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Form validation with Ajax call triggers when not validation

I have a simple form with Ajax call, but ajax call gets executed even if form is not validated.
In below code line console.log("This line should execute only if Form is validated"); gets executed when form is not validate.
Bootstrap 5 validation Codepen code
(function () {
"use strict";
const forms = document.querySelectorAll(".requires-validation");
Array.from(forms).forEach(function (form) {
form.addEventListener(
"submit",
function (event) {
if (!form.checkValidity()) {
event.preventDefault();
event.stopPropagation();
}
else
{
console.log("This line should execute only if Form is validated");
// Call Ajax Function
// AjaxCallSaveData();
}
form.classList.add("was-validated");
},
false
);
});
})();
//$(document).ready(function () {
function AjaxCallSaveData()
{
$("form").submit(function (event) {
var formData = {
name: $("#name").val(),
email: $("#email").val(),
message: $("#message").val(),
superheroAlias: $("#superheroAlias").val()
};
$.ajax({
type: "POST",
url: "SubmitFORM.php",
data: formData,
dataType: "json",
encode: true
}).done(function (data) {
console.log(data);
});
event.preventDefault();
});
}
//});
Not sure if i am doing it right?
HTML
<div class="form-body">
<div class="row">
<div class="form-holder">
<div class="form-content">
<div class="form-items">
<h3>Register you interest</h3>
<p>Fill in the data below, we will get back to you!</p>
<form class="requires-validation" action="SubmitFORM.php" method="POST" novalidate>
<div class="col-md-12 mb-3">
<input class="form-control" type="text" name="name" id="name" placeholder="Full Name" required>
<div class="valid-feedback">Username field is valid!</div>
<div class="invalid-feedback">Username field cannot be blank!</div>
</div>
<div class="col-md-12 mb-3">
<input class="form-control" type="email" name="email" id="email" placeholder="E-mail Address" required>
<div class="valid-feedback">Email field is valid!</div>
<div class="invalid-feedback">Email field cannot be blank!</div>
</div>
<div class="col-md-12 mb-3">
<textarea name="message" id="message" placeholder="Your Message"></textarea>
</div>
<div class="form-button mt-3">
<button id="submit" type="submit" class="btn btn-primary">Submit</button>
</div>
</form>
</div>
</div>
</div>
</div>
</div>

event.preventDefault() will only stop the form from submitting. It cannot stop next lines of the JavaScript function from executing.
You should use return in place of event.preventDefault().

Your session has expired. on ajax form post laravel

I have the following html snippit from my view and js code to handel the form request.
$('#quick-enquiry').on('submit', function(e) {
e.preventDefault();
$(".submit").prop("disabled", true);
data = $(this).serialize();
action = $(this).attr('action');
$.ajax({
type: 'POST',
url: action,
data: data,
headers: {
"X-CSRF-TOKEN": $('meta[name="csrf-token"]').attr("content")
},
success: function(data) {
if ($.isEmptyObject(data.error)) {
$("#quick-enquiry").trigger("reset");
$('.print-error-msg').find('ul').empty();
$('.print-error-msg').css('display', 'block');
$("#response-msg").toggleClass('uk-alert-danger uk-alert-success');
$('.print-error-msg').find('ul').append("<li>" + data.success + "</li>");
setTimeout(function() {
$('.print-error-msg').fadeOut();
$(".submit").prop("disabled", false);
UIkit.modal("#modal-quick-enquiry").hide();
}, 3000);
} else {
printMessageErrors(data.error);
}
}
});
});
function printMessageErrors(msg) {
$('.print-error-msg').find('ul').empty();
$('.print-error-msg').css('display', 'block');
$.each(msg, function(key, value) {
$('.print-error-msg').find('ul').append("<li>" + value + "</li>");
});
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/uikit/3.0.0-rc.26/js/uikit.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<link href="https://cdnjs.cloudflare.com/ajax/libs/uikit/3.0.0-rc.26/css/uikit.min.css" rel="stylesheet" />
<form action="{{ route('frontend-postEnquiry') }}" method="POST" id="quick-enquiry">
<input type="hidden" id="tour-id" value="1">
<div class="uk-margin">
<label class="uk-form-label" for="form-stacked-text">Full Name</label>
<div class="uk-form-controls">
<input class="uk-input uk-form-width-large" type="text" placeholder="Full Name" id="fullName" name="fullName">
</div>
</div>
<div class="uk-margin">
<label class="uk-form-label" for="form-stacked-text">Email</label>
<div class="uk-form-controls">
<input class="uk-input uk-form-width-large" type="email" placeholder="Email" id="email" name="email">
</div>
</div>
<div class="uk-margin">
<label class="uk-form-label" for="form-stacked-text">Message</label>
<div class="uk-form-controls">
<textarea class="uk-textarea uk-form-width-large" rows="4" placeholder="Some Message...." id="enquiryMessage" name="enquiryMessage"></textarea>
</div>
</div>
<p class="uk-text-right">
<button class="uk-modal-close-default" type="button" uk-close></button>
<button class="uk-button uk-button-primary submit uk-width-1-1" type="submit">Send</button>
</p>
</form>
With the above code I'm getting
419
Sorry, your session has expired. Please refresh and try again.
I've set CSRF-TOKEN in ajax and in head section also, but seems like my js code is not picking up csrf token.
I would be very thankful if anyone could highlight the mistake I've made above.

Try using this:
{{ csrf_field() }} instead of #csrf
419 error is mostly because of CSRF token issues.

val and fadeOut not working on click

i'm creating a ajax post request that works fine. however to make it more appealing i'm trying to implement so that when the user click on #sign_in it will change the text while request is going on. if it result in error a message will appear. this message will automatically remove after a couple of seconds. however if u click .close it will force close. The issue is however that following does not work:
$(".alert a").click(function(e) {
$('.alert').fadeOut();
});
Nothing happens when i click on .close. in addition to this below does not work either.
$('#sign_in').val('Logger ind...');
Full Code
<form id="sign_in">
<div class="form-group">
<input type="text" name="username" id="username" class="form-control" placeholder="Email">
</div>
<div class="form-group">
<input type="password" name="password" id="password" class="form-control" placeholder="Kodeord">
</div>
<a href="#">
<small>Forgot password?</small>
</a>
<div class="form-group text-center add_top_20">
<input class="btn_1 medium" id="sign_in" type="submit" value="Log ind">
<input type="hidden" name="next" value="{{ next }}" />
</div>
</form>
<div class="alert alert-error alert-danger" style="display: none;">
<a class="close" href="#">×</a>
Invalid email or password. Try clicking 'Forgot Password' if you're having trouble signing in.
</div>
jquery
$("#sign_in").submit(function (event) {
// Change sign in button text
$('#sign_in').val('Logger ind...');
// post request
event.preventDefault();
var username = $('#username').val();
var password = $('#password').val();
$.ajax({
url: "/account/login/auth/",
type: "POST",
dataType : 'json',
contentType: 'application/json',
data: {
'username': username,
'password': password
}, success: function (data) {
if (data.success) {
alert('success');
} else {
showAlert()
}
// Change sign in text back
$('#sign_in').val('Log ind');
}, error: function(error){
// Change sign in text back
$('#sign_in').val('Log ind');
}
});
});
function showAlert(){
if(!$('.alert').is(':visible'))
{
$('.alert').fadeIn()
$('.alert').delay(4000).fadeOut()
}
}
$(".alert a").click(function(e) {
$('.alert').fadeOut();
});
and all of this is wrapped in $(document).ready(function () {

Mmm, your event is launching but you need to use clearQueue in order to launch your fadeOut animation again interrupting the previous one.
$(".alert a").click(function(e) {
$('.alert').clearQueue();
$('.alert').fadeOut();
});

Change your form id or submit button id and change :visible to :hidden
function showAlert(){
if($('.alert').is(':hidden'))
{
$('.alert').fadeIn()
$('.alert').delay(4000).fadeOut()
}
}
Here I have change form 'id'
<form id="sign_in_form">
<div class="form-group">
<input type="text" name="username" id="username" class="form-control" placeholder="Email">
</div>
<div class="form-group">
<input type="password" name="password" id="password" class="form-control" placeholder="Kodeord">
</div>
<a href="#">
<small>Forgot password?</small>
</a>
<div class="form-group text-center add_top_20">
<input class="btn_1 medium" id="sign_in" type="submit" value="Log ind">
<input type="hidden" name="next" value="{{ next }}" />
</div>
</form>
<div class="alert alert-error alert-danger" style="display: none;">
<a class="close" href="#">×</a>
Invalid email or password. Try clicking 'Forgot Password' if you're having trouble signing in.
</div>
jQuery
$("#sign_in_form").submit(function (event) {
// Change sign in button text
$('#sign_in').val('Logger ind...');
// post request
event.preventDefault();
var username = $('#username').val();
var password = $('#password').val();
$.ajax({
url: "/account/login/auth/",
type: "POST",
dataType : 'json',
contentType: 'application/json',
data: {
'username': username,
'password': password
}, success: function (data) {
if (data.success) {
alert('success');
} else {
showAlert()
}
// Change sign in text back
$('#sign_in').val('Log ind');
}, error: function(error){
// Change sign in text back
$('#sign_in').val('Log ind');
}
});
});
function showAlert(){
if($('.alert').is(':hidden'))
{
$('.alert').fadeIn()
$('.alert').delay(4000).fadeOut()
}
}
$(".alert a").click(function(e) {
$('.alert').clearQueue();
$('.alert').fadeOut();
});

My JavaScript form validation function is called two times

I am trying to print the value from the form when a user submits the function but a blank value is returned.
Here is my JavaScript code:
var login = new function()
{
var name = null ;
this.validation = function()
{
this.name = document.getElementById("Username").value;
console.log(this.name);
document.getElementById("demo").innerHTML = this.name;
};
};
And my HTML form as :
<body>
<div class="container">
<div class="col-md-8">
<div class="starter-template">
<h1>Login with javascript</h1>
<p class="lead">Please Enter Following Details</p>
<h1 id="demo"></h1>
<form name="form" onSubmit="return login.validation();" action="#" method="post">
<div class="form-group">
<label for="exampleInputEmail1">Username</label>
<input type="text" name="username" class="form-control" id="Username" placeholder="Please Enter your Username">
</div>
<div class="form-group">
<label for="exampleInputEmail1">Email address</label>
<input type="email" class="form-control" id="Email" placeholder="Please enter your Password">
</div>
<div class="form-group">
<label for="exampleInputPassword1">Password</label>
<input type="password" class="form-control" id="Password" placeholder="Password">
</div>
<div class="form-group">
<label for="exampleInputPassword1">Re-Password</label>
<input type="password" class="form-control" id="Re-Password" placeholder="Password">
</div>
<button type="submit" class="btn btn-default">Submit</button>
</form>
</div>
</div>
</div>
<script src="js/login.js"></script>
<script href="js/bootstrap.js"></script>
<!-- /.container -->
</body>
Why does the value not get into html <p> tag.

Your code simply works. But since the function executes on submitting the form, the username gets logged in the console fast before the page refreshed with submitted data. You can confirm this and test it by adding event.preventDefault(); to the function to prevent submitting the form so the page would stay visible with the console.
<script>
var login = new function()
{
var name = null ;
this.validation = function()
{
event.preventDefault();
this.name = document.getElementById("Username").value;
console.log(this.name);
document.getElementById("demo").innerHTML = this.name;
};
};
</script>
If that's not what you're looking for, let me know.

We the javascript validation failed you need to return false. If you don't it will proceed your form further. Thanks
var login = new function()
{
var name = null ;
this.validation = function()
{
this.name = document.getElementById("Username").value;
document.getElementById("demo").innerHTML = this.name;
return false;
};
};

Form doesn't submit on callback

I am trying to send an e-mail after an ajax call has been successfully completed. I do not have access to the file that I am making the AJAX call to.
I am preventing the first submit, making the ajax call and submitting the form again upon competition. When doing this, I can't seem to figure out why I have to press the submit button twice for the email to be sent.
Here is my code:
"use strict";
var submitted = '';
/* Send info to the portal */
jQuery(function($) {
$('#quote').submit(function(e){
var firstName = $('#firstName').val(),
lastName = $('#lastName').val(),
email = $('#email').val(),
phone = $('#primaryPhone').val(),
weight = $('#weight').val(),
origin = $('#originPostalCode').val(),
destination = $('#destinationPostalCode').val(),
notes = $('#whatsTransported').val()
if( submitted != 1 )
{
e.preventDefault();
$.ajax({
type: "POST",
url: "https://somewhere.on/the/internet.php",
crossDomain: true,
dataType: "json",
data: {"key": "my secret key","first": firstName, "last": lastName, "email": email, "phone": phone, "weight": weight, "origin_postal": origin, "dest_country": destination, "note": notes }
})
.done(function(data){
if(data[1][0][0] == 2)
{
$('.alert').append( data[1][0][1].message ).addClass('alert-error').show();
} else if(data[1][0][0] == 0) {
console.log("Made it.");
$('#quote #submit').submit();
} else {
$('.alert').append( "Appologies, it seems like something went wrong. Please, <strong>call (877) 419-5523</strong> for immediate assistance or a free quote.");
}
})
.fail(function(data) { console.log(data); });
}
submitted = '1';
});
});
Here is the form HTML
<form action="<?php echo bloginfo($show='template_url').'/includes/form-email.php'; ?>" class="span6 offset1" id="quote" method="post">
<div class="row formRow">
<div class="firstName span3">
<label for="firstName"><?php _e('First Name:','StreamlinedService'); ?></label>
<input type="text" name="firstName" id="firstName">
</div>
<div class="lastName span3">
<label for="lastName"><?php _e('Last Name:','StreamlinedService'); ?></label>
<input type="text" name="lastName" id="lastName">
</div>
</div>
<div class="row formRow">
<div class="email span3">
<label for="email"><?php _e('Email Address:','StreamlinedService'); ?></label>
<input type="text" name="email" id="email">
</div>
<div class="primaryPhone span3">
<label for="primaryPhone"><?php _e('Phone Number:','StreamlinedService'); ?></label>
<input type="text" name="primaryPhone" id="primaryPhone">
</div>
</div>
<div class="row formRow">
<div class="weight span2">
<label for="weight"><?php _e('Weight (lbs):','StreamlinedService'); ?></label>
<input type="text" name="weight" id="weight">
</div>
</div>
<div class="row formRow">
<div class="originPostalCode span3">
<label for="originPostalCode"><?php _e('Origin:','StreamlinedService'); ?></label>
<input type="text" name="originPostalCode" id="originPostalCode">
</div>
<div class="destinationPostalCode span3">
<label for="destinationPostalCode"><?php _e('Destination:','StreamlinedService'); ?></label>
<input type="text" name="destinationPostalCode" id="destinationPostalCode">
</div>
</div>
<div class="row">
<div class="whatsTransported span6">
<label for="whatsTransported"><?php _e('What can we help you transport?','StreamlinedService'); ?></label>
<textarea name="whatsTransported" id="whatsTransported" rows="5"></textarea>
</div>
<input type="hidden" name="formType" value="quote" />
<input type="hidden" name="siteReferer" value="<?php echo $blog_id ?>">
<input type="submit" id="submit" name="submit" value="<?php _e('Get Freight Quote','StreamlinedService') ?>" class="btn btn-primary btn-large span3 offset3" style="float:right;">
</div>
</form>
My question is two-fold: Is there a more efficient way to do this? If not, why isn't this working?

Just use the .submit directly on the form node (note the [0])
$('#quote #submit').submit();
becomes
$('#quote')[0].submit();
this bypasses the jQuery bound event and forces a postback.

You use the wrong approach to Jquery
You miss the key : Write Less Do More, the heart of JQuery.
Anyway try this:
"use strict";
/* Send info to the portal */
jQuery(function($) {
$('#quote').submit(function(e){
var tis = $(this);
$.ajax({
type: "POST",
url: "https://somewhere.on/the/internet.php",
cache: true,
dataType: "json",
data: tis.serialize(),
success: function(data){
if(data[1][0][0] == 2){
$('.alert').append( data[1][0][1].message ).addClass('alert-error').show();
} else if(data[1][0][0] == 0) {
console.log("Made it.");
$('#quote #submit').submit();
} else {
$('.alert').append( "Appologies, it seems like something went wrong. Please, <strong>call (877) 419-5523</strong> for immediate assistance or a free quote.");
}
},
error: function(data){console.log(data);}
});
e.stroPropagation();
e.preventDefault();
});
});
Last thin.. you CAN'T request a remote page that's not hosted on the same domain of the script.. For that ther's This answer