I am trying to to extract a Json response in jquery sent from a php file.
This is the .js code:
$.ajax({
url: 'index.php?page=register', //This is the current doc
type: 'POST',
datatype: 'json',
data: {'userCheck': username},
success: function(data){
// Check if username is available or not
},
error: function(){
alert('Much wrong, such sad');
}
});
This is the response from the php file:
if($sth->fetchColumn()!=0){
//$response = array("taken");
$response = array("username"=>"taken");
echo json_encode($response);
//echo '{"username':'taken"}';
}else{
//$response = array("available");
$response = array("username"=>"available");
echo json_encode($response);
//echo '{"username":"available"}';
}
I have tried all combinations I can think of in both files, but nothing seems to work. It is a simple check for a username in the database. If I console log the data I get from the response, I get this:
{"username":"available"}<!DOCTYPE html>
// The rest of the page html
So the info is there, but how do I access it? I have tried several syntaxes found around the internet, but no luck so far. I seem to recall that a json response only can contain valid json, so is the problem the html? I don't think I can avoid this due to the structure of my application, so hopefully it is possible to access the json with my present structure.
in you Ajax
EDIT:
change
datatype:"json",
the case of parameter name was not respected, the t must be T
dataType:"json",
now retry please
$.ajax
({
url: 'index.php?page=register', //This is the current doc
type: 'POST',
dataType: 'json',
data: {'userCheck': username},
success: function(data)
{
// Check if username is available or not
switch(data.username)
{
case "available":
// do you want
break;
case "taken":
// do you want
break;
}
},
error: function()
{
alert('Much wrong, such sad');
}
});
in PHP
simply that, and don't forget to exit; to avoid include html page in your json response !
This is the code coming after the }".... who break your json output
and make it unreadable by javascript (worste, it simply break your javascript !)
echo json_encode(["username"=> ($sth->fetchColumn()!=0) ? "taken":"available"]);
exit;
When you're responding to an AJAX call, you should just return the JSON response, not the HTML of the page. Add:
exit();
after this code so you don't display the HTML after the JSON.
In the JS code, use if (data.username == 'available') to tell whether the username is available.
The other problem in your code is that you have a typo here:
datatype: 'json',
It should be dataType, with an uppercase T.
You can also put:
header("Content-type: application/json");
before echoing the JSON in the script, and jQuery will automatically parse the response.
Also you can set request headers in your jQuery ajax call beforeSend function like follows
beforeSend: function (xhr) {
xhr.setRequestHeader('Content-Type', 'application/json;charset=utf-8');
xhr.setRequestHeader('Accept', 'application/json');
}
So you're strictly declaring the data type to be json
Related
I have had this error for multiple days now, I have tried searching this error up but whenever I search this error up it gives a different reason for the error and when I try to add what other sites say it doesn't work which is why I am asking here as I don't see what else I can do.
I am trying to pass a variable from JavaScript to PHP but it is not working and I have no idea why.
Here is my JavaScript code:
<head>
<script type="text/javascript" src="jquery.js"> </script>
</head>
<script>
var variable = "hello";
console.log(variable);
$.ajax
({
url: "ajax.php",
type: "POST",
data:{pass : variable},
success: function() {
alert("Success");
}
});
</script>
Here is my PHP code:
$variable = $_POST['pass'];
echo($variable);
Everything seems to work perfectly. It writes the variable to the console, it comes up with the alert saying success. However I get an error message saying: 'Undefined array key "pass"'
What is causing this? Thank you?
Edit: People have told me to use isset, I have added that it removed the error however it still does not echo the PHP variable, meaning it is still not been passed to PHP, I am still trying to find how to fix this.
Your front end code looks OK, but I don't know your target PHP environement, but maybe your environnement doesn't accept formData.
By default, jQuery send ajax POST data as formData.
Try to send data as JSON
$.ajax({
url: "ajax.php",
type: "POST",
data: JSON.stringify({pass : variable}),
dataType: "json",
contentType: "application/json; charset=utf-8",
success: function(data){alert(data);},
});
And then you will probably have to adapt your php code:
$json = file_get_contents('php://input');
// Converts it into a PHP array
$data = json_decode($json, true);
$variable = $data['pass'];
echo($variable);
Can you please use the developer tools in chrome browser that will help you to find if data is properly sent to php file.
Also you can try $_REQUEST instead of post just to check what data is coming in REQUEST as it works for GET & POST both. If it still does not help you.
Also can you please use
data: {'pass':variable}
instead of
data: {pass:variable}
let me know if it works for you.
If you get this error in your ajax.php file which you Post the data to it, I say it's normal because when you open that file (ajax.php) it's like that there is no $_POST['pass'] because you just opened that file without running JS to send data.
If you want to receive data that you send you can do this:
Your JS code I call this file index:
var variable = "hello";
$.ajax
({
url: "ajax.php",
type: "POST",
data:{pass : variable},
success: function(res) {
alert(res);
}
});
The PHP file:
$variable = $_POST['pass'];
echo($variable);
Then if You open up that index file, after running the JS code it'll send that post data to your PHP file and your PHP file will echo that, then the value will store in that res variable which when every thing went fine, you can see the alert of that res in the page (index file).
Notice that as I said you can't open up the PHP file lonely because it doesn't receive a post data on its own, it is normal for undefined to return.
Re: #puckloe your code is working, php echo wouldn't be printed with ajax(correction echo is working but wouldn't show on page if you don't print it with JS too), you have to catch the response in ajax success function ( like success: function(response) ) and print or alert the response --> success: function(response) { alert("hi look this is echo from php"+response) }
you ajax code should look like
$.ajax
({
url: "ajax.php",
type: "POST",
data:{pass : variable},
success: function(response) {
alert("hi look this is echo from php" + response);
}
});
I am building a currency converter app for my school project and at the moment I am trying to get data from the database into a .js file. The exact goal is to get data from the database and save it into an array within a .js file.
As far as I know there is no way to get data from the database directly into a JavaScript file, so I am trying to make use of JQuery and PHP combination as pointed out in this thread.
I have a database called 'currencies' which has six columns: id, basecur1, basecur2, basecur3, basecur4, basecur5.
id field is for user id, and basecur_ fields are for storing user's prefered currencies and can only contain three characters of a currency code (like USD or GBP) or be empty. I need to get a result looking like const array_name = ["EUR", "GBP", "USD"];
Please note that I am using CodeIgniter PHP framework for back-end.
In this file query.php I am trying to create an array from the data fetched from the database and echo it:
<?php
$current_user = $this->session->user_id;
$query = $this->db->get_where('currencies', array('id' => $current_user));
$row1 = $query->row();
$base_currencies = array($row1->basecur1, $row1->basecur2, $row1->basecur3, $row1->basecur4, $row1->basecur5);
$post_data = json_encode($base_currencies);
echo $post_data;
?>
Unfortunately, I don't have deep understanding of JavaScript, so I can't really say what's wrong with this JS code, which is taken from the thread mentioned above, but it doesn't really work for me:
jQuery.extend({
getValues: function(url) {
var result = null;
$.ajax({
url: url,
type: 'get',
dataType: 'json',
async: false,
success: function(data) {
result = JSON.stringify(data);
}
});
return result;
}
});
var array_name = $.getValues("query.php");
Any help will be much appreciated.
Because of these line you already have a valid json string:
$post_data = json_encode($base_currencies);
echo $post_data;
exit;
and since you already set the dataType: 'json' jquery will parse the result as a json string regardless of the header.
Thus:
success: function(data) {
result = data;
}
You can debug using console.log it is a valuable tool for learning and making sure you are getting what you want at various points in your code. As another user suggested, make sure you aren't getting any 404 errors in the console. query.php doesn't look like a valid CodeIgniter route.
In your php file.
header('Content-Type: application/json');
in your ajax function
success: function(response){
console.log(resposne)
}
see if you are getting anything
I think you are not passing a valid url
try adding an error function to get some info:
var result = null;
$.ajax({
url: url,
type: 'get',
dataType: 'json',
async: false,
success: function(data) {
result = data
},
error: function(error) {
alert(error);
}
});
return result;
Update: Try to output the variable directly as alex has suggested
I'm trying to send an array from a JS file to a PHP file in the server but when I try to use the array in php, I got nothing.
This is my function in JS:
var sortOrder = [];
var request = function() {
var jsonString = JSON.stringify(sortOrder);
$.ajax({
type: "POST",
url: '<?php echo get_template_directory_uri(); ?>/MYPAGE.php',
data: { sort_order : jsonString },
cache: false,
success: function() {
alert('data sent');
}
})
};
and this is my php file MYPAGE.php:
<?php
$arrayJobs = json_decode(stripslashes($_POST['sort_order']));
echo($arrayJobs);?>
This is the first time that I use ajax and honestly I'm also confused about the url because I'm working on a template in wordpress.
Even if I don't use json it doesn't work!
These are the examples that I'm looking at:
Send array with Ajax to PHP script
Passing JavaScript array to PHP through jQuery $.ajax
First, where is that javascript code? It needs to be in a .php file for the php code (wordpress function) to execute.
Second, how do you know that there is no data received on the back-end. You are sending an AJAX request, and not receiving the result here. If you read the documentation on $.ajax you'll see that the response from the server is passed to the success callback.
$.ajax({
type: "POST",
url: '<?php echo get_template_directory_uri(); ?>/MYPAGE.php',
data: { sort_order : jsonString },
cache: false,
success: function(responseData) {
// consider using console.log for these kind of things.
alert("Data recived: " + responseData);
}
})
You'll see whatever you echo from the PHP code in this alert. Only then you can say if you received nothing.
Also, json_decode will return a JSON object (or an array if you tell it to). You can not echo it out like you have done here. You should instead use print_r for this.
$request = json_decode($_POST['sort_order']);
print_r($request);
And I believe sort_order in the javascript code is empty just for this example and you are actually sending something in your actual code, right?
the problem is in your url, javascript cannot interprate the php tags, what I suggest to you is to pass the "get_template_directory_uri()" as a variable from the main page like that :
<script>
var get_template_directory_uri = "<?php get_template_directory_uri() ?>";
</script>
and after, use this variable in the url property.
Good luck.
I hope it helps
My PHP is outputting data like this:
$data['full_feed'] = $sxml;
$data['other_stuff']= $new;
echo json_encode($data);
So, in my jQuery, I'm doing this.
$.ajax({
url: 'untitled.php',
type: 'GET',
success: function(data) {
console.log(data['full_feed']);
});
This comes back undefined. So does console.log(data.full_feed). I'm getting back from PHP a valid JSON object, but missing how I can "parse" it correctly.
Parse "data" parameter in response with jQuery.parseJSON function. Then use parsed.full_feed value. Like below:
$.ajax({
url: 'untitled.php',
type: 'GET',
success: function(data) {
data = jQuery.parseJSON(data);
console.log(data.full_feed);
});
You can do like #tilz0R said or for your example to work you need to tell the browser you are sending a json response. So need to set content type header like
header('Content-Type: application/json');
echo json_encode($data);
to see what the server is returning do console.log(typeof data). If its a string you need to parse it. if its an object, it is already parsed.
Also you can put dataType:'json' in your ajax call to let jquery know you are excepting a json response.
I have a registration form and am using $.ajax to submit it.
This is my AJAX request:
$(document).ready(function() {
$("form#regist").submit(function() {
var str = $("#regist").serialize();
$.ajax({
type: 'POST',
url: 'submit1.php',
data: $("#regist").serialize(),
dataType: 'json',
success: function() {
$("#loading").append("<h2>you are here</h2>");
}
});
return false;
});
});
In my submit1.php file I check for the existence of fields email address and username in the database.
I wish to display an error message if those value exist without a page refresh.
How can I add this to the success callback of my AJAX request?
The result is probably not in JSON format, so when jQuery tries to parse it as such, it fails. You can catch the error with error: callback function.
You don't seem to need JSON in that function anyways, so you can also take out the dataType: 'json' row.
Although the problem is already solved i add this in the hope it will help others.
I made the mistake an tried to use a function directly like this (success: OnSuccess(productID)). But you have to pass an anonymous function first:
function callWebService(cartObject) {
$.ajax({
type: "POST",
url: "http://localhost/AspNetWebService.asmx/YourMethodName",
data: cartObject,
contentType: "application/x-www-form-urlencoded",
dataType: "html",
success: function () {
OnSuccess(cartObject.productID)
},
error: function () {
OnError(cartObject.productID)
},
complete: function () {
// Handle the complete event
alert("ajax completed " + cartObject.productID);
}
}); // end Ajax
return false;
}
If you do not use an anonymous function as a wrapper OnSuccess is called even if the webservice returns an exception.
I tried removing the dataType row and it didn't work for me. I got around the issue by using "complete" instead of "success" as the callback. The success callback still fails in IE, but since my script runs and completes anyway that's all I care about.
$.ajax({
type: 'POST',
url: 'somescript.php',
data: someData,
complete: function(jqXHR) {
if(jqXHR.readyState === 4) {
... run some code ...
}
}
});
in jQuery 1.5 you can also do it like this.
var ajax = $.ajax({
type: 'POST',
url: 'somescript.php',
data: 'someData'
});
ajax.complete(function(jqXHR){
if(jqXHR.readyState === 4) {
... run some code ...
}
});
Make sure you're not printing (echo or print) any text/data prior to generate your JSON formated data in your PHP file. That could explain that you get a -sucessfull 200 OK- but your sucess event still fails in your javascript. You can verify what your script is receiving by checking the section "Network - Answer" in firebug for the POST submit1.php.
Put an alert() in your success callback to make sure it's being called at all.
If it's not, that's simply because the request wasn't successful at all, even though you manage to hit the server. Reasonable causes could be that a timeout expires, or something in your php code throws an exception.
Install the firebug addon for firefox, if you haven't already, and inspect the AJAX callback. You'll be able to see the response, and whether or not it receives a successful (200 OK) response. You can also put another alert() in the complete callback, which should definitely be invoked.
I was returning valid JSON, getting a response of 200 in my "complete" callback, and could see it in the chrome network console... BUT I hadn't specified
dataType: "json"
once I did, unlike the "accepted answer", that actually fixed the problem.
I had same problem. it happen because javascript expect json data type in returning data. but if you use echo or print in your php this situation occur. if you use echo function in php to return data, Simply remove dataType : "json" working pretty well.
You must declare both Success AND Error callback. Adding
error: function(err) {...}
should fix the problem
I'm using XML to carry the result back from the php on the server to the webpage and I have had the same behaviour.
In my case the reason was , that the closing tag did not match the opening tag.
<?php
....
header("Content-Type: text/xml");
echo "<?xml version=\"1.0\" encoding=\"utf-8\"?>
<result>
<status>$status</status>
<OPENING_TAG>$message</CLOSING_TAG>
</result>";
?>
I had this problem using an ajax function to recover the user password from Magento. The success event was not being fired, then I realized there were two errors:
The result was not being returned in JSON format
I was trying to convert an array to JSON format, but this array had non-utf characters
So every time I tried to use json_eoncde() to encode the returning array, the function was not working because one of its indexes had non-utf characters, most of them accentuation in brazilian portuguese words.
I tried to return string from controller but why control returning to error block not in success of ajax
var sownum="aa";
$.ajax({
type : "POST",
contentType : 'application/json; charset=utf-8',
dataType : "JSON",
url : 'updateSowDetails.html?sownum=' + sownum,
success : function() {
alert("Wrong username");
},
error : function(request, status, error) {
var val = request.responseText;
alert("error"+val);
}
});
I faced the same problem when querying controller which does not return success response, when modified my controller to return success message problem was solved.
note using Lavalite framework.
before:
public function Activity($id)
{
$data=getData();
return
$this->response->title('title')
->layout('layout')
->data(compact('data'))
->view('view')
->output();
}
after code looks like:
try {
$attributes = $request->all();
//do something
return $this->response->message('')
->code(204)
->status('success')
->url('url'. $data->id)
->redirect();
} catch (Exception $e) {
return $this->response->message($e->getMessage())
->code(400)
->status('error')
->url('nothing Wrong')
->redirect()
}
this worked for me
I had the same problem i solved it in that way:
My ajax:
event.preventDefault();
$.ajax('file.php', {
method: 'POST',
dataType: 'json',
contentType: 'application/json',
data: JSON.stringify({tab}),
success: function(php_response){
if (php_response == 'item')
{
console.log('it works');
}
}
})
Ok. The problem is not with json but only php response.
Before: my php response was:
echo 'item';
Now:
$variable = 'item';
echo json.encode($variable);
Now my success working.
PS. Sorry if something is wrong but it is my first comment on this forum :)
in my case the error was this was in the server side and for that reason it was returning a html
wp_nonce_field(basename(__FILE__), "mu-meta-box-nonce");
Add 'error' callback (just like 'success') this way:
$.ajax({
type: 'POST',
url: 'submit1.php',
data: $("#regist").serialize(),
dataType: 'json',
success: function() {
$("#loading").append("<h2>you are here</h2>");
},
error: function(jqXhr, textStatus, errorMessage){
console.log("Error: ", errorMessage);
}
});
So, in my case I saw in console:
Error: SyntaxError: Unexpected end of JSON input
at parse (<anonymous>), ..., etc.
The success callback takes two arguments:
success: function (data, textStatus) { }
Also make sure that the submit1.php sets the proper content-type header: application/json