Why in RegEx should be only dot after negative lookahead [duplicate] - javascript

I want to take all lines except which contains # symbol
This is the regex for it ^[^#]*$/gm
Now how do i select only words in it as \S\S*?
Finally i want to combine these two regex ^[^#]*$/gm and \S\S*
Sample here

You probably need to make it a two-step process: First filter all lines by /^[^#]*$/, afterwards get all matches for /\S+/ from that line. You can't have an arbitrary number of matches from a single regex (e.g. all »words« individually). Unless you want all words separated by whitespace in a single match, such as /\S+(\s+\S+)*/, but even then you'd essentially just get the whole line in a single match, so there's little point to it.

Related

javascript regular expression allow name with one space and special Alphabets

how to write regular expression allow name with one space and special Alphabets?
I tried with this [a-zA-Z]+(?:(?:\. |[' ])[a-zA-Z]+)* but not working for me,
example string Björk Guðmundsdóttir
You may try something along these lines:
^(?!.*[ ].*[ ])[ A-Za-zÀ-ÖØ-öø-ÿ]+$
The first negative lookahead asserts that we do not find two spaces in the name. This implies that at most one space is present (or no spaces at all). Then, we match any number of alphabets, with most accented letters included. Spaces can also be matched, but the lookahead would already ensure that at most one space can be present.
Demo
Use this one:
[a-zA-Z\u00C0-\u00ff]*[ ]{1}[a-zA-Z\u00C0-\u00ff]*
Answer from other question

Regex in Java Script: match spaces after 1-3 character words

For fun I'm making js function that would sweep through html file and would add non breaking spaces after words, that should be pushed to the next line, eg "and", "or" etc. I'm using replace on string containing entire HTML text and I can't seem to create regex that would match just the space after these words. I've tried to use positive lookbehind, like that:
(?<=[\u0020|\u00A0|\u000A][a-z]{1,3})[\u0020|\u00A0|\u000D]
where the first group should match spaces and three character words but exclude them from the final match, while the second group should match either space or next line, that would be changed to non breaking space. Clearly I don't understand something as this is not working.
Desired match of two character words in following string:
To make a good app I need to get better.
would be spaces after "To", "a", "I" and "to".
Try this one:
/(?:\b\w{1,2})(\s)/
demo

RegEx matching help: won't match on each appearence

I need to write a little RegEx matcher which will match any occurrence of strings in the form of
[a-zA-Z]+(_[a-zA-Z0-9]+)?
If I use the regex above it does match the sections needed but would also match onto the abc part of 4_abc which is not intended. I tried to exclude it with:
(?:[^a-zA-Z0-9_]|^)([a-zA-Z]+(_[a-zA-Z0-9]+)?)(?:[^a-zA-Z0-9_]|$)
The problem is that the 'not' matches at the beginning and end are not really working like I hoped they would. If I use them on the example
a_d Dd_da 4_d d_4
they would block matching the second Dd_da because the space was used in the first match.Sadly I can't use lookarounds because I am using JS.
So the input:
a_d Dd_da 4_d d_4
should match: a_d, Dd_da and d_4
but matches: a_d (there is a space at the end)
Is there another way to match the needed sections, or to not consume the 'anchor' matches?
I really appreciate your help.
You can make use of \b:
\b[a-zA-Z]+(_[a-zA-Z0-9]+)?\b
\b matches the (zero-width) point where either the preceding character or following character is a letter, digit or underscore, but not both. It also matches with the start/end of the string if the first/last character is a letter, digit or underscore.

Parsing units with javascript regex

Say I have a string which contains some units (which may or may not have prefixes) that I want to break into the individual units. For example the string may contain "Btu(th)" or "Btu(th).ft" or even "mBtu(th).ft" where mBtu(th) is the bastardised unit milli thermochemical BTU's (this is purely an example).
I currently have the following (simplified) regex however it fails for the case "mBtu(th).ft":
/(m|k)??(Btu\(th\)|ft|m)(?:\b|\s|$)/g
Currently this does not correctly detect the boundary between the end of 'Btu(th)' and the start of 'ft'. I understand javascript regex does not support look back so how do I accurately parse the string?
Additional notes
The regex presented above is greatly simplified around the prefixes and units groups. The prefixes could span multiple characters like 'Ki' and therefore character sets are not suitable.
The desire is for each group to catch the prefix match as group 1 and the unit as match two i.e for 'mBtu(th).ft' match one would be ['m','Btu(th)'] and match two would be ['','ft'].
The prefix match needs to be lazy so that the string 'm' would be matched as the unit metres rather than the prefix milli. Likewise the match for 'mm' would need to be the prefix milli and the unit metres.
I would try with:
/((m)|(k)|(Btu(\(th\))?)|(ft)|(m)|(?:\.))+/g
at least with example above, it matches all units merged into one string.
DEMO
EDIT
Another try (DEMO):
/(?:(m)|(k)|(Btu)|(th)|(ft)|[\.\(\)])/g
this one again match only one part, but if you use $1,$2,$3,$4, etc, (DEMO) you can extract other fragments. It ignores ., (, ), characters. The problem is to count proper matched groups, but it works to some degree.
Or if you accept multiple separate matches I think simple alternative is:
/(m|k|Btu|th|ft)/g
A word boundary will not separate two non-word characters. So, you don't actually want a word boundary since the parentheses and period are not valid word characters. Instead, you want the string to not be followed by a word character, so you can use this instead:
[mk]??(Btu\(th\)|ft|m)(?!\w)
Demo
I believe you're after something like this. If I understood you correctly that want to match any kind of element, possibly preceded by the m or k character and separated by parantheses or dots.
/[\s\.\(]*(m|k?)(\w+)[\s\.\)]*/g
https://regex101.com/r/eQ5nR4/2
If you don't care about being able to match the parentheses but just return the elements you can just do
/(m|k?)(\w+)/g
https://regex101.com/r/oC1eP5/1

Matching by beginning of a string or by a single character in JavaScript

I have two regular expressions:
/\/(\w\w+)/g
/(^\w\w+)/g
and am wondering if there's any way to combine them into a single regex? Basically I want to find any part of a string that either starts with /, or is the beginning of the string, and then is a word with 2 or more characters in it.
Thanks.
Yes you can:
/(?:^|\/)(\w{2,})/g
Use a non-capturing group to alternate between the starting conditions.
This will keep the capturing group number the same as in the originals too.

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