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Getting 403 error while making ajax request in jQuery

I'm getting a 403 error while making an AJAX request to a php page of my own website.
This is the error:
"jq.js:663 POST https://playonlineloto.com/backend/cstatus.php 403"
I'm using jQuery to make the request. The code is:
function status() {
var table = document.getElementById("table").value;
var name=document.getElementById("username").innerHTML;
var card=document.getElementById("card").innerHTML;
var dataString = "table=" + table+"&name="+name+"&card="+card;
$.ajax({
type: "POST",
url: "cstatus.php",
data: dataString,
cache: false,
success: function(html) {
if(html=="no"){
}else{
console.log("kicked out");
console.log(html);
var kick = document.getElementById("kick");
kick.style.display="block";
}
}
});
};
and I'm requesting from this url
https://playonlineloto.com/backend/custom-game.php?val=1&table=U7Gh8c7f6&admin=yes
My files have enough permission. Please help me!!

jQuery ajax POST request for log in

I am trying to write a .ajax request through a form to log in. When I submit my form, nothing happens with either the success or error functions. I notice that if I put an alert box after the .ajax call it does not work either. I would expect, that if I am just incorrectly putting the data, I would at least expect the error alert box to show up? Here is my code:
var clientType = "clienttype";
$(document).ready(function(){
$("#login-form").submit(function(e){
$.ajax({
type: "POST",
url: "myurl",
data: $(this).serialize() + "&client_type=" + clienttype,
success: function(data) {
alert("sent" + data);
},
error: function(){
alert("Did not work");
}
});
e.preventDefault();
});
});

I noticed you're already using JQuery. So perhaps use the built in post function. Example below:
Also side note: You've got a slight type in your variable: data: $(this).serialize() + "&client_type=" + clienttype, clienttype was declared with a capital T: clientType
var clientType = "clienttype";
$(document).ready(function(){
$("#login-form").submit(function(e){
e.preventDefault();
$.post("myurl",{data:$(this).serialize(),client_type:clientType},function(data){
console.log("Date returned from request:",data);
// Returns JSON Data. So data.clientType.
},'json');
});
});

If you add in a trigger to cancel the page from being submitted, it should work (return false;), take a look below.
var clientType = "clienttype";
$(document).ready(function(){
$("#login-form").submit(function(){
$.ajax({
type: "POST",
url: "myurl",
data: $(this).serialize() + "&client_type=" + clienttype,
success: function(data) {
alert("sent" + data);
},
error: function(){
alert("Did not work");
}
});
return false;
});
});

Jquery ajax() not working as expected

I have a function getActivityHP() which I am calling as soon as my page loads. This function makes an ajax calls to another test3.php page with certain data which will contain default values initially. However as soon as I add my ajax code the function stops working as if there is an error. Simple alert also doesn't work!
<script>
$(document).ready( function(){
alert("Welcome");// not working
getActivityHP();
}
function getActivityHP() {
$("#loading").show();
alert("Hello"); // not working
var search = $("#search").val();
var deployedon = $("#deployedon").val();
var platform = $("#platform").val();
var country = $("#country").val();
var carrier = $("#carrier").val();
$.ajax({
type: "POST",
url: "test3.php",
data: {
"action" : "activity",
"deployedon" : deployedon,
"platform" : platform,
"country" : country,
"carrier" : carrier
},
success: function(msg) {
$("#loading").hide();
$("#activity").html(msg);
}
error: function() {
alert("An error occurred while processing file.");
}
});
}
</script>
In my test3.php I am doing:-
$action=$_POST['action'];
$deployedon=$_POST['deployedon'];
$platform=$_POST['platform'];
$carrier=$_POST['carrier'];
$country=$_POST['country'];
and then I am using echo to print these in my html!

There is syntax error. You are missing ) at the end of -
$(document).ready( function(){
alert("Welcome");
getActivityHP();
});
And missing , at the end of success -
success: function(msg) {
$("#loading").hide();
$("#activity").html(msg);
},
Update your code and try to run.

You missed a comma right here:
success: function(msg) {
$("#loading").hide();
$("#activity").html(msg);
}, // <--- This comma
error: function() {
alert("An error occurred while processing file.");

jquery ajax function with json

Hi i am using this code to get contents from a json file but i am not able to show results
my code is
$(document).ready(function(){
$.ajax({
url: 'http://50.116.19.49/rest/user.json',
dataType: 'jsonp',
jsonp: 'jsoncallback',
timeout: 50000,
success: function(data, status){
alert(data);
},
error: function(){
output.text('There was an error loading the data.');
}
});
});
In google chrome i can see that the request status is 200 and data is loaded. here is the link from which i am copying code The Link.... Any help!!!!
Thanks

Your code doesn't work because the http://50.116.19.49/rest/user.json resource return a JSON response instead of JSONP (difference).
So you can't make cross-domain calls via ajax BUT you can create a some proxy script ON YOUR SERVER which will make it for you. Example:
cross-domain-call.php
<?php echo file_get_contents('http://50.116.19.49/rest/user.json');?>
And change your script to
$(document).ready(function(){
$.ajax({
url: 'http://127.0.0.1/cross-domain-call.php',
dataType: 'json',
timeout: 50000,
success: function(data, status){
console.log(data);
},
error: function(jqXHR, textStatus, errorThrown){
console.log(jqXHR);
console.log(textStatus);
console.log(errorThrown);
}
});
});

Since you don't seem to have access to remote webservice to convert it to JSONP, here is a solution using Yahoo's YQL as a proxy. YQL will retrieve file contents from any remote site and return as xml or jsonp.
Working DEmo http://jsfiddle.net/Uh8cz/2/
You will notice the response object has additional properties created by YQL
var yqlBaseUrl = 'http://query.yahooapis.com/v1/public/yql?q=';
var restUrl = 'http://50.116.19.49/rest/user.json';
var yqlQuery = 'select * from json where url="' + restUrl + '" ';
var yqlFormat = 'format=json'
var jQueryCallback = '?'
var fullQueryUrl = yqlBaseUrl + yqlQuery + '&' + yqlFormat + '&' + jQueryCallback;
$.getJSON(fullQueryUrl, function(json) {
var jsonString = JSON.stringify(json.query.results.json.json, null, ' ')
$('body').append('<h1>Response</h1><pre>' + jsonString)
}) ​

If you can control the content of "user.json", wrap it around a function:
user.json content:
execute_jsonp({you_json)
your javascript:
$(document).ready(function(){
$.ajax({
url: 'http://50.116.19.49/rest/user.json',
dataType: 'jsonp',
jsonp: 'jsoncallback',
timeout: 50000,
success: function(data, status){
data(); //execute the function that is sent
},
error: function(){
output.text('There was an error loading the data.');
}
});
function execute_jsonp(json){ //recreate the function so you may access the json as a parameter
alert(json);
}
});
Hope this helps ;)

jquery $ajax not working as expected

I Have to do a cross-domain request and fetch content from a url using $.ajax function.
But the below code only displays the first alert i.e alert(myUrl),
After that the execution stops.The second alert is not displayed. I don't know what is wrong with the code i have written.
Can somebody tell me what i am doing wrong here?Thanks in advance.
function getContentFromUrl(){
var myUrl="http://icant.co.uk";
alert(myUrl);
$.ajax({
url: "http://query.yahooapis.com/v1/public/yql?" +
"q=select%20*%20from%20html%20where%20url%3D%22" +
encodeURIComponent(myUrl) + "%22&format=xml'&callback=?",
dataType: 'json',
data: data,
success: function () {
alert("***********"+data.results[0]);
if (data.results[0]) {
var htmlText = data.results[0];
var jsonObject = parseAndConvertToJsonObj(htmlText);
} else {
document.getElementById("displayerrors").innerHTML = "Could not load the page.";
}
},
error: function() {
document.getElementById("displayerrors").innerHTML = "Could not load the page.";
}
});
}

Same Origin Policy:
The policy permits scripts running on pages originating from the same site to access each other's methods and properties with no specific restrictions, but prevents access to most methods and properties across pages on different sites.

You can't use regular JSON for cross-domain requests because of the same-origin policy. Instead, you'll need to use JSONP. In jQuery, you can do so like this:
$.ajax({
dataType: 'jsonp',
crossDomain: true
// other info
});
Note that there are security issues involved with JSONP. Only use JSONP if you trust the host domain.

I assume this is jQuery?
Try the following:
url = "http://query.yahooapis.com/v1/public/yql?" +"q=select%20*%20from%20html%20where%20url%3D%22" + encodeURIComponent(myUrl) + "%22&format=xml'&callback=?";
getContentFromURL(url);
function getContentFromURL(url)
{
$.get(url, function (data) {
console.log(data);
});
}
If it dumps out to the console a response, you can build from there.

The data here is not defined
$.ajax({
url: "http://query.yahooapis.com/v1/public/yql?" + "q=select%20*%20from%20html%20where%20url%3D%22" + encodeURIComponent(myUrl) + "%22&format=xml'&callback=?",
dataType: 'json',
data: data,
and you forget to add a param for the callback function
success: function (data) {
....
}
The finally code should like this
function getContentFromUrl() {
var myUrl = "http://icant.co.uk";
alert(myUrl);
$.ajax({
url: "http://query.yahooapis.com/v1/public/yql?" + "q=select%20*%20from%20html%20where%20url%3D%22" + encodeURIComponent(myUrl) + "%22&format=xml'&callback=?",
dataType: 'json',
data: {},
success: function (data) {
alert("***********" + data.results[0]);
if (data.results[0]) {
var htmlText = data.results[0];
var jsonObject = parseAndConvertToJsonObj(htmlText);
} else {
document.getElementById("displayerrors").innerHTML = "Could not load the page.";
}
},
error: function () { document.getElementById("displayerrors").innerHTML = "Could not load the page."; }
});
}