Js code
var server = '';
var orig_chat = chatUpdateSucess;
chatUpdateSucess = function(o){
if (o.GlobalChats && o.GlobalChats.length > 0) {
//TODO: Add setting to enable/diosable this
console.log(JSON.stringify(o.GlobalChats));
var xhr = new XMLHttpRequest();
xhr.open("POST", server+"/api.php?request=log_gc");
xhr.send(JSON.stringify(o.GlobalChats));
}
orig_chat.apply(this, arguments);
};
Server code named api.php
<?php
header("Access-Control-Allow-Origin: *");
if(!empty($_POST['o.GlobalChats'])){
$data = $_POST['o.GlobalChats'];
$fname = time() . ".txt";//generates random name
$file = fopen("" .$fname, 'w');//creates new file
fwrite($file, $fclose($file);
}
?>
console.log output
[{"PlayerId":237186,"toPlayerId":0,"chatid":16606292,"added":"/Date(1451764948837)/","addedText":"20:02","PlayerLink":"p=Kodabear|237186|T?|78|1|0|0-144-0-240-186-0-0-0-0-0-0-0-0|#IKnowAFighter|Neurofibromatosis Awareness day/Month|5-404-282-59","text":"Exmaple of a real chat"}]
I created a js that sends a file to my server every time the chat in the game is updated. But I am having problems with the server side code any advice would be great help. (PHP code was founded here
Saving a text file on server using JavaScript
Try to var_dump($_POST['o.GlobalChats']) to see if your data is reaching the server.
It seems like you are not writing the file to the system properly. Please read the examples at the manual (http://php.net/manual/pt_BR/function.fwrite.php)
Also, using time() is not safe, because two files may be created at the same UNIX timestamps in extreme cases, and one will overwrite the other
Try something like this:
$data = $_POST['o.GlobalChats'];
$fname = time() . "-" . rand ( 1 , 10000 ) . ".txt";
$handle = fopen($fname, 'w');
fwrite($handle, $data);
fclose($handle);
Related
I found a really good article with a feature I want to add to a page, but have been stuck the entire day with one small error. For reference the tutorial is located here.
Everything is working, the only thing that is not happening is the fact that the index.php webpage is not refreshing on changes made to the hosted php array. Could anyone glance at my code and tell me if I have a typo or missed part of the article?
My array file - selectedSystemStateResults.php
<?php
$selectedSystemStateResults = ["cart", "dogsss", "cows", "zebra", "snake"];
My serverside PHP script file - selectedSystemState-script.php
<?php
header("Cache-Control: no-cache");
header("Content-Type: text/event-stream");
// Require the file which contains the $animals array
require_once "selectedSystemStateResults.php";
// Encode the php array in json format to include it in the response
$selectedSystemStateResults = json_encode($selectedSystemStateResults);
echo "data: $selectedSystemStateResults" . "\n\n";
flush();
echo "retry: 1000\n";
echo "event: selectedSystemStateResultsMessage\n";
My Client side web page - index.php
<?php require "selectedSystemStateResults.php"; ?>
<html>
<body>
<?php foreach ($selectedSystemStateResults as $selectedSystemStateResult) : ?>
<li><?php echo $selectedSystemStateResult; ?></li>
<?php endforeach ?>
</ul>
<script src="/selectedSystemState-script.js"></script>
</body>
</html>
My javascript file - selectedSystemState-script.js
let eventSource = new EventSource('selectedSystemState-script.php');
eventSource.addEventListener("selectedSystemStateResultsMessage", function(event) {
let data = JSON.parse(event.data);
let listElements = document.getElementsByTagName("li");
for (let i = 0; i < listElements.length; i++) {
let selectedSystemStateResults = listElements[i].textContent;
if (!data.includes(selectedSystemStateResults)) {
listElements[i].style.color = "red";
}
}
});
I have read this and re-read this for the past 8 hours and feel really stuck. Does anyone see any blaring php or javascript typos or could the tutorial be wrong?
Please pardon the typo I had in the file names on my unedited original post. The directory shows the files all named properly.
Using this tutorial Using server-sent events
I found out that the script.php file must NOT stop executing !!
or (selectedSystemState-script.php) in your case .
So I guess the the tutorial you linked is wrong in some point ?
try this
while (1) {
// Every second, send a "selectedSystemStateResultsMessage" event.
echo "event: selectedSystemStateResultsMessage\n";
require("selectedSystemStateResults.php");
$selectedSystemStateResults = json_encode($selectedSystemStateResults);
echo "data: $selectedSystemStateResults" . "\n\n";
ob_end_flush();
flush();
sleep(1);
}
this is new to me but i noticed a few things :
1- the php event script file must have header text/event-stream
2- that file must not stop executing !
3- event: is sent before data: .
Hope this help
EDIT
After a test on your script It worked when I changed
<script src="/selectedSystemState-script.js"></script>
to <script src="./selectedSystemState-script.js"></script>
it was calling selectedSystemState-script.js from root folder ! and generate 404 error
and in selectedSystemState-script.php
<?php
header("Cache-Control: no-cache");
header("Content-Type: text/event-stream");
// Require the file which contains the $animals array
require_once "selectedSystemStateResults.php";
// Encode the php array in json format to include it in the response
$selectedSystemStateResults = json_encode($selectedSystemStateResults);
// data after event
flush();
echo "retry: 1000\n";
echo "event: selectedSystemStateResultsMessage\n";
echo "data: $selectedSystemStateResults" . "\n\n";
?>
and I edited selectedSystemState-script.js a bit :
let eventSource = new EventSource('selectedSystemState-script.php');
eventSource.addEventListener("selectedSystemStateResultsMessage", function(event) {
let data = JSON.parse(event.data);
let listElements = document.getElementsByTagName("li");
for (let i = 0; i < listElements.length; i++) {
let selectedSystemStateResults = listElements[i].textContent;
if (!data.includes(selectedSystemStateResults)) {
listElements[i].style.color = "red";
} else {
listElements[i].style.color = "blue";
}
}
});
<script src="/selectedSystemState-script.js"></script>
does not match your javascript filename selectSystemState-script.js. Verify javascript errors next time by opening the developer tools console!
Another error is that you're sending the data before setting the event name. The end of selectedSystemState-script.php should be:
echo "retry: 1000\n";
echo "event: selectedSystemStateResultsMessage\n";
echo "data: $selectedSystemStateResults" . "\n\n";
flush();
using javascript code in browser to access javascript variable in server php file
( the php file search a text file and returned result as a php variable, then I set that php variable as javascript variable)
//php file on server called data.php
<?php
$search = 'bing';
// Read from file
$lines = file('text.txt');
$linea='';
foreach($lines as $line)
{
// Check if the line contains the string we're looking for, and print if it does
if(strpos($line, $search) !== false) {
$liner=explode(': ',$line);
$linea.= $liner[1];
}
}
echo 'Search returned: '. $linea;
<script type=\"text/javascript\">
var varxxx = $linea;
</script>
?>
//text file on server
foo: bar
el: macho
bing: bong
cake color: blue berry
mayo: ello
//Java script code in browser.
var xhr = new XMLHttpRequest();
xhr.open("GET","http://.........data.php",false);
xhr.send(null);
$Variables.setValue(5, 'varxxx');
I got
reference error
x is not defined
if I just run http://.........data.php , it shows Search returned:"Bong"
it means data.php successfully returned the result, and php $linea is Bong.
so this part below in the php file is what causes the error?
<script type=\"text/javascript\">
var varxxx = $linea;
</script>
or something wrong with my Javascript code in browser?
Any help is appreciated
Thanks in advance
Try "echoing" the script tag to the .html body.
You're getting this error because the variable is being created on the server side only, thats why the variable is not defined. Also I recomend you to use let instead of var, let is more secure in terms of scope.
//php file on server called data.php
<?php
$search = 'bing';
// Read from file
$lines = file('text.txt');
$linea='';
foreach($lines as $line)
{
// Check if the line contains the string we're looking for, and print if it does
if(strpos($line, $search) !== false) {
$liner=explode(': ',$line);
$linea.= $liner[1];
}
}
echo 'Search returned: '. $linea;
?>
// New script
<?php
echo("<script> var varxxx = ".$linea." </script>")
?>
I have a HTML page JavaScript which send a GET request data to PHP file to return all datas saved in the database . PHP replies with a HTML-table - that works fine!
But: When if i click a button (which calls the same JavaScript function) to update my table in order to display the new data, i get the same result (and i have definitely new data on table).
If I call the PHP manually via the browser it'll show me the new results immediately and at this moment it is also working with JavaScript (but only once).
Here is a part of my code.
HTML/JS:
<button onclick="GetData()"></button>
<div id="test"></div>
<script>
function GetData(){
var xhttp = new XMLHttpRequest();
document.getElementById("test").innerHTML = "";
xhttp.onreadystatechange = function(){
if (xhttp.readyState == 4 && xhttp.status == 200){
document.getElementById("test").innerHTML = xhttp.responseText;
}
};
xhttp.open("GET", "../GetData.php", true);
xhttp.send();
}
</script>
PHP:
//DB details
$dbHost = 'localhost';
$dbUsername = 'lalalala';
$dbPassword = 'lalalalal';
$dbName = 'lalalala';
//Create connection and select DB
$db = new mysqli($dbHost, $dbUsername, $dbPassword, $dbName) or die ("UUUUPS");
$sql = "select name, beschreibung, image, video from data";
$result = $db->query($sql);
if ($result->num_rows > 0) {
$return = '<table class ="table table-hover"><thead><tr><th scope="col">Name</th><th scope="col">Beschreibung</th><th scope="col">Bilddatei</th><th scope="col">Video-Url</th></tr></thead><tbody>';
// output data of each row
while($row = $result->fetch_assoc()) {
$return .= "<tr><td>".$row["name"]."</td><td>".$row["beschreibung"]."</td><td><img src=data:image/png;base64,".base64_encode($row["image"])."/></td><td>".$row["video"]."</tr>";
}
$return .= "</tbody></table>";
$db->close();
echo $return;
} else {
echo "0 results";
}
Thank you for your help!
It seems your browser is caching your result, that's why you see data.
You can test it like this:
var random = Math.floor(Math.random() * 100);
xhttp.open("GET", "../GetData.php?"+random, true);
If this helps, look into expire headers in your PHP script. Also, the way you're doing queries in quite outdated. It's a very PHP4 way. Have a look here: http://php.net/manual/en/book.mysqli.php
I guess you probably know this, but just in case. Have you had a look in your browsers inspector, when testing you html page? especially the network tab within that inspector. There you can see the actual response from the server and you can see if it is served from cache or fetched (you can even disable cache there), maybe this helps.
Kind regard,
Mark
I am using a web labeling tool to generate image from the website, however I want to modify the function so that when I am done with labeling, instead of downloading the image to local, I want it to be uploaded into server. The function is in a javascript file and all the upload associated with JS has to do with submitting forms. There is no form and super globals, how am I supposed to upload a web generated image to server?
here is the code I currently have, it is not in html file, it is in js file.
var file_data = annotator.export();
var formData = dataURItoBlob(file_data);
var fd = new FormData(document);
fd.append("resultImage",formData);
url="upload/";
http.open("POST", url, true);
// headers
http.setRequestHeader("Content-type", "application/x-www-form- urlencoded");
http.setRequestHeader("Content-length", fd.length);
http.setRequestHeader("Connection", "close");
http.onreadystatechange = function() {
if(http.readyState == 4 && http.status == 200) {
alert(http.responseText);
}
}
http.send(fd);
php file
<?php
$upload_dir = "upload/";
$img = $_POST['hidden_data'];
$img = str_replace('data:image/png;base64,', '', $img);
$img = str_replace(' ', '+', $img);
$data = base64_decode($img);
$file = $upload_dir . mktime() . ".png";
$success = file_put_contents($file, $data);
print $success ? $file : 'Unable to save the file.';
?>
Really appreciate your help, thank you.
dataURItoBlob(file_data); by the name of the function it looks like that is going to be returning a blob object. blob/file objects when uploaded to a php script are going to be in the $_FILES global, not $_POST. And you would use move_uploaded_file to move it to your desired destination.
Also you seem to be using the wrong index. You are using hidden_data in your php but you set the name to resultImage in your javascript. You would need to use the same name in php as you did in the javascript.
So your php code should look something like
$upload_dir = "upload/";
$img = $_FILES['resultImage'];
if($img["error"] == UPLOAD_ERR_OK){
//should do other sanitation like making sure the file
//that is uploaded is the actual type of file you expect
$path = $upload_dir . mktime() . ".png";
move_uploaded_file($img["tmp_name"], $path);
}
As a side note, when using and FormData object you do not need to set the request headers like Content-Type as they will automatically be set by the api.
I am a newbie to scripting and am trying to use the following php code (taken from another post that was already answered: PHP Script to convert .CSV files to .XML, to convert csv data to xml (I named this file csv2xml.php). I am trying to pull the outputted xml file that is created in the php script into javascript using the DownloadURL function so that I can parse the data further, but I'm not sure if I can use a php file in the downloadURL function in order to parse it. Can anyone point me in the right direction? I have to have this done by tomorrow so any help would be appreciated. PHP code is first, followed by the section of javascript I am referring to.
<?php
error_reporting(E_ALL | E_STRICT);
ini_set('display_errors', true);
ini_set('auto_detect_line_endings', true);
$inputFilename = 'input.csv';
$outputFilename = 'output.xml';
// Open csv to read
$inputFile = fopen($inputFilename, 'rt');
// Get the headers of the file
$headers = fgetcsv($inputFile);
// Create a new dom document with pretty formatting
$doc = new DomDocument();
$doc->formatOutput = true;
// Add a root node to the document
$root = $doc->createElement('rows');
$root = $doc->appendChild($root);
// Loop through each row creating a <row> node with the correct data
while (($row = fgetcsv($inputFile)) !== FALSE)
{
$container = $doc->createElement('row');
foreach ($headers as $i => $header)
{
$child = $doc->createElement($header);
$child = $container->appendChild($child);
$value = $doc->createTextNode($row[$i]);
$value = $child->appendChild($value);
}
$root->appendChild($container);
}
echo $doc->saveXML();
?>
downloadUrl("csv2xml.php", function(data) {
var xmlDoc = xmlParse(data);
var records = xmlDoc.getElementsByTagName("row");
...(parsing code)