I am trying to put together a Leaflet based map for our college. We have just about everything done, but I'm running into a problem with the jQuery controls. We are using this block of code to highlight the jQuery buttons and send commands to Leaflet.
<script type="text/javascript">
jQuery(function(){
$(".img-swap").on('click', function() {
if ($(this).attr("class") == "img-swap") {
this.src = this.src.replace("_off","_on");
} else {
this.src = this.src.replace("_on","_off");
}
$(this).toggleClass("on");
});
});
</script>
<style type="text/css">
.img-swap {cursor: pointer;}
</style>
<p align="center"><img src="images/item1_off.png" class="img-swap" width="94" height="93" alt="Locate Item 1" /></p>
<p align="center"><img src="images/item2_off.png" class="img-swap" width="106" height="76" alt="Locate Item 2" /></p>
This code works just fine when you click on the objects. The issue we have is that we need to fire an event to deselect an object (and undo the corresponding Leaflet events) when a new object is clicked.
For example, if we have five items, and you click item one, it turns red and the map highlights some buildings. When you click item two, it should turn red, turn item one back to normal, and un-highlight the buildings that one highlighted.
I can't find a way to make this happen. It only works for items that are clicked, not the other items. Is there a modification to this code that does that?
Thanks!
Try the following:
jQuery(function(){
var selected = null;
$(".img-swap").on('click', function() {
if (selected) {
selected.src.replace("_on","_off");
$(selected).removeClass("on");
}
this.src.replace("_off","_on");
$(this).addClass("on");
selected = this;
});
});
Not tested but I would defined my on and off states in css then just change the class name on click.
<style>
.onImage
{
height: 20px;
background-repeat: repeat-x;
background-image: url("images/item1_on.png")
/* path relative to where the css is if not in page. */
}
.offImage
{
height: 20px; /* set the match the size of the icon */
background-repeat: no repeat;
background-image: url("images/item1_off.png")
/* path relative to where the css is if not in page. */
}
</style>
<script>
$(document).ready(function (){
$(".switch").on('click', function(evtObj) {
$(".onImage").removeClass("onImage").addClass("offImage");
$(evtObj.target).removeClass("offImage").addClass("onImage");
});
});
</script>
<div class='switch offIcon'></div>
<div class='switch offIcon'></div>
Related
I'm making a website with images on it, and if you click on one of the images it should enlarge. I did that by using the toggleClass function in jquery
I enlarged the selected image like so:
$(".img1, .img2").on('click',function(){
$(this).toggleClass('enlarged');
});
the used class:
.enlarged{
position:absolute;
z-index:2;
width:500px;
height:600px;
top:-10%;
left:300px;
}
it's hard to explain but right now what happens is, when you click an image it enlarges. when you click another image, it enlarges too but overlaps/stays hidden behind the other image that's enlarged.
What I would like to happen is when img1 is enlarged and the user selects img2, it should "close" img1 and enlarge img2.
Thank you :)
UPDATE
it now works barely, it opens after spamclicking and once enlarged I can minimize it again. but then I can't enlarge it anymore.
Can anybody help me with this?
<script>
$(document).ready(function() {
$("#header").load("header.html .header");
$("#footer").load("footer.html .footer");
$("body").on('click', function(){
if(!$(".img1, .img2").hasClass('enlarged')){
$(".img1, .img2").on('click',function(){
$(this).addClass('enlarged');
});
}else{
$("body").on('click', '.enlarged', function(){
$(this).removeClass('enlarged');
});
}
});
});
</script>
You could do something like the following. This will remove the enlarged class. Then add it to the image that you have clicked on. (See jsfiddle here)
$(".img1, .img2").on('click', function() {
$(".img1, .img2").removeClass("enlarged");
$(this).toggleClass('enlarged');
});
See working example below:
$(".img1, .img2").on('click', function() {
$(".img1, .img2").removeClass("enlarged");
$(this).toggleClass('enlarged');
});
.enlarged {
position: absolute;
z-index: 2;
width: 500px;
height: 600px;
top: -10%;
left: 300px;
}
label {
font-weight: bold;
}
input[type=text] {
width: 20em
}
p {
margin: 1em 0 0;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<img class="img1" src="https://placehold.it/350x150" alt="image" />
<img class="img2" src="https://placehold.it/350x150/F2F5A9" alt="image" />
Add a generic class to all clickable images, like 'gallery'
then
$(".gallery").on('click',function(){
//removes enlarged class from all images
$(".gallery.enlarged").removeClass('enlarged');
//adds enlarged class to clicked image
$(this).addClass('enlarged');
});
If you want to have only one "enlarged" class for the img you click on, I think the simpliest is to remove all "enlarged" class then add the class for the right element :
$(".img1, .img2").on('click',function(){
$(".img1, .img2").removeClass('enlarged');
$(this).addClass('enlarged');
});
I'm trying to swap background using jQuery. But the problem is that it doesn't successfully switch to new background, instead, the old one is removed and I get a white background instead.
I've been googling and trying out putting the path as a var instead for example, and some other unsuccessful suggestions.
My jQuery function looks like the following:
$("#btn").hover(function () {
$('#page1').css('background-image','url(../images/bg1_normal.jpg)');
});
And my CSS for the default background looks like this:
#page1 {
height: 100vh;
max-height: 100vh;
background-image: url("../images/bg1_rw.jpg");
background-repeat: no-repeat;
background-size: 100%;
}
I'm using Java Play Framework and the pictures are in the same folder, and it is the correct path to it since the default background works.
EDIT: I Tried as well to use an img source from the web, just to be 100% sure it wasn't some issues with the path, but it still only makes it white.
I believe jQuery's hover() function isn't able to remove that particular style when the mouse leaves.
You could just do it yourself
$("#btn").on({
mouseenter : function() {
$('#page1').css('background-image','url(../images/bg1_normal.jpg)');
},
mouseleave : function() {
$('#page1').removeAttr('style');
// or simply set the backround again to the other image
}
});
Try .addClass and .removeClass functions - it's simple and all style work is done in stylesheet file:
$("#btn").on({
mouseenter : function() {
$('#page1').addClass('inverted');
},
mouseleave : function() {
$('#page1').removeClass('inverted');
}
});
and then simply add
#page1.inverted {
//style as you need
}
to your stylesheet.
If you're using images you could do an image swap like this
https://jsfiddle.net/RachGal/oee3guxz/
$("#flowers").mouseover(function () {
var _this = $(this);
var current = _this.attr("src");
var swap = _this.attr("data-swap");
_this.attr('src', swap).attr("data-swap", current);
_this.toggleClass("opaque");
});
.opaque {
opacity:.5;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<img id='flowers' class="full" src='http://www.rachelgallen.com/images/snowdrops.jpg' width="500" height="400" data-swap='http://www.rachelgallen.com/images/daisies.jpg' width="500" height="400" />
or if you could just use color like this
$("#color").mouseleave(function () {
$("body").css("background-color","black");
});
$("#color").mouseover(function (){
$("body").css("background-color","red");
});
$("#color").click(function(){
$("body").css("background-color","green");
});
body, #color {
height: 800px;
width: 800px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div id="color"> </div>
https://jsfiddle.net/RachGal/8p783jfo/
Hope this helps
Rach
Basically I want the user to be able to click and change the background, and for there to be multiple backgrounds, for a specific div.
This works perfectly in Google Chrome but not in IE or Firefox.
HTML:
<div id="palette">
<div class="lightblue"></div>
<div class="gold"></div>
<div class="aqua"></div>
</div>
<div id="primary">
</div>
CSS:
#palette {
border: 2px solid white;
width: 25px;
}
#palette div {
height: 25px;
width: 25px;
}
.lightblue {
background: lightblue url(http://www.textureking.com/content/img/stock/big/DSC_4279.JPG);
}
.gold {
background: gold url(http://www.textureking.com/content/img/stock/big/DSC_4287.JPG);
}
.aqua {
background: aqua url(http://www.textureking.com/content/img/stock/big/DSC_4274.JPG);
}
JS:
$(document).ready(function() {
// attach onclick event to your palette colors
$('#palette div').on('click', function() {
// get background of selected palette color
var bg = $(this).css('background');
// change the background of the body
$('#primary').css({ 'background': bg });
});
});
http://jsfiddle.net/KNutQ/1/
It's not showing any errors and other javascripts run, so I'm not really sure what the problem is.
If it's easy to fix please leave an answer, if not I will try it this way: http://www.w3schools.com/jsref/tryit.asp?filename=tryjsref_style_backgroundimage
According to the CSS specification getting the computed style of a shorthand should not return anything. You need to list out the individual properties as I've done below.
Perhaps the CSS spec or Chrome will change in the future but at the moment Firefox and IE's behaviour is correct.
$(document).ready(function() {
// attach onclick event to your palette colors
$('#palette div').on('click', function() {
// get background of selected palette color
var backgrounds = $(this).css(['background-color','background-image', 'background-repeat', 'background-attachment', 'background-position']);
// change the background of the body
$('body').css(backgrounds);
});
});
I have a grid generator, it uses Javascript and jQuery to generate blocks in a grid that are displayed with HTML and CSS. I am trying to set up a button that will change the :hover behavior of the blocks (specifically, change their background-color). I am unable to do this and I'm not sure why my code is not working. I will copy and paste it here and I apologize that it is very long. You can see it in action here: http://codepen.io/anon/pen
HTML
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js">
</script>
<script type="text/javascript" src="script.js"></script>
<title> Odin #2 by Max Pleaner </title>
<link rel="stylesheet" type="text/css" href='stylesheet.css'>
</head>
<body>
<p> Welcome to my Odin Project #2 page. This is me showing off my basic JS and jQuery skills. If you move your mouse through the blocks you can see frogs come out of hiding. If you press the clear button below you can select a new number of blocks to fill the same space.</p>
<button id="button"> Generate a number of blocks of your liking that will position themselves to all fit in the 960px by 960px grid. </button>
<button id="button2"> <strike> Click here to generate new blocks and make hovering on blocks produce random colors.</strike> Why isn't this button working?! It's drawing new blocks fine, but not changing the :hover style as intended. </button>
<div id="square_holder">
</div>
<img src="Q6w802v.jpg" alt="froggy" ></img>
</body>
</html>
CSS
body {
background-color: grey;
}
p {
color: aqua;
}
#square_holder {
width: 960px;
}
.block {
background-color: green;
display:inline-block;
border: 1px solid black;
width: 232px;
height: 232px;
}
.block:hover {
background-color: blue;
//background-image:url("Q6w802v.jpg");
background-size: contain;
}
JS
$(document).ready(function(){
draw_grid(4);
$('#button').click(function(){
get_input();
});
$('#button2').click(function(){
get_input();
$('.block:hover').css("background-image", "none").css("background-color", get_random_color());
});
});
var draw_grid = function (blocks) {
var totalno = Math.pow(blocks, 2);
var dimension = (960 - 1 -(blocks * 2))/blocks;
for(var i = 0; i < totalno; i++){
$("#square_holder").append("<div class='block' id=" + i + "></div>");
};
$(".block").css("height", dimension).css("width", dimension);
}
var get_input = function(){
alert('Do you want to change the number of boxes?<b></b>');
$('#square_holder').empty();
var user_entry = prompt("What number do you choose?");
alert("Watch in awe as the grid fills ..... ");
draw_grid(user_entry);
}
var get_random_color = function() {
var letters = '0123456789ABCDEF'.split('');
var color = '#';
for (var i = 0; i < 6; i++ ) {
color += letters[Math.round(Math.random() * 15)];
}
return color;
};
You need to use background, not background-color. Taken from the MDN page for background-image:
The CSS background-image property sets one or several background images for an element. The images are drawn on successive stacking context layers, with the first specified being drawn as if it is the closest to the user. The borders of the element are then drawn on top of them, and the background-color is drawn beneath them.
This translates into a declaration of background-image at all (even as none) will sit on top of background-color. Therefore, if you set background instead of background-color, it will supercede all other property-specific declarations.
I am new to javascript and would like to have an image that is fully displayed but when you mouse over the image text appears over the top in a div tag and fades the image in the background.
This is my attempt however poor and it is not working.
<style>
/*CSS Style sheet*/
div.image_box_text {
opacity:0;
margin-top:-25px;
background-color:#FFF;
}
</style>
<script>
function fadeImg(obj) {
obj.style.opacity=0.5;
obj.filters.alpha.opacity=50;
}
function viewObj(obj1, obj2) {
fadeImg(obj1);
obj2.style.opacity=1;
bj2.filters.alpha.opacity=100;
}
</script>
<div>
<img id='img1' src="../images/index/square/posingS.jpg" onmouseover='viewImg(this, txt1)'/>
<div id='txt1' class='image_box_text' >This is image box one</div>
</div>
Thanks in advance.
This should get you started.
<style>
/*CSS Style sheet*/
div.image_box_text {
opacity:0;
margin-top:-25px;
background-color:#FFF;
}
</style>
<script>
function fadeImg(obj) {
obj.style.opacity=0.5;
}
function viewObj(obj1, obj2_name) {
var obj2 = document.getElementById(obj2_name);
fadeImg(obj1);
obj2.style.opacity=1;
}
</script>
First, you cannot simply call an object by an id as you did in viewObj. You must do a document.getElementById on its id. Next you will have to check if filters exists (it only does in IE). A better way to do this is to make .faded and .hidden classes in your stylesheet and have the hover event trigger the adding and removal of them.
Here's this code in action: http://jsfiddle.net/WpMGd/