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How to iterate through complex Json object and do something on each property which equals a certain value

I got the following problem,
I need to iterate through a big Json object ( child nodes consist of array's, strings and objects with at least 4-5 layers of depth in terms of nested properties ).
In some parts across the big Json file there is a specific object structure, it has a property named "erpCode". I need to scan the Json and find all the objects with that property, take the value use that code to ask a different API for details and once I get the details insert them into the object with the current 'erpCode'.
Just to clarify, in my case the parent node property name in the Json always equals the value in 'typeSysname' field which located on the same 'level' as the erpCode property.
A simple example :
{
"cars": [
{
"name": "X222",
"carType": {
"erpCode": "skoda",
"value": null,
"typeSysName": "carType"
}
}
],
"model": {
"year": 1999,
"details": {
"erpCode": "112"
"value": null,
"typeSysName": "details"
}
}
}
In this example I need to find 2 properties get the values skoda and 112 out of them and get the value and description data from a different API and set it into this Json in the right location.
P.S. Any chance there is a good npm package which can help me with that?
Edit:
I got a solution in C# from a few months ago which runs in a generic way on the Json and handles the complexity of the structure in a generic way.
But I now need to convert this into Javascript and I am a bit lost.
public static string TranslateDocErpCodes(string jsonString, string topRetailerSysName)
{
try
{
var doc = JObject.Parse(jsonString);
var erpCodeList = doc.SelectTokens("$..erpCode").ToList();
foreach (var erpCodeJToken in erpCodeList)
{
var value = erpCodeJToken?.Value<string>();
var erpCodeParent = erpCodeJToken?.Parent.Parent;
var erpCodeProperty = erpCodeParent?.Path.Split(".").Last();
var result =
_dataService.GetLovFromErpCode(topRetailerSysName, erpCodeProperty, value);
if (result == null)//reset lov obj
{
if (erpCodeParent?.Parent is JProperty prop)
prop.Value = JObject.FromObject(new LovObject { ErpCode = value });
}
else//set lov obj
{
result.ErpCode = value;
if (erpCodeParent?.Parent is JProperty prop)
prop.Value = JObject.FromObject(result);
}
}
return JsonConvert.SerializeObject(doc);
}
catch (Exception e)
{
throw new Exception("ErpConvert.TranslateDocErpCodes() : " + e);
}
}

mb something like;
function processObject(jsonData) {
for (prop in jsonData) {
if (jsonData.hasOwnProperty(prop)) {
// We get our prop
if (prop === 'code') {
let codeValue = jsonData[prop]
doSomeAsync(codeValue)
.then(response => {
jsonData[prop] = response;
})
}
let curValue = jsonData[prop];
if (Array.isArray(curValue)) {
// Loop through the array, if array element is an object, call processObject recursively.
processArray(curValue);
} else if (typeof curValue === 'object') {
processObject(curValue);
}
}
}
}

I took the answer from Aravindh as a starting point and managed to reach what seems to be a complete solution.
I will share it here,
async function convertErpCodes(jsonData, orgName, parentPropertyName){
for (let prop in jsonData) {
if (jsonData.hasOwnProperty(prop)) {
if (prop === 'erpCode') {
const erpCodeValue = jsonData[prop]
const req = {"query": {"erpCode": erpCodeValue, "orgName": orgName, "typeSysName": parentPropertyName}};
const result = await viewLookupErpService.findOne(req);
if(result)
return result;
}
const curValue = jsonData[prop];
if (Array.isArray(curValue)) {
for(let i in curValue){
const res = await convertErpCodes(curValue[i], orgName, prop);
}
} else if (curValue && typeof curValue === 'object') {
const response = await convertErpCodes(curValue, orgName, prop);
if(response){
jsonData[prop] = response;
}
}
}
}
}
P.S.
I set up the values only if I get a response from the third party API ( this is the reason for the result and response logic in the recursion.

I'd use object-scan and lodash.set in combination
// const objectScan = require('object-scan');
// const lodash = require('lodash');
const stats = { cars: [{ name: 'X222', carType: { erpCode: 'skoda', value: null, typeSysName: 'carType' } }], model: { year: 1999, details: { erpCode: '112', value: null, typeSysName: 'details' } } };
const entries = objectScan(['**.erpCode'], { rtn: 'entry' })(stats);
console.log(entries);
// => [ [ [ 'model', 'details', 'erpCode' ], '112' ], [ [ 'cars', 0, 'carType', 'erpCode' ], 'skoda' ] ]
// where you would query the external api and place results in entries
entries[0][1] = 'foo';
entries[1][1] = 'bar';
entries.forEach(([k, v]) => lodash.set(stats, k, v));
console.log(stats);
// => { cars: [ { name: 'X222', carType: { erpCode: 'bar', value: null, typeSysName: 'carType' } } ], model: { year: 1999, details: { erpCode: 'foo', value: null, typeSysName: 'details' } } }
.as-console-wrapper {max-height: 100% !important; top: 0}
<script src="https://bundle.run/object-scan#13.8.0"></script>
<script src="https://bundle.run/lodash#4.17.20"></script>
Disclaimer: I'm the author of object-scan

How can you destructure an array of objects in Javascript into two predefined variables in ES6?

I have an array containing one object of this form :
Array = [ { type: type, message: message } ]
I keep getting ESLint errors asking me to use object destructuring and array destructuring.
Currently my code looks like this :
let type=null;
let message=null;
if (data.length > 0) {
({ type, message } = data[0]);
}
So far this works and my variables are assigned correctly, however I am still getting the "Use array destructuring" message from ESLint.
Any help with this would be appreciated. Thank you

You can destructure the array:
let type=null;
let message=null;
if (data.length > 0) {
[{ type, message }] = data;
}
The code above is a shorter version of:
[ firstElement ] = data; // array destructruring
({ type, message } = firstElement); // object destructuring

Faly's way is good. You can also use default values when destructuring:
function test(label, data) {
// 1 -----------------------------vvvvv
let [{type = null, message = null} = {}] = data;
// 2 -----^^^^^^^---------^^^^^^^
console.log(label, type, message);
}
test("test1: ", []);
test("test2: ", [{type: "t"}]);
test("test3: ", [{type: "t", message: "m"}]);
That works because if data.length is 0, data[0] is undefined, and so triggers use of the default value {} (1) for the array part of that; within the object part of that, we use null (2) to handle any missing values on the object as well.

EsLint wants you to write
let type = null;
let message = null;
if (data.length > 0) {
[{ type, message }] = data;
}
which destructures the first item of an iterable data into the {type, message} target. (More items are ignored).
I would however recommend to use default values for the empty case:
const [{type, message} = {type:null, message:null}] = data;
or also
const [{type = null, message = null} = {}] = data;

Getting a list of unique fields within a collection including nested [duplicate]

I'd like to get the names of all the keys in a MongoDB collection.
For example, from this:
db.things.insert( { type : ['dog', 'cat'] } );
db.things.insert( { egg : ['cat'] } );
db.things.insert( { type : [] } );
db.things.insert( { hello : [] } );
I'd like to get the unique keys:
type, egg, hello

You could do this with MapReduce:
mr = db.runCommand({
"mapreduce" : "my_collection",
"map" : function() {
for (var key in this) { emit(key, null); }
},
"reduce" : function(key, stuff) { return null; },
"out": "my_collection" + "_keys"
})
Then run distinct on the resulting collection so as to find all the keys:
db[mr.result].distinct("_id")
["foo", "bar", "baz", "_id", ...]

With Kristina's answer as inspiration, I created an open source tool called Variety which does exactly this: https://github.com/variety/variety

You can use aggregation with the new $objectToArray aggregation operator in version 3.4.4 to convert all top key-value pairs into document arrays, followed by $unwind and $group with $addToSet to get distinct keys across the entire collection. (Use $$ROOT for referencing the top level document.)
db.things.aggregate([
{"$project":{"arrayofkeyvalue":{"$objectToArray":"$$ROOT"}}},
{"$unwind":"$arrayofkeyvalue"},
{"$group":{"_id":null,"allkeys":{"$addToSet":"$arrayofkeyvalue.k"}}}
])
You can use the following query for getting keys in a single document.
db.things.aggregate([
{"$match":{_id: "<<ID>>"}}, /* Replace with the document's ID */
{"$project":{"arrayofkeyvalue":{"$objectToArray":"$$ROOT"}}},
{"$project":{"keys":"$arrayofkeyvalue.k"}}
])

A cleaned up and reusable solution using pymongo:
from pymongo import MongoClient
from bson import Code
def get_keys(db, collection):
client = MongoClient()
db = client[db]
map = Code("function() { for (var key in this) { emit(key, null); } }")
reduce = Code("function(key, stuff) { return null; }")
result = db[collection].map_reduce(map, reduce, "myresults")
return result.distinct('_id')
Usage:
get_keys('dbname', 'collection')
>> ['key1', 'key2', ... ]

If your target collection is not too large, you can try this under mongo shell client:
var allKeys = {};
db.YOURCOLLECTION.find().forEach(function(doc){Object.keys(doc).forEach(function(key){allKeys[key]=1})});
allKeys;

If you are using mongodb 3.4.4 and above then you can use below aggregation using $objectToArray and $group aggregation
db.collection.aggregate([
{ "$project": {
"data": { "$objectToArray": "$$ROOT" }
}},
{ "$project": { "data": "$data.k" }},
{ "$unwind": "$data" },
{ "$group": {
"_id": null,
"keys": { "$addToSet": "$data" }
}}
])
Here is the working example

Try this:
doc=db.thinks.findOne();
for (key in doc) print(key);

Using python. Returns the set of all top-level keys in the collection:
#Using pymongo and connection named 'db'
reduce(
lambda all_keys, rec_keys: all_keys | set(rec_keys),
map(lambda d: d.keys(), db.things.find()),
set()
)

Here is the sample worked in Python:
This sample returns the results inline.
from pymongo import MongoClient
from bson.code import Code
mapper = Code("""
function() {
for (var key in this) { emit(key, null); }
}
""")
reducer = Code("""
function(key, stuff) { return null; }
""")
distinctThingFields = db.things.map_reduce(mapper, reducer
, out = {'inline' : 1}
, full_response = True)
## do something with distinctThingFields['results']

I am surprise, no one here has ans by using simple javascript and Set logic to automatically filter the duplicates values, simple example on mongo shellas below:
var allKeys = new Set()
db.collectionName.find().forEach( function (o) {for (key in o ) allKeys.add(key)})
for(let key of allKeys) print(key)
This will print all possible unique keys in the collection name: collectionName.

I think the best way do this as mentioned here is in mongod 3.4.4+ but without using the $unwind operator and using only two stages in the pipeline. Instead we can use the $mergeObjects and $objectToArray operators.
In the $group stage, we use the $mergeObjects operator to return a single document where key/value are from all documents in the collection.
Then comes the $project where we use $map and $objectToArray to return the keys.
let allTopLevelKeys = [
{
"$group": {
"_id": null,
"array": {
"$mergeObjects": "$$ROOT"
}
}
},
{
"$project": {
"keys": {
"$map": {
"input": { "$objectToArray": "$array" },
"in": "$$this.k"
}
}
}
}
];
Now if we have a nested documents and want to get the keys as well, this is doable. For simplicity, let consider a document with simple embedded document that look like this:
{field1: {field2: "abc"}, field3: "def"}
{field1: {field3: "abc"}, field4: "def"}
The following pipeline yield all keys (field1, field2, field3, field4).
let allFistSecondLevelKeys = [
{
"$group": {
"_id": null,
"array": {
"$mergeObjects": "$$ROOT"
}
}
},
{
"$project": {
"keys": {
"$setUnion": [
{
"$map": {
"input": {
"$reduce": {
"input": {
"$map": {
"input": {
"$objectToArray": "$array"
},
"in": {
"$cond": [
{
"$eq": [
{
"$type": "$$this.v"
},
"object"
]
},
{
"$objectToArray": "$$this.v"
},
[
"$$this"
]
]
}
}
},
"initialValue": [
],
"in": {
"$concatArrays": [
"$$this",
"$$value"
]
}
}
},
"in": "$$this.k"
}
}
]
}
}
}
]
With a little effort, we can get the key for all subdocument in an array field where the elements are object as well.

This works fine for me:
var arrayOfFieldNames = [];
var items = db.NAMECOLLECTION.find();
while(items.hasNext()) {
var item = items.next();
for(var index in item) {
arrayOfFieldNames[index] = index;
}
}
for (var index in arrayOfFieldNames) {
print(index);
}

Maybe slightly off-topic, but you can recursively pretty-print all keys/fields of an object:
function _printFields(item, level) {
if ((typeof item) != "object") {
return
}
for (var index in item) {
print(" ".repeat(level * 4) + index)
if ((typeof item[index]) == "object") {
_printFields(item[index], level + 1)
}
}
}
function printFields(item) {
_printFields(item, 0)
}
Useful when all objects in a collection has the same structure.

To get a list of all the keys minus _id, consider running the following aggregate pipeline:
var keys = db.collection.aggregate([
{ "$project": {
"hashmaps": { "$objectToArray": "$$ROOT" }
} },
{ "$group": {
"_id": null,
"fields": { "$addToSet": "$hashmaps.k" }
} },
{ "$project": {
"keys": {
"$setDifference": [
{
"$reduce": {
"input": "$fields",
"initialValue": [],
"in": { "$setUnion" : ["$$value", "$$this"] }
}
},
["_id"]
]
}
}
}
]).toArray()[0]["keys"];

I know I am late to the party, but if you want a quick solution in python finding all keys (even the nested ones) you could do with a recursive function:
def get_keys(dl, keys=None):
keys = keys or []
if isinstance(dl, dict):
keys += dl.keys()
list(map(lambda x: get_keys(x, keys), dl.values()))
elif isinstance(dl, list):
list(map(lambda x: get_keys(x, keys), dl))
return list(set(keys))
and use it like:
dl = db.things.find_one({})
get_keys(dl)
if your documents do not have identical keys you can do:
dl = db.things.find({})
list(set(list(map(get_keys, dl))[0]))
but this solution can for sure be optimized.
Generally this solution is basically solving finding keys in nested dicts, so this is not mongodb specific.

Based on #Wolkenarchitekt answer: https://stackoverflow.com/a/48117846/8808983, I write a script that can find patterns in all keys in the db and I think it can help others reading this thread:
"""
Python 3
This script get list of patterns and print the collections that contains fields with this patterns.
"""
import argparse
import pymongo
from bson import Code
# initialize mongo connection:
def get_db():
client = pymongo.MongoClient("172.17.0.2")
db = client["Data"]
return db
def get_commandline_options():
description = "To run use: python db_fields_pattern_finder.py -p <list_of_patterns>"
parser = argparse.ArgumentParser(description=description)
parser.add_argument('-p', '--patterns', nargs="+", help='List of patterns to look for in the db.', required=True)
return parser.parse_args()
def report_matching_fields(relevant_fields_by_collection):
print("Matches:")
for collection_name in relevant_fields_by_collection:
if relevant_fields_by_collection[collection_name]:
print(f"{collection_name}: {relevant_fields_by_collection[collection_name]}")
# pprint(relevant_fields_by_collection)
def get_collections_names(db):
"""
:param pymongo.database.Database db:
:return list: collections names
"""
return db.list_collection_names()
def get_keys(db, collection):
"""
See: https://stackoverflow.com/a/48117846/8808983
:param db:
:param collection:
:return:
"""
map = Code("function() { for (var key in this) { emit(key, null); } }")
reduce = Code("function(key, stuff) { return null; }")
result = db[collection].map_reduce(map, reduce, "myresults")
return result.distinct('_id')
def get_fields(db, collection_names):
fields_by_collections = {}
for collection_name in collection_names:
fields_by_collections[collection_name] = get_keys(db, collection_name)
return fields_by_collections
def get_matches_fields(fields_by_collections, patterns):
relevant_fields_by_collection = {}
for collection_name in fields_by_collections:
relevant_fields = [field for field in fields_by_collections[collection_name] if
[pattern for pattern in patterns if
pattern in field]]
relevant_fields_by_collection[collection_name] = relevant_fields
return relevant_fields_by_collection
def main(patterns):
"""
:param list patterns: List of strings to look for in the db.
"""
db = get_db()
collection_names = get_collections_names(db)
fields_by_collections = get_fields(db, collection_names)
relevant_fields_by_collection = get_matches_fields(fields_by_collections, patterns)
report_matching_fields(relevant_fields_by_collection)
if __name__ == '__main__':
args = get_commandline_options()
main(args.patterns)

As per the mongoldb documentation, a combination of distinct
Finds the distinct values for a specified field across a single collection or view and returns the results in an array.
and indexes collection operations are what would return all possible values for a given key, or index:
Returns an array that holds a list of documents that identify and describe the existing indexes on the collection
So in a given method one could do use a method like the following one, in order to query a collection for all it's registered indexes, and return, say an object with the indexes for keys (this example uses async/await for NodeJS, but obviously you could use any other asynchronous approach):
async function GetFor(collection, index) {
let currentIndexes;
let indexNames = [];
let final = {};
let vals = [];
try {
currentIndexes = await collection.indexes();
await ParseIndexes();
//Check if a specific index was queried, otherwise, iterate for all existing indexes
if (index && typeof index === "string") return await ParseFor(index, indexNames);
await ParseDoc(indexNames);
await Promise.all(vals);
return final;
} catch (e) {
throw e;
}
function ParseIndexes() {
return new Promise(function (result) {
let err;
for (let ind in currentIndexes) {
let index = currentIndexes[ind];
if (!index) {
err = "No Key For Index "+index; break;
}
let Name = Object.keys(index.key);
if (Name.length === 0) {
err = "No Name For Index"; break;
}
indexNames.push(Name[0]);
}
return result(err ? Promise.reject(err) : Promise.resolve());
})
}
async function ParseFor(index, inDoc) {
if (inDoc.indexOf(index) === -1) throw "No Such Index In Collection";
try {
await DistinctFor(index);
return final;
} catch (e) {
throw e
}
}
function ParseDoc(doc) {
return new Promise(function (result) {
let err;
for (let index in doc) {
let key = doc[index];
if (!key) {
err = "No Key For Index "+index; break;
}
vals.push(new Promise(function (pushed) {
DistinctFor(key)
.then(pushed)
.catch(function (err) {
return pushed(Promise.resolve());
})
}))
}
return result(err ? Promise.reject(err) : Promise.resolve());
})
}
async function DistinctFor(key) {
if (!key) throw "Key Is Undefined";
try {
final[key] = await collection.distinct(key);
} catch (e) {
final[key] = 'failed';
throw e;
}
}
}
So querying a collection with the basic _id index, would return the following (test collection only has one document at the time of the test):
Mongo.MongoClient.connect(url, function (err, client) {
assert.equal(null, err);
let collection = client.db('my db').collection('the targeted collection');
GetFor(collection, '_id')
.then(function () {
//returns
// { _id: [ 5ae901e77e322342de1fb701 ] }
})
.catch(function (err) {
//manage your error..
})
});
Mind you, this uses methods native to the NodeJS Driver. As some other answers have suggested, there are other approaches, such as the aggregate framework. I personally find this approach more flexible, as you can easily create and fine-tune how to return the results. Obviously, this only addresses top-level attributes, not nested ones.
Also, to guarantee that all documents are represented should there be secondary indexes (other than the main _id one), those indexes should be set as required.

We can achieve this by Using mongo js file. Add below code in your getCollectionName.js file and run js file in the console of Linux as given below :
mongo --host 192.168.1.135 getCollectionName.js
db_set = connect("192.168.1.135:27017/database_set_name"); // for Local testing
// db_set.auth("username_of_db", "password_of_db"); // if required
db_set.getMongo().setSlaveOk();
var collectionArray = db_set.getCollectionNames();
collectionArray.forEach(function(collectionName){
if ( collectionName == 'system.indexes' || collectionName == 'system.profile' || collectionName == 'system.users' ) {
return;
}
print("\nCollection Name = "+collectionName);
print("All Fields :\n");
var arrayOfFieldNames = [];
var items = db_set[collectionName].find();
// var items = db_set[collectionName].find().sort({'_id':-1}).limit(100); // if you want fast & scan only last 100 records of each collection
while(items.hasNext()) {
var item = items.next();
for(var index in item) {
arrayOfFieldNames[index] = index;
}
}
for (var index in arrayOfFieldNames) {
print(index);
}
});
quit();
Thanks #ackuser

Following the thread from #James Cropcho's answer, I landed on the following which I found to be super easy to use. It is a binary tool, which is exactly what I was looking for:
mongoeye.
Using this tool it took about 2 minutes to get my schema exported from command line.

I know this question is 10 years old but there is no C# solution and this took me hours to figure out. I'm using the .NET driver and System.Linq to return a list of the keys.
var map = new BsonJavaScript("function() { for (var key in this) { emit(key, null); } }");
var reduce = new BsonJavaScript("function(key, stuff) { return null; }");
var options = new MapReduceOptions<BsonDocument, BsonDocument>();
var result = await collection.MapReduceAsync(map, reduce, options);
var list = result.ToEnumerable().Select(item => item["_id"].ToString());

This one lines extracts all keys from a collection into a comma separated sorted string:
db.<collection>.find().map((x) => Object.keys(x)).reduce((a, e) => {for (el of e) { if(!a.includes(el)) { a.push(el) } }; return a}, []).sort((a, b) => a.toLowerCase() > b.toLowerCase()).join(", ")
The result of this query typically looks like this:
_class, _id, address, city, companyName, country, emailId, firstName, isAssigned, isLoggedIn, lastLoggedIn, lastName, location, mobile, printName, roleName, route, state, status, token

I extended Carlos LM's solution a bit so it's more detailed.
Example of a schema:
var schema = {
_id: 123,
id: 12,
t: 'title',
p: 4.5,
ls: [{
l: 'lemma',
p: {
pp: 8.9
}
},
{
l: 'lemma2',
p: {
pp: 8.3
}
}
]
};
Type into the console:
var schemafy = function(schema, i, limit) {
var i = (typeof i !== 'undefined') ? i : 1;
var limit = (typeof limit !== 'undefined') ? limit : false;
var type = '';
var array = false;
for (key in schema) {
type = typeof schema[key];
array = (schema[key] instanceof Array) ? true : false;
if (type === 'object') {
print(Array(i).join(' ') + key+' <'+((array) ? 'array' : type)+'>:');
schemafy(schema[key], i+1, array);
} else {
print(Array(i).join(' ') + key+' <'+type+'>');
}
if (limit) {
break;
}
}
}
Run:
schemafy(db.collection.findOne());
Output
_id <number>
id <number>
t <string>
p <number>
ls <object>:
0 <object>:
l <string>
p <object>:
pp <number>

I was trying to write in nodejs and finally came up with this:
db.collection('collectionName').mapReduce(
function() {
for (var key in this) {
emit(key, null);
}
},
function(key, stuff) {
return null;
}, {
"out": "allFieldNames"
},
function(err, results) {
var fields = db.collection('allFieldNames').distinct('_id');
fields
.then(function(data) {
var finalData = {
"status": "success",
"fields": data
};
res.send(finalData);
delteCollection(db, 'allFieldNames');
})
.catch(function(err) {
res.send(err);
delteCollection(db, 'allFieldNames');
});
});
After reading the newly created collection "allFieldNames", delete it.
db.collection("allFieldNames").remove({}, function (err,result) {
db.close();
return;
});

I have 1 simpler work around...
What you can do is while inserting data/document into your main collection "things" you must insert the attributes in 1 separate collection lets say "things_attributes".
so every time you insert in "things", you do get from "things_attributes" compare values of that document with your new document keys if any new key present append it in that document and again re-insert it.
So things_attributes will have only 1 document of unique keys which you can easily get when ever you require by using findOne()

traversing js object properties adds quotes to strings in jade view

I'm using npm module traverse to filter data coming from mongodb / mongoose.
I might get this data:
[ { rating: 5,
title: { da: 'Web udvikling', en: 'Web Development' } },
{ rating: 5, title: { da: 'Node.js', en: 'Node.js' } } ]
'da' and 'en' indicates languages. I use traverse to filter mongoose data after current language like this:
var filtered = filterLanguage(lang, results);
// filter json obj by language
var filterLanguage = function(language, obj) {
return traverse(obj).map(function (item) {
if (this.key === language) {
this.parent.update(item);
}
});
};
I then show this in my template:
res.render('index', {
skills: filtered.skills
});
Finally I display it in the jade view:
ul.list-group
each skill, i in skills
if i < 5
li.list-group-item.sidebar-list-item= skill.title
Unfortunately it's displayed with quotes:
<ul>
<li>'Web Development'</li>
<li>'Node.js'</li>
</ul>
These quotes are not there in the unfiltered data (results.skill.title.da). So traverse is adding them. I used the module with 'plain' json and it's working perfectly.
The mongoose data seems plain and simple but of course there are a lot of properties on the prototype. Also traverse stalls if I don't omit '_id' (type bson/objectid) property from result set.
So traverse seems to have problems with mongoose data... Why is this? And how can I fix it?
-- EDIT --
I found a solution:
Before filtering I do this:
var json = JSON.parse(JSON.stringify(results));
var filtered = filterLanguage(lang, json);
This removes the quotes, but I'm not sure exactly what it does. Somehow converting the mongoose result to JSON? An explanation would be highly appreciated.

Fields in Mongoose documents are getters/setters, which seem to confuse either traverse or Jade/Pug.
The shortest method I found that seems to fix all of your issues is pretty ugly:
var filtered = filterLanguage(lang, results.map(r => JSON.parse(JSON.stringify(r))));
A more elaborate version:
var filtered = filterLanguage(lang, results.map(r => {
let j = r.toJSON()
j._id = j._id.toString()
return j;
}));

It would have been helpful to see what is the body of filterLanguage exactly or understand why it's called twice but as it stands, I don't think you need to use the traverse package at all.
A function such as below should do the trick and I even expanded it to work if the data is more tree-like and not as flat as represented in your example.
const reduceByLang = (data, lang) => {
// Look for a `lang` key in obj or
// if not found but still an object, recurse
const reduceByLangObj = (obj) => {
Object.keys(obj).forEach((key) => {
if (obj[key] === null) {
return;
}
if (obj[key][lang]) {
obj[key] = obj[key][lang]; // replace with desired lang
} else if (typeof obj[key] === 'object') {
reduceByLangObj(obj[key]); // recurse
}
});
return obj;
};
if (Array.isArray(data)) {
return data.map(reduceByLangObj);
} else {
return reduceByLangObj(data);
}
};
See example in JS Bin.
Also, if possible at all and if you do this type of selecting very often, I would look into saving the data in a different structure:
{ ratings: x, locales: { en: { title: 'Y' }, { da: { title: 'Z' } } } }
maybe, so that you can pick the selected language easily either in the query itself and/or in the controller.
EDIT: Checking for null.

Use function to rewrite JSON object keys?

I have a program and want to change the object key names in a JSON file with a function. I have already created a function that changes the keys when it is displayed via Angular, but I want to create a function that allows me to change the object key names directly in the JSON file.
Here is a sample of my JSON file ( the actual array contains over 300 entries ):
[
{
"FIELD1":"key",
"FIELD2":"company",
"FIELD3":"team",
"FIELD4":"num_female_eng",
"FIELD5":"num_eng",
"FIELD6":"percent_female_eng",
"FIELD7":"last_updated",
"FIELD8":"Submit more data!",
"FIELD9":"https://github.com/triketora/women-in-software-eng"
},
{
"FIELD1":"all",
"FIELD2":"ALL",
"FIELD3":"N/A",
"FIELD4":"2798",
"FIELD5":"14810",
"FIELD6":"18.89",
"FIELD7":"11/18/2015",
"FIELD8":"",
"FIELD9":""
},
{
"FIELD1":"wellsfargo",
"FIELD2":"Wells Fargo",
"FIELD3":"N/A",
"FIELD4":"1296",
"FIELD5":"5407",
"FIELD6":"23.97",
"FIELD7":"7/22/2015",
"FIELD8":"",
"FIELD9":""
}
]
and what I have done thus far to change the key names:
(function() {
'use strict';
angular
.module("app.companies")
.controller('CompaniesCtrl', CompaniesCtrl);
CompaniesCtrl.$inject = ['$scope', 'CompanyFactory'];
function CompaniesCtrl($scope, CompanyFactory) {
$scope.work = "i work";
$scope.companies = CompanyFactory;
$scope.makeChart = function(company){
$scope.femaleDevs = parseInt(company.num_female_eng);
$scope.allDevs = parseInt(company.num_eng);
$scope.company = company.company;
$scope.maleDevs = $scope.allDevs - $scope.femaleDevs;
console.log($scope.maleDevs);
};
}
})();
Thank you for all of your help :) !

Maybe this should help you:
var fieldsmap = {
'FIELD1': 'key',
'FIELD2': 'company',
'FIELD3': 'team',
'FIELD4': 'num_female_eng',
'FIELD5': 'num_eng',
'FIELD6': 'percent_female_eng',
'FIELD7': 'last_updated',
'FIELD8': 'name2',
'FIELD9': 'name3'
};
function renameObjectKeys(obj) {
for (var key in fieldsmap) {
if (obj.hasOwnProperty(key) && fieldsmap.hasOwnProperty(key)) {
obj[fieldsmap[key]] = obj[key]; //copy the key into new key
delete(obj[key]); // delete old key
}
}
}
myArray.forEach(function(object) {
renameObjectKeys(object);
});