So I have this:
https://jsfiddle.net/ysr50m2m/1/
Html
class="photoset">
<img src="http://inspirebee.com/wp-content/uploads/2013/04/animal-fashion-parade.jpg" />
<img src="http://www.fubiz.net/wp-content/uploads/2013/03/Fashion-Zoo-Animals18.jpg" />
<img src="http://inspirebee.com/wp-content/uploads/2013/04/animal-in-fashion.jpg" />
<img src="http://www.fubiz.net/wp-content/uploads/2013/03/Fashion-Zoo-Animals20.jpg" />
</div>
<div class="photoset">
<img src="http://www.fubiz.net/wp-content/uploads/2013/03/Fashion-Zoo-Animals26.jpeg" />
<img src="http://www.fubiz.net/wp-content/uploads/2013/03/Fashion-Zoo-Animals14.jpg" />
<img src="http://inspirebee.com/wp-content/uploads/2013/04/animal-fashion.jpg" />
<img src="https://framboisemood.files.wordpress.com/2013/04/fashion-zoo-animals13.jpg" />
<img src="http://www.fubiz.net/wp-content/uploads/2013/03/Fashion-Zoo-Animals9.jpg" />
</div>
CSS
.photoset > img:not(:first-child) {
display: none;
}
JavaScript
$(document).ready(function() {
$('.photoset').each(function(){
$(this).data('counter', 0);
});
var showCurrent = function(photoset) {
$items = photoset.find('img');
var counter = photoset.data('counter');
var numItems = $items.length;
var itemToShow = Math.abs(counter % numItems);
$items.fadeOut();
$items.eq(itemToShow).fadeIn();
};
$('.photoset').on('click', function(e) {
e.stopPropagation();
var photoset = $(this);
var pWidth = photoset.innerWidth();
var pOffset = photoset.offset();
var x = e.pageX - pOffset.left;
if (pWidth / 2 > x) {
photoset.data('counter', photoset.data('counter') - 1);
showCurrent(photoset);
} else {
photoset.data('counter', photoset.data('counter') + 1);
showCurrent(photoset);
}
});
});
and I want the images to overlap. When I click an image, the next one appears first on the bottom and then it appears in place of the first image.
How can I solve this issue? Thanks in advance.
Since 2 elements can't occupy the same position unless they're positioned to do so, I absolutely placed the other image above the previous one, and when the previous one disappears, I removed the absolute positioning.
Fiddle:
https://jsfiddle.net/qu1Lxjo1/
CSS:
.photoset {
position: relative;
}
.photoset img {
position: relative;
top: 0px;
left: 0pxx
}
JS:
$items.fadeOut();
$items.eq(itemToShow).fadeIn({done: function() {
$(this).css('position','relative')
}}).css('position', 'absolute');
};
Related
So I have to code a button that uses z-index to go to the next picture in the slideshow. I am having difficulty trying to get it to work and I feel as though I am doing something wrong. It has to have a count of 0, 1, 2, 0, 1, 2
<!DOCTYPE html>
<html lang = "en">
<head>
<title>Lab 5, Part 1</title>
<meta charset = "utf-8"/>
<script type = "text/javascript">
function Next() {
document.getElementById('anime1').style.zIndex = 0;
document.getElementById('anime2').style.zIndex = 1;
document.getElementById('anime3').style.zIndex = 2;
}
</script>
<style type = "text/css">
.anime1 {position: absolute;
top: 150px; left: 250px; z-index: 10;}
.anime2 {position: absolute;
top: 200px; left: 300px; z-index: 15;}
.anime3 {position: absolute;
top: 250px; left: 350px; z-index: 20;}
</style>
</head>
<body>
<h1 style= "text-align: center">Lab 5, Part 1</h1>
<p>
<div class="slideshow">
<img class = "anime1" id = "anime1" height = "300"
width = "450" src = "http://images5.fanpop.com/image/photos/29300000/Megurine-Luka-megurine-luka-29391390-1680-1050.jpg"
alt = "First Image"/>
<img class = "anime2" id = "anime2" height = "300"
width = "450" src = "http://orig06.deviantart.net/a28f/f/2015/079/9/a/hinata_final_lr_by_artgerm-d8me6vb.jpg"
alt = "Second Image"/>
<img class = "anime3" id = "anime3" height = "300"
width = "450" src = "http://images6.fanpop.com/image/photos/35700000/Hatsune-Miku-snowangel_-35736242-1600-1200.jpg"
alt = "Third Image"/>
</p>
<input type="button" value="Next" onclick="Next();">
</body>
</html>
I have looked every where online to see if anything could help me but I can't find anything
If you're willing to take a more programmatic approach, you can use an array to hold the order and iterate it to set the z-indexes.
Using this method you can
pop() the item from the end of the array and unshift() it onto the beginning, or
shift() the item from the beginning of the array and push() it onto the end.
Which allows you to easily handle any number of elements while keeping your code DRY.
I've taken the liberty of making a back button as well as the next button, to show you how easy it is when approaching it this way. I've also generalized the class names and used different placeholder images for the demo.
(function(){ // keep it safe
var slideshow = document.querySelector('.slideshow'); // store the parent
var controls = slideshow.querySelector('.controls'); // store the controls
var els = slideshow.querySelectorAll('.slide'); // store the slides
var order = Object.keys(els); // store the order
var cn; // make the class holder
// assign a click handler to the parent
controls.onclick = function(e) {
// if the class is back or next, store it, otherwise stop here
if(!(cn = (e.target.className.match(/back|next/)||[false])[0])) return;
// if back clicked, move the last element to the beginning
if(cn === "back") order.unshift(order.pop());
// if next clicked, move the first element to the end
if(cn === "next") order.push(order.shift());
// iterate the order, set the z-index of each element sequentially
for(var i in order) els[order[i]].style.zIndex = i;
}
})();
.slides { position: relative; margin-top: 5px; }
.slide { position: absolute; }
.slide2 { top: 25px; left: 25px; }
.slide3 { top: 50px; left: 50px; }
<div class="slideshow">
<div class="controls">
<button class="back">Back</button>
<button class="next">Next</button>
</div>
<div class="slides">
<img class="slide slide1" src="http://placehold.it/150x150/f9fd42/fff">
<img class="slide slide2" src="http://placehold.it/150x150/42f9fd/fff">
<img class="slide slide3" src="http://placehold.it/150x150/fd42f9/fff">
</div>
</div>
Further Reading
Array.prototype.pop() (MDN)
Array.prototype.unshift() (MDN)
Array.prototype.shift() (MDN)
Array.prototype.push() (MDN)
Don't Repeat Yourself (Wikipedia)
Are you looking for something like this: https://jsfiddle.net/5L7jk73g/
var cnt = 0;
function Next() {
if (cnt == 0) {
document.getElementById('anime1').style.zIndex = 0;
document.getElementById('anime2').style.zIndex = 1;
document.getElementById('anime3').style.zIndex = 2;
cnt++;
} else if (cnt == 1) {
document.getElementById('anime1').style.zIndex = 1;
document.getElementById('anime2').style.zIndex = 2;
document.getElementById('anime3').style.zIndex = 0;
cnt++;
} else {
document.getElementById('anime1').style.zIndex = 2;
document.getElementById('anime2').style.zIndex = 0;
document.getElementById('anime3').style.zIndex = 1;
cnt = cnt - 2;
}
}
I have created a simple slider
html
<div id="sldvid1" class="slider" >
<img picnum="1" src="https://s3.amazonaws.com/qa.SentientPrime.media/Ecommerce/44c068f106659d396f1ea0f2401f3879/1/thumbnail1.png" />
<img picnum="2" style="display:none;" src="https://s3.amazonaws.com/qa.SentientPrime.media/Ecommerce/44c068f106659d396f1ea0f2401f3879/1/thumbnail7.png" />
<img picnum="3" style="display:none;" src="https://s3.amazonaws.com/qa.SentientPrime.media/Ecommerce/44c068f106659d396f1ea0f2401f3879/1/thumbnail14.png" />
</div>
<hr>
<div id="sldvid2" class="slider" >
<img picnum="1" src="https://s3.amazonaws.com/qa.SentientPrime.media/Ecommerce/44c068f106659d396f1ea0f2401f3879/1/thumbnail1.png" />
<img picnum="2" style="display:none;" src="https://s3.amazonaws.com/qa.SentientPrime.media/Ecommerce/44c068f106659d396f1ea0f2401f3879/1/thumbnail7.png" />
<img picnum="3" style="display:none;" src="https://s3.amazonaws.com/qa.SentientPrime.media/Ecommerce/44c068f106659d396f1ea0f2401f3879/1/thumbnail14.png" />
</div>
$
var timer1 = setInterval(runSlide, 1000);
var curnum = 1;
function runSlide()
{
curnum = $(".slider img:visible").attr('picnum');
//$("#sldvid1 img[picnum=" + curnum + "]").fadeOut();
if(curnum == 3){
curnum = 1;
}
else
{
curnum++;
}
// $(".slider img").hide();
//$(".slider img[picnum=" + curnum + "]").show();
$(".slider img").hide();
$(".slider img[picnum=" + curnum + "]").show();
//console.log(curnum);
}
CSS
.slider{
height:50px;
}
Demo
http://jsfiddle.net/mparvez1986/vf401e2y/
Everything is working fine, I just need some one to improve effect so that it could effect like moving from left to right, I tried with some effect, but it seems it required some css manipulation as well
Thanks
I modified your code to create a carousel where images are slid in and out. I accomplished this by animating the margin-left CSS property with jQuery. I specified a size for the .slider class and used overflow: hidden; to ensure the sliding images were not displayed outside of it.
If you wish, you can change the transition effect by changing the CSS property that is animated and ensuring that the elements are in the correct position for the animation before it begins.
You can also change the speed of the animation by changing the magic number 1000 that I've left in the calls to animate. This number is specified in milliseconds.
By the way, I should point out that while custom HTML attributes are allowed in HTML5 they should begin with data-; they are called data attributes.
jsfiddle
HTML
<div id="sldvid1" class="slider">
<img class="active" data-slide-to="0" src="https://s3.amazonaws.com/qa.SentientPrime.media/Ecommerce/44c068f106659d396f1ea0f2401f3879/1/thumbnail1.png"/>
<img data-slide-to="1" src="https://s3.amazonaws.com/qa.SentientPrime.media/Ecommerce/44c068f106659d396f1ea0f2401f3879/1/thumbnail7.png"/>
<img data-slide-to="2" src="https://s3.amazonaws.com/qa.SentientPrime.media/Ecommerce/44c068f106659d396f1ea0f2401f3879/1/thumbnail14.png"/>
</div>
<hr>
<div id="sldvid2" class="slider">
<img class="active" data-slide-to="0" src="https://s3.amazonaws.com/qa.SentientPrime.media/Ecommerce/44c068f106659d396f1ea0f2401f3879/1/thumbnail1.png"/>
<img data-slide-to="1" src="https://s3.amazonaws.com/qa.SentientPrime.media/Ecommerce/44c068f106659d396f1ea0f2401f3879/1/thumbnail7.png"/>
<img data-slide-to="2" src="https://s3.amazonaws.com/qa.SentientPrime.media/Ecommerce/44c068f106659d396f1ea0f2401f3879/1/thumbnail14.png"/>
</div>
CSS
.slider {
position: relative;
width: 50px;
height: 50px;
overflow: hidden;
}
.slider img {
display: none;
width: 100%;
position: absolute;
}
.slider .active {
display: inline-block;
}
.slider .sliding {
display: inline-block;
}
JavaScript
var timer = setInterval(runSlide, 2000);
function runSlide() {
// Slide each slider on the page.
$(".slider").each(function (index, element) {
// Get the elements involved in the slide.
var numChildren = $(this).children().length;
var activeChild = $(this).children(".active");
var activeSlideTo = $(activeChild).attr("data-slide-to");
var nextSlideTo = (parseInt(activeSlideTo) + 1) % numChildren;
var nextChild = $(this).find("*[data-slide-to=" + nextSlideTo + "]");
// Prepare for slide.
$(activeChild).css("margin-left", "0%");
$(nextChild).css("margin-left", "-100%");
$(activeChild).addClass("sliding");
$(nextChild).addClass("sliding");
$(activeChild).removeClass("active");
// Slide using CSS margin-left.
$(activeChild).animate({"margin-left": "100%"}, 1000, function () {
$(this).removeClass("sliding");
});
$(nextChild).animate({"margin-left": "0%"}, 1000, function () {
$(this).addClass("active");
$(this).removeClass("sliding");
});
});
}
Ended with following
setInterval(function() {
$('#sldvid1 > img:first')
.fadeOut(1000)
.next()
.fadeIn(1000)
.end()
.appendTo('#sldvid1');
}, 3000);
i have 2 css classes , left side and right side of screen and i need to put them togheter, in these classes i have images which look like a puzzle:
By dragging image from the right side to the left side.At drop,must fit with the image from left side. I read about drag and drop but didnt find something like that :(
What i've tried?
EDIT: http://postimg.org/image/je31ptb6d/ (this is an example with my pictures.On top are images separated as classes - class="left" for ca and class="right" for nă.On bottom are images after i drop the image from right to one from left.My question is how to specify the correct drop zone to make images look like bottom one from link after i drop image from right side? )
JS/Jquery:
// shuffle function for right side only
$(document).ready(function() {
var a = $(".right > img").remove().toArray();
for (var i = a.length - 1; i >= 1; i--) {
var j = Math.floor(Math.random() * (i + 1));
var bi = a[i];
var bj = a[j];
a[i] = bj;
a[j] = bi;
}
$(".right").append(a);
});
// drag and drop
$(function() {
$( ".right img" ).draggable
({
cursor: 'move',
revert: 'invalid',
});
$( ".left img" ).droppable({
tolerance: 'fit',
});
});
HTML:
<div class="left">
<img class="piese" id="piesa1" src="images/Text_1.svg" />
<img class="piese" id="piesa2" src="images/Text_2.svg" />
<img class="piese" id="piesa3" src="images/Text_3.svg" />
<img class="piese" id="piesa4" src="images/Text_4.svg" />
</div>
<div class="right">
<img class="piese" id="piesa5" src="images/Text_5.svg" />
<img class="piese" id="piesa6" src="images/Text_6.svg" />
<img class="piese" id="piesa7" src="images/Text_7.svg" />
<img class="piese" id="piesa8" src="images/Text_8.svg" />
</div>
To solve your problem you must build a grid
and use drag drop by taking as a reference the location of the squares of the grid.
This is a simple example to give you an idea.
<!DOCTYPE HTML>
<html>
<head>
<title>Example</title>
<style>
#grid{
background-color: #09F;
height: 130px;
width: 390px;
position:relative;
margin:100px auto;
}
.square{
height: 128px;
width: 128px;
border:1px solid #999;
float:left;
}
#first-image{
position: absolute;
left: 0px;
}
#second-image{
position: absolute;
right: 0px;
}
</style>
</head>
<body>
<!--take two images by 120px with this class and id -->
<div id="grid">
<img class="dr" id="first-image" src="your-image.png" width="128" height="128">
<img class="dr" id="second-image" src="your-image.png" width="128" height="128">
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script>
$(document).ready(function(){
for(xx = 0; xx < 3; xx++) {
$("#grid").append($('<div class="square"></div>'));
};
$('.dr').on("dragstart", function (event) {
var dt = event.originalEvent.dataTransfer;
dt.setData('Text', $(this).attr('id'));
});
$('div.square').on("dragenter dragover drop", function (event) {
event.preventDefault();
if (event.type === 'drop') {
var data = event.originalEvent.dataTransfer.getData('Text',$(this).attr('id'));
de=$('#'+data).detach();
var x = $(this).position().left;
var y = $(this).position().top;
de.css({'position':'absolute','top':y+'px','left':x+'px'}).appendTo($(this));
};
});
});
</script>
</body>
</html>
HTML
<div id="slider">
<img src="http://www.alleywatch.com/wp-content/uploads/2013/04/brand.jpeg" id="image1" />
<img src="http://www.ereleases.com/prfuel/wp-content/uploads/2012/07/brand_stamp.jpg" id="image2" />
<img src="http://www.submitedge.com/blog/wp-content/uploads/2013/04/Creating-a-Positive-Brand-Image.jpg" id="image3" />
</div>
<div id="slider-back"></div>
CSS
#slider {
height:296px;
overflow:hidden;
width:822px;
position:absolute;
left:50%;
margin-left:-411px;
top:87px;
z-index:20;
}
#slider-back {
position:absolute;
left:50%;
margin-left:-411px;
height:296px;
z-index:29;
top:87px;
width:822px;
background: url("/test/backimage.png") no-repeat scroll 0px 0px transparent;
jquery
$(document).ready(function () {
var imgs = $('#slider > a > img');
var z = 1;
var previousImageId = "";
$(imgs[0]).show();
function loop(ev) {
imgs.delay(5000).slideUp('slow').eq(z).slideDown(500, function () {
check = z != imgs.length - 1 ? z++ : z = 0;
loop();
});
}
loop();
});
I tried in fiddle
http://jsfiddle.net/ee9R6/
I want to output like
http://www.lulupu.com/ (Right side our manufactures modlue vertical slider)
I would go a slightly different route
http://jsfiddle.net/ee9R6/4/
Instead of sliding all of the elements up, which ends up queuing the slide down, you can slide up the current img and slide down the next image at the same time.
function loop(ev) {
$(imgs[z]).slideUp("slow");
check = z != imgs.length - 1 ? z++ : z = 0;
$(imgs[z]).slideDown("slow");
setTimeout(loop, 5000);
}
I have created the following slideshow in javascript. But for some reason on the first slide through of images, the first image just moves off and the second image does the "sliding". Any help would be appreciated. I have included comments to help make the code more readable.
<!DOCTYPE html>
<html>
<head>
<title></title>
<style type="text/css">
img.pic {
position: absolute;
height: 768px;
width: 1024px;
}
html, body {
background-color:#3b3b35;
width: 1024px;
height: 768px;
margin: 0;
padding: 0;
overflow:hidden;
}
</style>
</head>
<body onload="startImages()">
<img class="pic" id="slide0" src="1.jpg" alt="pic1" />
<img class="pic" id="slide1" src="2.jpg" alt="pic2" />
<img class="pic" id="slide2" src="3.jpg" alt="pic3" />
<img class="pic" id="slide3" src="4.jpg" alt="pic4" />
<img class="pic" id="slide4" src="5.jpg" alt="pic5" />
<img class="pic" id="slide5" src="6.jpg" alt="pic6" />
<img class="pic" id="slide6" src="7.jpg" alt="pic7" />
<img class="pic" id="slide7" src="8.jpg" alt="pic8" />
<img class="pic" id="slide8" src="9.jpg" alt="pic9" />
<img class="pic" id="slide9" src="10.jpg" alt="pic10" />
<script type="text/javascript">
// Define the x start variable
var xstart = 0;
// Constructor for an image object:
function Image(obj, x) {
this.object = obj;
this.xpos = x;
}
// Image array
var Images = [];
// Sets up the images
function startImages() {
for (var Imageamount = 0; Imageamount < 10; Imageamount++) {
var Imgstore = document.getElementById("slide" + Imageamount);
// Puts image in the array
Images[Imageamount] = new Image(Imgstore, xstart);
xstart = xstart - 1024;
}
// Controlls the delays
setInterval(function () {
var val = 0;
var Interval = setInterval(function () {
imSlide();
val++;
if (val == 16) clearInterval(Interval); // 16*64 = 1024, ie image size
}, 30);
}, 5000);
}
function imSlide() { // Controlls sliding
for (var Slide = 0; Slide < Images.length; Slide++) {
var image = Images[Slide];
// Update + 64 to give a smooth slide. Updates 16 times so 16*64=1024
var x = image.xpos + 64;
// Move image from far right back to front of image stack
if (x == 5120) {
x = -5120;
}
// Store position back in array
image.xpos = x;
// Move the image
image.object.style.left = x + "px";
}
}
</script>
</body>
</html>
The reason that your slide show skips on the first interval is because you aren't setting the image's position when you first create your Image objects; you're only setting a variable that you have named 'xpos'. This causes all your images to overlap each other and display the last image, #slide9, on top of the others on page load.
modify your Image object declaration to this:
function Image(obj, x) {
this.object = obj;
this.xpos = x;
this.object.style.left = x + "px"; //<--- this is the new part
}
here is the jsfiddle: http://jsfiddle.net/w9qQx/4/