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REGEX-JAVASCRIPT Unable to find pattern [closed]

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I am trying to figure how I can search for a pattern that gives me only digits or digits followed by only one letter. I know I can use /\D\g to find only digits but I dont know how to find digits with only one letter after it. The letters can only be the following:['a','A','b','B','c','C','d','D','n','N','e','E','s','S','w','W']
const testPattern = /[A-Za-z][0-9]/
console.log('item_10a_object10a'.pattern(testPattern))

First, you need to group the whole thing with (), and end with /g so it matches multiple groups.
If you want digits first then a number, you need to put the letter block after the numbers: ([0-9][A-Za-z])
If you want multiple digits to match, you need a + after the numbers block: [0-9]+
All together: /([0-9]+[A-Za-z])/g
For reference, \d does the same thing as [0-9], so you could do /(\d+[A-Za-z])/g instead
LPT: use regex101 to build and test regex queries

Javascript Regex to match $, but not ${ [closed]

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I have just created a snippet generator tool for Sublime Text, Atom and VS Code, you can find it here: https://snippets.now.sh.
Snippets for these apps need to have the $ escaped e.g. $('.class'), but not when it is used for placeholders e.g. ${1:foo}.
What is the regex to match only occurrences of the $ when it is not followed by a {?
Just to reiterate:
Match this: $foo
Don't match this: ${foo

Use the following regex pattern:
\$(?!{).+\b
(?!{) - negative lookahead assertion, ensures that $ is not followed by {
https://regex101.com/r/qQZIZQ/2
Additional case with substitution for the condition :
$ dollar signs need to be escaped, like so \$, but not when followed
by {, like so; ${
\$(?!{)(.+\b)?
substitution: \\$0
https://regex101.com/r/qQZIZQ/4

What is JavaScript regex for string matches which starts with $$ and ends with $$? [closed]

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I want Javascript regex for all strings that start with $$ and ends with $$
example:
$$hello$$
$$world$$

^\${2}.*?\${2}$
How this works: first, you look for two dollar signs, then, it allows any input, and then it looks whether the string ends with two dollar signs.

A pattern like this should work:
^\$\$.*\$\$$
This will match the beginning of the string (^) followed by $$, followed by zero or more of any character, followed by $$, and the end of the string ($). For example:
/^\$\$.*\$\$$/.test('$$hello$$') // true
If you're looking for a substring of a larger string which matches this pattern, use something like this:
\$\$.*?\$\$
This will match $$, followed by zero or more of any character, non-greedily, followed by $$. For example:
/\$\$.*?\$\$/.exec('print "$$hello$$"') // ['$$hello$$']
But for something this simple, you can just use plain old string manipulation:
var string = '$$hello$$';
var result = (string.substr(0, 2) == '$$') && (string.substr(-2) == '$$'); // true

Regex to not allow special characters (Javascript) [closed]

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I have a following requirement to only allow capital letters and , in a javascript form . I am unsure on how to check for special characters and script tags . I have written the following code . I do not want to allow characters such as $,%,& etc .
var upperCase= new RegExp('[A-Z]');
var lowerCase= new RegExp('^[a-z]');
var numbers = new RegExp('^[0-9]');
if($(this).val().match(upperCase) && $(this).val().match(lowerCase) && $(this).val().match(numbers))
{
$("#passwordErrorMsg").html("OK")
}

Based on what you've given us, this may suit the bill. It will determine if any characters are not in character classes a-z, A-Z or 0-9 but note this will also treat é or similar characters as rejected symbols.
So if the value is 'test_' or 'test a' it will fail but it will pass for 'testa'. If you want it to accept spaces change the regex to /[^a-zA-Z0-9 ]/.
if(!/[^a-zA-Z0-9]/.test($(this).val())) {
$("#passwordErrorMsg").html("OK");
}

This may be helpful.
javascript regexp remove all special characters
if the only characters you want are numbers, letters, and ',' then you just need to whitespice all characters that are not those
$(this).val().replace(/[^\w\s\][^,]/gi, '')

This link may be helpful:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Regular_Expressions
It has a lot of information on JS Regexps.
For a dollar sign ($), the regexp syntax would be: \$. You need to escape the special character so it is read as a literal. The syntax would be the same for the other special characters, I believe.

TITLE VALIDATION in JavaScript for REGEXP which can take alphanumeric and can take Special char [, / ( ) & - : . space] [closed]

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For my website , i need a REGEXP in java script for validation TITLE which can take alphabates, digits and Special char set [, / ( ) & - : . space], but if any user enter only single and double spaces or single or double .. like [..] in title or double digit [1 2] then it's should not allowed, atlest one aplhabate is required. please help

You can use this pattern:
^[-a-z0-9,/()&:. ]*[a-z][-a-z0-9,/()&:. ]*$
This will match any number of your special characters followed by a Latin letter, followed by number of your special characters. It's effectively equivalent to [-a-z0-9,/()&:. ]+ except it requires at least one [a-z] somewhere in the string.
Of course, you need to escape the \ when written as a regex literal in javascript, and you probably want to use the i flag for case-insensitive matching:
var pattern = /^[-a-z0-9,\/()&:. ]*[a-z][-a-z0-9,\/()&:. ]*$/i