, to only get children of that element that match the selector. Very useful!
Just be aware that IE7 and below do not support this function.
Assuming your id as image
document.getElementById('image').onclick = function() {
alert("button was clicked");
}​;​

See all select options on fullscreen using jQuery/JS [closed]

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I want when I click in the select, I see all options on full screen.
I have an example in this link.(By choosing the state)
Note : I don't want to use jQuery mobile.
It's been a few hours I'm looking for this feature, but unfortunately I can not find any result.
Thank you.
Try this plugin, and just set the maxHieght and menuWidth properties to the page size. I would use a dynamic calculation, to determine current pages coordinates, then plugin them into the plugins properties. Plugin can be found here: https://github.com/fnagel/jquery-ui/wiki/Selectmenu. Hopefully this will help you out. Happy coding!

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