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Push a random character from an array into another array [closed]

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var legalCharactersForSaveCode = ["B","C","D","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z", "+", "/",];
var saveCode = [];
function generateSaveCode() {
for(var c = 0; c > 30; c++){
v = Math.round(Math.random() * legalCharactersForSaveCode.length);
saveCode.push(legalCharactersForSaveCode[v]);
}
saveCode.push(store.get("money"));
alert(saveCode);
}
I'm trying to make it so it pushes a random character.
When I ask it to alert the saveCode array all it does is alert the money.
(I'm using store.js)
I was expecting for it to push a random characters from the legalCharacters array into the saveCode array.

Your "for" loop does not work as the condition is c > 30, and should be c < 30

JavaScript filter method not giving unique result [closed]

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Closed 9 months ago.
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i am trying to filter the unique ones from a given array using filter method but its throwing an empty array, here is the code
function dual(a) {
if (Array.isArray(a)) {
let unique = a.filter((val, index) => {
a.indexOf(val) == index
})
return unique;
}
}
console.log(dual([3, 1, 1, 2, 2])) //expected result [3,1,2] but showing []

You may use Set() to create a unique array:
const arr = [3,1,1,2,2]
var uniqueArray = [...new Set(arr)]
console.log(uniqueArray)

You are missing return statements from both your function and your filter array method.

Why is my answer in the compiler not the same, with the answer from leetcode compiler? [closed]

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Closed 1 year ago.
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I have a simple code, its essence is to remove duplicate numbers from a sheet. But on my server, the data received does not match the data on leetcode. For what reason could this be?
var deleteDuplicates = (head) => {
for(let i = 0; i < head.length; i++) {
for(let a = i + 1; a < head.length; a++) {
if(head[i] === head[a] ) {
head.splice([a], 1)
}
}
}
return head;
};
console.log(deleteDuplicates([1,1,2]));
Output: [1,2]
Leetcode:
Your input
[1,1,2]
Output
[1,1,2]
Expected
[1,2]

How about using a Set? It's simpler and you'll avoid modifying a list that you're iterating over.
var deleteDuplicates = (head) => [...new Set(head)];

Unexpected number length value Javascript [closed]

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Closed 1 year ago.
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Why does this if statement always log true no matter how long pin actually is?
const pin = 1
if (pin.toString().length = 4 || 6) {
console.log(true);
}
//logs true
Edit: If a mod sees this, should I delete this question? I was very bad at javascript when I asked this.

Both statements in your || (or) statement will resolve to true, so the log will always be called.
pin.toString().length = 4
resolves to true because you're SETTING the length to 4 and then the check becomes 'is there a length' which is only falsy if the length === 0.
The second part of the equality is simply '6'. Any number that's not 0 is truthy, so will resolve to true.
You probably mean something like this:
const pin = 1;
if (pin.toString().length === 4 || pin.toString().length === 6) {
console.log(true);
}
This will never log true, because '1'.length === 1.

Issues with displaying certain array elements with a conditional in javascript [closed]

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Closed 2 years ago.
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I'm trying to use a for loop to display all the elements in my array that are greater than 5. I am using an if-statement to determine the values greater than five, but when I run the code, I get values printed to the console that are both below and over five. I have tried creating variables to store the index values and tried using the && operator, but none of these have worked.
Here is the code for reference:
var myArray = [];
appendItem(myArray, randomNumber(1,10));
appendItem(myArray, randomNumber(1,10));
appendItem(myArray, randomNumber(1,10));
console.log("Original: " + myArray);
console.log("Values greater than 5");
// the part I have issues with
for (var i = 0; i < myArray.length; i++) {
if (myArray[i] > 5) {
console.log(i);
}
}

You are printing i not the array element.
try
console.log(myArray[i]);