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Accordion Functionality

I've put together an accordion script that works quite nicely (haven't cross-browser tested) and allows for lots of content inside each drawer to be accessed and visible on screen. A lot of times accordions open and cause issues with positioning after opening. Anyway, the code I'm using has a toggle active function and a scroll function being called on click.
function toggleActive(link){ // Set anchor to active
if ( $(link).hasClass("active") ) {
$(link).removeClass("active");
} else {
$(link).addClass("active");
};
};
function scrollToElement(selector, time, verticalOffset) { // param 1 = id, param 2 = speed
time = typeof(time) != 'undefined' ? time : 1000;
verticalOffset = typeof(verticalOffset) != 'undefined' ? verticalOffset : 0;
element = $(selector);
offset = element.offset();
offsetTop = offset.top + verticalOffset;
$('html, body').animate({scrollTop: offsetTop }, time);
}
$('#accordion a').click(function(e) {
var link = '#' + event.target.id
$(".tab-content").slideUp();
$(".tab").removeClass("active");
toggleActive(link);
$(link).next().slideToggle("fast");
setTimeout(function() {
scrollToElement($(link), 500);
}, 500);
e.preventDefault();
});
So when clicked, all of the tabs are closed and made inactive, then the targeted "drawer" is opened and made active. If for any reason you click an already "active" drawer, it runs through the script again. What I'd like to do is place an IF statement that determines if what you just clicked is already open, and then simply close that drawer. Thanks in advance. I don't know why this is causing me headaches.
JSFiddle

As I understand you need another function as below:
function isAlreadyActive(link)
{
if ( $(link).hasClass("active") ) {
$(link).removeClass("active");
return true;
} else {
return false;
};
}
And you should call that function in your click event. This function will check if the link already active, if so just deactivates it and changes as you want.
$('#accordion a').click(function(e) {
var link = '#' + event.target.id
/* if it is already active, just deactivate it and exit*/
if(isAlreadyActive(link)){
return false;
}
$(".tab-content").slideUp();
$(".tab").removeClass("active");
toggleActive(link);
$(link).next().slideToggle("fast");
setTimeout(function() {
scrollToElement($(link), 500);
}, 500);
e.preventDefault();
});
I hope this helps.

jQuery hover function to display an overlay but closes when hover displayed content

I am a little new to JS / jQuery and have done a hover function so when hover a link it shows a hidden DIV area but when I go to then hover over the div area shown of course it closes. I would like that if I then go into the content area won't close but stay open but then if leave that area would close?
JS:
$('.mini-cart').hover(
function () {
cartOpen();
},
function () {
cartClose();
}
);
var overlay = $("#cart_slide");
var cartContainer = $("#cart_over");
function cartOpen() {
cartContainer.fadeIn("slow");
overlay.addClass("overlay");
}
function cartClose() {
cartContainer.fadeOut("medium");
overlay.removeClass("overlay");
}
HTML:
<a class="mini-cart">hover link</a>
<div id="cart_over" style="display:none;">testing</div>

You could introduce the usage of a flag (isCartOpen) variable which is going to control the whether the DIV should be displayed or not.
See this working JSFiddle example and find below the related code:
var isCartOpen = false;
$('.mini-cart, #cart_over').hover(
function() {
isCartOpen = true;
cartOpen();
},
function() {
isCartOpen = false;
setTimeout(cartClose, 1000); // after 1 sec
}
);
var overlay = $("#cart_slide");
var cartContainer = $("#cart_over");
function cartOpen() {
cartContainer.fadeIn("slow");
overlay.addClass("overlay");
}
function cartClose() {
if (isCartOpen)
return;
cartContainer.fadeOut("medium");
overlay.removeClass("overlay");
}

Looks like you'll need to separate your open/close functions . Look at the following:
$('.mini-cart').hover(
cartOpen();
);
// You'll need to create a close button.. ex. <div class="close-button"></div>
$(".close-button").click(function(){
cartClose();
});

JQuery slide wait variable not setting

I am confused as to why this is not working, please could someone point me in the right direction? I have wrote some JQuery to slide down a submenu. However when moving the mouse around the menu it will fire thousands of events I am trying to have it wait for a hide to finish before doing another slidedown. However this does not seem to work:
$("li.title").children('ul').hide();
var hidden = true;
$("li.title").hover(
function() {
if (hidden == true){
var height = $(this).children('ul').height() + $(this).height();
$(this).height(height);
$(this).children('ul').slideDown();
var hidden = false;
}
},
function() {
$(this).height(25);
$(this).children('ul').hide(function() {
var hidden = true;
});
}
);

Remove var from your hidden variable within the callback functions in hover. You're reassigning those variables locally, so its not listening to the global hidden variable.
Change this:
var hidden = false;
to this:
hidden = false;

You need to remove var. The problem is you are creating a new instance of hidden scoped to your callback functions and not seeing the global hidden.
$("li.title").children('ul').hide();
var hidden = true,
myTimeout;
$("li.title").hover(
function() {
clearTimeout(myTimeout);
myTimeout = setTimeout(function(){
if (hidden == true){
var height = $(this).children('ul').height() + $(this).height();
$(this).height(height);
$(this).children('ul').slideDown();
hidden = false; //Removed var here
}
},100);
},
function() {
clearTimeout(myTimeout);
myTimeout = setTimeout(function(){
$(this).height(25);
$(this).children('ul').hide(function() {
hidden = true; //and here
});
},100);
}
);

need to modify this jquery pop menu script to work with ajax

I am using this script from: http://pop.seaofclouds.com/
The problem is if you call the script multiple times it causes a cascading effect of a pop-out within a pop-out for as many times as you call the script.
I'm trying to figure out how to prevent it from executing when the popout has already been set. Here's the script:
//
// pop! for jQuery
// v0.2 requires jQuery v1.2 or later
//
// Licensed under the MIT:
// http://www.opensource.org/licenses/mit-license.php
//
// Copyright 2007,2008 SEAOFCLOUDS [http://seaofclouds.com]
//
(function($) {
$.pop = function(options){
// inject html wrapper
function initpops (){
$(".pop").each(function() {
var pop_classes = $(this).attr("class");
if ( $(this).find('.pop_menu').length) {
// do nothing
} else {
$(this).addClass("pop_menu");
$(this).wrap("<div class='"+pop_classes+"'></div>");
$(".pop_menu").attr("class", "pop_menu");
$(this).before(" \
<div class='pop_toggle'></div> \
");
}
});
}
initpops();
// assign reverse z-indexes to each pop
var totalpops = $(".pop").length + 100;
$(".pop").each(function(i) {
var popzindex = totalpops - i;
$(this).css({ zIndex: popzindex });
});
// close pops if user clicks outside of pop
activePop = null;
function closeInactivePop() {
$(".pop").each(function (i) {
if ($(this).hasClass('active') && i!=activePop) {
$(this).removeClass('active');
}
});
return false;
}
$(".pop").mouseover(function() { activePop = $(".pop").index(this); });
$(".pop").mouseout(function() { activePop = null; });
$("body").on("click", ".pop", function(){
closeInactivePop();
});
// toggle that pop
$("body").on("click", ".pop_toggle", function(){
$(this).parent(".pop").toggleClass("active");
});
}
})(jQuery);
now when i load this script on an ajax call the new pop-out menus work but the old ones do not react to the onclick event.

You shouldn't mess with the plugin. It works exactly like it should.
Better show us how you call this on elements that you already have.
Also I don't like this plugin. Better use something from JqueryUI
You can do such thing in much easier way.
[edit]
I tried your first code (the plugin) and it works correctly for me.
[edit]
OK. I get it. You call $.pop(); multiple times. You shouldn't! Calling $.pop(); will pin up the drop down menu to all elements that has class="pop". This is the reason why you have such funny stack.
Just use $.pop(); once.
Plugin doesn't give ability to connect NEW elements that was dynamically created on the page.

Removed pop from ajax call and just called this on success:
$(".pop").each(function() {
var pop_classes = $(this).attr("class");
if ( $(this).find('.pop_menu').length) {
// do nothing
} else {
$(this).addClass("pop_menu");
$(this).wrap("<div class='"+pop_classes+"'></div>");
$(".pop_menu").attr("class", "pop_menu");
$(this).before(" \
<div class='pop_toggle'></div> \
");
}
});
// assign reverse z-indexes to each pop
var totalpops = $(".pop").length + 100;
$(".pop").each(function(i) {
var popzindex = totalpops - i;
$(this).css({ zIndex: popzindex });
});
// close pops if user clicks outside of pop
activePop = null;
function closeInactivePop() {
$(".pop").each(function (i) {
if ($(this).hasClass('active') && i!=activePop) {
$(this).removeClass('active');
}
});
return false;
}
$(".pop").mouseover(function() { activePop = $(".pop").index(this); });
$(".pop").mouseout(function() { activePop = null; });

does jQuery stop() work on custom functions?

There are three images that I have made a tooltip for each.
I wanted to show tooltips within timed intervals say for 2 seconds first tooltip shows and for the second interval the 2nd tooltips fades in and so on.
for example it can be done with this function
function cycle(id) {
var nextId = (id == "block1") ? "block2": "block1";
$("#" + id)
.delay(shortIntervalTime)
.fadeIn(500)
.delay(longIntervalTime)
.fadeOut(500, function() {cycle(nextId)});
}
now what i want is to stop the cycle function when moseover action occurs on each of the images and show the corresponding tooltip. And again when the mouse went away again the cycle function fires.

If I understand everthing correctly, than try this code. Tt stops the proccess if you hover the image and continues if you leave the image. The stop() function will work on custom functions if you implement them like the fadeOut(), slideIn(), ... functions of jquery.
$('#' + id)
.fadeIn(500, function () {
var img = $(this).find('img'),
self = $(this),
fadeOut = true;
img.hover(function () {
fadeOut = false;
},
function () {
window.setTimeout(function () {
self.fadeOut(500);
}, 2000);
}
);
window.setTimeout(function () {
if (fadeOut === false) {
return;
}
self.fadeOut(500);
}, 2000);
});​