javascript: will argument value change lead to parameter value change? - javascript

It is said in w3cschool that "If a function changes an argument's value, it does not change the parameter's original value."
However, i don't quite understand that with the following example:
function bar(a){
arguments[0] = 10;
console.log("a",a);//10
return a;
}
function foo(cc){
cc = 10;
return arguments[0];
}
console.log(bar(333));//10
console.log(foo(333));//10
I have tested them in both chrome and firefox.
From my understanding , if argument value changes can not lead to parameter value change, why 'bar' fail to return 333?

Given a function:
function bar(a) {
arguments[0] = 10;
return a;
}
Calling it like bar(50) will return 10, because the value inside bar's scope was replaced by 10.
What "If a function changes an argument's value, it does not change the parameter's original value." means is that doing:
var x = 90;
var y = bar(x);
console.log(y);
console.log(x);
// y is 10
// x is still 90
... won't change the value of x outside of bar.
For more info see:
W3Schools tutorial on function parameters
MDN's guide to functions (in particular the section on function scope)

As Rudolfs stated the rule is related to the variable in the outer scope. But it is not always true. For arrays & objects the rule is not applied
function modify(obj) {
obj.value = 'modified';
}
var objOuter = {value: 'original'};
console.log('The original value is ' + objOuter.value); //original
modify(objOuter);
console.log('The modified value is ' + objOuter.value); //modified

Related

What do I need a return statement for in JavaScript?

I'm trying to wrap my head around the return statement but I can't see a reason why I should use one. My code works just fine without using one...
In both examples my console prints out 10 not matter if I use return or not.
Without return:
var sum = 5;
function myFunction() {
sum += 5;
}
myFunction();
console.log(sum);
With return:
var sum = 5;
function myFunction() {
return sum += 5;
}
myFunction();
console.log(sum);
By default, functions return the value undefined. If you want the function to return some other value, you need to have a return statement.
You may also use a return statement to halt execution of the function based on some logic, again returning a value that has some meaning or just undefined.
In the first example in the OP, the function is called and the return value is not used for anything, so it doesn't matter what the return value is and a return statement isn't necessary.
In another scenario, the return value might be important, e.g. a function that generates an integer random number between 0 and 10:
function getRandomInteger(){
return Math.floor(Math.random() * 11);
}
function showRandomNumber() {
document.getElementById('s0').textContent = getRandomInteger();
}
<button onclick="showRandomNumber()">Show random number</button>
<span id="s0"></span>
In the above, the getRandomInteger function needs to return a specific value, so it uses a return statement. The showRandomNumber function just displays the random number, so it doesn't need a return statement as the caller (the listener on the button) doesn't care what the return value is.
Here is what is happening with your example:
var sum = 5; //Sets the sum to =5
function myFunction() {
return sum += 5; // += reassigns the global (sum) to 10
}
myFunction();
console.log(sum);
A better example would be this:
sum = 5;
function myFunction() {
var sumOther = sum + 5;
return sumOther;
}
console.log(“sum:” + sum); // 5
console.log(“myFunction:” + myFunction()); // 10
This is how you would get the run of the function and not the global variable ‘sum’
This is because you use (global) variable declared outside the function (function modify it directly so there is no need to return value). However it is not good way of write functions because they are less reusable because they need proper global context to be used. Better is to use something like this:
function myFunction(num) {
return num += 5;
}
var sum = 5;
var result = myFunction(5) ;
console.log(result); // -> 10
this function can be easily used ind different context because it have parameter num and works only on it (function uses only values declared inside its declaration and body)
The trick in your case a is scope of a function. In both cases variable sum is defined in global scope. When you calling the function, it goes through the following steps:
Look whether var sum is defined in current step Since it not defined
inside the function, go one step over and take a look into outer
scope. Yes, it is defined here, start using it.
Perform calculation.
You are using incremental operator sum += 5 so actually it can be
written as sum = sum + 5. If you will look into second case,
you'll notice that variable have increased value now. And since that
variable is taken from global scope, your function just mutates it.
NOTE: At this point no matter whether you are returning something
from function or not. Your function just mutated outer variable.
The last step - exit from function. As I said earlier, return value
matters only if you want to use result of function call directly,
for instance: var result = myFunction()

How does one modify a global variable that is used as an argument [duplicate]

How do I pass variables by reference in JavaScript?
I have three variables that I want to perform several operations to, so I want to put them in a for loop and perform the operations to each one.
Pseudocode:
myArray = new Array(var1, var2, var3);
for (var x = 0; x < myArray.length; x++){
// Do stuff to the array
makePretty(myArray[x]);
}
// Now do stuff to the updated variables
What is the best way to do this?
There is no "pass by reference" available in JavaScript. You can pass an object (which is to say, you can pass-by-value a reference to an object) and then have a function modify the object contents:
function alterObject(obj) {
obj.foo = "goodbye";
}
var myObj = { foo: "hello world" };
alterObject(myObj);
alert(myObj.foo); // "goodbye" instead of "hello world"
You can iterate over the properties of an array with a numeric index and modify each cell of the array, if you want.
var arr = [1, 2, 3];
for (var i = 0; i < arr.length; i++) {
arr[i] = arr[i] + 1;
}
It's important to note that "pass-by-reference" is a very specific term. It does not mean simply that it's possible to pass a reference to a modifiable object. Instead, it means that it's possible to pass a simple variable in such a way as to allow a function to modify that value in the calling context. So:
function swap(a, b) {
var tmp = a;
a = b;
b = tmp; //assign tmp to b
}
var x = 1, y = 2;
swap(x, y);
alert("x is " + x + ", y is " + y); // "x is 1, y is 2"
In a language like C++, it's possible to do that because that language does (sort-of) have pass-by-reference.
edit — this recently (March 2015) blew up on Reddit again over a blog post similar to mine mentioned below, though in this case about Java. It occurred to me while reading the back-and-forth in the Reddit comments that a big part of the confusion stems from the unfortunate collision involving the word "reference". The terminology "pass by reference" and "pass by value" predates the concept of having "objects" to work with in programming languages. It's really not about objects at all; it's about function parameters, and specifically how function parameters are "connected" (or not) to the calling environment. In particular, note that in a true pass-by-reference language — one that does involve objects — one would still have the ability to modify object contents, and it would look pretty much exactly like it does in JavaScript. However, one would also be able to modify the object reference in the calling environment, and that's the key thing that you can't do in JavaScript. A pass-by-reference language would pass not the reference itself, but a reference to the reference.
edit — here is a blog post on the topic. (Note the comment to that post that explains that C++ doesn't really have pass-by-reference. That is true. What C++ does have, however, is the ability to create references to plain variables, either explicitly at the point of function invocation to create a pointer, or implicitly when calling functions whose argument type signature calls for that to be done. Those are the key things JavaScript doesn't support.)
Primitive type variables like strings and numbers are always passed by value.
Arrays and Objects are passed by reference or by value based on these conditions:
if you are setting the value of an object or array it is Pass by Value.
object1 = { prop: "car" };
array1 = [1,2,3];
if you are changing a property value of an object or array then it is Pass by Reference.
object1.prop = "car";
array1[0] = 9;
Code
function passVar(obj1, obj2, num) {
obj1.prop = "laptop"; // will CHANGE original
obj2 = { prop: "computer" }; //will NOT affect original
num = num + 1; // will NOT affect original
}
var object1 = {
prop: "car"
};
var object2 = {
prop: "bike"
};
var number1 = 10;
passVar(object1, object2, number1);
console.log(object1); // output: Object { prop: "laptop" }
console.log(object2); // output: Object { prop: "bike" }
console.log(number1); // ouput: 10
Workaround to pass variable like by reference:
var a = 1;
inc = function(variableName) {
window[variableName] += 1;
};
inc('a');
alert(a); // 2
And yup, actually you can do it without access a global variable:
inc = (function () {
var variableName = 0;
var init = function () {
variableName += 1;
alert(variableName);
}
return init;
})();
inc();
Simple Object
function foo(x) {
// Function with other context
// Modify `x` property, increasing the value
x.value++;
}
// Initialize `ref` as object
var ref = {
// The `value` is inside `ref` variable object
// The initial value is `1`
value: 1
};
// Call function with object value
foo(ref);
// Call function with object value again
foo(ref);
console.log(ref.value); // Prints "3"
Custom Object
Object rvar
/**
* Aux function to create by-references variables
*/
function rvar(name, value, context) {
// If `this` is a `rvar` instance
if (this instanceof rvar) {
// Inside `rvar` context...
// Internal object value
this.value = value;
// Object `name` property
Object.defineProperty(this, 'name', { value: name });
// Object `hasValue` property
Object.defineProperty(this, 'hasValue', {
get: function () {
// If the internal object value is not `undefined`
return this.value !== undefined;
}
});
// Copy value constructor for type-check
if ((value !== undefined) && (value !== null)) {
this.constructor = value.constructor;
}
// To String method
this.toString = function () {
// Convert the internal value to string
return this.value + '';
};
} else {
// Outside `rvar` context...
// Initialice `rvar` object
if (!rvar.refs) {
rvar.refs = {};
}
// Initialize context if it is not defined
if (!context) {
context = this;
}
// Store variable
rvar.refs[name] = new rvar(name, value, context);
// Define variable at context
Object.defineProperty(context, name, {
// Getter
get: function () { return rvar.refs[name]; },
// Setter
set: function (v) { rvar.refs[name].value = v; },
// Can be overrided?
configurable: true
});
// Return object reference
return context[name];
}
}
// Variable Declaration
// Declare `test_ref` variable
rvar('test_ref_1');
// Assign value `5`
test_ref_1 = 5;
// Or
test_ref_1.value = 5;
// Or declare and initialize with `5`:
rvar('test_ref_2', 5);
// ------------------------------
// Test Code
// Test Function
function Fn1(v) { v.value = 100; }
// Test
function test(fn) { console.log(fn.toString()); console.info(fn()); }
// Declare
rvar('test_ref_number');
// First assign
test_ref_number = 5;
test(() => test_ref_number.value === 5);
// Call function with reference
Fn1(test_ref_number);
test(() => test_ref_number.value === 100);
// Increase value
test_ref_number++;
test(() => test_ref_number.value === 101);
// Update value
test_ref_number = test_ref_number - 10;
test(() => test_ref_number.value === 91);
Yet another approach to pass any (local, primitive) variables by reference is by wrapping variable with closure "on the fly" by eval. This also works with "use strict". (Note: be aware that eval is not friendly to JavaScript optimizers, and also missing quotes around variable name may cause unpredictive results)
"use strict"
// Return text that will reference variable by name (by capturing that variable to closure)
function byRef(varName){
return "({get value(){return "+varName+";}, set value(v){"+varName+"=v;}})";
}
// Demo
// Assign argument by reference
function modifyArgument(argRef, multiplier){
argRef.value = argRef.value * multiplier;
}
(function(){
var x = 10;
alert("x before: " + x);
modifyArgument(eval(byRef("x")), 42);
alert("x after: " + x);
})()
Live sample: https://jsfiddle.net/t3k4403w/
There's actually a pretty sollution:
function updateArray(context, targetName, callback) {
context[targetName] = context[targetName].map(callback);
}
var myArray = ['a', 'b', 'c'];
updateArray(this, 'myArray', item => {return '_' + item});
console.log(myArray); //(3) ["_a", "_b", "_c"]
I personally dislike the "pass by reference" functionality offered by various programming languages. Perhaps that's because I am just discovering the concepts of functional programming, but I always get goosebumps when I see functions that cause side effects (like manipulating parameters passed by reference). I personally strongly embrace the "single responsibility" principle.
IMHO, a function should return just one result/value using the return keyword. Instead of modifying a parameter/argument, I would just return the modified parameter/argument value and leave any desired reassignments up to the calling code.
But sometimes (hopefully very rarely), it is necessary to return two or more result values from the same function. In that case, I would opt to include all those resulting values in a single structure or object. Again, processing any reassignments should be up to the calling code.
Example:
Suppose passing parameters would be supported by using a special keyword like 'ref' in the argument list. My code might look something like this:
//The Function
function doSomething(ref value) {
value = "Bar";
}
//The Calling Code
var value = "Foo";
doSomething(value);
console.log(value); //Bar
Instead, I would actually prefer to do something like this:
//The Function
function doSomething(value) {
value = "Bar";
return value;
}
//The Calling Code:
var value = "Foo";
value = doSomething(value); //Reassignment
console.log(value); //Bar
When I would need to write a function that returns multiple values, I would not use parameters passed by reference either. So I would avoid code like this:
//The Function
function doSomething(ref value) {
value = "Bar";
//Do other work
var otherValue = "Something else";
return otherValue;
}
//The Calling Code
var value = "Foo";
var otherValue = doSomething(value);
console.log(value); //Bar
console.log(otherValue); //Something else
Instead, I would actually prefer to return both new values inside an object, like this:
//The Function
function doSomething(value) {
value = "Bar";
//Do more work
var otherValue = "Something else";
return {
value: value,
otherValue: otherValue
};
}
//The Calling Code:
var value = "Foo";
var result = doSomething(value);
value = result.value; //Reassignment
console.log(value); //Bar
console.log(result.otherValue);
These code examples are quite simplified, but it roughly demonstrates how I personally would handle such stuff. It helps me to keep various responsibilities in the correct place.
Happy coding. :)
I've been playing around with syntax to do this sort of thing, but it requires some helpers that are a little unusual. It starts with not using 'var' at all, but a simple 'DECLARE' helper that creates a local variable and defines a scope for it via an anonymous callback. By controlling how variables are declared, we can choose to wrap them into objects so that they can always be passed by reference, essentially. This is similar to one of the Eduardo Cuomo's answer above, but the solution below does not require using strings as variable identifiers. Here's some minimal code to show the concept.
function Wrapper(val){
this.VAL = val;
}
Wrapper.prototype.toString = function(){
return this.VAL.toString();
}
function DECLARE(val, callback){
var valWrapped = new Wrapper(val);
callback(valWrapped);
}
function INC(ref){
if(ref && ref.hasOwnProperty('VAL')){
ref.VAL++;
}
else{
ref++;//or maybe throw here instead?
}
return ref;
}
DECLARE(5, function(five){ //consider this line the same as 'let five = 5'
console.log("five is now " + five);
INC(five); // increment
console.log("five is incremented to " + five);
});
Actually it is really easy. The problem is understanding that once passing classic arguments, you are scoped into another, read-only zone.
The solution is to pass the arguments using JavaScript's object-oriented design. It is the same as putting the arguments in a global/scoped variable, but better...
function action(){
/* Process this.arg, modification allowed */
}
action.arg = [["empty-array"], "some string", 0x100, "last argument"];
action();
You can also promise stuff up to enjoy the well-known chain:
Here is the whole thing, with promise-like structure
function action(){
/* Process this.arg, modification allowed */
this.arg = ["a", "b"];
}
action.setArg = function(){this.arg = arguments; return this;}
action.setArg(["empty-array"], "some string", 0x100, "last argument")()
Or better yet...
action.setArg(["empty-array"],"some string",0x100,"last argument").call()
JavaScript can modify array items inside a function (it is passed as a reference to the object/array).
function makeAllPretty(items) {
for (var x = 0; x < myArray.length; x++){
// Do stuff to the array
items[x] = makePretty(items[x]);
}
}
myArray = new Array(var1, var2, var3);
makeAllPretty(myArray);
Here's another example:
function inc(items) {
for (let i=0; i < items.length; i++) {
items[i]++;
}
}
let values = [1,2,3];
inc(values);
console.log(values);
// Prints [2,3,4]
Putting aside the pass-by-reference discussion, those still looking for a solution to the stated question could use:
const myArray = new Array(var1, var2, var3);
myArray.forEach(var => var = makePretty(var));
As we don't have javascript pass by reference functionality, the only way to do this is to make the function return the value and let the caller assign it:
So
"makePretty(myArray[x]);"
should be
"myArray[x] = makePretty(myArray[x]);"
This is in case you need assignment inside the function, if only mutation is necessary, then passing the object and mutating it should be enough
I know exactly what you mean. The same thing in Swift will be no problem. The bottom line is use let, not var.
The fact that primitives are passed by value, but the fact that the value of var i at the point of iteration is not copied into the anonymous function is quite surprising to say the least.
for (let i = 0; i < boxArray.length; i++) {
boxArray[i].onclick = function() { console.log(i) }; // Correctly prints the index
}
If you want to pass variables by reference, a better way to do that is by passing your arguments in an object and then start changing the value by using window:
window["varName"] = value;
Example:
// Variables with first values
var x = 1, b = 0, f = 15;
function asByReference (
argumentHasVars = {}, // Passing variables in object
newValues = []) // Pass new values in array
{
let VarsNames = [];
// Getting variables names one by one
for(let name in argumentHasVars)
VarsNames.push(name);
// Accessing variables by using window one by one
for(let i = 0; i < VarsNames.length; i += 1)
window[VarsNames[i]] = newValues[i]; // Set new value
}
console.log(x, b, f); // Output with first values
asByReference({x, b, f}, [5, 5, 5]); // Passing as by reference
console.log(x, b, f); // Output after changing values
I like to solve the lack of by reference in JavaScript like this example shows.
The essence of this is that you don't try to create a by reference. You instead use the return functionality and make it able to return multiple values. So there isn't any need to insert your values in arrays or objects.
var x = "First";
var y = "Second";
var z = "Third";
log('Before call:',x,y,z);
with (myFunc(x, y, z)) {x = a; y = b; z = c;} // <-- Way to call it
log('After call :',x,y,z);
function myFunc(a, b, c) {
a = "Changed first parameter";
b = "Changed second parameter";
c = "Changed third parameter";
return {a:a, b:b, c:c}; // <-- Return multiple values
}
function log(txt,p1,p2,p3) {
document.getElementById('msg').innerHTML += txt + '<br>' + p1 + '<br>' + p2 + '<br>' + p3 + '<br><br>'
}
<div id='msg'></div>
Using Destructuring here is an example where I have 3 variables, and on each I do the multiple operations:
If value is less than 0 then change to 0,
If greater than 255 then change to 1,
Otherwise dived the number by 255 to convert from a range of 0-255 to a range of 0-1.
let a = 52.4, b = -25.1, c = 534.5;
[a, b, c] = [a, b, c].map(n => n < 0 ? 0 : n > 255 ? 1 : n / 255);
console.log(a, b, c); // 0.20549019607843136 0 1

Understanding of JavaScript

I tried to search for explanation of this JavaScript function. I want to understand how does this function get the value? Could someone please suggest a place where I can read more about passing/using value this way.
pie.value = function(_) {
if (!arguments.length) return value;
value = _;
return pie;
};
This code is from D3 JS.
It is a getter/setter that relies on a closure.
var value = 5; // initial value
var getterSetter = function(newValue) {
// value is closed from the outer scope
if (!arguments.length) {
// CASE A
return value;
}
// // CASE B
value = newValue;
return getterSetter;
};
getterSetter() // arguments.length is 0 (CASE A) so displays value (5)
getterSetter(10) // arguments.length is 1 (CASE B) so values is set to 10
getterSetter() // now this displays 10 since value now is 10 (CASE A)
console.log(value); // Also displays 10, this is the same value variable
Now in CASE B, you can see that getterSetter returns itself. This way it becomes (kind of) chainable, which means you can do:
getterSetter(1)(2)(3)(); // assign 1 then 2 then 3 and displays 3;
Your case is a bit difference as the pie object is returned in CASE B,instead of the function pie.value, which means you can do that:
pie.value(1).value(2).value(3).value();

Pass variables by reference in JavaScript

How do I pass variables by reference in JavaScript?
I have three variables that I want to perform several operations to, so I want to put them in a for loop and perform the operations to each one.
Pseudocode:
myArray = new Array(var1, var2, var3);
for (var x = 0; x < myArray.length; x++){
// Do stuff to the array
makePretty(myArray[x]);
}
// Now do stuff to the updated variables
What is the best way to do this?
There is no "pass by reference" available in JavaScript. You can pass an object (which is to say, you can pass-by-value a reference to an object) and then have a function modify the object contents:
function alterObject(obj) {
obj.foo = "goodbye";
}
var myObj = { foo: "hello world" };
alterObject(myObj);
alert(myObj.foo); // "goodbye" instead of "hello world"
You can iterate over the properties of an array with a numeric index and modify each cell of the array, if you want.
var arr = [1, 2, 3];
for (var i = 0; i < arr.length; i++) {
arr[i] = arr[i] + 1;
}
It's important to note that "pass-by-reference" is a very specific term. It does not mean simply that it's possible to pass a reference to a modifiable object. Instead, it means that it's possible to pass a simple variable in such a way as to allow a function to modify that value in the calling context. So:
function swap(a, b) {
var tmp = a;
a = b;
b = tmp; //assign tmp to b
}
var x = 1, y = 2;
swap(x, y);
alert("x is " + x + ", y is " + y); // "x is 1, y is 2"
In a language like C++, it's possible to do that because that language does (sort-of) have pass-by-reference.
edit — this recently (March 2015) blew up on Reddit again over a blog post similar to mine mentioned below, though in this case about Java. It occurred to me while reading the back-and-forth in the Reddit comments that a big part of the confusion stems from the unfortunate collision involving the word "reference". The terminology "pass by reference" and "pass by value" predates the concept of having "objects" to work with in programming languages. It's really not about objects at all; it's about function parameters, and specifically how function parameters are "connected" (or not) to the calling environment. In particular, note that in a true pass-by-reference language — one that does involve objects — one would still have the ability to modify object contents, and it would look pretty much exactly like it does in JavaScript. However, one would also be able to modify the object reference in the calling environment, and that's the key thing that you can't do in JavaScript. A pass-by-reference language would pass not the reference itself, but a reference to the reference.
edit — here is a blog post on the topic. (Note the comment to that post that explains that C++ doesn't really have pass-by-reference. That is true. What C++ does have, however, is the ability to create references to plain variables, either explicitly at the point of function invocation to create a pointer, or implicitly when calling functions whose argument type signature calls for that to be done. Those are the key things JavaScript doesn't support.)
Primitive type variables like strings and numbers are always passed by value.
Arrays and Objects are passed by reference or by value based on these conditions:
if you are setting the value of an object or array it is Pass by Value.
object1 = { prop: "car" };
array1 = [1,2,3];
if you are changing a property value of an object or array then it is Pass by Reference.
object1.prop = "car";
array1[0] = 9;
Code
function passVar(obj1, obj2, num) {
obj1.prop = "laptop"; // will CHANGE original
obj2 = { prop: "computer" }; //will NOT affect original
num = num + 1; // will NOT affect original
}
var object1 = {
prop: "car"
};
var object2 = {
prop: "bike"
};
var number1 = 10;
passVar(object1, object2, number1);
console.log(object1); // output: Object { prop: "laptop" }
console.log(object2); // output: Object { prop: "bike" }
console.log(number1); // ouput: 10
Workaround to pass variable like by reference:
var a = 1;
inc = function(variableName) {
window[variableName] += 1;
};
inc('a');
alert(a); // 2
And yup, actually you can do it without access a global variable:
inc = (function () {
var variableName = 0;
var init = function () {
variableName += 1;
alert(variableName);
}
return init;
})();
inc();
Simple Object
function foo(x) {
// Function with other context
// Modify `x` property, increasing the value
x.value++;
}
// Initialize `ref` as object
var ref = {
// The `value` is inside `ref` variable object
// The initial value is `1`
value: 1
};
// Call function with object value
foo(ref);
// Call function with object value again
foo(ref);
console.log(ref.value); // Prints "3"
Custom Object
Object rvar
/**
* Aux function to create by-references variables
*/
function rvar(name, value, context) {
// If `this` is a `rvar` instance
if (this instanceof rvar) {
// Inside `rvar` context...
// Internal object value
this.value = value;
// Object `name` property
Object.defineProperty(this, 'name', { value: name });
// Object `hasValue` property
Object.defineProperty(this, 'hasValue', {
get: function () {
// If the internal object value is not `undefined`
return this.value !== undefined;
}
});
// Copy value constructor for type-check
if ((value !== undefined) && (value !== null)) {
this.constructor = value.constructor;
}
// To String method
this.toString = function () {
// Convert the internal value to string
return this.value + '';
};
} else {
// Outside `rvar` context...
// Initialice `rvar` object
if (!rvar.refs) {
rvar.refs = {};
}
// Initialize context if it is not defined
if (!context) {
context = this;
}
// Store variable
rvar.refs[name] = new rvar(name, value, context);
// Define variable at context
Object.defineProperty(context, name, {
// Getter
get: function () { return rvar.refs[name]; },
// Setter
set: function (v) { rvar.refs[name].value = v; },
// Can be overrided?
configurable: true
});
// Return object reference
return context[name];
}
}
// Variable Declaration
// Declare `test_ref` variable
rvar('test_ref_1');
// Assign value `5`
test_ref_1 = 5;
// Or
test_ref_1.value = 5;
// Or declare and initialize with `5`:
rvar('test_ref_2', 5);
// ------------------------------
// Test Code
// Test Function
function Fn1(v) { v.value = 100; }
// Test
function test(fn) { console.log(fn.toString()); console.info(fn()); }
// Declare
rvar('test_ref_number');
// First assign
test_ref_number = 5;
test(() => test_ref_number.value === 5);
// Call function with reference
Fn1(test_ref_number);
test(() => test_ref_number.value === 100);
// Increase value
test_ref_number++;
test(() => test_ref_number.value === 101);
// Update value
test_ref_number = test_ref_number - 10;
test(() => test_ref_number.value === 91);
Yet another approach to pass any (local, primitive) variables by reference is by wrapping variable with closure "on the fly" by eval. This also works with "use strict". (Note: be aware that eval is not friendly to JavaScript optimizers, and also missing quotes around variable name may cause unpredictive results)
"use strict"
// Return text that will reference variable by name (by capturing that variable to closure)
function byRef(varName){
return "({get value(){return "+varName+";}, set value(v){"+varName+"=v;}})";
}
// Demo
// Assign argument by reference
function modifyArgument(argRef, multiplier){
argRef.value = argRef.value * multiplier;
}
(function(){
var x = 10;
alert("x before: " + x);
modifyArgument(eval(byRef("x")), 42);
alert("x after: " + x);
})()
Live sample: https://jsfiddle.net/t3k4403w/
There's actually a pretty sollution:
function updateArray(context, targetName, callback) {
context[targetName] = context[targetName].map(callback);
}
var myArray = ['a', 'b', 'c'];
updateArray(this, 'myArray', item => {return '_' + item});
console.log(myArray); //(3) ["_a", "_b", "_c"]
I personally dislike the "pass by reference" functionality offered by various programming languages. Perhaps that's because I am just discovering the concepts of functional programming, but I always get goosebumps when I see functions that cause side effects (like manipulating parameters passed by reference). I personally strongly embrace the "single responsibility" principle.
IMHO, a function should return just one result/value using the return keyword. Instead of modifying a parameter/argument, I would just return the modified parameter/argument value and leave any desired reassignments up to the calling code.
But sometimes (hopefully very rarely), it is necessary to return two or more result values from the same function. In that case, I would opt to include all those resulting values in a single structure or object. Again, processing any reassignments should be up to the calling code.
Example:
Suppose passing parameters would be supported by using a special keyword like 'ref' in the argument list. My code might look something like this:
//The Function
function doSomething(ref value) {
value = "Bar";
}
//The Calling Code
var value = "Foo";
doSomething(value);
console.log(value); //Bar
Instead, I would actually prefer to do something like this:
//The Function
function doSomething(value) {
value = "Bar";
return value;
}
//The Calling Code:
var value = "Foo";
value = doSomething(value); //Reassignment
console.log(value); //Bar
When I would need to write a function that returns multiple values, I would not use parameters passed by reference either. So I would avoid code like this:
//The Function
function doSomething(ref value) {
value = "Bar";
//Do other work
var otherValue = "Something else";
return otherValue;
}
//The Calling Code
var value = "Foo";
var otherValue = doSomething(value);
console.log(value); //Bar
console.log(otherValue); //Something else
Instead, I would actually prefer to return both new values inside an object, like this:
//The Function
function doSomething(value) {
value = "Bar";
//Do more work
var otherValue = "Something else";
return {
value: value,
otherValue: otherValue
};
}
//The Calling Code:
var value = "Foo";
var result = doSomething(value);
value = result.value; //Reassignment
console.log(value); //Bar
console.log(result.otherValue);
These code examples are quite simplified, but it roughly demonstrates how I personally would handle such stuff. It helps me to keep various responsibilities in the correct place.
Happy coding. :)
I've been playing around with syntax to do this sort of thing, but it requires some helpers that are a little unusual. It starts with not using 'var' at all, but a simple 'DECLARE' helper that creates a local variable and defines a scope for it via an anonymous callback. By controlling how variables are declared, we can choose to wrap them into objects so that they can always be passed by reference, essentially. This is similar to one of the Eduardo Cuomo's answer above, but the solution below does not require using strings as variable identifiers. Here's some minimal code to show the concept.
function Wrapper(val){
this.VAL = val;
}
Wrapper.prototype.toString = function(){
return this.VAL.toString();
}
function DECLARE(val, callback){
var valWrapped = new Wrapper(val);
callback(valWrapped);
}
function INC(ref){
if(ref && ref.hasOwnProperty('VAL')){
ref.VAL++;
}
else{
ref++;//or maybe throw here instead?
}
return ref;
}
DECLARE(5, function(five){ //consider this line the same as 'let five = 5'
console.log("five is now " + five);
INC(five); // increment
console.log("five is incremented to " + five);
});
Actually it is really easy. The problem is understanding that once passing classic arguments, you are scoped into another, read-only zone.
The solution is to pass the arguments using JavaScript's object-oriented design. It is the same as putting the arguments in a global/scoped variable, but better...
function action(){
/* Process this.arg, modification allowed */
}
action.arg = [["empty-array"], "some string", 0x100, "last argument"];
action();
You can also promise stuff up to enjoy the well-known chain:
Here is the whole thing, with promise-like structure
function action(){
/* Process this.arg, modification allowed */
this.arg = ["a", "b"];
}
action.setArg = function(){this.arg = arguments; return this;}
action.setArg(["empty-array"], "some string", 0x100, "last argument")()
Or better yet...
action.setArg(["empty-array"],"some string",0x100,"last argument").call()
JavaScript can modify array items inside a function (it is passed as a reference to the object/array).
function makeAllPretty(items) {
for (var x = 0; x < myArray.length; x++){
// Do stuff to the array
items[x] = makePretty(items[x]);
}
}
myArray = new Array(var1, var2, var3);
makeAllPretty(myArray);
Here's another example:
function inc(items) {
for (let i=0; i < items.length; i++) {
items[i]++;
}
}
let values = [1,2,3];
inc(values);
console.log(values);
// Prints [2,3,4]
Putting aside the pass-by-reference discussion, those still looking for a solution to the stated question could use:
const myArray = new Array(var1, var2, var3);
myArray.forEach(var => var = makePretty(var));
As we don't have javascript pass by reference functionality, the only way to do this is to make the function return the value and let the caller assign it:
So
"makePretty(myArray[x]);"
should be
"myArray[x] = makePretty(myArray[x]);"
This is in case you need assignment inside the function, if only mutation is necessary, then passing the object and mutating it should be enough
I know exactly what you mean. The same thing in Swift will be no problem. The bottom line is use let, not var.
The fact that primitives are passed by value, but the fact that the value of var i at the point of iteration is not copied into the anonymous function is quite surprising to say the least.
for (let i = 0; i < boxArray.length; i++) {
boxArray[i].onclick = function() { console.log(i) }; // Correctly prints the index
}
If you want to pass variables by reference, a better way to do that is by passing your arguments in an object and then start changing the value by using window:
window["varName"] = value;
Example:
// Variables with first values
var x = 1, b = 0, f = 15;
function asByReference (
argumentHasVars = {}, // Passing variables in object
newValues = []) // Pass new values in array
{
let VarsNames = [];
// Getting variables names one by one
for(let name in argumentHasVars)
VarsNames.push(name);
// Accessing variables by using window one by one
for(let i = 0; i < VarsNames.length; i += 1)
window[VarsNames[i]] = newValues[i]; // Set new value
}
console.log(x, b, f); // Output with first values
asByReference({x, b, f}, [5, 5, 5]); // Passing as by reference
console.log(x, b, f); // Output after changing values
I like to solve the lack of by reference in JavaScript like this example shows.
The essence of this is that you don't try to create a by reference. You instead use the return functionality and make it able to return multiple values. So there isn't any need to insert your values in arrays or objects.
var x = "First";
var y = "Second";
var z = "Third";
log('Before call:',x,y,z);
with (myFunc(x, y, z)) {x = a; y = b; z = c;} // <-- Way to call it
log('After call :',x,y,z);
function myFunc(a, b, c) {
a = "Changed first parameter";
b = "Changed second parameter";
c = "Changed third parameter";
return {a:a, b:b, c:c}; // <-- Return multiple values
}
function log(txt,p1,p2,p3) {
document.getElementById('msg').innerHTML += txt + '<br>' + p1 + '<br>' + p2 + '<br>' + p3 + '<br><br>'
}
<div id='msg'></div>
Using Destructuring here is an example where I have 3 variables, and on each I do the multiple operations:
If value is less than 0 then change to 0,
If greater than 255 then change to 1,
Otherwise dived the number by 255 to convert from a range of 0-255 to a range of 0-1.
let a = 52.4, b = -25.1, c = 534.5;
[a, b, c] = [a, b, c].map(n => n < 0 ? 0 : n > 255 ? 1 : n / 255);
console.log(a, b, c); // 0.20549019607843136 0 1

How do I understand a function that returns a function?

Here's the example code I'm struggling with:
function greaterThan(x) {
return function(y) {
return y > x;
};
}
var greaterThanTen = greaterThan(10);
show(greaterThanTen(9));
Is there a way to put it in math terms or follow the flow or something? I don't know why 10 is x and 9 is y.
In the line:
var greaterThanTen = greaterThan(10);
You are assinging the variable x to the value 10 and then you store the function in the greaterThanTen Variable to be called later. this means that:
greaterThanTen = function(y) {
return y > 10;
};
So when you do:
greaterThanTen(9); #y = 9
You are calling:
return 9 > 10;
This function doesn't call a function, it returns a function.
This code is creating a new unary function where the original binary (greater than) operator's right-hand operand is prebound to a specific value.
In lambda calculus this binding is known as currying.
In Javascript the binding happens because the supplied value of the parameter x in greaterThan is permanently retained in the scope of the inner function (or "closure") that is returned.
So, when you call:
var greaterThanTen = greaterThan(10);
what you now have is a new function (named greaterThanTen) which always compares its single parameter to the bound value of 10.
Hence:
greaterThanTen(9);
will return false.
Create greaterThan(10)
Create function:
function(y){return y > x}
return function.
So, when you call greaterThan(10), the function returns a function whose local variable x is set to 10.
var greaterThanTen = greaterThan(10) equals:
var greaterThanTen = function(y){return y > 10};
To finish, greaterThanTen(9) is called, which equals 9 > 10, which is false.
The only thing that greaterThan does is to set a value for x in
function(y) {return (y>x);}
and store the resulting function in a variable name, in this case greaterThanTen, now with the contents
function(y) {return (y>10);}
Calling greaterThanTen(9) is the same as looking at
function(y = 9) {return (y>10);}
which is the same as
function(y = 9) {return (9>10);}
which is false. Hence false is returned.
Edit:
Example of function that returns a function here: http://i.imgur.com/aiHSH.jpg (x and y is switched around in y>x)
Namaste
The greaterThanTen variable represents a function taking one argument and returning a boolean value whether this argument is greater then 10.

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