I have the following snippet directly inside the body tag:
<div id="container">
<div class="section profile">
<div class="row">
<div class="col-sm-6">
A
</div>
<div class="col-sm-6">
B
</div>
</div>
</div>
<div class="section technical">
</div>
</div>
My CSS file if it is neccessary:
body {
background-color: #808080;
}
.section {
}
.section.profile {
background-color: #2980b9;
}
.section.technical {
background-color: #bdc3c7
}
However, when I use FullPageJS, the result is like this:
(note: their are thin lines at the left and right)
The problem only happens if I use row div. It also happen if I wrap the row by another div. Also, the problem disappear if I resize the browser window.
This is how I call the script, just like the documentation:
<script>
$(document).ready(function () {
$("#container").fullpage();
});
</script>
I'm not pretty sure what are you expecting to happen, but check this:
Rows must be placed within a .container (fixed-width) or
.container-fluid (full-width) for proper alignment and padding.
Use rows to create horizontal groups of columns.
Content should be placed within columns, and only columns may be
immediate children of rows.
The container must be a class, not an id, but this also will add some padding to the sides.
Also, you should move the .row class to the upper level id and delete the current one with the .row class in it, the row <div> can have both classes without any problem.
Related
https://leiacarts.github.io/index.html
https://codepen.io/leiacarts/pen/PoqRxNZ
I'm trying to get images to show in the red portions and to stay within the content div, but any time I add images, the layout breaks. I would really appreciate some help with these two things I want to achieve and thank you in advance:
1.) keep images constrained to and auto resizable within the (red) content div
2.) hide the images when the section is "shut" onclick.
HTML:
<div class="section">
<div class="bookmark">↑ ten ↔ sion ↓</div>
<div class="content"><p></p>
<!-- <div class="space"></div> -->
<!-- <img class="fit" src="images/ziptiesmall.png">
<img class="fit" src="images/ziptiesmall2.png">
<img class="fit" src="images/ziptiesmall3.png"> -->
</div>
</div>
the JavaScript:
var sections = document.querySelectorAll(".section")
sections.forEach(function(section) {
section.addEventListener("click", expandSection);
})
function expandSection(event) {
let section = (event.target.classList.contains("section")) ? event.target : event.target.parentNode;
sections.forEach(function(section) {
section.classList.remove("open")
})
section.classList.add("open");
}
I just added this class to the rest of the divs which didnt have any images on them, hence the reason for them to show the red content div. Remove the 100%, the image text in between every column as well and create ids for every column and add background image to them and you are good to go :).
.content.bg.zip {
margin-left: 40px;
/* width: 100%; */
background-color: #000;
background-image: url(images/ziptiepattern.png);
background-repeat: repeat;
}
In my container, there is multiple childrens, one of the 'div' getting appended by content in that.
when the total height of the container(parent) overflows, i would like to add the scroll bar to the div
is it possible to do by css?
here is the html :
<div id="container">
<div>
<h2>Heading</h2>
</div>
<div class="content">
</div>
<div class="footer">
Footer
</div>
</div>
<button>Add</button>
Js :
var p= "</p>Some testing text</p>";
$('button').click(function(){
$('.content').append(p);
});
jsfiddle
UPDATE
I don't want to put the over-flow to container, if so my footer will hide. i require my user need to see the add button always. I can't put my button out side of the container again there would be multiple content in to the container
UPDATE
I find a solution by js is it possible to made without using `js'?
jsSolution
Yes, it is possible to do in CSS. Simply add this CSS rule to #container:
overflow-y:scroll;
Alternatively add this to show the scroll bar only when necessary:
overflow-y:auto;
http://jsfiddle.net/doesfmnm/2/
var p= "</p>Some testing text</p>";
$('button').click(function(){
$('.content').append(p);
});
.content{
border:1px solid red;
height:300px;
width:200px;
overflow-y:auto;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="container">
<div>
<h2>Heading</h2>
</div>
<div class="content">
</div>
<div class="footer">
Footer
</div>
</div>
<button>Add</button>
Adding a little more explanation to what #Guy3000 said. You're appending (adding after) into an element with the class 'content'. Let's consider what that means for the parent .container class. By adding content into a div inside of the parent, your parent will need to either grow to compensate for the added content, or it will need to have a y-axis scroll that permits content longer than the height of the container.
This means you can approach the dilemma you're facing by adding height to the container element, or you can keep a fixed height on the container and have a frame with a y-axis scroll bar contain the added content.
Here is the solution i find :
<div id="container">
<div id="up">Text<br />Text<br />Text<br /></div>
<div id="down">
<div class="content"></div>
</div>
<div class="misc"><button>Add</button></div>
</div>
css :
#container { width: 300px; height: 300px; border:1px solid red;display:table;}
#up { background: green;display:table-row;height:0; }
#down { background:pink;display:table-row; overflow-y:auto}
.misc {
display:table-row;
background:gray;
height:30px;
}
.content {
overflow:auto;
height:100%;
}
Live
js solution :
http://jsfiddle.net/doesfmnm/4/
i'm facing to css problem.basically i have main div tag and 3 div s class named pic_con,body_con and msg_con .
div msg_con length and height depend on the text of it.if text is too long it should have morethan one line to display all.look at the picture.first one with small text,second one with big text ..div msg_con have minimem width and maximum width.
i want to position this 3 div look like in the picture.
<div id="apDiv1">
<div id="div_id_1" class="msg_w_1">
<div class="pic_con">
<div class="body_con">small icon"</div>
<div class="msg_con">hi</div>
</div>
<div id="div_id_2" class="msg_w_1">
<div class="pic_con">
<div class="body_con">small icon"</div>
<div class="msg_con">hey this is multiline text</div>
</div>
</div>
my css
.pic_con {
float:left;
background-color:#096;
}
.back_con {
float:left;
background-color:#3CC;
border:5px solid red;
width:150;
}
.body_con {
/*float:left;*/
margin:0 auto 0 auto;
background-color:#C39;
border:5px solid red;
}
i set flote left but it's not work.
As far as I understood you want to align them one after another.
You can manage this, as you tried, by using float: left. Furthermore, you should set the parent div to clear: both.
Another thing that I saw is that you didn't close the pic-con DIVs. Try with this:
HTML
<div id="apDiv1">
<div id="div_id_1" class="msg_w_1">
<div class="pic_con">pic</div>
<div class="body_con">small icon</div>
<div class="msg_con">hi</div>
</div>
<div id="div_id_2" class="msg_w_1">
<div class="pic_con"></div>
<div class="body_con">small icon"</div>
<div class="msg_con"> hey this is multiline text</div>
</div>
</div>
CSS
.msg_w_1 {
clear: both;
}
.msg_w_1 div {
float: left;
}
Edit: I didn't see the updated post containing CSS when I posted this. Try removing the float: left and width from your CSS classes before trying this
use display:table style.
.msg_con {
display : table
}
this makes .msg_con behave like a table element, it will re-size according to its content's length ( both height and width ).
I've used the technique explained here (js.fiddle link) to achieve vertical alignment for a section on my page.
The problem I have is that I would like to re-use this same technique on a different part of my page.
At the moment this works, but obviously the height of the first instance is then applied to a completely unrelated section somewhere else, and the vertical alignment is not achieved. Could someone help me with modifying the js (maybe using 'this'?) to allow the use of the same code to apply the height to different elements in different parts of my page?
Or do I have to duplicate this code with different var/class names each time I want to use it?
Code snippets below
HTML
<div class="row row_v_align">
<div class="small-3 columns column_v_align">
<div class="v_align"><img src="spade.png"></div>
</div>
<div class="small-9 columns">
<h3>Title</h3><p>Content</p>
</div>
</div>
<div class="row row_v_align">
<div class="small-3 columns column_v_align">
<div class="v_align"><img src="bullsEye.png"></div>
</div>
<div class="small-9 columns">
<h3>Title</h3><p>Content.</p>
</div>
</div>
CSS
.row_v_align {
display: table;
}
.v_align {
display: table-cell;
vertical-align: middle;
}
JS
$(window).on("resize", function () {
var rowHeight = $(".row_v_align").height();
console.log(rowHeight);
$(".column_v_align").height(rowHeight);
$(".v_align").height(rowHeight);
}).resize();
I tested code below with fiddle you linked.
$(document).ready(function(){
$(".row").each(function(){
var rowHeight = $(this).height();
console.log(rowHeight);
$(".column", this).height(rowHeight);
$(".v_align", this).height(rowHeight);
});
});
So for you this should work:
$(window).on("resize", function () {
$(".row_v_align").each(function(){
var rowHeight = $(this).height();
console.log(rowHeight);
$(".column_v_align", this).height(rowHeight);
$(".v_align", this).height(rowHeight);
});
}).resize();
each() run function for every matched element
$("...", this) makes sure that changes are made inside current row
I'm building a slideshow in jQuery that allows the user to see four images, and page through them, forwards and backwards by appending a new div with the image to the bottom via .load, and then hiding the top div. I'm very new to programming.
I'm having trouble working out a selector to allows the user to go "back" showing the next hidden div, after the first shown div, and hiding the last showing div - faux code example below.
<div class="slideShow" >image one (display = none)</div>
<div class="slideShow" >image two (display = none)</div>
<div class="slideShow" >image three </div>
<div class="slideShow" >image four </div>
<div class="slideShow" >image five </div>
<div class="slideShow">image six </div>
<a href="#" class="scrollUp" >Scrollup</a>
<a href="#" class="scrollDown" >ScrollDown</a>
Jquery to load a new image and attach to the bottom, and hide the first div currently displaying.
$('.scrollDown').click(function() {
$('.slideShow:last').after('<div class="slideShow"></div>'); // add a new div to the bottom.
$('.appendMe:last').load('myimagescript.py'); // load in the image to the new div.
// here I need to find a way of selecting in this example the first shown image (image three) and applying a .slideUp(); to it
});
Jquery to allows the user to go back to an image that they have previously seen and hide the last shown div at the bottom
$('.scrollUp').click(function() {
// here I need to find a way of selecting in this example the first hidden div (image two) after the first shown div (image three) and applying a slideDown(); to it.
$('.slideShow:last').slideUp(); // hide the last image on the page - trouble is what happens if they user now clicks scrollDown - how do I reshow this div rather than just loading a new one?
});
I dont quite understand correctly, however this info may help...you need to match the first visible div then use .prevAll() and filter to get the hidden sibling
$('div.slideShow:visible:first').prevAll(':hidden:first').slideDown();
I've spent hours today on this site trying to do something very similar to what was posted in this question.
What I have is Previous | Next links navigation doing through a series of divs, hiding and showing.
Though what I ended up with was different than the answer here....this was the one that most got me where I needed to be.
So, thanks.
And in case anyone is interested, here's what I did:
<script language="javascript">
$(function() {
$("#firstPanel").show();
});
$(function(){
$(".nextButton").click(function () {
$(".panel:visible").next(".panel:hidden").show().prev(".panel:visible").hide();
});
});
$(function(){
$(".backButton").click(function () {
$(".panel:visible").prev(".panel:hidden").show().next(".panel:visible").hide();
});
});
</script>
<style type="text/css">
.defaultHidden { display: none; }
.navigation { display: block; width: 700px; text-align: center; }
#contentWrapper { margin-top: 20px !important; width: 700px; }
.nextButton { cursor: pointer; }
.backButton { cursor: pointer; }
</style>
<div class="navigation">
<span class="backButton"><< Previous</span> | <span class="nextButton">Next >></span></button>
</div>
<div id="contentWrapper">
<div id="firstPanel" class="panel defaultHidden">
<img src="images/quiz/Slide1.jpg" width="640" />
</div>
<div class="panel defaultHidden">
<h1>Information Here</h1>
<p>Text for the paragraph</p>
</div>
<div class="panel defaultHidden">
<h1>Information Here</h1>
<p>Text for the paragraph</p>
</div>
<div class="panel" style="display: none;">
<img src="images/quiz/Slide4.jpg" width="640" />
</div>
<div class="panel defaultHidden">
<h1>Information Here</h1>
<p>Text for the paragraph</p>
</div>
<div class="panel defaultHidden">
<img src="images/quiz/Slide6.jpg" width="640" />
</div>
Repeat ad naseum...
</div>
a shot in the dark but...
selecting the first shown div and sliding it up
$('.slideShow:visible:first').slideUp();
selecting the first hidden div after the first shown div and sliding it down...
$('.slideShow:visible:first').next('.slideShow:hidden').slideDown()
psuedo selectors FTW!
Something like the following should do the trick
$(function() {
$(".scrollUp").click(function() {
//Check if any previous click animations are still running
if ($("div.slideShow:animated").length > 0) return;
//Get the first visible div
var firstVisibleDiv = $("div.slideShow:visible:first");
//Get the first hidden element before the first available div
var hiddenDiv = firstVisibleDiv.prev("div.slideShow");
if (hiddenDiv.length === 0) return; //Hit the top so early escape
$("div.slideShow:visible:last").slideUp();
hiddenDiv.slideDown();
});
$(".scrollDown").click(function() {
if ($("div.slideShow:animated").length > 0) return;
var lastVisibleDiv = $("div.slideShow:visible:last");
if (lastVisibleDiv.next("div.slideShow").length === 0) {
//No next element load in content (or AJAX it in)
$("<div>").addClass("slideShow")
.css("display", "none")
.text("Dummy")
.insertAfter(lastVisibleDiv);
}
$("div.slideShow:visible:first").slideUp();
lastVisibleDiv.next().slideDown();
});
});
Only thing that this solution does is check if an element that was previously invisible is now being animated. This solves some of the problems regarding multiple clicks of the links that occur before the animations have completed. If using AJAX you'd have to do something similar (e.g. turn a global variable on / off - or just disable the scroll down link) to avoid multiple requests being made to the server at once...