I'm trying to pass the variable from a JavaScript function - selected text - to the same page using php post method:
if (isset($_POST['u_name']))
{
echo $_POST['u_name'] . '</p>';
}
echo "<script type='text/javascript'>";
echo "var var1 = 0; var range = window.getSelection ();";
echo "function gst () { var range = window.getSelection (); alert (range.toString ()); var1 = range.toString ();}";
echo "document.write('<form method=\'post\'>');";
echo "document.write('<p>selected area:<br />');";
echo "document.write('<button onclick=\'gst ()\' type=\'submit\' name=\'u_name\' value = \'' + var1 + ' \' />Button</button>');";
echo "document.write('</form>');";
echo "alert (interesting);";
echo "</script>";
after pressing the button the selected page text is correct: it is checked with alert (range.toString ()) , however, the initial value of var1 variable - 0 is posted.
What could cause it and how one can pass the value, obtained from the javascript function through post method ?
Anton
That's because you set value attribute on the page load.
You can change it dynamically on button click. Replace one of your rows to:
echo "document.write('<button onclick=\"this.setAttribute(\'value\', var1); gst()\" type=\'submit\' name=\'u_name\' value = \'' + var1 + ' \' />Button</button>');";
Note this.setAttribute.
If you want to pass JavaScript variables to PHP, you'll have to use an Ajax request.
PHP is server sided, whereas JavaScript is client sided. This means that all PHP code is done before any JavaScript is even triggered. You can manipulate JavaScript with PHP, but if you want to manipulate PHP with JavaScript, use an Ajax call.
Related
<script>
var strWidth = document.getElementById("mydiv").style.width;
var strHeight = document.getElementById("mydiv").style.height;
var link = "<?php if(isset($_GET["ggg"])) {
echo $_GET["ggg"].".php?width=800&height=460";
} else {
echo "page1.php?width=800&height=460";
}
?>";
</script>
this is my script, php inside javascript. how do i place this variable strWidth inside
php?width=800&height=460
so becomes some how like this
php?width=strWidth&height=460
EDIT 2
well, the only thing i am trying to do here to show variable value between those line is it a big deal ?
it might be done by separating like using concatenation or something ?
Add an input-field in PHP, hide it (if necessary) and read the value of this field with JS.
First of all if you want to use php values in javascript you need the script to be written in a php file. Suppose you do this then you can do this in this way:
<script>
var strWidth = document.getElementById("mydiv").style.width;
var strHeight = document.getElementById("mydiv").style.height;
var link='<?php echo (isset($_GET["ggg"]))?isset($_GET["ggg"]):''; ?>'; // this assigns the valueto link variable
if(link==''){
// your logic starts here
}else{
// your logic starts here
}
</script>
Add an input-field and assign a value to the hidden element and then get value through javascript.
It is not a good idea to combine PHP and Javascript.
Refer this about explanation on client-side vs server-side coding.
you can't really do that. but this works
<?php
echo "<script>\n";
echo "var strWidth = document.getElementById(\"mydiv\").style.width;\n";
echo "var strHeight = document.getElementById(\"mydiv\").style.height;\n";
if(isset($_GET["ggg"])) {
echo "var link =" . $_GET["ggg"] . ".php?width=800&height=460';\n";
}
else {
echo "var link ='page1.php?width=' + strWidth + '&height=' + strHeight + '';\n";
}
echo "</script>\n";
?>
the reference to ggg completely confuses the understanding of this process so really it should be taken out:
__ page1.php
<?php
if (!isset($_GET['foundWidth'])){
//stops double hit
echo "<script>\n";
echo "var strWidth = document.getElementById(\"mydiv\").style.width;\n";
echo "var strHeight = document.getElementById(\"mydiv\").style.height;\n";
echo "var link ='/page1.php?foundWidth=true&width=' + strWidth + '&height=' + strHeight + '';\n";
echo "window.location = link;"
echo "</script>\n";
}
elseif (isset($_GET['foundWidth']) && ($_GET['foundWidth']=='true')) {
if (isset($_GET['width']) && is_numeric($_GET['width'])){
//use your width here SERVER SIDE
// or
echo "<script> alert('Width is: '+ " . $_GET['width']) . "); </script>\n";
}
if (isset($_GET['height']) && is_numeric($_GET['height'])){
//use your height here SERVER SIDE
// or
echo "<script> alert('Height is: '+ " . $_GET['height']) . "); </script>\n";
}
}
?>
using this "trick" you can then write the PHP params into the javascript url with whatever get string you like, including triggering a reload of the page with the width as a param, so if you want to test if $_GET['width'] is set to a number you can insert it etc
Scenario: I need to compare a database cell on the page load (php) against itself in an interval loop every x amount of minutes for changes.
My Initial load data looks like this:
var olddata = JSON.stringify(<?php echo json_encode($data1); ?>) + "~|~" +
JSON.stringify(<?php echo json_encode($data2); ?>) + "~|~" +
JSON.stringify(<?php echo json_encode($data3); ?>);
So on page load, I save the cells into a javascript variable with a "~|~" delimiter, where $data1, $data2, and $data3 are 3 different cells in the database (arrays of data).
And my interval loop data (ajax call) looks like this:
// PHP on the AJAX page
echo json_encode($data1)."~|~".json_encode($data2). "~|~".json_encode($data3);
// AJAX code that gets called every x Intervals
$.get("ajaxpage.php", function(data) {
if (data == olddata) {
console.log("Good!");
}
});
When I compare olddata against data they look almost identical except... data that has a / in it will look like \/ in the data variable and not in theolddata` variable.
Example:
"10":["10"],"11":["11 5\/25"] // data = return from the AJAX call
"10":["10"],"11":["11 5/25"] // olddata = what was originally echoed on page load.
How can I compare the two so that they will match perfectly? So that what I echo from the database and json_encode, will line up with what I get from the exact same thing echoed on a page and jason encoded from the json function return.
Note: If I remove the JSON.stringify then it will return [object Object]
You're using a very bad practice. Just use AJAX to get this:
var olddata = JSON.stringify(<?php echo json_encode($data1); ?>) + "~|~" +
JSON.stringify(<?php echo json_encode($data2); ?>) + "~|~" +
JSON.stringify(<?php echo json_encode($data3); ?>);
And store "olddata" in a JavaScript Global var, then compare the old data with the new data returned by $.get. This isn't the solution for your bug, but it's a better way to do what you're doing.
To fix the bug just declare the type of the return value in the your $.get function, like that:
$.get("ajaxpage.php", function(data) {
if (data == olddata) {
console.log("Good!");
}
}, 'text');
For more information about the return type, look the jQuery Documentation: jQuery $.get Documentation
Just change it to:
var olddata = '<?php echo json_encode($data1, JSON_HEX_APOS); ?>~|~<?php echo json_encode($data2, JSON_HEX_APOS); ?>~|~<?php echo json_encode($data3, JSON_HEX_APOS); ?>';
And the backend to:
echo json_encode($data1, JSON_HEX_APOS)."~|~".json_encode($data2, JSON_HEX_APOS). "~|~".json_encode($data3, JSON_HEX_APOS);
Now you're simply comparing two strings.
I am attempting to call a javascript function inside a php where loop. I've succeeded in calling the variable, however the function only works on the first line, and then breaks a subsequent query.
The javascript is a simple show/hide of a div or span tag with a specific id. I'm trying to have this appear for every instance of a variable, but only open the span associated with that entry, so I used a php variable from the query.
The javascript code is contained in the header; it works fine without the php, and the php works fine without the javascript but I can't seem to make them work together.
Here's the code:
while($row = mysqli_fetch_array($qir)) {
$ingredient_id = $row['ingredient_id'];
echo '<input type="checkbox" value="' . $ingredient_id . '" name="markdelete[]">';
echo $row['amt'] . ' ' .$row['ingredient_name']; ?> <button onclick="showHide('<?php echo $row['ingredient_id']; ?>'); return false">Edit amount</button> <br />
<span id="<?php echo $row['ingredient_id']; ?>" class="hide">
<?php include_once('amt.php');
echo '</span> ';
// }
echo '<br />';
}
echo '<input type ="submit" name="remove" value="Remove">';
First of all, the showHide is only working on the first record
It is also making this query not respond at all.
if (isset($_POST['remove'])) {
iF (!empty($_POST['markdelete'])) {
foreach ($_POST['markdelete'] as $delete_id) {
// remove specific source from source_subject
$rem_ing = "DELETE from dish_ingredient
where ingredient_id = $delete_id
and dish_id = $dish_id ";
mysqli_query($dbc, $rem_ing)
or die ('Error removing ingredient: '.mysqli_error($dbc));
}
}
}
I tried removing the return false;, to no avail. Please let me know if I need to show more of the code (e.g. the javascript itself)
Edit:
I've tried working within the php string (this is actually what I had tried first) but it seems to break everything (no javascript, no php)
echo $row['amt'] . ' ' .$row['ingredient_name'] . '<button onclick="showHide(\''. $row['ingredient_id'] .'\') return false">Edit amount</button> <br />';
echo '<span id=" '. $row['ingredient_id'] .' " class="hide">';
include_once('amt.php');
echo '</span> ';
Edit: I am open to other solutions if this is not something that is possible. I'm feeling a bit stumped. Realistically I just want to have a list of items called from a mysql database, and have a field appear onclick to edit an associated variable if desired without having to send it to another page or reload the script for usability (hence the javascript piece).
Thanks again, anyone who can assist.
Note: this is the script that I am calling:
<script language="JavaScript" type="text/JavaScript">
menu_status = new Array();
function showHide(theid){
if (document.getElementById) {
var switch_id = document.getElementById(theid);
if(menu_status[theid] != 'show') {
switch_id.className = 'show';
menu_status[theid] = 'show';
}else{
switch_id.className = 'hide';
menu_status[theid] = 'hide';
}
}
}
</script>
You don't need tag there as you are already in php block.Try it without and use
showHide(\''.$row['ingredient_id'].'\')
and change
<?php include_once(....);
to
include_once(........);
Hopefully that would work
===========
try this for you javascript
<script language="JavaScript" type="text/JavaScript">
function showHide(theid){
if (document.getElementById) {
var switch_id = document.getElementById(theid);
if(!switch_id) {
switch_id.className = (switch_id.className.indexOf("show") > -1) ? "hide" : "show"
}
}
}
Okay after a long time on this, I finally figured out what was going on. Part of the issue was that I was trying to call a form inside a form, which I had forgotten is not permitted in HTML, so this required some redesign.
Other issues involved calling loops within inside loops, which caused problems where the first record would work, but not for the remaining records.
The javascript above did not need to be modified, only the way that it was called.
Here is what worked. The main key was using include() instead of include_once().
while($r = $qir->fetch_assoc()) {
$ingredient_id = $r['ingredient_id'];
$amt = $r['amt'];
$ingredient_name = $r['ingredient_name'];
echo $r['amt'] . ' ' .$r['ingredient_name'];
if ($row['user_id'] == $user_id) {
echo ' <span class="openlink"><button onclick="showHide(\''.$ingredient_id. '\')">edit amount</button></span><br/>';
echo '<div id="'.$ingredient_id.'" class="hide">';
include('amt1.php');
echo '</div>';
}
}
I am facing some trouble in passing a simple variable from a php to javascript file.
I have a form which submits through a php file which basically updates the record at the server end. And if the updation is succesful, I just want to pass the message back to the javascript where I can update it on a certain section of the page.
My codes are:
Javascript code - abc.js
function expand_cards(project, SlNo)
{
name = project['project_name'];
j = "ShowForm-"+SlNo+"";
s = "<div class='edit_project_card'>";
s += "<form method='post' action='Edit_Project.php'><div class='project_form'>
// Form Contents
s += "<div class='Form_button'> <input type='submit'> </div>";
s += "</form></div>";
$("#"+j+"").html(s);
response = $.parseJSON(data);
$("#"+j+"").html(response);
}
PHP file - Edit_Project.php
<?php
//The updation stuff at the server end
if (!mysqli_query($connection,$sqlquery)) {
$response = "'Error in your code: ' . mysqli_error($connection)";
}
else {
$response = "1 record updated";
}
echo json_encode($response);
mysqli_close($connection);
?>
But the problem is the screen is printing $response variable as it is and not exactly passing it back to the javascript function as wished. I know I can use a $.post function which can can receive argument but it's a long form and passing parameters would be difficult in that.
Can anybody help me out here ?
Thanks
Dirty, but it will work:
<script type="text/javascript">
var my_var = <?php echo $some_variable; ?>
// Do something with the new my_var
some_func(my_var);
</script>
I wouldn't do too much detailed stuff with this though, if you can use AJAX that is better.
Note, this can only work on a .php file or one being read as such.
you'll want to do some variable handling in your php side because if the string is empty you'll end up with a
var my_var = ;
which will break the script. so something like:
var my_var = <?php echo "'" . $some_variable . "'";?>
if it's a string or if it's a number:
var my_var = <?php echo (empty($some_variable) ? null : $some_variable);
This is int specific, I'm sure you can come up with a function that will handle it better.
References:
empty function http://php.net/manual/en/function.empty.php
shorthand if http://davidwalsh.name/php-ternary-examples
Since you're submitting the form to the PHP file directly the browser loads the Edit_Project.php file as it would a normal page. If you want a json response to the already loaded page you'll have to use $.post or $.ajax
You can post the whole form simply by using serialize() like this:
$('#form_id').on('submit', function(e) {
// Stop the browser from posting the form
e.preventDefault();
// Post the form via Ajax
$.ajax({
url : 'Edit_Project.php',
type : 'POST',
data : $(this).serialize(),
success : function(response) {
// Here you do the HTML update
$("#"+j+"").html(response.reply);
}
});
});
The Edit_Project.php needs to be changed as well:
//The updation stuff at the server end
if (!mysqli_query($connection,$sqlquery)) {
$response = "'Error in your code: ' . mysqli_error($connection)";
}
else {
$response = "1 record updated";
}
mysqli_close($connection);
/*
* As SuperDJ suggested, you need to tell the browser that it's
* receiving a JSON ojbect although he did use the wrong content type:
*/
header('Content-Type: application/json');
/*
* According to php.net most decoders should handle a simple string as
* json object but to be safe always encode an array or an object since
* you can't know how the decoder will respond.
*/
echo json_encode(array('reply' => $response));
I want to send 2 variables (im using php to create an html element) and when the user clicks, an alert pops up with the 2 variables.
I've set this up:
PHP:
$item = array (
'string' => $node->getElementsByTagName('string1')->item(0)->nodeValue,
'string2' => $node->getElementsByTagName('string2')->item(0)->nodeValue,
);
$string1 = str_replace(' & ', ' & ', $item['string']);
$string2 = str_replace(' & ', ' & ', $item['string2']);
'.$title.'</strong><br />';
Javascript:
<script>
function doSomething(variable1,variable2) {
var myVar1 = variable1;
var myVar2 = variable2;
alert (myVar1+ ' ' +myVar2);
return false;
}
</script>
I tried this but when I click the link nothing happens.
What is the proper way to send variables from php to javascript?
Thank you for your time.
Is it possible to do this?
<a href="#" onclick"doSomething(this) id="'.string1.'" description="'.string2.'" />link </a>
And do this instead of the other solution?
<script>
function doSomething(obj) {
if(obj!= null)
alert ('Obj is Null');
}else {
alert (obj.getAttributeById("id")+' '+obj.getAttributeById("description"));
return false;
}
</script>
You didn't quote the parameters in your onclick, so your code looks literally like:
<a href="#" onclick="doSomething(Hello, World!)" ...
turning your variables' contents into undefined variables and a syntax error ("Not bracket"?).
Try
<a href="#" onclick="doSomething('$title', '$string')" id= etc...
instead.. Note the quotes around the variables. Also note that you should NEVER directly dump PHP data into a Javascript context like this. As you've found out, the slightest glitch and you've introduced a JS syntax error, which kills the ENTIRE javascript block.
Always output json_encode()'d data, ensuring that you're generating syntactically valid JS code.
You just need to concat the values into your echo string:
echo '' . $title . '</strong><br />';
When you are printing the php variables it prints only the variable, so if $title equals Hello the Java Script interpreter think there a variable in Java Script named Hello.
To avoid this you have to print into the HTML the variable value inside quotes.
$string = 'World!';
$title = 'Hello';
echo ''.$title.'</strong><br />';