This question already has answers here:
Replace method doesn't work
(4 answers)
Closed 4 years ago.
I am trying to replace a single dash '-' character in a string with double dashes.
2015–09–01T16:00:00.000Z
to be
2015-–09-–01T16:00:00.000Z
This is the code I am using but it doesn't seem to be working:
var temp = '2015–09–01T16:00:00.000Z'
temp.replace(/-/g,'--')
In JavaScript Strings are immutable. So, when you modify a string, a new string object will be created with the modification.
In your case, the replace has replaced the characters but returns a new string. You need to store that in a variable to use it.
For example,
var temp = '2015–09–01T16:00:00.000Z';
temp = temp.replace(/–/g,'--');
Note The string which you have shown in the question, when copied, I realised that it is a different character but looks similar to – and it is not the same as hyphen (-). The character codes for those characters are as follows
console.log('–'.charCodeAt(0));
// 8211: en dash
console.log('-'.charCodeAt(0));
// 45: hyphen
The hyphen character – you have in the string is different from the one you have in the RegExp -. Even though they look alike, they are different characters.
The correct RegExp in this case is temp.replace(/–/g,'--')
Probably the easiest thing would be to just use split and join.
var temp = '2015–09–01T16:00:00.000Z'.split("-").join("--");
Related
This question already has answers here:
Javascript/regex: Remove text between square brackets
(4 answers)
Closed 5 months ago.
In short i need to replace every occurrence of text betweeen brackets including the brackets in a string, and the text to be replaced will be in a variable in Javascript.
A simple regex in a replace method wont work because of the brackets.
Example, replace "[test] [teste] test [hello]" with a variable with the value of "hi".
Output: "hi hi test [hello]"
"[test] [teste] test".replace(/\[.*?\]/g, 'hi')
escape the brackets with "\" and use g flag
edit: removed the i flag and chnaged w to . to handle anything inside brackets
I'm not quite sure what you're looking for but .match will store off the matches in an array and .replace will perform the replace for you.
const regex = /\[.*?\]/g;
var mutable = "[test] [teste] test";
const matches = mutable.match(regex); // Save all matches to an array
mutable = mutable.replace(regex, 'dude'); // Replace matches
console.log(mutable);
console.log(matches);
So, the way i found to do it was to get my variable to be replaced, example:
var test= "[test]",
Then i replaced the brackets in it so it would become "\[test\]", then i used:
var regex = new RegExp(test+"+","gm")
then i used this regex in JS replace method.
This question already has answers here:
Replace forward slash "/ " character in JavaScript string?
(9 answers)
Why this javascript regex doesn't work?
(1 answer)
Closed 4 years ago.
I have a string field 01/01/1986 and I am using replace method to replace all occurrence of / with -
var test= '01/01/1986';
test.replace('//g','-')
but it does't give desire result. Any pointer would be helpful.
You just have a couple issues: don't put the regex in quotes. That turns it into a string instead of a regex and looks for that literal string. Then use \/ to escape the /:
var test= '01/01/1986';
console.log(test.replace(/\//g,'-'))
A quick way is to use split and join.
var test= '01/01/1986';
var result = test.split('/').join('-');
console.log(result);
Note too that you need to save the result. The original string itself will never be modified.
This question already has answers here:
Replace method doesn't work
(4 answers)
Closed 4 years ago.
I'm trying to further my understanding of regular expressions in JavaScript.
So I have a form that allows a user to provide any string of characters. I'd like to take that string and remove any character that isn't a number, parenthesis, +, -, *, /, or ^. I'm trying to write a negating regex to grab anything that isn't valid and remove it. So far the code concerning this issue looks like this:
var pattern = /[^-\+\(\)\*\/\^0-9]*/g;
function validate (form) {
var string = form.input.value;
string.replace(pattern, '');
alert(string);
};
This regex works as intended on http://www.infobyip.com/regularexpressioncalculator.php regex tester, but always alerts with the exact string I supply without making any changes in the calculator. Any advice or pointers would be greatly appreciated.
The replace method doesn't modify the string. It creates a new string with the result of the replacement and returns it. You need to assign the result of the replacement back to the variable:
string = string.replace(pattern, '');
This question already has answers here:
Replace method doesn't work
(4 answers)
Closed 4 years ago.
I have a simple string that I'm trying to manipulate:
Your order will be processed soon:
I grab the string using:
var html = jQuery('.checkout td h4').html();
I then try to replace the ':' using:
html.replace(":", ".");
When I print it out to the console, the string is the same as the original string. I've also tried making sure that the html variable is of type "string" by doing the following:
html = html + "";
That doesn't do anything. In searching around, it seems that the replace function does a RegEx search and that the ":" character might have a special meaning. I do not know how to fix this. Can someone help me get rid of this stinkin' colon?
Slightly related...
I couldn't get these answers to work to replace all ":" in a string for the url encoded character %3a and modified this answer by'xdazz' to work: Javascript: Replace colon and comma characters to get...
str = str.replace(/:\s*/g, "%3a");
In your case it would be
str = str.replace(/:\s*/g, ".");
If you wanted to replace all colons with periods on a longer string.
Hope this helps somebody else.
The replace function returns a new string with the replacements made.
Javascript strings are immutable—it cannot modify the original string.
You need to write html = html.replace(":", ".");
I think c++ is the only high level language where strings are mutable. This means that replace cannot modify the string it operates on and so must return a new string instead.
Try the following instead
var element = jQuery('.checkout td h4');
element.html(element.html().replace(":", "."));
Or, perhaps more correctly (since you may have multiple elements).
jQuery('.checkout td h4').html(
function (index, oldHtml) {
return oldHtml.replace(":", ".");
}
);
This question already has answers here:
Replace method doesn't work
(4 answers)
Closed 7 years ago.
var src = "http://blah.com/SOMETHING.jpg";
src.replace(/.*([A-Z])\.jpg$/g, "X");
at this point, shouldn't src be:
http://blah.com/SOMETHINX.jpg
If I use match() with the same regular expression, it says it matched. Regex Coach also shows a match on the character "G".
Try
src = src.replace(/.*([A-Z])\.jpg$/g, "X");
String#replace isn't a mutator method; it returns a new string with the modification.
EDIT: Separately, I don't think that regexp is exactly what you want. It says "any number of any character" followed by a captured group of one character A-Z followed by ".jpg" at the end of the string. src becomes simply "X".
The replace function doesn't change src.
I think what you want to do is:
src = src.replace(/.*([A-Z])\.jpg$/g, "X");
src.replace will replace the entire match "http://blah.com/SOMETHING.jpg", not just the part you captured with brackets.