I have an array of objects. I want to find by some field, and then to change it:
var item = {...}
var items = [{id:2}, {id:2}, {id:2}];
var foundItem = items.find(x => x.id == item.id);
foundItem = item;
I want it to change the original object. How? (I don't care if it will be in Lodash too.)
You can use findIndex to find the index in the array of the object and replace it as required:
var item = {...}
var items = [{id:2}, {id:2}, {id:2}];
var foundIndex = items.findIndex(x => x.id == item.id);
items[foundIndex] = item;
This assumes unique IDs. If your IDs are duplicated (as in your example), it's probably better if you use forEach:
items.forEach((element, index) => {
if(element.id === item.id) {
items[index] = item;
}
});
My best approach is:
var item = {...}
var items = [{id:2}, {id:2}, {id:2}];
items[items.findIndex(el => el.id === item.id)] = item;
Reference for findIndex
And in case you don't want to replace with new object, but instead to copy the fields of item, you can use Object.assign:
Object.assign(items[items.findIndex(el => el.id === item.id)], item)
as an alternative with .map():
Object.assign(items, items.map(el => el.id === item.id? item : el))
Functional approach:
Don't modify the array, use a new one, so you don't generate side effects
const updatedItems = items.map(el => el.id === item.id ? item : el)
Note
Properly used, references to objects are not lost, so you could even use the original object reference, instead of creating new ones.
const myArr = [{ id: 1 }, { id: 2 }, { id: 9 }];
const [a, b, c] = myArr;
// modify original reference will change object in the array
a.color = 'green';
console.log(myArr[0].color); // outputs 'green'
This issue usually happens when consuming lists from database and then mapping the list to generate HTML content which will modify the elements of the list, and then we need to update the list and send it back to database as a list.
Good news is, references are kept, so you could organize your code to get advantage of it, and think about a list as an Object with identities for free, which are integers from 0 to length -1. So every time you access any property of your Object, do it as list[i], and you don't lose reference, and original object is changed. Keep in mind that this is useful when your source of truth is only one (the Object created), and your app is always consistently consuming the same Object (not fetching several times from database and assigning it to list along the lifespan of the component).
Bad news is that the architecture is wrong, and you should receive an object by ids (dictionary) if this is what you need, something like
{
1232: { id: 1232, ...},
asdf234asf: { id: 'asdf234asf', ...},
...
}
This way, you don't search in arrays, which is resource consuming. You "just access by key in the object", which is instant and performant.
One-liner using spread operator.
const updatedData = originalData.map(x => (x.id === id ? { ...x, updatedField: 1 } : x));
An other approach is to use splice.
The splice() method changes the contents of an array by removing or replacing existing elements and/or adding new elements in place.
N.B : In case you're working with reactive frameworks, it will update the "view", your array "knowing" you've updated it.
Answer :
var item = {...}
var items = [{id:2}, {id:2}, {id:2}];
let foundIndex = items.findIndex(element => element.id === item.id)
items.splice(foundIndex, 1, item)
And in case you want to only change a value of an item, you can use find function :
// Retrieve item and assign ref to updatedItem
let updatedItem = items.find((element) => { return element.id === item.id })
// Modify object property
updatedItem.aProp = ds.aProp
Given a changed object and an array:
const item = {...}
let items = [{id:2}, {id:3}, {id:4}];
Update the array with the new object by iterating over the array:
items = items.map(x => (x.id === item.id) ? item : x)
May be use Filter.
const list = [{id:0}, {id:1}, {id:2}];
let listCopy = [...list];
let filteredDataSource = listCopy.filter((item) => {
if (item.id === 1) {
item.id = 12345;
}
return item;
});
console.log(filteredDataSource);
Array [Object { id: 0 }, Object { id: 12345 }, Object { id: 2 }]
Whereas most of the existing answers are great, I would like to include an answer using a traditional for loop, which should also be considered here. The OP requests an answer which is ES5/ES6 compatible, and the traditional for loop applies :)
The problem with using array functions in this scenario, is that they don't mutate objects, but in this case, mutation is a requirement. The performance gain of using a traditional for loop is just a (huge) bonus.
const findThis = 2;
const items = [{id:1, ...}, {id:2, ...}, {id:3, ...}];
for (let i = 0, l = items.length; i < l; ++i) {
if (items[i].id === findThis) {
items[i].iAmChanged = true;
break;
}
}
Although I am a great fan of array functions, don't let them be the only tool in your toolbox. If the purpose is mutating the array, they are not the best fit.
I don't see this approach in the answers yet, so here's a simple little one liner
let item = {id: 1, new: true};
let items = [{id: 1}, {id: 2}];
let replaced = [item, ...items.filter(i => i.id !== item.id)]
You're just adding the item to the original array filtered of the item you're replacing.
worked for me
let returnPayments = [ ...this.payments ];
returnPayments[this.payments.findIndex(x => x.id == this.payment.id)] = this.payment;
In my case, I wanted to find some element ( and its length) and wanted to add a new element no_of_agents in the object itself. So following did help me
details.forEach(obj => {
const length = obj["fleet_ids"].length || 0;
obj.set("no_of_agents" , length)
});
Somehow map() returned with other details(like '$__': InternalCache,
strictMode, shardval, etc) which was not required,
You can do like this too
var item = {...}
var items = [{id:2}, {id:2}, {id:2}];
var foundItem = items.filter((x) => x.id == item.id).pop();
foundItem = item;
OR
items.filter((x) => x.id == item.id).pop()=item;
Related
The story is, I should be able to put Bob, Sally and Jack into a box. I can also remove either from the box. When removed, no slot is left.
people = ["Bob", "Sally", "Jack"]
I now need to remove, say, "Bob". The new array would be:
["Sally", "Jack"]
Here is my react component:
...
getInitialState: function() {
return{
people: [],
}
},
selectPeople(e){
this.setState({people: this.state.people.concat([e.target.value])})
},
removePeople(e){
var array = this.state.people;
var index = array.indexOf(e.target.value); // Let's say it's Bob.
delete array[index];
},
...
Here I show you a minimal code as there is more to it (onClick etc). The key part is to delete, remove, destroy "Bob" from the array but removePeople() is not working when called. Any ideas? I was looking at this but I might be doing something wrong since I'm using React.
When using React, you should never mutate the state directly. If an object (or Array, which is an object too) is changed, you should create a new copy.
Others have suggested using Array.prototype.splice(), but that method mutates the Array, so it's better not to use splice() with React.
Easiest to use Array.prototype.filter() to create a new array:
removePeople(e) {
this.setState({people: this.state.people.filter(function(person) {
return person !== e.target.value
})});
}
To remove an element from an array, just do:
array.splice(index, 1);
In your case:
removePeople(e) {
var array = [...this.state.people]; // make a separate copy of the array
var index = array.indexOf(e.target.value)
if (index !== -1) {
array.splice(index, 1);
this.setState({people: array});
}
},
Here is a minor variation on Aleksandr Petrov's response using ES6
removePeople(e) {
let filteredArray = this.state.people.filter(item => item !== e.target.value)
this.setState({people: filteredArray});
}
Simple solution using slice without mutating the state
const [items, setItems] = useState(data);
const removeItem = (index) => {
setItems([
...items.slice(0, index),
...items.slice(index + 1)
]);
}
Use .splice to remove item from array. Using delete, indexes of the array will not be altered but the value of specific index will be undefined
The splice() method changes the content of an array by removing existing elements and/or adding new elements.
Syntax: array.splice(start, deleteCount[, item1[, item2[, ...]]])
var people = ["Bob", "Sally", "Jack"]
var toRemove = 'Bob';
var index = people.indexOf(toRemove);
if (index > -1) { //Make sure item is present in the array, without if condition, -n indexes will be considered from the end of the array.
people.splice(index, 1);
}
console.log(people);
Edit:
As pointed out by justin-grant, As a rule of thumb, Never mutate this.state directly, as calling setState() afterward may replace the mutation you made. Treat this.state as if it were immutable.
The alternative is, create copies of the objects in this.state and manipulate the copies, assigning them back using setState(). Array#map, Array#filter etc. could be used.
this.setState({people: this.state.people.filter(item => item !== e.target.value);});
Easy Way To Delete Item From state array in react:
when any data delete from database and update list without API calling that time you pass deleted id to this function and this function remove deleted recored from list
export default class PostList extends Component {
this.state = {
postList: [
{
id: 1,
name: 'All Items',
}, {
id: 2,
name: 'In Stock Items',
}
],
}
remove_post_on_list = (deletePostId) => {
this.setState({
postList: this.state.postList.filter(item => item.post_id != deletePostId)
})
}
}
filter method is the best way to modify the array without touching the state.
It returns a new array based on the condition.
In your case filter check the condition person.id !== id and create a new array excluding the item based on condition.
const [people, setPeople] = useState(data);
const handleRemove = (id) => {
const newPeople = people.filter((person) => person.id !== id);
setPeople( newPeople);
};
<button onClick={() => handleRemove(id)}>Remove</button>
Not advisable:
But you can also use an item index for the condition if you don't have any id.
index !== itemIndex
This is your current state variable:
const [animals, setAnimals] = useState(["dogs", "cats", ...])
Call this function and pass the item you would like to remove.
removeItem("dogs")
const removeItem = (item) => {
setAnimals((prevState) =>
prevState.filter((prevItem) => prevItem !== item)
);
};
your state variable now becomes:
["cats", ...]
Another way of doing it is by using useState hook. Check docs: https://reactjs.org/docs/hooks-reference.html#functional-updates It states: Unlike the setState method found in class components, useState does not automatically merge update objects. You can replicate this behavior by combining the function updater form with object spread syntax as shown below or use useReducer hook.
const [state, setState] = useState({});
setState(prevState => {
return {...prevState, ...updatedValues};
});
Some answers mentioned using 'splice', which did as Chance Smith said mutated the array. I would suggest you to use the Method call 'slice'
(Document for 'slice' is here) which make a copy of the original array.
Just filter out deleted item and update the state with remaining items again,
let remainingItems = allItems.filter((item) => {return item.id !== item_id});
setItems(remainingItems);
const [people, setPeople] = useState(data);
const handleRemove = (id) => {
const newPeople = people.filter((person) => { person.id !== id;
setPeople( newPeople );
});
};
<button onClick={() => handleRemove(id)}>Remove</button>
It's Very Simple
First You Define a value
state = {
checked_Array: []
}
Now,
fun(index) {
var checked = this.state.checked_Array;
var values = checked.indexOf(index)
checked.splice(values, 1);
this.setState({checked_Array: checked});
console.log(this.state.checked_Array)
}
removePeople(e){
var array = this.state.people;
var index = array.indexOf(e.target.value); // Let's say it's Bob.
array.splice(index,1);
}
Redfer doc for more info
Almost all the answers here seem to be for class components, here's a code that worked for me in a functional component.
const [arr,setArr]=useState([]);
const removeElement=(id)=>{
var index = arr.indexOf(id)
if(index!==-1){
setArr(oldArray=>oldArray.splice(index, 1));
}
}
If you use:
const[myArr, setMyArr] = useState([]);
for add:
setMyArr([...myArr, value]);
and for remove:
let index = myArr.indexOf(value);
if(index !== -1)
setPatch([...myArr.slice(0, index), ...myArr.slice(index, myArr.length-1)]);
Removing an element with a certain value
//
Note filter function always returns a new array.
const people = ["Bob", "Sally", "Jack"]
const removeEntry = (remove) => {
const upDatePeople = people.filter((Person) =>{
return Person !== remove
});
console.log(upDatePeople)
//Output: [ 'Sally', 'Jack' ]
}
removeEntry("Bob");
You forgot to use setState. Example:
removePeople(e){
var array = this.state.people;
var index = array.indexOf(e.target.value); // Let's say it's Bob.
delete array[index];
this.setState({
people: array
})
},
But it's better to use filter because it does not mutate array.
Example:
removePeople(e){
var array = this.state.people.filter(function(item) {
return item !== e.target.value
});
this.setState({
people: array
})
},
const [randomNumbers, setRandomNumbers] = useState([111,432,321]);
const numberToBeDeleted = 432;
// Filter (preferred)
let newRandomNumbers = randomNumbers.filter(number => number !== numberToBeDeleted)
setRandomNumbers(newRandomNumbers);
//Splice (alternative)
let indexOfNumberToBeDeleted = randomNumbers.indexOf(numberToBeDeleted);
let newRandomNumbers = Array.from(randomNumbers);
newRandomNumbers.splice(indexOfNumberToBeDeleted, 1);
setRandomNumbers(newRandomNumbers);
//Slice (not preferred - code complexity)
let indexOfNumberToBeDeleted = randomNumbers.indexOf(numberToBeDeleted);
let deletedNumber = randomNumbers.slice(indexOfNumberToBeDeleted, indexOfNumberToBeDeleted+1);
let newRandomNumbers = [];
for(let number of randomNumbers) {
if(deletedNumber[0] !== number)
newRandomNumbers.push(number);
};
setRandomNumbers(newRandomNumbers);
The story is, I should be able to put Bob, Sally and Jack into a box. I can also remove either from the box. When removed, no slot is left.
people = ["Bob", "Sally", "Jack"]
I now need to remove, say, "Bob". The new array would be:
["Sally", "Jack"]
Here is my react component:
...
getInitialState: function() {
return{
people: [],
}
},
selectPeople(e){
this.setState({people: this.state.people.concat([e.target.value])})
},
removePeople(e){
var array = this.state.people;
var index = array.indexOf(e.target.value); // Let's say it's Bob.
delete array[index];
},
...
Here I show you a minimal code as there is more to it (onClick etc). The key part is to delete, remove, destroy "Bob" from the array but removePeople() is not working when called. Any ideas? I was looking at this but I might be doing something wrong since I'm using React.
When using React, you should never mutate the state directly. If an object (or Array, which is an object too) is changed, you should create a new copy.
Others have suggested using Array.prototype.splice(), but that method mutates the Array, so it's better not to use splice() with React.
Easiest to use Array.prototype.filter() to create a new array:
removePeople(e) {
this.setState({people: this.state.people.filter(function(person) {
return person !== e.target.value
})});
}
To remove an element from an array, just do:
array.splice(index, 1);
In your case:
removePeople(e) {
var array = [...this.state.people]; // make a separate copy of the array
var index = array.indexOf(e.target.value)
if (index !== -1) {
array.splice(index, 1);
this.setState({people: array});
}
},
Here is a minor variation on Aleksandr Petrov's response using ES6
removePeople(e) {
let filteredArray = this.state.people.filter(item => item !== e.target.value)
this.setState({people: filteredArray});
}
Simple solution using slice without mutating the state
const [items, setItems] = useState(data);
const removeItem = (index) => {
setItems([
...items.slice(0, index),
...items.slice(index + 1)
]);
}
Use .splice to remove item from array. Using delete, indexes of the array will not be altered but the value of specific index will be undefined
The splice() method changes the content of an array by removing existing elements and/or adding new elements.
Syntax: array.splice(start, deleteCount[, item1[, item2[, ...]]])
var people = ["Bob", "Sally", "Jack"]
var toRemove = 'Bob';
var index = people.indexOf(toRemove);
if (index > -1) { //Make sure item is present in the array, without if condition, -n indexes will be considered from the end of the array.
people.splice(index, 1);
}
console.log(people);
Edit:
As pointed out by justin-grant, As a rule of thumb, Never mutate this.state directly, as calling setState() afterward may replace the mutation you made. Treat this.state as if it were immutable.
The alternative is, create copies of the objects in this.state and manipulate the copies, assigning them back using setState(). Array#map, Array#filter etc. could be used.
this.setState({people: this.state.people.filter(item => item !== e.target.value);});
Easy Way To Delete Item From state array in react:
when any data delete from database and update list without API calling that time you pass deleted id to this function and this function remove deleted recored from list
export default class PostList extends Component {
this.state = {
postList: [
{
id: 1,
name: 'All Items',
}, {
id: 2,
name: 'In Stock Items',
}
],
}
remove_post_on_list = (deletePostId) => {
this.setState({
postList: this.state.postList.filter(item => item.post_id != deletePostId)
})
}
}
filter method is the best way to modify the array without touching the state.
It returns a new array based on the condition.
In your case filter check the condition person.id !== id and create a new array excluding the item based on condition.
const [people, setPeople] = useState(data);
const handleRemove = (id) => {
const newPeople = people.filter((person) => person.id !== id);
setPeople( newPeople);
};
<button onClick={() => handleRemove(id)}>Remove</button>
Not advisable:
But you can also use an item index for the condition if you don't have any id.
index !== itemIndex
This is your current state variable:
const [animals, setAnimals] = useState(["dogs", "cats", ...])
Call this function and pass the item you would like to remove.
removeItem("dogs")
const removeItem = (item) => {
setAnimals((prevState) =>
prevState.filter((prevItem) => prevItem !== item)
);
};
your state variable now becomes:
["cats", ...]
Another way of doing it is by using useState hook. Check docs: https://reactjs.org/docs/hooks-reference.html#functional-updates It states: Unlike the setState method found in class components, useState does not automatically merge update objects. You can replicate this behavior by combining the function updater form with object spread syntax as shown below or use useReducer hook.
const [state, setState] = useState({});
setState(prevState => {
return {...prevState, ...updatedValues};
});
Some answers mentioned using 'splice', which did as Chance Smith said mutated the array. I would suggest you to use the Method call 'slice'
(Document for 'slice' is here) which make a copy of the original array.
Just filter out deleted item and update the state with remaining items again,
let remainingItems = allItems.filter((item) => {return item.id !== item_id});
setItems(remainingItems);
const [people, setPeople] = useState(data);
const handleRemove = (id) => {
const newPeople = people.filter((person) => { person.id !== id;
setPeople( newPeople );
});
};
<button onClick={() => handleRemove(id)}>Remove</button>
It's Very Simple
First You Define a value
state = {
checked_Array: []
}
Now,
fun(index) {
var checked = this.state.checked_Array;
var values = checked.indexOf(index)
checked.splice(values, 1);
this.setState({checked_Array: checked});
console.log(this.state.checked_Array)
}
removePeople(e){
var array = this.state.people;
var index = array.indexOf(e.target.value); // Let's say it's Bob.
array.splice(index,1);
}
Redfer doc for more info
Almost all the answers here seem to be for class components, here's a code that worked for me in a functional component.
const [arr,setArr]=useState([]);
const removeElement=(id)=>{
var index = arr.indexOf(id)
if(index!==-1){
setArr(oldArray=>oldArray.splice(index, 1));
}
}
If you use:
const[myArr, setMyArr] = useState([]);
for add:
setMyArr([...myArr, value]);
and for remove:
let index = myArr.indexOf(value);
if(index !== -1)
setPatch([...myArr.slice(0, index), ...myArr.slice(index, myArr.length-1)]);
Removing an element with a certain value
//
Note filter function always returns a new array.
const people = ["Bob", "Sally", "Jack"]
const removeEntry = (remove) => {
const upDatePeople = people.filter((Person) =>{
return Person !== remove
});
console.log(upDatePeople)
//Output: [ 'Sally', 'Jack' ]
}
removeEntry("Bob");
You forgot to use setState. Example:
removePeople(e){
var array = this.state.people;
var index = array.indexOf(e.target.value); // Let's say it's Bob.
delete array[index];
this.setState({
people: array
})
},
But it's better to use filter because it does not mutate array.
Example:
removePeople(e){
var array = this.state.people.filter(function(item) {
return item !== e.target.value
});
this.setState({
people: array
})
},
const [randomNumbers, setRandomNumbers] = useState([111,432,321]);
const numberToBeDeleted = 432;
// Filter (preferred)
let newRandomNumbers = randomNumbers.filter(number => number !== numberToBeDeleted)
setRandomNumbers(newRandomNumbers);
//Splice (alternative)
let indexOfNumberToBeDeleted = randomNumbers.indexOf(numberToBeDeleted);
let newRandomNumbers = Array.from(randomNumbers);
newRandomNumbers.splice(indexOfNumberToBeDeleted, 1);
setRandomNumbers(newRandomNumbers);
//Slice (not preferred - code complexity)
let indexOfNumberToBeDeleted = randomNumbers.indexOf(numberToBeDeleted);
let deletedNumber = randomNumbers.slice(indexOfNumberToBeDeleted, indexOfNumberToBeDeleted+1);
let newRandomNumbers = [];
for(let number of randomNumbers) {
if(deletedNumber[0] !== number)
newRandomNumbers.push(number);
};
setRandomNumbers(newRandomNumbers);
Suppose I have an array of object:
const apple = [{"bookName" :'Harry Pottar',part:"1"},{"bookName" :'Harry Pottar',part:"2"},
{"bookName": 'LOTR',part:"1"},{"bookName": 'LOTR',part:"2"},{"bookName": 'LOTR',part:"3"}]
I want to get count of all common values along with the value name as :
Expected O/P : [{"Harry Pottar":2},{"LOTR":3"}]
For this I tried as:
const id = "Harry Pottar";
const count = array.reduce((acc, cur) => cur.bookName === id ? ++acc : acc, 0);
As this gives the count, by this I can get count for each bookName. But how can I achieve my expected O/P scenario.
If anyone needs any further information please do let me know.
Good to see you know about .reduce! You’re pretty close, just need to save the result to a hashmap (plain object in JS).
const array = [{"bookName" :'Harry Pottar',part:"1"},{"bookName" :'Harry Pottar',part:"2"},{"bookName": 'LOTR',part:"1"},{"bookName": 'LOTR',part:"2"},{"bookName": 'LOTR',part:"3"}]
const result = array.reduce((acc, item) => {
const key = item.bookName
if (!acc.hasOwnProperty(key)) {
acc[key] = 0
}
acc[key] += 1
return acc
}, {})
// not sure why you want the result to be multiple objects. But here you go:
const output = Object.entries(result).map(([key, value])=> ({ [key]: value }))
Create a map from your data keyed by the book names, where the corresponding values are the objects you want in the output, with the count set to zero (you can use the computed property name syntax for the object's dynamic property). Then iterate the data again to increment the counters. Finally extract the values from the map into an array:
const apple = [{"bookName" :'Harry Pottar',part:"1"},{"bookName" :'Harry Pottar',part:"2"},
{"bookName": 'LOTR',part:"1"},{"bookName": 'LOTR',part:"2"},{"bookName": 'LOTR',part:"3"}];
let map = new Map(apple.map(({bookName}) => [bookName, { [bookName]: 0 }]));
for (let {bookName} of apple) map.get(bookName)[bookName]++;
let result = Array.from(map.values());
console.log(result);
You were pretty close. You don't necessarily need to have those objects in an array though. Just have an object with the booknames as the property keys. It would make it easier to manage.
If you then want to create an array of objects from that data you can use map over the Object.entries of that object.
const apple = [{"bookName" :'Harry Pottar',part:"1"},{"bookName" :'Harry Pottar',part:"2"},{"bookName": 'LOTR',part:"1"},{"bookName": 'LOTR',part:"2"},{"bookName": 'LOTR',part:"3"}];
const out = apple.reduce((acc, { bookName }) => {
// If the property doesn't exist, create it
// and set it to zero, otherwise increment the value
// of the existing property
acc[bookName] = (acc[bookName] || 0) + 1;
return acc;
}, {});
console.log(out);
const result = Object.entries(out).map(([ key, value ]) => {
return { [key]: value };
});
console.log(result);
I am trying to filter through an array of objects and delete one of the object but keep the rest inside an array of objects but i keep returning either an array of arrays or i create nested objects. Is it possible to send in an array of objects and return and array of objects without that specific object? Below is the code I have been trying to work with.
function deleteWorkout(workoutName) {
const updatedArray = myWorkoutToDisplay.map((item) => item.newWorkToAdd.filter((workout) => workout.name !== workoutName))
const objectArray = [{updatedArray}]
const newWorkToAdd = objectArray.filter(e => e.length)
const workouts = [{newWorkToAdd}]
setMyWorkoutToDisplay(updatedArray)
}
You can easily do this with Array.prototype.filter. I guess the easiest way to delete 1 object is like this:
//let arr = arrayLike
//let objToDelete = whatever you want to delete
let newArr = arr.filter(obj => obj !== objToDelete)
newArr now has the array, without the deleted item. arr however still has it. To delete item by index, use this:
//let arr = arrayLike
//let ind = index to delete
let newArr = arr.filter((_, index) => index !== ind)
I've an array of errors, each error has a non-unique param attribute.
I'd like to filter the array based on whether the param has been seen before.
Something like this:
const filteredErrors = [];
let params = [];
for(let x = 0; x < errors.length; x++) {
if(!params.includes(errors[x].param)) {
params.push(errors[x].param);
filteredErrors.push(errors[x]);
}
}
But I've no idea how to do this in ES6.
I can get the unique params const filteredParams = Array.from(new Set(errors.map(error => error.param)));
but not the objects themselves.
Pretty sure this is just a weakness in my understanding of higher order functions, but I just can't grasp it
You could destrucure param, check against params and add the value to params and return true for getting the object as filtering result.
As result you get an array of first found errors of the same type.
const
params = [],
filteredErrors = errors.filter(({ param }) =>
!params.includes(param) && params.push(param));
Instead of an array you can make use of an object to keep a map of existing values and make use of filter function
let params = {};
const filteredErrors = errors.filter(error => {
if(params[error.param]) return false;
params[error.param] = true;
return true;
});
i'd probably do it like this with a reduce and no need for outside parameters:
const filteredErrors = Object.values(
errors.reduce((acc, val) => {
if (!acc[val.param]) {
acc[val.param] = val;
}
return acc;
}, {}))
basically convert it into an object keyed by the param with the object as values, only setting the key if it hasn't been set before, then back into an array of the values.
generalized like so
function uniqueBy(array, prop) {
return Object.values(
array.reduce((acc, val) => {
if (!acc[val[prop]]) {
acc[val[prop]] = val;
}
return acc;
}, {}))
}
then just do:
const filteredErrors = uniqueBy(errors, 'param');
If your param has a flag identifier if this param has been seen before then you can simply do this.
const filteredErrors = errors.filter(({ param }) => param.seen === true);
OR
const filteredErrors = errors.filter((error) => error.param.seen);
errors should be an array of objects.
where param is one of the fields of the element of array errors and seen is one of the fields of param object.
You can do it by using Array.prototype.reduce. You need to iterate through the objects in the array and keep the found params in a Set if it is not already there.
The Set.prototype.has will let you find that out. If it is not present in the Set you add it both in the Set instance and the final accumulated array, so that in the next iteration if the param is present in your Set you don't include that object:
const errors = [{param: 1, val: "err1"}, {param: 2, val: "err2"}, {param: 3, val: "err3"}, {param: 2, val: "err4"}, {param: 1, val: "err5"}];
const { filteredParams } = errors.reduce((acc, e) => {
!acc.foundParams.has(e.param) && (acc.foundParams.add(e.param) &&
acc.filteredParams.push(e));
return acc;
}, {foundParams: new Set(), filteredParams: []});
console.log(filteredParams);