JSFiddle link - http://jsfiddle.net/lustre/p0z9wp51/1/
I didn't create this code, but the blog which it was created from isn't working at the moment...
Is it possible to have the spinner center itself on the segment it lands on? For example, sometimes it may just land on segment "A", could it then shift to center itself on segment "A"? Or would that require a complete rebuild of the spinner itself?
It's worth noting that the number of segments is dynamic, in that users can add their own names.
The code below begins the spin, and calculates the angle, and total time to spin.
spin: function() {
spinAngleStart = Math.random() * 10 + 10;
spinTime = 0;
spinTimeTotal = Math.random() * 3 + 4 * 1000;
rotateWheel();
},
And this code actually rotates the wheel (afaik).
var rotateWheel = function rotateWheel() {
spinTime += 30;
if(spinTime >= spinTimeTotal) {
stopRotateWheel();
return;
}
var spinAngle = spinAngleStart - easeOut(spinTime, 0, spinAngleStart, spinTimeTotal);
startAngle += (spinAngle * Math.PI / 180);
drawWheel();
spinTimeout = setTimeout(rotateWheel, 30);
}
index returns the segment/array index of the section it's landed on.
outterRadius is the radius of the outer circle. Responsively, the circle is resized with CSS percentages, would this affect the outer radius in HTML5? Or not as it's rendered before the CSS takes effect?
If it would require a complete rebuild, that's fine. Just looking for feedback on whether it's even possible with this code from people more experience in HTML5 than me :)
Related
I am trying to move an object smoothly from point A to point B using HTML canvas and regular javascript.
Point A is a set of coordinates
Point B is in the case the cursor location.
I made a jsfiddle of what I have so far: https://jsfiddle.net/as9fhmw8/
while(projectile.mouseX > projectile.x && projectile.mouseY < projectile.y)
{
ctx.save();
ctx.beginPath();
ctx.translate(projectile.x, projectile.y);
ctx.arc(0,0,5,0,2*Math.PI);
ctx.fillStyle = "blue";
ctx.fill();
ctx.stroke();
ctx.restore();
if(projectile.mouseX > projectile.x && projectile.mouseY < projectile.y)
{
var stepsize = (projectile.mouseX - projectile.x) / (projectile.y - projectile.mouseY);
projectile.x += (stepsize + 1);
}
if(projectile.mouseY < projectile.y)
{
var stepsize = (projectile.y - projectile.mouseY) / (projectile.mouseX - projectile.x);
projectile.y -= (stepsize + 1);
}
}
Essentially what I can't figure out to do is to make the while loop slower (so that it appears animated in stead of just going through every iteration and showing the result).
I also can't figure out how to prevent the Arc from duplicating so that it creates a line that is permanent, instead of appearing to move from point a to point b.
Smooth animation here is really about determining how far to move your object for each iteration of the loop.
There is a little math involved here, but it's not too bad.
Velocity
Velocity in your case is just the speed at which your particles travel in any given direction over a period of time. If you want your particle to travel 200px over the course of 4 seconds, then the velocity would be 50px / second.
With this information, you can easily determine how many pixels to move (animate) a particle given some arbitrary length of time.
pixels = pixelsPerSecond * seconds
This is great to know how many pixels to move, but doesn't translate into individual X and Y coordinates. That's where vectors come in.
Vectors
A vector in mathematics is a measurement of both direction and magnitude. For our purposes, it's like combining our velocity with an angle (47°).
One of the great properties of vectors is it can be broken down into it's individual X and Y components (for 2-Dimensional space).
So if we wanted to move our particle at 50px / second at a 47° angle, we could calculate a vector for that like so:
function Vector(magnitude, angle){
var angleRadians = (angle * Math.PI) / 180;
this.magnitudeX = magnitude * Math.cos(angleRadians);
this.magnitudeY = magnitude * Math.sin(angleRadians);
}
var moveVector = new Vector(50, 47);
The wonderful thing about this is that these values can simply be added to any set of X and Y coordinates to move them based on your velocity calculation.
Mouse Move Vector
Modeling your objects in this way has the added benefit of making things nice and mathematically consistent. The distance between your particle and the mouse is just another vector.
We can back calculate both the distance and angle using a little bit more math. Remember that guy Pythagoras? Turns out he was pretty smart.
function distanceAndAngleBetweenTwoPoints(x1, y1, x2, y2){
var x = x2 - x1,
y = y2 - y1;
return {
// x^2 + y^2 = r^2
distance: Math.sqrt(x * x + y * y),
// convert from radians to degrees
angle: Math.atan2(y, x) * 180 / Math.PI
}
}
var mouseCoords = getMouseCoords();
var data = distanceAndAngleBetweenTwoPoints(particle.x, particle.y, mouse.x, mouse.y);
//Spread movement out over three seconds
var velocity = data.distance / 3;
var toMouseVector = new Vector(velocity, data.angle);
Smoothly Animating
Animating your stuff around the screen in a way that isn't jerky means doing the following:
Run your animation loop as fast as possible
Determine how much time has passed since last time
Move each item based on elapsed time.
Re-paint the screen
For the animation loop, I would use the requestAnimationFrame API instead of setInterval as it will have better overall performance.
Clearing The Screen
Also when you re-paint the screen, just draw a big rectangle over the entire thing in whatever background color you want before re-drawing your items.
ctx.globalCompositeOperation = "source-over";
ctx.fillStyle = "black";
ctx.fillRect(0, 0, canvas.width, canvas.height);
Putting It All Together
Here is a Fiddle demonstrating all these techniques: https://jsfiddle.net/jwcarroll/2r69j1ok/3/
I'm having an issue with a HTML5 canvas idea. It's basically a game, whereby the player is always centered in the canvas - this means that for 'movement' the rest of the scene must move instead. I have this setup, but I also wanted to have a clickable grid (50x50 px) on top of the scene (as if the game's elements are made up of blocks).
For drawing the mouse box I have the following code:
// Draw mouse box
if(game.mouse.o){
var mouseBlockX = (Math.floor(game.mouse.x / 50) * 50) + (game.view.x % 50);
// Previous attempt:
// var mouseBlockX = (Math.floor((game.mouse.x - ( 0.5 * game.view.x % 50)) / 50) * 50) + (game.view.x % 50);
var mouseBlockY = (Math.floor((game.mouse.y - ( 0.5 * game.view.y % 50)) / 50) * 50) + (game.view.y % 50);
ctx.fillText('Block: ' + mouseBlockX.toString() + '/' + mouseBlockY.toString(), 5, 400);
ctx.fillText(Math.abs(game.view.x) % 50, 5, 410);
ctx.strokeStyle = '#DDDDFF';
ctx.strokeWidth = 1;
ctx.strokeRect(mouseBlockX, mouseBlockY, 50, 50);
}
Essentially, my main issue here is that the following line doesn't work properly:
(Math.floor((game.mouse.x - ( 0.5 * game.view.x % 50)) / 50) * 50) + (game.view.x % 50)
...and I've tried to find a correct version, but it's beating me at the minute. What would be the correct formula so that the mouse's box follows the mouse, but also compensates for the view moving? Have I made it too complicated so I'm missing the answer?
JSFiddle: http://jsfiddle.net/y14ftv0o/
UPDATE: changed variables to be clearer. To try and explain in a better way: when the view moves, the 'grid' doesn't properly stick to its original position. When the view moves, the grid should look like it is fixed to the original objects on the scene (essentially so the user thinks they're 'clicking' on things in the scene on a grid).
I have 100 items entering the viewport in random order. Together, they need to form a circle inside a DOM container. I need some way to calculate the position the items need to move to...
The structure is kinda like this:
http://codepen.io/anon/pen/WvbKjb (visual sample with a bit of css and js inside)
<div id="circle"><!-- 100 items in here --></div</div>
And then the JS, for this sample, would generate 100 divs and set their position with css:
for (i = 0; i <= 100; i++) {
var item = document.createElement('div');
item.id = 'item'+i;
item.className = 'item';
item.setAttribute('style', 'left:0px;top:0px');
document.getElementById('circle').appendChild(item);
}
So I would generate 100 .item elements and move them around the screen. This movement is not an issue: what I don't know how to do is find the position each item has to end up at to properly fill the circle. Is there any way to easily calculate this with a formula? I'm afraid it's way beyond my math skills...
Thanks in advance for any help.
EDIT: using jQuery would be fine too.
You may start with this, just a bit of a math:
Example
the main part is:
var spacing = 360 / count;
var l = Math.cos(rotation * Math.PI / 180) * radius - itemRadius;
var t = Math.sin(rotation * Math.PI / 180) * radius - itemRadius;
rotation += spacing;
Where spacing is actually an angle
Probably a little overloaded but this is what i tried and what worked for me: https://jsfiddle.net/tx7po9eg/1/
Main Part is this function which will calculate the position of a specific element depending on the defined center and the radius.
function getPos(cent, rad, amount, iteration) {
var degree = 360 / amount * iteration;
var changeY = cent.y - (Math.sin(degree * Math.PI / 180) * rad);
var changeX = cent.x - (Math.cos(degree * Math.PI / 180) * rad);
var ret = {};
ret.x = Math.round(changeX * 100) / 100;
ret.y = Math.round(changeY * 100) / 100;
return ret;
}
here an example including visualization:
https://jsfiddle.net/tx7po9eg/3/
You will have to decide exactly HOW you want to fit all the elements inside the circle. Do you want them in a single line around the parameter? At Random? Fill the circle?
If you want to fill the circle, one thing you could do is work like that - move from the center outside, starting by putting an item in the middle, then going out and putting another circle around it, then another around it, and like that keep wrapping it in layers until you hit the end of the circle. The only thing to figure out here would be the spacing (e.g. how many circles in each layer), and that would depend on the size of each element (are the sizes fixed)?
If you can make the container circle as large as you desire, you can just start making layers until you run out of items, and then place the big circle around them.
Hope this helps...
this is my first question after having relied on this site for years!
Anyway, I'd like to accomplish something similar to this effect:
http://www.flashmonkey.co.uk/html5/wave-physics/
But on a circular path, instead of a horizon. Essentially, a floating circle/blob in the center of the screen that would react to mouse interaction. What I'm not looking for is gravity, or for the circle to bounce around the screen - only surface ripples.
If at all possible I'd like to apply a static texture to the shape, is this a possibility? I'm completely new to Canvas!
I've already tried replacing some code from the above example with circular code from the following link, to very limited success:
http://www.html5canvastutorials.com/tutorials/html5-canvas-circles/
If only it were that easy :)
Any ideas?
Thanks in advance!
I tried to figure out how wave simulation works using View Source and JavaScript console. It's working fine but threw some JS errors. Also, it seems physics update is entangled with rendering in the render() method.
Here is what I found about the code:
The mouseMove() method creates disturbances on the wave based on mouse position, creating a peak around the mouse. The target variable is the index of the particle that needs to be updated, it's calculated from mouse pos.
if (particle && mouseY > particle.y) {
var speed = mouseY - storeY;
particles[target - 2].vy = speed / 6;
particles[target - 1].vy = speed / 5;
particles[target].vy = speed / 3;
particles[target + 1].vy = speed / 5;
particles[target + 2].vy = speed / 6;
storeY = mouseY;
}
Then, the particles around target are updated. The problem I found is that it does no bounds checking, i.e. it can potentially particles[-1] when target == 0. If that happens, an exception is thrown, the method call ends, but the code does not stop.
The render() method first updates the particle positions, then renders the wave.
Here is its physics code:
for (var u = particles.length - 1; u >= 0; --u) {
var fExtensionY = 0;
var fForceY = 0;
if (u > 0) {
fExtensionY = particles[u - 1].y - particles[u].y - springs[u - 1].iLengthY;
fForceY += -fK * fExtensionY;
}
if (u < particles.length - 1) {
fExtensionY = particles[u].y - particles[u + 1].y - springs[u].iLengthY;
fForceY += fK * fExtensionY;
}
fExtensionY = particles[u].y - particles[u].origY;
fForceY += fK / 15 * fExtensionY;
particles[u].ay = -fForceY / particles[u].mass;
particles[u].vy += particles[u].ay;
particles[u].ypos += particles[u].vy;
particles[u].vy /= 1.04;
}
Basically, it's Hooke's Law for a chain of particles linked by springs between them. For each particle u, it adds the attraction to the previous and next particles (the if statements check if they are available), to the variable fForceY. I don't fully understand the purpose of the springs array.
In the last four lines, it calculates the acceleration (force / mass), updates the velocity (add acceleration), then position (add velocity), and finally, reduce velocity by 1.04 (friction).
After the physics update, the code renders the wave:
context.clearRect(0, 0, stageWidth, stageHeight);
context.fillStyle = color;
context.beginPath();
for (u = 0; u < particles.length; u++) {
...
}
...
context.closePath();
context.fill();
I'm not explaining that, you need to read a canvas tutorial to understand it.
Here are some ideas to get started, note that I didn't test these code.
To modify the code to draw a circular wave, we need introduce a polar coordinate system, where the particle's x-position is the angle in the circle and y-position the distance from center. We should use theta and r here but it requires a large amount of refactoring. We will talk about transforming later.
mouseMove(): Compute particle index from mouse position on screen to polar coordinates, and make sure the disturbance wrap around:
Define the function (outside mouseMove(), we need this again later)
function wrapAround(i, a) { return (i + a.length) % a.length; }
Then change
particles[target - 2] --> particles[wrapAround(target - 2, particles)]
particles[target - 1] --> particles[wrapAround(target - 1, particles)]
...
The modulo operator does the job but I added particles.length so I don't modulo a negative number.
render(): Make sure the force calculation wrap around, so we need to wrapAround function again. We can strip away the two if statements:
fExtensionY = particles[wrapAround(u - 1, particles)].y - particles[u].y - springs[wrapAround(u - 1, springs)].iLengthY;
fForceY += -fK * fExtensionY;
fExtensionY = particles[u].y - particles[wrapAround(u + 1, particles)].y - springs[warpAround(u, springs)].iLengthY;
fForceY += fK * fExtensionY;
Here is the result so far in jsfiddle: Notice the wave propagate from the other side. http://jsfiddle.net/DM68M/
After that's done, the hardest part is rendering them on a circle. To do that, we need coordinate transform functions that treat particle's (x, y) as (angle in the circle, distance from center), and we also need inverse transforms for mouse interaction in mouseMove().
function particleCoordsToScreenCoords(particleX, particleY) {
return [ radiusFactor * particleY * Math.cos(particleX / angleFactor),
radiusFactor * particleY * Math.sin(particleX / angleFactor) ];
}
function screenCoordsToParticleCoords(screenX, screenY) {
// something involving Math.atan2 and Math.sqrt
}
Where the ...Factor variables needed to be determined separately. The angleFactor is two pi over the highest x-position found among particles array
Then, in the coordinates supplied to the context.lineTo, context.arc, use the particleCoordsToScreenCoords to transform the coordinates.
The following code creates a circle in HTML 5 Canvas using jQuery:
Code:
//get a reference to the canvas
var ctx = $('#canvas')[0].getContext("2d");
DrawCircle(75, 75, 20);
//draw a circle
function DrawCircle(x, y, radius)
{
ctx.beginPath();
ctx.arc(x, y, radius, 0, Math.PI*2, true);
ctx.fillStyle = 'transparent';
ctx.lineWidth = 2;
ctx.strokeStyle = '#003300';
ctx.stroke();
ctx.closePath();
ctx.fill();
}
I am trying to simulate any of the following types of circles:
I have researched and found this article but was unable to apply it.
I would like for the circle to be drawn rather than just appear.
Is there a better way to do this? I'm sensing there's going to be a lot of math involved :)
P.S. I like the simplicity of PaperJs, maybe this would be the easiest approach using it's simplified paths?
There are already good solutions presented here. I wanted to add a variations of what is already presented - there are not many options beyond some trigonometry if one want to simulate hand drawn circles.
I would first recommend to actually record a real hand drawn circle. You can record the points as well as the timeStamp and reproduce the exact drawing at any time later. You could combine this with a line smoothing algorithm.
This here solution produces circles such as these:
You can change color, thickness etc. by setting the strokeStyle, lineWidth etc. as usual.
To draw a circle just call:
handDrawCircle(context, x, y, radius [, rounds] [, callback]);
(callback is provided as the animation makes the function asynchronous).
The code is separated into two segments:
Generate the points
Animate the points
Initialization:
function handDrawCircle(ctx, cx, cy, r, rounds, callback) {
/// rounds is optional, defaults to 3 rounds
rounds = rounds ? rounds : 3;
var x, y, /// the calced point
tol = Math.random() * (r * 0.03) + (r * 0.025), ///tolerance / fluctation
dx = Math.random() * tol * 0.75, /// "bouncer" values
dy = Math.random() * tol * 0.75,
ix = (Math.random() - 1) * (r * 0.0044), /// speed /incremental
iy = (Math.random() - 1) * (r * 0.0033),
rx = r + Math.random() * tol, /// radius X
ry = (r + Math.random() * tol) * 0.8, /// radius Y
a = 0, /// angle
ad = 3, /// angle delta (resolution)
i = 0, /// counter
start = Math.random() + 50, /// random delta start
tot = 360 * rounds + Math.random() * 50 - 100, /// end angle
points = [], /// the points array
deg2rad = Math.PI / 180; /// degrees to radians
In the main loop we don't bounce around randomly but increment with a random value and then increment linearly with that value, reverse it if we are at bounds (tolerance).
for (; i < tot; i += ad) {
dx += ix;
dy += iy;
if (dx < -tol || dx > tol) ix = -ix;
if (dy < -tol || dy > tol) iy = -iy;
x = cx + (rx + dx * 2) * Math.cos(i * deg2rad + start);
y = cy + (ry + dy * 2) * Math.sin(i * deg2rad + start);
points.push(x, y);
}
And in the last segment we just render what we have of points.
The speed is determined by da (delta angle) in the previous step:
i = 2;
/// start line
ctx.beginPath();
ctx.moveTo(points[0], points[1]);
/// call loop
draw();
function draw() {
ctx.lineTo(points[i], points[i + 1]);
ctx.stroke();
ctx.beginPath();
ctx.moveTo(points[i], points[i + 1]);
i += 2;
if (i < points.length) {
requestAnimationFrame(draw);
} else {
if (typeof callback === 'function')
callback();
}
}
}
Tip: To get a more realistic stroke you can reduce globalAlpha to for example 0.7.
However, for this to work properly you need to draw solid to an off-screen canvas first and then blit that off-screen canvas to main canvas (which has the globalAlpha set) for each frame or else the strokes will overlap between each point (which does not look good).
For squares you can use the same approach as with the circle but instead of using radius and angle you apply the variations to a line. Offset the deltas to make the line non-straight.
I tweaked the values a little but feel free to tweak them more to get a better result.
To make the circle "tilt" a little you can first rotate the canvas a little:
rotate = Math.random() * 0.5;
ctx.save();
ctx.translate(cx, cy);
ctx.rotate(-rotate);
ctx.translate(-cx, -cy);
and when the loop finishes:
if (i < points.length) {
requestAnimationFrame(draw);
} else {
ctx.restore();
}
(included in the demo linked above).
The circle will look more like this:
Update
To deal with the issues mentioned (comment fields too small :-) ): it's actually a bit more complicated to do animated lines, especially in a case like this where you a circular movement as well as a random boundary.
Ref. comments point 1: the tolerance is closely related to radius as it defined max fluctuation. We can modify the code to adopt a tolerance (and ix/iy as they defines how "fast" it will variate) based on radius. This is what I mean by tweaking, to find that value/sweet-spot that works well with all sizes. The smaller the circle the smaller the variations. Optionally specify these values as arguments to the function.
Point 2: since we're animating the circle the function becomes asynchronous. If we draw two circles right after each other they will mess up the canvas as seen as new points are added to the path from both circles which then gets stroked criss-crossed.
We can get around this by providing a callback mechanism:
handDrawCircle(context, x, y, radius [, rounds] [, callback]);
and then when the animation has finished:
if (i < points.length) {
requestAnimationFrame(draw);
} else {
ctx.restore();
if (typeof callback === 'function')
callback(); /// call next function
}
Another issues one will run into with the code as-is (remember that the code is meant as an example not a full solution :-) ) is with thick lines:
When we draw segment by segment separately canvas does not know how to calculate the butt angle of the line in relation to previous segment. This is part of the path-concept. When you stroke a path with several segments canvas know at what angle the butt (end of the line) will be at. So here we to either draw the line from start to current point and do a clear in between or only small lineWidth values.
When we use clearRect (which will make the line smooth and not "jaggy" as when we don't use a clear in between but just draw on top) we would need to consider implementing a top canvas to do the animation with and when animation finishes we draw the result to main canvas.
Now we start to see part of the "complexity" involved. This is of course because canvas is "low-level" in the sense that we need to provide all logic for everything. We are basically building systems each time we do something more with canvas than just draw simple shapes and images (but this also gives the great flexibility).
Here are some basics I created for this answer:
http://jsfiddle.net/Exceeder/TPDmn/
Basically, when you draw a circle, you need to account for hand imperfections. So, in the following code:
var img = new Image();
img.src="data:image/png;base64,...";
var ctx = $('#sketch')[0].getContext('2d');
function draw(x,y) {
ctx.drawImage(img, x, y);
}
for (var i=0; i<500; i++) {
var radiusError = +10 - i/20;
var d = 2*Math.PI/360 * i;
draw(200 + 100*Math.cos(d), 200 + (radiusError+80)*Math.sin(d) );
}
Pay attention how vertical radiusError changes when the angle (and the position) grows. You are welcome to play with this fiddle until you get a "feel" what component does what. E.g. it would make sense to introduce another component to radiusError that emulates "unsteady" hand by slowly changing it my random amounts.
There are many different ways to do this. I choose trig functions for the simplicity of the simulation, as speed is not a factor here.
Update:
This, for example, will make it less perfect:
var d = 2*Math.PI/360 * i;
var radiusError = +10 - i/20 + 10*Math.sin(d);
Obviously, the center of the circle is at (200,200), as the formula for drawing a circle (rather, ellipsis with vertical radius RY and horizontal radius RX) with trigonometric functions is
x = centerX + RX * cos ( angle )
y = centerY + RY * sin ( angle )
Your task seems to have 3 requirements:
A hand-drawn shape.
An “organic” rather than “ultra-precise” stroke.
Revealing the circle incrementally instead of all-at-once.
To get started, check out this nice on-target demo by Andrew Trice.
This amazing circle is hand drawn by me (you can laugh now...!)
Andrew's demo does steps 1 and 2 of your requirements.
It lets you hand draw a circle (or any shape) using an organic looking “brush effect” instead of the usual ultra-precise lines normally used in canvas.
It achieves the “brush effect” by by repeated drawing a brush image between hand drawn points
Here’s the demo:
http://tricedesigns.com/portfolio/sketch/brush.html#
And the code is available on GitHub:
https://github.com/triceam/HTML5-Canvas-Brush-Sketch
Andrew Trice’s demo draws-and-forgets the lines that make up your circle.
Your task would be to impliment your third requirement (remembering strokes):
Hand draw a circle of your own,
Save each line segment that makes up your circle in an array,
“Play” those segements using Andrew’s stylized brush technique.
Results: A hand-drawn and stylized circle that appears incrementally instead of all at once.
You have an interesting project…If you feel generous, please share your results!
See live demo here. Also available as a gist.
<div id="container">
<svg width="100%" height="100%" viewBox='-1.5 -1.5 3 3'></svg>
</div>
#container {
width:500px;
height:300px;
}
path.ln {
stroke-width: 3px;
stroke: #666;
fill: none;
vector-effect: non-scaling-stroke;
stroke-dasharray: 1000;
stroke-dashoffset: 1000;
-webkit-animation: dash 5s ease-in forwards;
-moz-animation:dash 5s ease-in forwards;
-o-animation:dash 5s ease-in forwards;
animation:dash 5s ease-in forwards;
}
#keyframes dash {
to { stroke-dashoffset: 0; }
}
function path(δr_min,δr_max, el0_min, el0_max, δel_min,δel_max) {
var c = 0.551915024494;
var atan = Math.atan(c)
var d = Math.sqrt( c * c + 1 * 1 ), r = 1;
var el = (el0_min + Math.random() * (el0_max - el0_min)) * Math.PI / 180;
var path = 'M';
path += [r * Math.sin(el), r * Math.cos(el)];
path += ' C' + [d * r * Math.sin(el + atan), d * r * Math.cos(el + atan)];
for (var i = 0; i < 4; i++) {
el += Math.PI / 2 * (1 + δel_min + Math.random() * (δel_max - δel_min));
r *= (1 + δr_min + Math.random()*(δr_max - δr_min));
path += ' ' + (i?'S':'') + [d * r * Math.sin(el - atan), d * r * Math.cos(el - atan)];
path += ' ' + [r * Math.sin(el), r * Math.cos(el)];
}
return path;
}
function cX(λ_min, λ_max, el_min, el_max) {
var el = (el_min + Math.random()*(el_max - el_min));
return 'rotate(' + el + ') ' + 'scale(1, ' + (λ_min + Math.random()*(λ_max - λ_min)) + ')'+ 'rotate(' + (-el) + ')';
}
function canvasArea() {
var width = Math.floor((Math.random() * 500) + 450);
var height = Math.floor((Math.random() * 300) + 250);
$('#container').width(width).height(height);
}
d3.selectAll( 'svg' ).append( 'path' ).classed( 'ln', true) .attr( 'd', path(-0.1,0, 0,360, 0,0.2 )).attr( 'transform', cX( 0.6, 0.8, 0, 360 ));
setTimeout(function() { location = '' } ,5000)