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Filter out the required stuff from an input

So I'm using webSpeechSysthesis to make something that can take inputs and give out results on it with the commands that I have , one command is the "solve" something like "solve √45" and it'll give the answer
I cant figure out how do I separate the √45 and use it to calculate , in Speech synthesis the string that is said is stored in a variable "text"
I tried using replace() and replace the solve with nothing so that I only have numbers and operators but I only get the ' ' , nothing after it
Let word = "solve"
if(text.startsWith(word)){
let final = word.replaceAll(/\bsolve\b/g,'')
Console.log(final)
}

You should use let final = text.replaceAll(/\bsolve\b/g,'') instead of let final = word.replaceAll(/\bsolve\b/g,'').
let text = "solve √45";
let word = "solve";
if(text.startsWith(word)) {
let final = text.replaceAll(/\bsolve\b/g,'');
console.log(final);
};

You don't need to check if a word starts with solve, you can do this with regex as well using the ^ character. There is also no need to use the global flag with replaceAll.
let word = "solve √45";
let final = word.replace(/^solve\b /g, "");
console.log(final);

search a regex and filter it

Hi i am try to find a variable date in a string with a regex and after this i want to save the date in a new variable my code looks like:
var valide =new RegExp(/\d{2}([./-])\d{2}\1\d{4}$/mg);
var text = 'lalaahfdsdfl 02.02.1989';//example
if(valide.test(text) === true){
}
how can i put the found date (02.02.1989) in a new variable

You can create groups in your Regex expression (just put the values you want between parenthesis) and then use this to get the specific group value.
Note, however, I think your regex is wrong... it seems you end with 1 plus 4 digits

You can use match on a string:
var valide =new RegExp(/\d{2}([./-])\d{2}\1\d{4}$/mg);
var text = 'lalaahfdsdfl 02.02.1989';//example
console.dir(text.match(valide)) // ["02.02.1989"]
if(valide.test(text) === true){
}

Using REGEXP function match you can extract the part that match your regular expression.
After this you will get an object. In this case i turn it into a string so you can do a lot more things with it.
var myDate = text.match(valide).toString();
Hope this helps :>
var valide =new RegExp(/\d{2}([./-])\d{2}\1\d{4}$/mg);
var text = 'lalaahfdsdfl 02.02.1989';//example
if(valide.test(text) === true){
var myDate = text.match(valide).toString();
console.log(myDate)
}

You can use match for that:
var valide =new RegExp(/\d{2}([./-])\d{2}\1\d{4}$/mg);
var text = 'lalaahfdsdfl 02.02.1989';//example
var foundDate = text.match(valide);
console.log(foundDate);
Also, you can make the regex a bit simpler if you switch the ([./-]) to ([-.]), because - is considered a literal match if it comes first inside a character class.

You could do something like this.
var result = text.match(valide)
Here is a reference for the match method String.prototype.match

Using RegExp to substring a string at the position of a special character

Suppose I have a sting like this: ABC5DEF/G or it might be ABC5DEF-15 or even just ABC5DEF, it could be shorter AB7F, or AB7FG/H.
I need to create a javascript variable that contains the substring only up to the '/' or the '-'. I would really like to use an array of values to break at. I thought maybe to try something like this.
...
var srcMark = array( '/', '-' );
var whereAt = new RegExp(srcMark.join('|')).test.str;
alert("whereAt= "+whereAt);
...
But this returns an error: ReferenceError: Can't find variable: array
I suspect I'm defining my array incorrectly but trying a number of other things I've been no more successful.
What am I doing wrong?

Arrays aren't defined like that in JavaScript, the easiest way to define it would be with:
var srcMark = ['/','-'];
Additionally, test is a function so it must be called as such:
whereAt = new RegExp(srcMark.join('|')).test(str);
Note that test won't actually tell you where, as your variable suggests, it will return true or false. If you want to find where the character is, use String.prototype.search:
str.search(new RegExp(srcMark.join('|'));
Hope that helps.

You need to use the split method:
var srcMark = Array.join(['-','/'],'|'); // "-|/" or
var regEx = new RegExp(srcMark,'g'); // /-|\//g
var substring = "222-22".split(regEx)[0] // "222"
"ABC5DEF/G".split(regEx)[0] // "ABC5DEF"

From whatever i could understand from your question, using this RegExp /[/-]/ in split() function will work.
EDIT:
For splitting the string at all special characters you can use new RegExp(/[^a-zA-Z0-9]/) in split() function.
var arr = "ABC5DEF/G";
var ans = arr.split(/[/-]/);
console.log(ans[0]);
arr = "ABC5DEF-15";
ans = arr.split(/[/-]/);
console.log(ans[0]);
// For all special characters
arr = "AB7FG/H";
ans = arr.split(new RegExp(/[^a-zA-Z0-9]/));
console.log(ans[0]);

You can use regex with String.split.
It will look something like that:
var result = ['ABC5DEF/G',
'ABC5DEF-15',
'ABC5DEF',
'AB7F',
'AB7FG/H'
].map((item) => item.split(/\W+/));
console.log(result);
That will create an Array with all the parts of the string, so each item[0] will contain the text till the / or - or nothing.

If you want the position of the special character (non-alpha-numeric) you can use a Regular Expression that matches any character that is not a word character from the basic Latin alphabet. Equivalent to [^A-Za-z0-9_], that is: \W
var pattern = /\W/;
var text = 'ABC5DEF/G';
var match = pattern.exec(text);
var position = match.index;
console.log('character: ', match[0]);
console.log('position: ', position);

Change occurrences of sum(something) to something_sum

Admittedly I'm terrible with RegEx and pattern replacements, so I'm wondering if anyone can help me out with this one as I've been trying now for a few hours and in the process of pulling my hair out.
Examples:
sum(Sales) needs to be converted to Sales_sum
max(Sales) needs to be converted to Sales_max
min(Revenue) needs to be converted to Revenue_min
The only available prefixed words will be sum, min, max, avg, xcount - not sure if this makes a difference in the solution.
Hopefully that's enough information to kind of show what I'm trying to do. Is this possible via RegEx?
Thanks in advance.

There are a few possible ways, for example :
var str = "min(Revenue)";
var arr = str.match(/([^(]+)\(([^)]+)/);
var result = arr[2]+'_'+arr[1];
result is then "Revenue_min".
Here's a more complex example following your comment, handling many matches and lowercasing the verb :
var str = "SUM(Sales) + MIN(Revenue)";
var result = str.replace(/\b([^()]+)\(([^()]+)\)/g, function(_,a,b){
return b+'_'+a.toLowerCase()
});
Result : "Sales_sum + Revenue_min"

Try with:
var input = 'sum(Sales)',
matches = input.match(/^([^(]*)\(([^)]*)/),
output = matches[2] + '_' + matches[1];
console.log(output); // Sales_sum
Also:
var input = 'sum(Sales)',
output = input.replace(/^([^(]*)\(([^)]*)\)/, '$2_$1');

You can use replace with tokens:
'sum(Sales)'.replace(/(\w+)\((\w+)\)/, '$2_$1')

Using a whitelist for your list of prefixed words:
output = input.replace(/\b(sum|min|max|avg|xcount)\((.*?)\)/gi,function(_,a,b) {
return b.toLowerCase()+"_"+a;
});
Added \b, a word boundary. This prevents something like "haxcount(xorz)" from becoming "haxorz_xcount"

Remove everything after a certain character

Is there a way to remove everything after a certain character or just choose everything up to that character? I'm getting the value from an href and up to the "?", and it's always going to be a different amount of characters.
Like this
/Controller/Action?id=11112&value=4444
I want the href to be /Controller/Action only, so I want to remove everything after the "?".
I'm using this now:
$('.Delete').click(function (e) {
e.preventDefault();
var id = $(this).parents('tr:first').attr('id');
var url = $(this).attr('href');
console.log(url);
}

You can also use the split() function. This seems to be the easiest one that comes to my mind :).
url.split('?')[0]
jsFiddle Demo
One advantage is this method will work even if there is no ? in the string - it will return the whole string.

var s = '/Controller/Action?id=11112&value=4444';
s = s.substring(0, s.indexOf('?'));
document.write(s);
Sample here
I should also mention that native string functions are much faster than regular expressions, which should only really be used when necessary (this isn't one of those cases).
Updated code to account for no '?':
var s = '/Controller/Action';
var n = s.indexOf('?');
s = s.substring(0, n != -1 ? n : s.length);
document.write(s);
Sample here

var href = "/Controller/Action?id=11112&value=4444";
href = href.replace(/\?.*/,'');
href ; //# => /Controller/Action
This will work if it finds a '?' and if it doesn't

May be very late party :p
You can use a back reference $'
$' - Inserts the portion of the string that follows the matched substring.
let str = "/Controller/Action?id=11112&value=4444"
let output = str.replace(/\?.*/g,"$'")
console.log(output)

It works for me very nicely:
var x = '/Controller/Action?id=11112&value=4444';
var remove_after= x.indexOf('?');
var result = x.substring(0, remove_after);
alert(result);

If you also want to keep "?" and just remove everything after that particular character, you can do:
var str = "/Controller/Action?id=11112&value=4444",
stripped = str.substring(0, str.indexOf('?') + '?'.length);
// output: /Controller/Action?

You can also use the split() method which, to me, is the easiest method for achieving this goal.
For example:
let dummyString ="Hello Javascript: This is dummy string"
dummyString = dummyString.split(':')[0]
console.log(dummyString)
// Returns "Hello Javascript"
Source: https://thispointer.com/javascript-remove-everything-after-a-certain-character/

if you add some json syringified objects, then you need to trim the spaces too... so i add the trim() too.
let x = "/Controller/Action?id=11112&value=4444";
let result = x.trim().substring(0, x.trim().indexOf('?'));

Worked for me:
var first = regexLabelOut.replace(/,.*/g, "");

It can easly be done using JavaScript for reference see link
JS String
EDIT
it can easly done as. ;)
var url="/Controller/Action?id=11112&value=4444 ";
var parameter_Start_index=url.indexOf('?');
var action_URL = url.substring(0, parameter_Start_index);
alert('action_URL : '+action_URL);