I have a page that has a JavaScript function that uses Post to send a variable to a php file. The problem is, that I am using "header" to download the file and my JS does not open the PHP script in a new page.
When I open the php file in a new page, it does not receive the needed variable from the JS.
I know it sounds confusing, but I hope my code can shed some light on my problem.
The short version is, I am trying to download a file that is selected by a radiobutton. I use JS to check which radiobutton is checked and then send that to my php file. Which then needs to download the file.
Thank you all in advance.
PHP:
<?php
if (isset($_POST['routenumber'])) {
if(!isset($_SESSION)){session_start();}
$routenumber = (isset($_POST['routenumber']) ? $_POST['routenumber'] : null);
$directory = ("Users/".$_SESSION['id']."/SavedRoutes/");
$routes = scandir($directory);
sort($routes);
$route = $routes[$routenumber];
$file =("Users/".$_SESSION['id']."/SavedRoutes/".$route);
header("Content-type: application/gpx+xml");
// header("Content-Disposition: attachment;Filename=".json_encode($route).".gpx");
header("Content-Disposition: attachment;Filename=route.gpx");
readfile($file);
}
?>
JS:
function fuAccountDownloadRoute(){
var i=2;
var SelectedRadio
while (i < routecounter){
var str1='radio';
var str2=JSON.stringify(i);
var result = str1.concat(str2);
if (document.getElementById(result).checked){
SelectedRadio = result.slice(5);
}
i=i+1;
}
$.post('accountPage.php',{routenumber:SelectedRadio});
}
When you open the url: http://localhost/accountPage.php in your browser it makes a GET request. You should change all the $_POST to $_GET in your code if you want to make it possible, and then you can open it like this: http://localhost/accountPage.php?routenumber=3, though it's probably not what you really want.
Related
I am developing a web page using HTML, PHP and Javascript. I am using aWAMP server to develop on my local machine. It has one PHP function:
<?php
$file = fopen("Records.txt","r");
$line = fgets($file);
fclose($file);
?>
It has one line of code within the Javascript portion to retrieve $line:
let fullstring = <?php echo json_encode($line); ?>;
It works fine using WAMP. If I view the source I see that the above line is:
let fullstring = "Record1,Record2,Record3,Record4,Record5,Record6";
I then uploaded the file to GoDaddy and it fails. I see this instead:
let fullstring = false;
Anyone know why? Is there a different way to retrieve a PHP variable via Javascript? Eventually I need to change this because the variable $line value should not be exposed to the user.
I wan't to know "How to show only image on the url not other content even html?". Like see this url link of Image. This url only shows image not any other content on webpage and also see the url of website it's dynamic url not a specific image url.
So, how to achieve that?
You simply make the request to the URL of the image.
For example, if your image is called test1.png and you have it in a directory called images, you would make the URL like this:
https://your.domain/images/test1.png
If you want to hide the full path to the images and serve them through a page (so you have some control over the request for some reason), you can do something more like the following. Let's call the PHP page img.php. And the request could be like
https://your.domain/img.php/test1
<?php
$request = './default.png';
if (isset($_SERVER['PATH_INFO'])){
$request = './images'.$_SERVER['PATH_INFO'].'.png';
if (! file_exists($request)){
$request = './default.png';
}
}
// we now know we have a valid request and the file was found
header('Content-type: image/png');
header('Content-Length: '.filesize($request));
echo file_get_contents($request);
exit;
?>
With this approach you could have any number of images in the /images/ directory and serve them if they match the request.
The website in your sample maybe using the same $_SERVER['PATH_INFO'] info approach but would be dynamically creating the image using the passed variables and explode('/',$_SERVER['PATH_INFO']) along with imagecreate()
A very quick hack version would be something like the following. The request would be like this:
https://your.domain/test.php/100x50/919/222
And the very quick code, with almost no error checking could be:
<?php
function hexToColor($hx){
$rgb = array(0,0,0);
if (strlen($hx) == 3){
$rgb[0] = hexdec($hx[0].$hx[0]);
$rgb[1] = hexdec($hx[1].$hx[1]);
$rgb[2] = hexdec($hx[2].$hx[2]);
} else {
$rgb[0] = hexdec($hx[0].$hx[1]);
$rgb[1] = hexdec($hx[2].$hx[3]);
$rgb[2] = hexdec($hx[4].$hx[5]);
}
return $rgb;
}
// default values
$sizeW = 100;
$sizeH = 100;
$bg = array(0,0,0);
$fg = array(255,255,255);
if (isset($_SERVER['PATH_INFO'])){
$opts = explode('/',substr($_SERVER['PATH_INFO'],1));
$bgSet = false;
foreach($opts as $k => $v){
// check for a width x height request
if (strpos($v,'x')){
$tmp = explode('x',$v);
$sizeW = $tmp[0];
$sizeH = $tmp[1];
} elseif ($bgSet){
// must be a foreground request
$fg = hexToColor($v);
} else {
$bg = hexToColor($v);
$bgSet = true;
}
}
}
header("Content-Type: image/png");
$im = #imagecreate($sizeW,$sizeH)
or die("Cannot Initialize new GD image stream");
$background_color = imagecolorallocate($im,$bg[0],$bg[1],$bg[2]);
$text_color = imagecolorallocate($im,$fg[0],$fg[1],$fg[2]);
imagestring($im,1,5,5,$sizeW.' x '.$sizeH,$text_color);
imagepng($im);
imagedestroy($im);
exit;
?>
But I would strongly recommend a heap of error checking before using that code!
As I understand you want to dynamically update the picture.
You can see that on their main website they created a form for the entered values:
After that, on the picture URL there are all the values you need to display this image:
https://dummyimage.com/600x400/8a1a8a/232dba&text=xzcxzcnbngh
which is this image:
what you can't see is their server side, which takes the parameters 600x400/8a1a8a/232dba&text=xzcxzcnbngh, creates a picture using their server and returning it to you.
I'll suggest you to create a server side that will return a picture and text based on the given parameters.
based on your server you will need to find out how to create the picture and return it.
As you can see here, I just modified the "src" value of the and it changed the text on the photo.
which means that their server receives the request and send back the image.
If you want a simple solution you could just send back those parameters to your page scripts, and create this image element using JavaScript.
That way, your html code will be clean without even the img element tag.
create your img in JS and send put it on the html body.
Image placeholder that’s updated by scripting
HTML code:
<img id="abc" src="">
Javascript code:
var abcImage = document.getElementById('abc');
abcImage.src = 'https://dummyimage.com/600x400/000/fff';
I'm trying to pass a variable ( n ) from a JS script to PHP thru the URL and get it to write said variable to a file. Unfortunately I can see the PHP script being called over the network, with the appropriate URL and with 200 status, but it doesn't seem to be executing. The file it should be writing to never changes. The disk is not full, the file is not in use by another process and the file it is writing to has completely open permissions as a testing measure. Hopefully this is a simple fix, thanks in advance.
<?php
$my_file='count.txt';
$count= $_GET['n'];
$handle = fopen($my_file, 'w');
fwrite($handle, $count);
fclose($handle);
?>
Examples of requests being sent
Your code is working fine and its writing whatever value for n is passed. however it keeps on overwriting previous value for every new request.
$handle = fopen($my_file, 'w');
In 'w' mode it create new file for read and write while placing pointer at the beginning.
Use 'w+' mode this places the pointer at the end of file.
$handle = fopen($my_file, 'w+');
For more details on files you can check below url for different modes and other functions
http://php.net/manual/en/function.fopen.php
I want to take the image data from my canvas on the client and save it as a .png on my server.
This is the code on my client that gets the image data from the canvas and sends it to saveImage.php:
function render()
{
var imageData = ctx.canvas.toDataURL("image/png");
var postData = "imageData="+imageData;
var ajax = new XMLHttpRequest();
ajax.open("POST","saveImage.php",true);
ajax.setRequestHeader("Content-Type","application/x-www-form-urlencoded");
ajax.onreadystatechange=function()
{
console.log(ajax.responseText);
}
ajax.send(postData);
}
And this is what saveImage.php looks like:
<?php
if(isset($_POST["imageData"]))
{
$imageEncoded = $_POST["imageData"];
$imageDataExploded = explode(',', $imageEncoded);
$imageDecoded = base64_decode($imageDataExploded[1]);
$filename = time()."image".mt_rand();
$file = fopen("./".$filename.".png","wb");
fwrite($file, $imageDecoded);
fclose($file);
echo $filename;
exit();
}
?>
The code actually works fine, my problem is just that the images that gets created are faulty in some way.
When I try to open one, windows says that it cant show me the image because it doesn't support the format? even though its a .png?
what am I doing wrong here?
You should be encoding your data with encodeURIComponent() before including it in POST data.
You should also be using a framework like jQuery to account for browser differences. I guarantee that code will not work the same in all browsers.
On the PHP, try looking into file_put_contents() for writing data. Much quicker to type!
Have you checked what is actually being sent over HTTP? $imageEncoded probably starts with data:image/png;base64,xxxxx
Strip everything up to the comma after base64:
https://stackoverflow.com/a/15153931/3766670
I'm making a PHP script for a JavaScipt site I've made.
The goal is to save the contents of a string as an HTML file when I click a button.
I'm using jQuery to make a Post request.
I'm using an Ubuntu OS with an Apache 2 server. The folder I'm writing to has permissions 777 (for testing only, will repeal this).
A requirement is the PHP must live in another file.
The issue is whenever I make the request, the file saves blank.
A requirement is each filename must be a timestamp. The file has the correct file name, but not contents.
So far, here is my code:
<?php
$fileName = $_GET['fileNameData'];
$htmlImport = $_GET['htmlToSaveData'];
$htmlToSave = (string)$htmlImport;
$myFile = fopen($fileName, "w") or die('You do not have write permissions');
//fwrite($myFile, $htmlToSave);
file_put_contents($myFile, $htmlToSave);
fclose($myFile);
?>
I've tried the frwite function that I've commented out, same effect.
I have tested this in terminal by passing in arguments ($argv[1] and $argv[2]). That works fine.
The JS I've made to run my site looks like:
var newURL = 'saveHTML.php/?fileNameData=' + fileName + '&htmlToSaveData=' + htmlToSave
$.post(newURL)
.done(function(){
alert('Your file saved as ...' + htmlToSave)
})
I've also tried this code, with the same result:
$.post('saveHTML.php/', {
fileNameData : fileName,
htmlToSaveData : htmlToSave
})
Both the fileName and htmlToSave are strings, although htmlToSave is rather long and is actually html text that I've converted to a string.
Does anyone have ideas about what's going on here? I'm not a PHP developer at all.
I'm using a callback so I can be sure I've collected all my html before I pass the string to PHP.
I've read and tested the recommendations on this question here and this has been fruitless.
EDIT Don't be alarmed about the code, I realise it's a security issue but this is a learning project and this will not be in production.
I can see right off the bat that you have
$myFile = fopen($fileName, "w") or die('You do not have write permissions');
//fwrite($myFile, $htmlToSave);
file_put_contents($myFile, $htmlToSave);
fclose($myFile);
file_put_contents takes a file name, not a handle. So you would only need
file_put_contents($fileName, $htmlToSave);
Edit: I also feel like I should point out that you should not allow your users to name your files. They could potentially do some nasty stuff to your machine.