Related
I am trying to achieve a tracing effect where the lines have a faded trail. The way I am trying to do it is simply by drawing the solid background once, and then on further frames draw a transparent background before drawing the new lines, so that you can still see a little of the image before it.
The issue is that I do want the lines to fade out completely after some time, but they seem to leave a permanent after image, even after drawing over them repeatedly.
I've tried setting different globalCompositeOperation(s) and it seemed like I was barking up the wrong tree there.
This code is called once
//initiate trace bg
traceBuffer.getContext("2d").fillStyle = "rgba(0, 30, 50, 1)";
traceBuffer.getContext("2d").fillRect(0, 0, traceBuffer.width, traceBuffer.height);
then inside the setInterval function it calls
//draw transparent background
ctx.fillStyle = "rgba(0, 30, 50, 0.04)";
ctx.fillRect(0, 0, ctx.canvas.width, ctx.canvas.height);
//set drawing settings
ctx.strokeStyle = "#AAAAAA";
ctx.lineWidth = 4;
for (let i = 0; i < tracer.layer2.length; i++){
ctx.beginPath();
ctx.moveTo(newX, newY);
ctx.lineTo(oldX, oldY);
ctx.stroke();
}
Here's an example: https://i.imgur.com/QTkeIVf.png
On the left is what I am currently getting, and on the right is the edit of what I actually want to happen.
This is how I would do it. I would build a history of the particles moving on the track. The older the position the smaller the value of the alpha value for the fill. Also for a nicer effect I would reduce the size of the circle.
I hope this is what you need.
PS: I would have loved to have your curve. Since I don't have it I've drawn a different one.
const hypotrochoid = document.getElementById("hypotrochoid");
const ctx = hypotrochoid.getContext("2d");
const cw = (hypotrochoid.width = 300);
const ch = (hypotrochoid.height = 300);
const cx = cw / 2,
cy = ch / 2;
ctx.lineWidth = 1;
ctx.strokeStyle = "#d9d9d9";
// variables for the hypotrochoid
let a = 90;
let b = 15;
let h = 50;
// an array where to save the points used to draw the track
let track = [];
//add points to the track array. This will be used to draw the track for the particles
for (var t = 0; t < 2 * Math.PI; t += 0.01) {
let o = {};
o.x = cx + (a - b) * Math.cos(t) + h * Math.cos((a - b) / b * t);
o.y = cy + (a - b) * Math.sin(t) - h * Math.sin((a - b) / b * t);
track.push(o);
}
// a function to draw the track
function drawTrack(ry) {
ctx.beginPath();
ctx.moveTo(ry[0].x, ry[0].y);
for (let t = 1; t < ry.length; t++) {
ctx.lineTo(ry[t].x, ry[t].y);
}
ctx.closePath();
ctx.stroke();
}
// a class of points that are moving on the track
class Point {
constructor(pos) {
this.pos = pos;
this.r = 3;//the radius of the circle
this.history = [];
this.historyLength = 40;
}
update(newPos) {
let old_pos = {};
old_pos.x = this.pos.x;
old_pos.y = this.pos.y;
//save the old position in the history array
this.history.push(old_pos);
//if the length of the track is longer than the max length allowed remove the extra elements
if (this.history.length > this.historyLength) {
this.history.shift();
}
//gry the new position on the track
this.pos = newPos;
}
draw() {
for (let i = 0; i < this.history.length; i++) {
//calculate the alpha value for every element on the history array
let alp = i * 1 / this.history.length;
// set the fill style
ctx.fillStyle = `rgba(0,0,0,${alp})`;
//draw an arc
ctx.beginPath();
ctx.arc(
this.history[i].x,
this.history[i].y,
this.r * alp,
0,
2 * Math.PI
);
ctx.fill();
}
}
}
// 2 points on the track
let p = new Point(track[0]);
let p1 = new Point(track[~~(track.length / 2)]);
let frames = 0;
let n, n1;
function Draw() {
requestAnimationFrame(Draw);
ctx.clearRect(0, 0, cw, ch);
//indexes for the track position
n = frames % track.length;
n1 = (~~(track.length / 2) + frames) % track.length;
//draw the track
drawTrack(track);
// update and draw the first point
p.update(track[n]);
p.draw();
// update and draw the second point
p1.update(track[n1]);
p1.draw();
//increase the frames counter
frames++;
}
Draw();
canvas{border:1px solid}
<canvas id="hypotrochoid"></canvas>
I'm trying to create a little circular "equalizer" effect using JavaScript and HTML canvas for a little project I'm working on, and it works great, except one little thing. It's just a series of rectangular bars moving in time to an mp3 - nothing overly fancy, but at the moment all the bars point in one direction (i.e. 0 radians, or 90 degrees).
I want each respective rectangle around the edge of the circle to point directly away from the center point, rather than to the right. I have 360 bars, so naturally, each one should be 1 degree more rotated than the previous.
I thought that doing angle = i*Math.PI/180 would fix that, but it doesn't seem to matter what I do with the rotate function - they always end up pointing in weird and wonderful directions, and being translated a million miles from where they were. And I can't see why. Can anyone see where I'm going wrong?
My frame code, for reference, is as follows:
function frames() {
// Clear the canvas and get the mp3 array
window.webkitRequestAnimationFrame(frames);
musicArray = new Uint8Array(analyser.frequencyBinCount);
analyser.getByteFrequencyData(musicArray);
ctx.clearRect(0, 0, canvas.width, canvas.height);
bars = 360;
for (var i = 0; i < bars; i++) {
// Find the rectangle's position on circle edge
distance = 100;
var angle = i * ((Math.PI * 2) / bars);
var x = Math.cos(angle) * distance + (canvas.width / 2);
var y = Math.sin(angle) * distance + (canvas.height / 2);
barWidth = 5;
barHeight = (musicArray[i] / 4);
// Fill with a blue-green gradient
var grd = ctx.createLinearGradient(x, 0, x + 40, 0);
grd.addColorStop(0, "#00CCFF");
grd.addColorStop(1, "#00FF7F");
ctx.fillStyle = grd;
// Rotate the rectangle according to position
// ctx.rotate(i*Math.PI/180); - DOESN'T WORK
// Draw the rectangle
ctx.fillRect(x, y, barHeight, barWidth);
}
For clarity I've removed part of your code. I'm using rotate as you intended. Also I'm using barHeight = (Math.random()* 50); instead your (musicArray[i]/4); because I wanted to have something to show.
Also I've changed your bars to 180. It's very probable that you won't have 360 bars but 32 or 64 or 128 or 256 . . . Now you can change the numbers of bare to one of these numbers to see the result.
I'm drawing everything around the origin of the canvas and translating the context in the center.
I hope it helps.
const canvas = document.getElementById("c");
const ctx = canvas.getContext("2d");
let cw = canvas.width = 400;
let ch = canvas.height = 400;
let bars = 180;
let r = 100;
ctx.translate(cw / 2, ch / 2)
for (var i = 0; i < 360; i += (360 / bars)) {
// Find the rectangle's position on circle edge
var angle = i * ((Math.PI * 2) / bars);
//var x = Math.cos(angle)*r+(canvas.width/2);
//var y = Math.sin(angle)*r+(canvas.height/2);
barWidth = 2 * Math.PI * r / bars;
barHeight = (Math.random() * 50);
ctx.fillStyle = "green";
// Rotate the rectangle according to position
// ctx.rotate(i*Math.PI/180); - DOESN'T WORK
// Draw the rectangle
ctx.save();
ctx.rotate(i * Math.PI / 180);
ctx.fillRect(r, -barWidth / 2, barHeight, barWidth);
//ctx.fillRect(r ,0, barHeight, barWidth);
ctx.restore();
}
canvas {
border: 1px solid
}
<canvas id="c"></canvas>
Here is another solution, I'm preserving your initial trigonometry approach.
But instead of rectangles I used lines, I don't think it makes a difference for you, if what you need is bars moving in time to an mp3 all you need to do is change the var v = Math.random() + 1; to a reading from the Amplitude, and those bars will be dancing.
const canvas = document.getElementById("c");
canvas.width = canvas.height = 170;
const ctx = canvas.getContext("2d");
ctx.translate(canvas.width / 2, canvas.height / 2)
ctx.lineWidth = 2;
let r = 40;
let bars = 180;
function draw() {
ctx.clearRect(-100, -100, 200, 200)
for (var i = 0; i < 360; i += (360 / bars)) {
var angle = i * ((Math.PI * 2) / bars);
var x = Math.cos(angle) * r;
var y = Math.sin(angle) * r;
ctx.beginPath();
var v = Math.random() + 1;
ctx.moveTo(x, y);
ctx.lineTo(x * v, y * v)
grd = ctx.createLinearGradient(x, y, x*2, y*2);
grd.addColorStop(0, "blue");
grd.addColorStop(1, "red");
ctx.strokeStyle = grd;
ctx.stroke();
}
}
setInterval(draw, 100)
<canvas id="c"></canvas>
I am visualising flight paths with D3 and Canvas. In short, I have data for each flight's origin and destination
as well as the airport coordinates. The ideal end state is to have an indiviudal circle representing a plane moving
along each flight path from origin to destination. The current state is that each circle gets visualised along the path,
yet the removal of the previous circle along the line does not work as clearRect gets called nearly constantly.
Current state:
Ideal state (achieved with SVG):
The Concept
Conceptually, an SVG path for each flight is produced in memory using D3's custom interpolation with path.getTotalLength() and path.getPointAtLength() to move the circle along the path.
The interpolator returns the points along the path at any given time of the transition. A simple drawing function takes these points and draws the circle.
Key functions
The visualisation gets kicked off with:
od_pairs.forEach(function(el, i) {
fly(el[0], el[1]); // for example: fly('LHR', 'JFK')
});
The fly() function creates the SVG path in memory and a D3 selection of a circle (the 'plane') - also in memory.
function fly(origin, destination) {
var pathElement = document.createElementNS(d3.namespaces.svg, 'path');
var routeInMemory = d3.select(pathElement)
.datum({
type: 'LineString',
coordinates: [airportMap[origin], airportMap[destination]]
})
.attr('d', path);
var plane = custom.append('plane');
transition(plane, routeInMemory.node());
}
The plane gets transitioned along the path by the custom interpolater in the delta() function:
function transition(plane, route) {
var l = route.getTotalLength();
plane.transition()
.duration(l * 50)
.attrTween('pointCoordinates', delta(plane, route))
// .on('end', function() { transition(plane, route); });
}
function delta(plane, path) {
var l = path.getTotalLength();
return function(i) {
return function(t) {
var p = path.getPointAtLength(t * l);
draw([p.x, p.y]);
};
};
}
... which calls the simple draw() function
function draw(coords) {
// contextPlane.clearRect(0, 0, width, height); << how to tame this?
contextPlane.beginPath();
contextPlane.arc(coords[0], coords[1], 1, 0, 2*Math.PI);
contextPlane.fillStyle = 'tomato';
contextPlane.fill();
}
This results in an extending 'path' of circles as the circles get drawn yet not removed as shown in the first gif above.
Full code here: http://blockbuilder.org/larsvers/8e25c39921ca746df0c8995cce20d1a6
My question is, how can I achieve to draw only a single, current circle while the previous circle gets removed without interrupting other circles being drawn on the same canvas?
Some failed attempts:
The natural answer is of course context.clearRect(), however, as there's a time delay (roughly a milisecond+) for each circle to be drawn as it needs to get through the function pipeline clearRect gets fired almost constantly.
I tried to tame the perpetual clearing of the canvas by calling clearRect only at certain intervals (Date.now() % 10 === 0 or the like) but that leads to no good either.
Another thought was to calculate the previous circle's position and remove the area specifically with a small and specific clearRect definition within each draw() function.
Any pointers very much appreciated.
Handling small dirty regions, especially if there is overlap between objects quickly becomes very computationally heavy.
As a general rule, a average Laptop/desktop can easily handle 800 animated objects if the computation to calculate position is simple.
This means that the simple way to animate is to clear the canvas and redraw every frame. Saves a lot of complex code that offers no advantage over the simple clear and redraw.
const doFor = (count,callback) => {var i=0;while(i < count){callback(i++)}};
function createIcon(drawFunc){
const icon = document.createElement("canvas");
icon.width = icon.height = 10;
drawFunc(icon.getContext("2d"));
return icon;
}
function drawPlane(ctx){
const cx = ctx.canvas.width / 2;
const cy = ctx.canvas.height / 2;
ctx.beginPath();
ctx.strokeStyle = ctx.fillStyle = "red";
ctx.lineWidth = cx / 2;
ctx.lineJoin = "round";
ctx.lineCap = "round";
ctx.moveTo(cx/2,cy)
ctx.lineTo(cx * 1.5,cy);
ctx.moveTo(cx,cy/2)
ctx.lineTo(cx,cy*1.5)
ctx.stroke();
ctx.lineWidth = cx / 4;
ctx.moveTo(cx * 1.7,cy * 0.6)
ctx.lineTo(cx * 1.7,cy*1.4)
ctx.stroke();
}
const planes = {
items : [],
icon : createIcon(drawPlane),
clear(){
planes.items.length = 0;
},
add(x,y){
planes.items.push({
x,y,
ax : 0, // the direction of the x axis of this plane
ay : 0,
dir : Math.random() * Math.PI * 2,
speed : Math.random() * 0.2 + 0.1,
dirV : (Math.random() - 0.5) * 0.01, // change in direction
})
},
update(){
var i,p;
for(i = 0; i < planes.items.length; i ++){
p = planes.items[i];
p.dir += p.dirV;
p.ax = Math.cos(p.dir);
p.ay = Math.sin(p.dir);
p.x += p.ax * p.speed;
p.y += p.ay * p.speed;
}
},
draw(){
var i,p;
const w = canvas.width;
const h = canvas.height;
for(i = 0; i < planes.items.length; i ++){
p = planes.items[i];
var x = ((p.x % w) + w) % w;
var y = ((p.y % h) + h) % h;
ctx.setTransform(-p.ax,-p.ay,p.ay,-p.ax,x,y);
ctx.drawImage(planes.icon,-planes.icon.width / 2,-planes.icon.height / 2);
}
}
}
const ctx = canvas.getContext("2d");
function mainLoop(){
if(canvas.width !== innerWidth || canvas.height !== innerHeight){
canvas.width = innerWidth;
canvas.height = innerHeight;
planes.clear();
doFor(800,()=>{ planes.add(Math.random() * canvas.width, Math.random() * canvas.height) })
}
ctx.setTransform(1,0,0,1,0,0);
// clear or render a background map
ctx.clearRect(0,0,canvas.width,canvas.height);
planes.update();
planes.draw();
requestAnimationFrame(mainLoop)
}
requestAnimationFrame(mainLoop)
canvas {
position : absolute;
top : 0px;
left : 0px;
}
<canvas id=canvas></canvas>
800 animated points
As pointed out in the comments some machines may be able to draw a circle if one colour and all as one path slightly quicker (not all machines). The point of rendering an image is that it is invariant to the image complexity. Image rendering is dependent on the image size but colour and alpha setting per pixel have no effect on rendering speed. Thus I have changed the circle to show the direction of each point via a little plane icon.
Path follow example
I have added a way point object to each plane that in the demo has a random set of way points added. I called it path (could have used a better name) and a unique path is created for each plane.
The demo is to just show how you can incorporate the D3.js interpolation into the plane update function. The plane.update now calls the path.getPos(time) which returns true if the plane has arrived. If so the plane is remove. Else the new plane coordinates are used (stored in the path object for that plane) to set the position and direction.
Warning the code for path does little to no vetting and thus can easily be made to throw an error. It is assumed that you write the path interface to the D3.js functionality you want.
const doFor = (count,callback) => {var i=0;while(i < count){callback(i++)}};
function createIcon(drawFunc){
const icon = document.createElement("canvas");
icon.width = icon.height = 10;
drawFunc(icon.getContext("2d"));
return icon;
}
function drawPlane(ctx){
const cx = ctx.canvas.width / 2;
const cy = ctx.canvas.height / 2;
ctx.beginPath();
ctx.strokeStyle = ctx.fillStyle = "red";
ctx.lineWidth = cx / 2;
ctx.lineJoin = "round";
ctx.lineCap = "round";
ctx.moveTo(cx/2,cy)
ctx.lineTo(cx * 1.5,cy);
ctx.moveTo(cx,cy/2)
ctx.lineTo(cx,cy*1.5)
ctx.stroke();
ctx.lineWidth = cx / 4;
ctx.moveTo(cx * 1.7,cy * 0.6)
ctx.lineTo(cx * 1.7,cy*1.4)
ctx.stroke();
}
const path = {
wayPoints : null, // holds way points
nextTarget : null, // holds next target waypoint
current : null, // hold previously passed way point
x : 0, // current pos x
y : 0, // current pos y
addWayPoint(x,y,time){
this.wayPoints.push({x,y,time});
},
start(){
if(this.wayPoints.length > 1){
this.current = this.wayPoints.shift();
this.nextTarget = this.wayPoints.shift();
}
},
getNextTarget(){
this.current = this.nextTarget;
if(this.wayPoints.length === 0){ // no more way points
return;
}
this.nextTarget = this.wayPoints.shift(); // get the next target
},
getPos(time){
while(this.nextTarget.time < time && this.wayPoints.length > 0){
this.getNextTarget(); // get targets untill the next target is ahead in time
}
if(this.nextTarget.time < time){
return true; // has arrivecd at target
}
// get time normalised ove time between current and next
var timeN = (time - this.current.time) / (this.nextTarget.time - this.current.time);
this.x = timeN * (this.nextTarget.x - this.current.x) + this.current.x;
this.y = timeN * (this.nextTarget.y - this.current.y) + this.current.y;
return false; // has not arrived
}
}
const planes = {
items : [],
icon : createIcon(drawPlane),
clear(){
planes.items.length = 0;
},
add(x,y){
var p;
planes.items.push(p = {
x,y,
ax : 0, // the direction of the x axis of this plane
ay : 0,
path : Object.assign({},path,{wayPoints : []}),
})
return p; // return the plane
},
update(time){
var i,p;
for(i = 0; i < planes.items.length; i ++){
p = planes.items[i];
if(p.path.getPos(time)){ // target reached
planes.items.splice(i--,1); // remove
}else{
p.dir = Math.atan2(p.y - p.path.y, p.x - p.path.x) + Math.PI; // add 180 because i drew plane wrong way around.
p.ax = Math.cos(p.dir);
p.ay = Math.sin(p.dir);
p.x = p.path.x;
p.y = p.path.y;
}
}
},
draw(){
var i,p;
const w = canvas.width;
const h = canvas.height;
for(i = 0; i < planes.items.length; i ++){
p = planes.items[i];
var x = ((p.x % w) + w) % w;
var y = ((p.y % h) + h) % h;
ctx.setTransform(-p.ax,-p.ay,p.ay,-p.ax,x,y);
ctx.drawImage(planes.icon,-planes.icon.width / 2,-planes.icon.height / 2);
}
}
}
const ctx = canvas.getContext("2d");
function mainLoop(time){
if(canvas.width !== innerWidth || canvas.height !== innerHeight){
canvas.width = innerWidth;
canvas.height = innerHeight;
planes.clear();
doFor(810,()=>{
var p = planes.add(Math.random() * canvas.width, Math.random() * canvas.height);
// now add random number of way points
var timeP = time;
// info to create a random path
var dir = Math.random() * Math.PI * 2;
var x = p.x;
var y = p.y;
doFor(Math.floor(Math.random() * 80 + 12),()=>{
var dist = Math.random() * 5 + 4;
x += Math.cos(dir) * dist;
y += Math.sin(dir) * dist;
dir += (Math.random()-0.5)*0.3;
timeP += Math.random() * 1000 + 500;
p.path.addWayPoint(x,y,timeP);
});
// last waypoin at center of canvas.
p.path.addWayPoint(canvas.width / 2,canvas.height / 2,timeP + 5000);
p.path.start();
})
}
ctx.setTransform(1,0,0,1,0,0);
// clear or render a background map
ctx.clearRect(0,0,canvas.width,canvas.height);
planes.update(time);
planes.draw();
requestAnimationFrame(mainLoop)
}
requestAnimationFrame(mainLoop)
canvas {
position : absolute;
top : 0px;
left : 0px;
}
<canvas id=canvas></canvas>
800 animated points
#Blindman67 is correct, clear and redraw everything, every frame.
I'm here just to say that when dealing with such primitive shapes as arc without too many color variations, it's actually better to use the arc method than drawImage().
The idea is to wrap all your shapes in a single path declaration, using
ctx.beginPath(); // start path declaration
for(i; i<shapes.length; i++){ // loop through our points
ctx.moveTo(pt.x + pt.radius, pt.y); // default is lineTo and we don't want it
// Note the '+ radius', arc starts at 3 o'clock
ctx.arc(pt.x, pt.y, pt.radius, 0, Math.PI*2);
}
ctx.fill(); // a single fill()
This is faster than drawImage, but the main caveat is that it works only for single-colored set of shapes.
I've made an complex plotting app, where I do draw a lot (20K+) of entities, with animated positions. So what I do, is to store two sets of points, one un-sorted (actually sorted by radius), and one
sorted by color. I then do use the sorted-by-color one in my animations loop, and when the animation is complete, I draw only the final frame with the sorted-by-radius (after I filtered the non visible entities). I achieve 60fps on most devices. When I tried with drawImage, I was stuck at about 10fps for 5K points.
Here is a modified version of Blindman67's good answer's snippet, using this single-path approach.
/* All credits to SO user Blindman67 */
const doFor = (count,callback) => {var i=0;while(i < count){callback(i++)}};
const planes = {
items : [],
clear(){
planes.items.length = 0;
},
add(x,y){
planes.items.push({
x,y,
rad: 2,
dir : Math.random() * Math.PI * 2,
speed : Math.random() * 0.2 + 0.1,
dirV : (Math.random() - 0.5) * 0.01, // change in direction
})
},
update(){
var i,p;
for(i = 0; i < planes.items.length; i ++){
p = planes.items[i];
p.dir += p.dirV;
p.x += Math.cos(p.dir) * p.speed;
p.y += Math.sin(p.dir) * p.speed;
}
},
draw(){
var i,p;
const w = canvas.width;
const h = canvas.height;
ctx.beginPath();
ctx.fillStyle = 'red';
for(i = 0; i < planes.items.length; i ++){
p = planes.items[i];
var x = ((p.x % w) + w) % w;
var y = ((p.y % h) + h) % h;
ctx.moveTo(x + p.rad, y)
ctx.arc(x, y, p.rad, 0, Math.PI*2);
}
ctx.fill();
}
}
const ctx = canvas.getContext("2d");
function mainLoop(){
if(canvas.width !== innerWidth || canvas.height !== innerHeight){
canvas.width = innerWidth;
canvas.height = innerHeight;
planes.clear();
doFor(8000,()=>{ planes.add(Math.random() * canvas.width, Math.random() * canvas.height) })
}
ctx.setTransform(1,0,0,1,0,0);
// clear or render a background map
ctx.clearRect(0,0,canvas.width,canvas.height);
planes.update();
planes.draw();
requestAnimationFrame(mainLoop)
}
requestAnimationFrame(mainLoop)
canvas {
position : absolute;
top : 0px;
left : 0px;
z-index: -1;
}
<canvas id=canvas></canvas>
8000 animated points
Not directly related but in case you've got part of your drawings that don't update at the same rate as the rest (e.g if you want to highlight an area of your map...) then you might also consider separating your drawings in different layers, on offscreen canvases. This way you'd have one canvas for the planes, that you'd clear every frame, and other canvas for other layers that you would update at different rate. But that's an other story.
I am writing a simple JavaScript game where you are looking for a hidden image on a page. When you click on it the image appears. On every click a sound bite plays. It is essentially Marco-polo. As you get closer to the hidden object I want the volume of the sound bite to get louder. I have this working however with a linear relation between distance and volume it is quite hard to nail down exactly where the image is, so, I want to develop a relation where there is a really steep volume incline as you get really close. Something along the lines of y = x^5. Doesn't have to be x^5 but this is sort of what I have in mind.
Now, the image is placed on the page at page load randomly centred at the point (imgX, imgY). The page has dimensions (pageX, pageY) and I click on the screen at (clickX, clickY).
Now, my thinking is that there will always be a 'largest distance' LD on the page from the image coordinates (in theory this should be a corner on the screen). We can simply get the coordinates for the four corners and find the biggest distance, NBD.
The volume, going from 0 to 1 should have a function similar to
V = 1 - D
Where D is some relation I can't nail down right now.
To get a simple linear relation I am currently using
D = d / LD
Where
d = sqrt((imgX - clickX)^2 + (imgY - clickY)^2)
Edit
Just thought I would clarify my intention: 1-d/LD works however this causes a straight line increase in volume as you get closer. It's not intuitively clear but in practice as you get around 80%-100% volume it all sounds very much the same meaning that the area around the image seems to have the same volume to the human ear. I want a much more dramatic increase as you get really close. I.e., it should only get to above 80% volume when within 3-4% distance (if that makes sense)
Further to my earlier comment, here's a visualisation of what I think you need.
I've just realised that I didn't bother to re-calculate the distance from the most distant corner - I've simply used the distance from the centre of the square to the corners. This omission is the reason the red dot may be drawn to the left of the Y axis if the distance to the target exceeds the distance from the centre of the square to a corner.
Clicking on the 2nd canvas re-positions the hidden target. Moving the mouse will cause it's distance to this target to be computed. This value will then be divided by the above-mentioned max-distance-to-a-corner figure.
Finally, this value will be used as the X-coordinate of the attenuation function. The value [0..1] will be used to drive the resultant volume.
I've left a variable, steepnessFactor in the code for quick and easy modification of the attenuation curve. This value is simply the one to which the linear distance is raised to the power of.
function allByClass(clss,parent){return (parent==undefined?document:parent).getElementsByClassName(clss)}
function byId(id){return document.getElementById(id)}
window.addEventListener('load', onDocLoaded, false);
var steepnessFactor = 5; // inputs [0..1] will be raised to this power
var visSize = 128; // width/height of the 2 canvases
// click pos and corners of our window
var targetPoint;
var topLeft, topRight, botLeft, botRight;
// initialized to dist from center to (any) corner
var maxDist = (Math.sqrt(2) * visSize) / 2;
function onDocLoaded(evt)
{
targetPoint = new vec2_t(visSize/2,visSize/2);
topLeft = new vec2_t(0,0);
topRight = new vec2_t(visSize,0);
botLeft = new vec2_t(0,visSize);
botRight = new vec2_t(visSize,visSize);
var can1 = byId('graph');
var can2 = byId('map');
can1.width = visSize;
can1.height = visSize;
can2.width = visSize;
can2.height = visSize;
byId('map').addEventListener('click', onMapClicked, false);
byId('map').addEventListener('mousemove', onMapMouseMoved, false);
drawGraph();
drawMap(byId('map'));
}
function drawGraph()
{
var can = byId('graph');
var ctx = can.getContext('2d');
ctx.clearRect(0,0,can.width,can.height);
// draw the axis lines
ctx.strokeStyle = "#555555";
ctx.moveTo(0,can.height/2);
ctx.lineTo(can.width, can.height/2);
ctx.moveTo(can.width/2, 0);
ctx.lineTo(can.width/2, can.height);
ctx.stroke();
// draw the unit markers (spaced at 0.1 unit intervals)
var numDivisions = 20;
for (var x=0; x<can.width; x+= can.width/(numDivisions) )
{
ctx.moveTo(x, (can.height/2) - 4 );
ctx.lineTo(x, (can.height/2) + 4 );
}
for (var y=0; y<can.height; y+= can.height/(numDivisions) )
{
ctx.moveTo( (can.width/2)-4, y);
ctx.lineTo( (can.width/2)+4, y);
}
ctx.stroke();
var scaleX = 2 / can.width;
var scaleY = 2 / can.height;
ctx.beginPath();
ctx.moveTo(0,can.height);
for (var curX=0; curX<can.width; curX++)
{
var scaledX = -1;
scaledX += curX * scaleX;
var curY = Math.pow( scaledX, steepnessFactor); // steepness of curve
curY *= can.height/2;
curY = can.height/2 - curY;
ctx.lineTo(curX, curY);
}
ctx.strokeStyle = "#7e6cb5";
ctx.stroke();
}
function vec2_t(x,y)
{
this.x=x;
this.y=y;
this.equals = function(vec2){this.x = vec2.x; this.y = vec2.y;}
this.addVec = function(vec2){this.x += vec2.x; this.y += vec2.y;}
this.scalarMult = function(scalar){this.x *= scalar; this.y *= scalar;}
this.vecLen = function(){return Math.sqrt( this.x*this.x + this.y*this.y );}
this.normalize = function(){ let k = 1.0 / this.vecLen(); this.scalarMult(k); }
this.vecSub = function(vec2){this.x-=vec2.x;this.y-=vec2.y;}
this.toString = function(){return"<"+this.x+","+this.y+">"}
return this;
}
function onMapClicked(evt)
{
targetPoint.x = evt.offsetX;
targetPoint.y = evt.offsetY;
drawMap(this);
}
function drawMap(canvasElem)
{
var ctx = canvasElem.getContext('2d');
ctx.clearRect(0,0,canvasElem.width,canvasElem.height);
var radius = 5;
ctx.beginPath();
ctx.arc(targetPoint.x, targetPoint.y, radius, 0, 2 * Math.PI, false);
ctx.fillStyle = 'green';
ctx.fill();
}
function onMapMouseMoved(evt)
{
var x = evt.offsetX, y = evt.offsetY;
var curPos = new vec2_t(x, y);
var curVec = new vec2_t();
curVec.equals( curPos );
curVec.vecSub( targetPoint );
var curDist = curVec.vecLen();
var linearDist = (1-(curDist/maxDist));
// console.log("CurDist / MaxDist = " + linearDist );
// console.log("CurValue = " + Math.pow(linearDist, 5) );
x = linearDist;
y = Math.pow(linearDist, steepnessFactor); // steepness of curve
setVolumeSVG(y * 100);
drawGraph();
var mapCan = byId('graph');
var ctx = mapCan.getContext('2d');
var scaleX = mapCan.width / 2;
var scaleY = -mapCan.height / 2;
var radius = 5;
ctx.beginPath();
ctx.arc( x*scaleX + mapCan.width/2,
y*scaleY + mapCan.height/2, radius, 0, 2 * Math.PI, false);
ctx.fillStyle = 'red';
ctx.fill();
ctx.beginPath();
}
function setVolumeSVG(percent)
{
var svg = byId('mSvg');
var barWidth = (percent/100) * svg.width.baseVal.value;
var barHeight = (percent/100) * svg.height.baseVal.value;
var msg = "0,"+svg.height.baseVal.value + " "
+ barWidth + "," + (svg.height.baseVal.value-barHeight) + " "
+ barWidth + "," + svg.height.baseVal.value;
allByClass('barSlider')[0].setAttribute('points', msg);
}
#graph{ border: solid 1px black; }
#map{ border: solid 1px red; }
<canvas width=256 height=256 id='graph'></canvas>
<canvas width=256 height=256 id='map'></canvas><br>
<svg id='mSvg' xmlns="http://www.w3.org/2000/svg" viewBox="0 0 285 100" width=285 height=100>
<g>
<polygon class="barFrame" points="0,100 285,100 285,0"></polygon>
<polygon class='barSlider' points="0,100 143,100 143,50"></polygon>
</g>
<style>
.barFrame{ fill: #d1d3d4; }
.barSlider{ fill: #69bd45; }
</style>
</svg>
I would like to generate a canvas image using gradients in some clever way. I would like the image to looks something like this:
I just can't get my head around it. I need to generate lines in the form and arc - or use gradients with color stops in some clever way. Maybe it would be a lot easier if I converted to HSL and just go through the HUE values?
For example in a rectangle format I could
for (var i = 0; i < h; ++i) {
var ratio = i/h;
var hue = Math.floor(360*ratio);
var sat = 100;
var lum = 50;
line(dc, hslColor(hue,sat,lum), left_margin, top_margin+i, left_margin+w, top_margin+i);
}
Does anybody have any clever tips on how to produce this image using canvas?
This is not perfect (due to drawing steps ...), but it can help you :
http://jsfiddle.net/afkLY/2/
HTML:
<canvas id="colors" width="200" height="200"></canvas>
Javascript:
var canvas = document.getElementById("colors");
var graphics = canvas.getContext("2d");
var CX = canvas.width / 2,
CY = canvas.height/ 2,
sx = CX,
sy = CY;
for(var i = 0; i < 360; i+=0.1){
var rad = i * (2*Math.PI) / 360;
graphics.strokeStyle = "hsla("+i+", 100%, 50%, 1.0)";
graphics.beginPath();
graphics.moveTo(CX, CY);
graphics.lineTo(CX + sx * Math.cos(rad), CY + sy * Math.sin(rad));
graphics.stroke();
}
The idea is to draw the disc line by line with a hue value corresponding to the line direction.
You can change the color base rotation by adding a radius angle to rad variable (adding -pi/2 to rad would make the gradient look like your figure).
EDIT:
I made a new demo that generalizes the concept a bit and renders a rainbow polygon. Here is the CodePen.
To get rid of the small voids beteween the colors, I used quads that overflow to the next color part, except for the last one.
Small adjustment to make it have a white center
var canvas = document.getElementById('colorPicker');
var graphics = canvas.getContext("2d");
var CX = canvas.width / 2,
CY = canvas.height / 2,
sx = CX,
sy = CY;
for (var i = 0; i < 360; i += 0.1) {
var rad = i * (2 * Math.PI) / 360;
var grad = graphics.createLinearGradient(CX, CY, CX + sx * Math.cos(rad), CY + sy * Math.sin(rad));
grad.addColorStop(0, "white");
grad.addColorStop(0.01, "white");
grad.addColorStop(0.99, "hsla(" + i + ", 100%, 50%, 1.0)");
grad.addColorStop(1, "hsla(" + i + ", 100%, 50%, 1.0)");
graphics.strokeStyle = grad;
graphics.beginPath();
graphics.moveTo(CX, CY);
graphics.lineTo(CX + sx * Math.cos(rad), CY + sy * Math.sin(rad));
graphics.stroke();
}
Here is an alternate approach that takes a slightly more functional approach:
var canvas = document.getElementById("radial"),
ctx = canvas.getContext("2d"),
width = canvas.width,
height = canvas.height,
center = { x: width/2, y: height/2 },
diameter = Math.min(width, height);
var distanceBetween = function(x1,y1,x2,y2) {
// Get deltas
var deltaX = x2 - x1,
deltaY = y2 - y1;
// Calculate distance from center
return Math.sqrt(deltaX*deltaX+deltaY*deltaY);
}
var angleBetween = function(x1,y1,x2,y2) {
// Get deltas
var deltaX = x2 - x1,
deltaY = y2 - y1;
// Calculate angle
return Math.atan2(deltaY, deltaX);
}
var radiansToDegrees = _.memoize(function(radians) {
// Put in range of [0,2PI)
if (radians < 0) radians += Math.PI * 2;
// convert to degrees
return radians * 180 / Math.PI;
})
// Partial application of center (x,y)
var distanceFromCenter = _.bind(distanceBetween, undefined, center.x, center.y)
var angleFromCenter = _.bind(angleBetween, undefined, center.x, center.y)
// Color formatters
var hslFormatter = function(h,s,l) { return "hsl("+h+","+s+"%,"+l+"%)"; },
fromHue = function(h) { return hslFormatter(h,100,50); };
// (x,y) => color
var getColor = function(x,y) {
// If distance is greater than radius, return black
return (distanceFromCenter(x,y) > diameter/2)
// Return black
? "#000"
// Determine color
: fromHue(radiansToDegrees(angleFromCenter(x,y)));
};
for(var y=0;y<height;y++) {
for(var x=0;x<width;x++) {
ctx.fillStyle = getColor(x,y);
ctx.fillRect( x, y, 1, 1 );
}
}
It uses a function to calculate the color at each pixel – not the most efficient implementation, but perhaps you'll glean something useful from it.
Note it uses underscore for some helper functions like bind() – for partial applications – and memoize.
Codepen for experimentation.