We Keep Coding

On click add class to child element without Jquery

I have a task where Jquery is not working, so I need a workaround to perform an add class event to child element of a div upon click event.
How do I go about that.
The Jquery for that purpose would be
$('.wpb_vc_column').click(function(e) {
alert();
e.preventDefault();
$(this).find('.vc_controls').addClass('show-controls');
});
.show-controls {
color: red
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="wpb_vc_column">
<div class="vc_controls">SomeThing</div>
</div>
Its basically a wordpress backend thing which need to be workable on mobile devices.
Regards

You can use querySelectorAll() to select all the elements with class wpb_vc_column and associate the click event to each element. Then click on these element will find the child elements with class vc_controls and add the class to it.
function clickedColumn(e){
e.preventDefault();
if(this.querySelector('.vc_controls')){
this.classList.add('show-controls');
}
}
document.querySelectorAll('.wpb_vc_column').forEach(function(el){
el.addEventListener('click', clickedColumn);
});
.show-controls{
color:red;
}
<div class="wpb_vc_column">
<div class="vc_controls">SomeThing 1</div>
<div class="vc_controls">SomeThing 2</div>
</div>

var myEle = document.getElementsByClassName('vc_controls');
myEle.className = "show-controls";

make use of querySelector method and and search for child in parent element
el.querySelector("#child").className = 'show-controls';
or
el.querySelector('.vc_controls').className = 'show-controls';

function changeClass(element){
var get_vc_controls=element.getElementsByClassName('vc_controls');
get_vc_controls[0].className='show-controls';
}
.show-controls {
color: red
}
<div class="wpb_vc_column" style="border:1px solid;" onclick="changeClass(this)">
<div class="vc_controls">SomeThing</div>
</div>

div into a js button [duplicate]

This question already has answers here:
Add click event on div tag using JavaScript
(6 answers)
Closed 5 years ago.
I have a <div> that I have formatted very carefully to look nice, and I need to make it have the functionality of a button. How would I go about doing this?

You can give that div tag a onclick function as follows.
function myfns() {
console.log("Clicked")
}
<div id="btn" onclick="myfns()">Click</div>

First recommendation is to use a <button> instead. You can style that however you want as well. If that is not an option for some reason, you'll have to do a few different things to create a proper button out of a div element (to ensure that it works with keyboard and screen readers).
Add click handler. Eg btn.addEventListener('click', clickHandler);
Add enter key handler. Eg btn.addEventListener('keyup', keyHandler);
Add button role. role="button"
Add it to tab order: tabindex="0"
var buttons = document.querySelectorAll('.btn');
buttons.forEach(function (btn) {
btn.addEventListener('click', function(e) {
console.log('clicked');
});
btn.addEventListener('keyup', function(e) {
if (e.key === 'Enter') {
console.log('keyup');
}
});
});
.btn {
display: inline-block;
background: #eee;
border: 1px solid #aaa;
padding: 6px;
cursor: pointer;
}
<div class="btn" role="button" tabindex="0">My Button</div>
<div class="btn" role="button" tabindex="0">My Button</div>
<div class="btn" role="button" tabindex="0">My Button</div>

document.getElementByID("#divID").addEventListenet('click',()=>{
//write your logic
})
handle all button event similarly
e.g. doubleclick etc

Like if you have div
<div class="demo" >
....
</div>
And If you are using javascript
document.getElementsByClassName('demo')[0]
.addEventListener('click', function (event) {
// do something
});
using jquery u can do like
$(".demo").click(function(){
//do something
});

How to create onClick function for a dynamically generated div

I am trying to implement onClick function for a div which is getting generated depending on some validations while submitting the page. I am trying to implement the same from an external js file.
HTML design is something like :
<div id="QViewInfo" style="top: 207px; left: 531.5px;">
//dynamically generated
<div>
---
----
</div>
</div>
Now, I am trying to implement the onClick function like below :
$('img.popUpClose.popUpCloseQview').each(function (index) {
$(this).on("click", function (e) {
//DO something
});
});
But the issue is, this $('img.popUpClose.popUpCloseQview') element is not there in the code on the first time. After the submit button click valiations are happening and depending on the condition this pop up message is coming up and this function is not working anytime.
Tried some other options too. But none of these are working.
Please advise.
Thanks,
Aniket

If you are dynamically generating the div in jquery, you can add the click event then. For example:
var div = $("<div>");
div.click(function(){//dostuff});
$("#QViewInfo").append(div);

You could attach the click event to all the div's of element #QViewInfo using event delegation on() like :
$('#QViewInfo').on('click', 'div', function(){
//DO something
})
NOTE : No need for using each() loop.
Hope this helps.
$('#QViewInfo').append('<div>Div 3</div>');
$('#QViewInfo').on('click', 'div', function(){
console.log($(this).text());
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="QViewInfo" style="top: 207px; left: 531.5px;">
<div>Div 1</div>
<div>Div 2</div>
</div>
Working snippet with comment code :
var img = '<img src="/Images/...." onclick="alert(\'QView.close();\')" alt="Close Quick View" class="popUpClose popUpCloseQview">';
$('.oosInfo').append(img);
$('#QViewInfo').on('click', 'img.popUpClose.popUpCloseQview', function(){
alert("A");
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="QViewInfo">
<div class="oosInfo">
<div class="alertImgDiv">
<span class="oosAlertImg"></span>
</div>
</div>
</div>

Listen event from Shadow Dom

How do I listen a mouseover event from shadow DOM. I did try as snipcode below but nothing happen. The template instance is generated after button Add is clicked and I register mouseover event for it and hopping this event is fired when mouseover.
Thank a lot
HTML
<body>
<h1 class="text-center">Test import Node</h1>
<div class="container-fluid" style=" background-color: #FAFAFA"></div>
<div class="col-md-12" id = 'root'>
<button type="button" class="btn btn-default go" id='_add'><i class="fa fa-pencil-square-o"></i> Add</button>
<div id = 'textbox' style="height: 200px; width: 400px; font-size: 18px"></div>
</div>
<template id = 'area'>
<div style="height : 400px; width: 300px ; background-color: red"></div>
</template>
</body>
Javascript
$(document).ready(function() {
var button = document.querySelector('#_add');
button.addEventListener('click', function(){
check();
}, false);
});
function check(){
// document.querySelector('#textbox').innerHTML = "Ukie";
var content = document.querySelector('#area').content;
content.addEventListener('mouseover', function(){
display();
}, false);
var root = document.querySelector('#root');
root.appendChild(document.importNode(content, true));
}
function display(){
document.querySelector('#textbox').innerHTML = "Here";
}

As per addEventListener docs:
The event target may be an Element in a document, the Document itself, a Window, or any other object that supports events (such as XMLHttpRequest).
Therefore element must exist in the DOM, when you call addEventListener on it.
As a workaround, you can use event delegation using jquery on method to achieve the same. Here is a working jsfiddle by tweaking your sample a bit.
$('#root').on('mouseover', '.dyn', function(){
display();
});
Here bound element will be parent of template content(about which you are sure that it will exist while binding event) and you'll pass selector of your content html to .on method as argument. Thus whenever event occurs on child(in this case your template content) it will bubble up to parent and callback will be triggered.

You can use on function with jQuery. With on function you can "bind" events on element which not created in the DOM when the code was executed.
Read this: http://api.jquery.com/on/

jquery toggle open all div s on one click

Please take a look at below codes, for whatever reason I am unable to open one div only when I click on the edit link, it opens all divs when I click the edit link.
jQuery
$(document).ready(function () {
$("input:button[name='uploadboy']").click(function () {
$(this).parent().children('.uploadboy').slideToggle(200, 'swing');
});
});
HTML
<div style="overflow:auto;" class="links-box ">
<p style="float:left; width:250px;" id="links">
<input type="button" name="uploadboy" id="uploadboy" value="Uploaded" title="Uploaded" style="text-decoration:none; color: white; text-shadow:none; background: #0692fe; float:left;" class="g-button">
</p>
</div>
<div class="uploadboy" width: 600px;min-height:50px;background-color: #F2FDD7;border-radius: 10px;border: 1px solid #8EBD43;">
<p>content</p>
</div>
<div style="overflow:auto;" class="links-box ">
<p style="float:left; width:250px;" id="links">
<input type="button" name="uploadboy" id="uploadboy" value="Uploaded" title="Uploaded" style="text-decoration:none; color: white; text-shadow:none; background: #0692fe; float:left;" class="g-button">
</p>
</div>
<div class="uploadboy" width: 600px;min-height:50px;background-color: #F2FDD7;border-radius: 10px;border: 1px solid #8EBD43;">
<p>content</p>
</div>
example in jsFiddle

Use the below script, .find method only searches for the descendants (http://api.jquery.com/find/).
$(document).ready(function () {
$("input:button[name='uploadboy']").click(function () {
$(this).parent().parent().next('.uploadboy').slideToggle(200, 'swing');
});
});

As I mentioned in my comment above, IDs must be unique. That said, try this:
$("input").click(function () {
$(this).slideToggle(200, 'swing');
});
jsFiddle example

What I initially see here that's an issue is that you have 2 input buttons with the same id. While this may not be the overall issue, you still can't have 2 elements with the same id. I also am not sure if this is just generic code you cleaned to ask a question, but your selectors seem pretty complicated. You attach the .click event to both input buttons, then you go to the buttons parent, which is the paragraph, then you go the child object which is the button. You are essentially going from point one spot, up a level, then back down a level. When the click handler is attached to the button, anytime you click a button, you can reference $(this) to refer to the button.
<input type="button" name="uploadboy" id="button1" />
<input type="button" name="uploadboy" id="button2" />
$(document).ready(function(){
$("input:button[name='uploadboy']").click(function () {
$(this).SlideToggle(200, 'swing');
});
});
If you look at the function that is ran when the input button is clicked, it simply refers to the $(this) object. This is a benefit of jquery and $(this) is the specific button that you clicked. Even if there are 20 buttons on the page, whatever button is clicked will be this. So in the above example, the button clicked will have the slide toggle occur. You could also navigate the dom off of this if you need to move around like before.