This question already has answers here:
Convert string to Title Case with JavaScript
(68 answers)
Closed 7 years ago.
I'm trying to target the first letter of each word in a string. I'm working in JavaScript. I've found discussions for Python and PHP that don't address my problem specific to JavaScript.
str = "i'm a little tea pot"
regEx = /^.|\b[a-z]/g
I have a function that uppercases each letter the regEx finds. My result is the m after the apostrophe is capitalized. How do I avoid this?
After uppercase function:
I'M A Little Tea Pot"
Capitalize first letter of every word?
var string = prompt("Enter a string");
function capitalizeFirstWord(str) {
return str.split(/\s+/).map(function(word) {
return word[0].toUpperCase() + word.slice(1).toLowerCase();
}).join(' ');
}
document.getElementById("capitalized").innerHTML = capitalizeFirstWord(string);
<p id="capitalized"></p>
You split a string at a word boundary. As a parameter you pass in either an empty string or the whitespace character \s. This creates an array of all words in the sentence.
To get the first character, you can use word[0] or word.charAt(0). You then perform string concatenation with the rest of the string.
This gives you an entirely new array, which needs to be converted back to a string. Call the join method on this new array
You may use call-back function in str.replace.
var str = "i'm a little tea pot"
alert(str.replace(/(^|\s)([a-z])/g, function(match, group_1, group_2){return group_1 + group_2.toUpperCase()}))
And also if you want to convert the chars following the first char to lowercase then try this.
str.replace(/(^|\s)([a-z])(\S*)/g, function(x,y, z, a){return y + z.toUpperCase() + a.toLowerCase()})
Related
This question already has an answer here:
Why this javascript regex doesn't work?
(1 answer)
Closed 3 years ago.
Trying to replace everything inside brackets [ ] with an element of an array. Example:
function replacingText(){
var names = ["Cole", "Kyle", "Chase"];
var sentance = 'This is [Cole].'
var regex = "\[(.*?)\]/gm";
console.log(sentance.replace(regex, names[1]));
}
So the output should be 'This is Kyle.' instead of 'This is [Cole].'
The only thing that needs fixed is the regex string needs to be
var regex = /\[(.*?)\]/gm;
The /gm on the end just means it wont stop at the first one it finds and the "m" stands for multi-line matching.
The javascript string replace can accept both strings and regular expressions as the first argument. See the examples presented here.
In your case you are passing the first as a string of a regular expression: "\[(.*?)\]"
Instead you should either match the exact string sentence.replace("[Cole]", names[1]) or, what you probably want, is to use the regular expression to match any name sentence.replace(/\[.+\]/g, names[1]) (note that the first argument does not contain any quotes)
The /g (global) is used to match all occurrences in the sentence. Otherwise only the first occurrence would be replaced.
Could you try this :
function replacingText() {
var names = ["Cole", "Kyle", "Chase"];
var sentance = "This is [Cole] [ahmed]";
var regex = /\[([0-9]|[aA-zZ])*\]/g;
console.log(sentance.replace(regex, names[1]));
}
I just tried it and it works as expected
This question already has answers here:
Regular Expression to get a string between parentheses in Javascript
(10 answers)
Closed 4 years ago.
I have string like this:
var str = "Hello (World) I'm Newbie";
how to get World from string above using RegExp?, I'm sorry I don't understand about regex.
Thank's
Rather than using a regex - use .split()...Note the escaped characters in the splits. The first split gives "World) I'm Newbie" and the second gives "World".
var str = "Hello (World) I'm Newbie";
var strContent = str.split('\(')[1].split('\)')[0];
console.log(strContent); // gives "World"
Assuming that there will be atleast one such word, you can do it using String#match. The following example matches the words between parentheses.
console.log(
"Hello (World) I'm Newbie"
.match(/\(\w+\)/g)
.map(match => match.slice(1, -1))
)
This might help you for your regex
\w match whole world
+ plus with another regex
[] starts group
^ except
(World) matching word
var str = "Hello (World) I'm Newbie";
var exactword=str.replace(/\w+[^(World)]/g,'')
var filtered = str.replace(/(World)/g,'')
alert(exactword)
alert(filtered)
This question already has an answer here:
Javascript Regular Expression for hashtags with emoji
(1 answer)
Closed 4 years ago.
I have a corpus of text that I'm parsing with a regular expression to find the most common words. Currently I'm using .match(/(?!'.*')\b\[\w'\]+\b/g). My problem is that \w does not match on non-alphanumeric characters and my emoji never get parsed. Specifically, I'm trying to make a regex that will identify words (including contractions) and emoji, separating on the word boundary.
As an example I'd like to be able to take "Hey there! 👋, let's go to the moon 🌝🚀" and get
Array( "Hey", "there", "👋", "let's", "go", "to", "the", "moon", "🌝", "🚀")
To work around it you may find spread operator helpful:
var str = "Hey there! 👋, let's go to the moon 🌝🚀";
var words = [], word = '';
[...str].forEach(function(char) {
// Test if current char is an English letter, a digit or '
if (/[a-z0-9']/i.test(char)) {
word += char;
}
// Test if current char is a non-whitespce char out of ASCII
else if (/(?=\S)[^\u0000-\u007f]/.test(char)) {
words.push(char)
} else if (word !== '') {
// Add a word to words array
words.push(word)
word = '';
}
})
console.log(words);
With guidance from commenters, I was able to get the following pattern to work:
\b[\w']+\b|\uD83D(?:[\uDC76\uDC66\uDC67](?:\uD83C[\uDFFB-\uDFFF])?|\uDC68(?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92]|\u2708\uFE0F?|\uD83E[\uDDB0-\uDDB3]))?)|\u200D(?:\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D(?:\uDC69\u200D\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?)|\uDC68\u200D\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?)|\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?|[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92])|\u2708\uFE0F?|\uD83E[\uDDB0-\uDDB3]|\u2764(?:\uFE0F\u200D\uD83D(?:\uDC8B\u200D\uD83D\uDC68|\uDC68)|\u200D\uD83D(?:\uDC8B\u200D\uD83D\uDC68|\uDC68)))))?|\uDC69(?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92]|\u2708\uFE0F?|\uD83E[\uDDB0-\uDDB3]))?)|\u200D(?:\u2695\uFE0F?|\uD83C[\uDF93\uDFEB\uDF3E\uDF73\uDFED\uDFA4\uDFA8]|\u2696\uFE0F?|\uD83D(?:\uDC69\u200D\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?)|\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?|[\uDD27\uDCBC\uDD2C\uDCBB\uDE80\uDE92])|\u2708\uFE0F?|\uD83E[\uDDB0-\uDDB3]|\u2764(?:\uFE0F\u200D\uD83D(?:\uDC8B\u200D\uD83D[\uDC68\uDC69]|[\uDC68\uDC69])|\u200D\uD83D(?:\uDC8B\u200D\uD83D[\uDC68\uDC69]|[\uDC68\uDC69])))))?|[\uDC74\uDC75](?:\uD83C[\uDFFB-\uDFFF])?|\uDC6E(?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|\uDD75(?:(?:\uFE0F(?:\u200D(?:[\u2642\u2640]\uFE0F?))?|\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|[\uDC82\uDC77](?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|\uDC78(?:\uD83C[\uDFFB-\uDFFF])?|\uDC73(?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|\uDC72(?:\uD83C[\uDFFB-\uDFFF])?|\uDC71(?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|[\uDC70\uDC7C](?:\uD83C[\uDFFB-\uDFFF])?|[\uDE4D\uDE4E\uDE45\uDE46\uDC81\uDE4B\uDE47\uDC86\uDC87\uDEB6](?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|[\uDC83\uDD7A](?:\uD83C[\uDFFB-\uDFFF])?|\uDC6F(?:\u200D(?:[\u2642\u2640]\uFE0F?))?|[\uDEC0\uDECC](?:\uD83C[\uDFFB-\uDFFF])?|\uDD74(?:(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F))?|\uDDE3\uFE0F?|[\uDEA3\uDEB4\uDEB5](?:(?:\uD83C(?:[\uDFFB-\uDFFF](?:\u200D(?:[\u2642\u2640]\uFE0F?))?)|\u200D(?:[\u2642\u2640]\uFE0F?)))?|[\uDCAA\uDC48\uDC49\uDC46\uDD95\uDC47\uDD96](?:\uD83C[\uDFFB-\uDFFF])?|\uDD90(?:(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F))?|[\uDC4C-\uDC4E\uDC4A\uDC4B\uDC4F\uDC50\uDE4C\uDE4F\uDC85\uDC42\uDC43](?:\uD83C[\uDFFB-\uDFFF])?|\uDC41(?:(?:\uFE0F(?:\u200D\uD83D\uDDE8\uFE0F?)?|\u200D\uD83D\uDDE8\uFE0F?))?|[\uDDE8\uDDEF\uDD73\uDD76\uDECD\uDC3F\uDD4A\uDD77\uDD78\uDDFA\uDEE3\uDEE4\uDEE2\uDEF3\uDEE5\uDEE9\uDEF0\uDECE\uDD70\uDD79\uDDBC\uDDA5\uDDA8\uDDB1\uDDB2\uDCFD\uDD6F\uDDDE\uDDF3\uDD8B\uDD8A\uDD8C\uDD8D\uDDC2\uDDD2\uDDD3\uDD87\uDDC3\uDDC4\uDDD1\uDDDD\uDEE0\uDDE1\uDEE1\uDDDC\uDECF\uDECB\uDD49]\uFE0F?|[\uDE00-\uDE06\uDE09-\uDE0B\uDE0E\uDE0D\uDE18\uDE17\uDE19\uDE1A\uDE42\uDE10\uDE11\uDE36\uDE44\uDE0F\uDE23\uDE25\uDE2E\uDE2F\uDE2A\uDE2B\uDE34\uDE0C\uDE1B-\uDE1D\uDE12-\uDE15\uDE43\uDE32\uDE41\uDE16\uDE1E\uDE1F\uDE24\uDE22\uDE2D\uDE26-\uDE29\uDE2C\uDE30\uDE31\uDE33\uDE35\uDE21\uDE20\uDE37\uDE07\uDE08\uDC7F\uDC79\uDC7A\uDC80\uDC7B\uDC7D\uDC7E\uDCA9\uDE3A\uDE38\uDE39\uDE3B-\uDE3D\uDE40\uDE3F\uDE3E\uDE48-\uDE4A\uDC64\uDC65\uDC6B-\uDC6D\uDC8F\uDC91\uDC6A\uDC63\uDC40\uDC45\uDC44\uDC8B\uDC98\uDC93-\uDC97\uDC99-\uDC9C\uDDA4\uDC9D-\uDC9F\uDC8C\uDCA4\uDCA2\uDCA3\uDCA5\uDCA6\uDCA8\uDCAB-\uDCAD\uDC53-\uDC62\uDC51\uDC52\uDCFF\uDC84\uDC8D\uDC8E\uDC35\uDC12\uDC36\uDC15\uDC29\uDC3A\uDC31\uDC08\uDC2F\uDC05\uDC06\uDC34\uDC0E\uDC2E\uDC02-\uDC04\uDC37\uDC16\uDC17\uDC3D\uDC0F\uDC11\uDC10\uDC2A\uDC2B\uDC18\uDC2D\uDC01\uDC00\uDC39\uDC30\uDC07\uDC3B\uDC28\uDC3C\uDC3E\uDC14\uDC13\uDC23-\uDC27\uDC38\uDC0A\uDC22\uDC0D\uDC32\uDC09\uDC33\uDC0B\uDC2C\uDC1F-\uDC21\uDC19\uDC1A\uDC0C\uDC1B-\uDC1E\uDC90\uDCAE\uDD2A\uDDFE\uDDFB\uDC92\uDDFC\uDDFD\uDD4C\uDD4D\uDD4B\uDC88\uDE82-\uDE8A\uDE9D\uDE9E\uDE8B-\uDE8E\uDE90-\uDE9C\uDEB2\uDEF4\uDEF9\uDEF5\uDE8F\uDEA8\uDEA5\uDEA6\uDED1\uDEA7\uDEF6\uDEA4\uDEA2\uDEEB\uDEEC\uDCBA\uDE81\uDE9F-\uDEA1\uDE80\uDEF8\uDD5B\uDD67\uDD50\uDD5C\uDD51\uDD5D\uDD52\uDD5E\uDD53\uDD5F\uDD54\uDD60\uDD55\uDD61\uDD56\uDD62\uDD57\uDD63\uDD58\uDD64\uDD59\uDD65\uDD5A\uDD66\uDD25\uDCA7\uDEF7\uDD2E\uDD07-\uDD0A\uDCE2\uDCE3\uDCEF\uDD14\uDD15\uDCFB\uDCF1\uDCF2\uDCDE-\uDCE0\uDD0B\uDD0C\uDCBB\uDCBD-\uDCC0\uDCFA\uDCF7-\uDCF9\uDCFC\uDD0D\uDD0E\uDCA1\uDD26\uDCD4-\uDCDA\uDCD3\uDCD2\uDCC3\uDCDC\uDCC4\uDCF0\uDCD1\uDD16\uDCB0\uDCB4-\uDCB8\uDCB3\uDCB9\uDCB1\uDCB2\uDCE7-\uDCE9\uDCE4-\uDCE6\uDCEB\uDCE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which is basically word boundaries with all the emojis added in.
https://regex101.com/r/5rgYDx/3
This question already has answers here:
Convert string to Title Case with JavaScript
(68 answers)
Closed 7 years ago.
var string = "deceMber iS Here"
I tried this but I get an error saying it is not a function.
string.split(" ").toUpperCase()
I want output this way "December, Is, Here"
edit: This question is not a duplicate. I did lot of search and the links that provided did not meet my need. It is very specific question.
First make the string lowercase, then replace first letter of each word with the uppercase.
var string = "deceMber iS Here";
console.log(string.toLowerCase().replace(/(^|\s)([a-z])/g, function(m,p1,p2){ return p1+p2.toUpperCase(); }));
When you call string.split(" "), the result is an array of the substrings split by spaces. toUppercase() must be called on a string, not an array. This is why you are getting an error stating toUppercase() is not a function.
To capitalize the first letter in each of the split substrings, I'd see Sehab's recommendation: How do I make the first letter of a string uppercase in JavaScript?
With string.split(" ").toUpperCase(), what you're doing is splitting a string into an array (['deceMber'],['iS'],['Here']) and trying to toUpperCase() it. Array's don't have this method, hence the error message.
You need to loop through each element in this array, set it to lower case, and then capitalize the first letter. After this, you can join them together with a ", ".
var string = "deceMber iS Here"
var arr = string.split(" ");
for(var i = 0; i < arr.length; i++){
arr[i] = arr[i].toLowerCase();
arr[i] = arr[i].charAt(0).toUpperCase() + arr[i].slice(1);
}
str = arr.join(', ');
This question already has answers here:
JavaScript regex pattern concatenate with variable
(3 answers)
Closed 7 years ago.
I have a regex to check if a string contains a specific word. It works as expected:
/\bword\b/.test('a long text with the desired word amongst others'); // true
/\bamong\b/.test('a long text with the desired word amongst others'); // false
But i need the word which is about to be checked in a variable. Using new RegExp does not work properly, it always returns false:
var myString = 'a long text with the desired word amongst others';
var myWord = 'word';
new RegExp('\b' + myWord + '\b').test(myString); // false
myWord = "among";
new RegExp('\b' + myWord + '\b').test(myString); // false
What is wrong here?
var myWord = 'word';
new RegExp('\\b' + myWord + '\\b')
You need to double escape the \ when building a regex from a string.
This is because \ begins an escape sequence in a string literal, so it never makes it to the regex. By doing \\, you're including a literal '\' character in the string, which makes the regex /\bword\b/.