Unable to calculate the hover element's exact position - javascript

I am just trying to get the mouse hover div's position at the right according to the space around. Somehow I am able to do this in first two columns but not for other columns. May be my calculations while writing the condition state are wrong.
Can anyone please help?
JS Fiddle URL:
http://jsfiddle.net/mufeedahmad/2u1zr11f/7/
JS Code:
$('.thumb-over-team li').find('.cover').css({opacity:0});
$('.thumb-over-team li').on('mouseenter', function(){
var $this = $(this),
thisoffset = $this.position().left,
openDivId = $(this).find('.cover'),
thumbContainer = '.thumb-over-team',
speedanim = 200;
if(thisoffset + openDivId.outerWidth() >= $(thumbContainer).outerWidth()){
//thisoffset = $(thumbContainer).outerWidth() - openDivId.outerWidth() - 212;
thisoffset = thisoffset - openDivId.outerWidth()+10;
openDivId.stop().css({'z-index':'9999'}).animate({'opacity':'1', 'left':-thisoffset}, 200);
}else{
openDivId.stop().css({'z-index':'9999'}).animate({'opacity':'1', 'left':'212px'}, 200);
}
}).on('mouseleave', function(){
$(this).find('.cover').stop().css({'z-index':'-1'}).animate({'opacity':'0', 'left':'200px'}, 200);
});
$('.close-parent').on('click', function(){
$(this).parents('.cover').stop().css({'z-index':'-1'}).animate({'opacity':'0', 'left':'200px'}, 200);
});;

In your first conditional, try to calculate the position of the offset as:
thisoffset = ($(thumbContainer).outerWidth() - openDivId.outerWidth() - thisoffset);
That way, you're adjusting the appearing square (.cover) when it doesn't fit inside the container, to be as close possible to its rightmost edge: (maximum width - appearing square width - current li position)
Calculated this way, you can animate it with the new offset in positive:
openDivId.stop().css({'z-index':'9999'}).animate({'opacity':'1', 'left':thisoffset}, 200);
See it working here.
For elements that "almost" fit, the current system isn't completely precise because of what I already pointed out in my previous comment: the appearing square, even if it were at 0 opacity, would still be inside the containing element (($(thumbContainer)) or .thumb-over-team) and it would add its width to the total width of the container.
So your conditional may think that there's enough available space in the container to make the expandable element fit, but that would go out of the screen. As an example, notice that there's a horizontal scrollbar from the very beginning, caused by this effect, where your containing .thumb-over-team element doesn't fit in the screen.
But I would say that more precision in this point would require a fresh new approach to your system where the appearing .cover elements were out of the containing ul .thumb-over-team

Fresh take on the problem, essentially based on the main issue: the expandable text block (.cover) used to add its width to the container (.thumb-over-team). This altered the calculations on available container space, and made the text containers go off screen.
The solution is to make sure the expandable .cover elements aren't contained inside the .thumb-over-team element, so they won't impact the calculations on available width.
Here is a JSFiddle containing this new approach: link.
Explanation of how it works:
The idea was to create a separate element called .cover-container and let's put all the expandable .cover elements in there.
We want to associate every image in the li elements in .thumb-over-team with their appropriate .cover (so the first image triggers the first .cover to show, the second image would show the second cover, and so on.) We achieve is by finding out the index of the element that triggered the event:
thisLiIndex = $this.index() + 1
And then selecting the cover in the matching position:
openDivId = $('.cover-container .cover:nth-child(' + thisLiIndex + ')')
The expandable covers shouldn't interfere with the mouseenter or mouseleave events of .thumb-over-team, so we make it to ignore mouse events via CSS:
.cover-container{pointer-events:none;}
Changing from one image to another would automatically trigger new events, so the expanding covers stay visible when the mouse stays on the images, but close automatically when the mouse exits them.
Since the covers are now outside of $(thumbContainer), openDivID.outerWidth() does not alter $(thumbContainer).outerWidth(), and we can use that safely in our positioning.
If I understand the placement that you want, for covers that fit, the position is the current offset (position of the li element that triggered the event) plus the width of the image and some subtle margin
imageWidth + rightSeparation + thisoffset
And for covers that won't fit inside of the screen, we keep them just inside of the screen
thisoffset = $(thumbContainer).outerWidth() - openDivId.outerWidth();

Related

How can I create overlapping images that reveal themselves as you scroll

I am looking to create a scrolling effect similar to that shown here: http://www.seaham-hall.co.uk/
However I am unable to achieve the desired effect, and inspecting the sites code gives me no hints. Quite difficult to google for as it is also quite difficult to describe. The closest I can get to finding a solution is this JSFiddle:
http://jsfiddle.net/xtyus/1/
(function($){
/* Store the original positions */
var d1 = $('.one');
var d1orgtop = d1.position().top;
var d2 = $('.two');
var d2orgtop = d2.position().top;
var d3 = $('.three');
var d3orgtop = d3.position().top;
var d4 = $('.four');
var d4orgtop = d4.position().top;
/* respond to the scroll event */
$(window).scroll(function(){
/* get the current scroll position */
var st = $(window).scrollTop();
/* change classes based on section positions */
if (st >= d1orgtop) {
d1.addClass('latched');
} else {
d1.removeClass('latched');
}
if (st >= d2orgtop) {
d2.addClass('latched');
} else {
d2.removeClass('latched');
}
if (st >= d3orgtop) {
d3.addClass('latched');
} else {
d3.removeClass('latched');
}
if (st >= d4orgtop) {
d4.addClass('latched');
} else {
d4.removeClass('latched');
}
});
})(window.jQuery);
However I am not sure that is going in the right direction, this pulls images up and covers the previous image, but notice on the Seaham Hall site the images don't appear to move up at all, they are stationary and become revealed as you scroll.
How do I recreate this effect? My initial thought was to have the first image shrink as you scroll from 1000px down to 0px, and the second image grow to 1000px, and as you continue to scroll this image then shrinks and the third grows, and so on. However this means that after the first image all the other images have a starting size of 0px and there would technically be no scrolling on the page to begin with, so that is an issue.
My second thought is that perhaps the second image is fixed to the page, the first image slides up revealing the second as you scroll, the second image would not appear to move. Once the first image has gone off the top of the page the second image is detached from the page and allowed to move up with scrolling, while the third image is attached and revealed as the second moves up, this would give the exact effect seen in the Seaham website but I have no clue of it is the correct answer.
If anyone can point me to tutorials or a JSFiddle with a basic concept I can probably figure it out from there. Just stumped what direction to approach this from.
That's a nice effect. Here's one way to do it.
Put each image in a fixed position div, which takes up the entire viewport (initially) and has overflow:hidden.
Set each div's z-index to be higher than the next div's.
As the window scrolls, adjust the height of the divs as a function of the window height times the div's position (index) in the DOM, minus the window's scrollTop:
$(window).scroll(function() {
$('.D').each(function(index) {
$(this).css({
height: $(window).height()*(index+1) - $(window).scrollTop()
});
});
});
Additional content will need a higher z-index than the image divs. And note that z-index works with positioned elements only.
Fiddle
Your desired effect isn't technically a parallax background, but it's close enough that parallax jQuery frameworks should work for you.
I would suggest you research jQuery Parallax plugins as they'll likely provide the functionality you'd like without much custom work. Of course since you're dealing with large images it's also best to keep an eye on the resource management; a good plugin should be fairly efficient but others may be slow or resource intensive.
Check this jquery plugin:ScrollMagic
usage: taken from github
The basic ScrollMagic design pattern is one controller, which has several scenes attached.
Each scene has a definite start and end position and defines what happens when the container is scrolled to the specific offset.
/*
Basic workflow example
*/
// init controller
var controller = new ScrollMagic();
// assign handler "scene" and add it to controller
var scene = new ScrollScene({duration: 100})
.setPin("#my-sticky-element") // pins the element for a scroll distance of 100px
.addTo(controller); // add scene to controller
// adding multiple scenes at once
var scene2 = new ScrollScene();
var scene3;
controller.addScene([
scene2,
scene3 = new ScrollScene({duration: 200}), // add scene and assign handler "scene2"
new ScrollScene({offset: 20}) // add anonymous scene
]);

How can I position a div relative to a list item?

I have an unordered list of pictures, and when I hover over one I want the two pictures to the left to fade out, and a div to appear in their place with text. I've gotten this working, except for positioning the div - I've tried this:
div.position({my: 'left top', at: 'left top', of: other_list_item});
but that just returns an Object ( the new location ) of {left: 0, top: 0}.
I've also tried putting the div in another li element, but it's still a no-go. Here's the div HTML:
<div style="width: 255px; height: 110px; position: absolute;" id="name_popup"><p>Jon Jensen</p><p>Chief Technical Officer</p><p>London, England</p></div>
EDIT I'm working on a JSFiddle example, but there's kind of a lot to put in, so idk when it'll be ready. Anyways, I forgot to mention this bit of fun:
when I call .position() by itself on the element that I'm trying to anchor to, it returns the correct offsets, but when I try to use position() on the other element to match their positions, nothing happens.
I did not quite understand the question, but from my reasoning I get that you are trying to position new divs in place of the faded out images, so here is some code that could fit your situation
$('div').click(function(){
//get the positions of the divs to be faded out
var prev_position = $(this).prev('div').position();
var next_position = $(this).next('div').position();
//create and position new divs
$(this).insertBefore('<div style="position:absolute;top:' +prev_position.top+ 'px;left:' +prev_position.left+ 'px;">Replacing DIV</div>');
$(this).insertAfter('<div style="position:absolute;top:' +next_position.top+ 'px;left:' +next_position.left+ 'px;">Replacing DIV</div>');
//hide the divs
$(this).prev('div').fadeOut();
$(this).next('div').fadeOut();
});
Sometimes, if your parent element has a position set, then the .position() will get the position relative to the parent element, and depending in your needs this might throw off your design. So instead you could get the coordinates of the previous and next divs relative to the WINDOW and you could get those like these:
function getPosition($el){
//get the offset coordinates of the recently clicked link
var offset = $el.offset();
var top = offset.top;
var left = offset.left;
//get position of this link relative to the window
var rel_top = top - $(window).scrollTop();
var rel_left = left - $(window).scrollLeft();
}

How do I move the background image of a DIV based on the scrollbar movement?

I have been looking into parallax effects for vertical scrolling on my web page, and after some research, I'm not sure that what I want to do is technically a parallax effect.
From what I've seen, most parallax effects assume you want to be able to scroll indefinitely with many background images rolling by, or with huge images that repeat.
What I want to do is have the background of two DIVs be filled with a background image as the scroll bar reaches the bottom of the page. Note that I do not want the background images to stretch. I'm assuming to get the effect I want that these images would have a vertical height bigger than most people's viewport, and then their vertical position would change. When the user's scrollbar is at the top, a certain amount of the background is visible, and then it moves vertically to fill the background space as the user scrolls down.
Please see the image below for a visual explanation of the effect I hope to acheive:
The height of the veiwport will vary depending on the length of content inside the inner DIV.
My trouble is that if what I am trying to do is not exactly a parallax effect, then I don't know what else to call it, and my attempts to search by describing it keep landing me back at pages offering tutorials on parallax effects. So I've been stumped by a lack of terminology.
If someone could direct me to how I can control the vertical position of the background depending on the scrollbar position, that would be much appreciated. If this can be done with just CSS that would be great, but I'm assuming some Javascript would be required. A jQuery solution would also work for me.
Update:
After searching using the terms provided in comments, I've got the background image in the outer DIV to almost do what I want with the following code:
$(window).scroll(function () {
var yPos = $("#outerDiv").height() - ($("#outerDIV").height() * ($(window).scrollTop() / $(window).height()));
document.getElementById('outerDIV').style.backgroundPosition="0px " + yPos + "px";
});
It moves the background image in the right direction relative to the scrolling, but what it lacks is constraining that motion to within the viewport. Getting the right proportions based on the viewport and DIV sizes is proving to be just a little beyond my mathematical abilities.
For your requirement, you have to use a jquery parallax plugin to guide this activity, my best suggest it to use a Superscollorama and play with the elements as your wish...
As far as your question, Try this example,
controller.addTween(
'#examples-background',
(new TimelineLite())
.append([
TweenMax.fromTo($('#parallax-it-left'), 1,
{css:{backgroundPosition:"(0 -54px)"}, immediateRender:true},
{css:{backgroundPosition:"(0 -54px)"}}),
TweenMax.fromTo($('#parallax-it-right'), 1,
{css:{backgroundPosition:"(0 -54px)"}, immediateRender:true},
{css:{backgroundPosition:"(0 54px)"}})
]),
1000 // scroll duration of tween
);
You serial vice change as far as your wish...
Try practice this plugin, hope that works for you...
http://johnpolacek.github.io/superscrollorama/
Thanks...
Turns out what I want to acheive is possible with no special plugins, just some carefully thought out math. I did use a little jQuery syntax, but I don't think it's strictly necessary.
The code below has copious notes, so hopefully it's largely explanatory. In summary, you just need to find the position of the background image when the scroll would be at the top, and the position it would be if the scroll bar was at the bottom, and then you can use the percentage of the scrollbar's movement to work out where you are between those two points. It's a little tricker than just that, of course, in that you have to account for the difference between the total height of the scroll bar and where your DIV appears on the page and a few other adjustments, but the details of what I did are below.
What I've done here is just for the "outer DIV" that I described in my question. To get a background to move like the "inner DIV" I described, you'd have to modify the code, presumeably by reversing a few parameters. I haven't done that yet, but it seems like a straightforward task.
Hope others find this code useful. If anyone has suggestions on how it can be made more efficient or better, please let me know.
function moveBG(){
// imageHeight is not the total height of the image,
// it's the vertical amount you want to ensure remains visible no matter what.
var imageHeight = 300;
// Get the maximum amount within the DIV that the BG can move vertically.
var maxYPos = $("#outerDIV").height() - imageHeight;
// Get the amount of vertical distance from the top of the document to
// to the top of the DIV.
var headerHeight = document.getElementById("outerDIV").offsetTop;
// Calculate the BG Y position for when the scrollbar is at the very top.
var bgTopPos = $(window).height() - headerHeight - imageHeight;
// I don't want the image to wander outside of the DIV, so ensure it never
// goes below zero.
if (bgTopPos < 0)
{
bgTopPos = 0;
}
// Calculate the BG Y position when the scrollbar is at the very top.
var bgBottomPos = $(document).height() - $(window).height() - headerHeight;
// To prevent the BG image from getting cut off at the top, make sure
// its position never exceeds the maximum distance from the top of the DIV.
if (bgBottomPos > maxYPos)
{
bgBottomPos = maxYPos;
}
// Subtract the top position from the bottom, and you have the spread
// the BG will travel.
var totalYSpan = bgBottomPos - bgTopPos;
// Get the scrollbar position as a "percentage". Note I simply left it as a
// value between 0 and 1 instead of converting to a "true" percentage between
// 0 and 100, 'cause we don't need that in this situation.
var scrollPercent = ($(window).scrollTop() / ( $(document).height() - $(window).height()));
// The percentage of spread is added to the top position, and voila!
// You have your Y position for the BG image.
var bgYPos = bgTopPos + (Math.round(totalYSpan * scrollPercent));
// Apply it to the DIV.
document.getElementById('outerDIV').style.backgroundPosition="0px " + bgYPos + "px";
}
// Place the BG image correctly when opening the page.
$(document).ready(function() {
moveBG();
});
// Make it update when the scrollbar moves.
$(window).scroll(function () {
moveBG();
});

How can I get the element visible in the viewport? jQuery

I have a list of images on a page. As I scroll through the page I would like to show some options in a naviationbar of the image currently in the viewport. Therefore I need to get the image element currently in the viewport, is this possible ?
Jakob
Who says there's just one image in viewport? What would you like to do when there are many?
But otherwise you can always get the scroll position of your container with images as well as your images' top offset to see which one is currently in-view.
So these values will get you to your result
container scroll position
container visible client height
images' top offset
Using these values will make it possible to locate all images in the view regardless whether they're fully or partially displayed (at the top or bottom).
This is a simplified JSFiddle that gives red border around the first fully-in-the-view image. The code does this:
// get top positions and references to all images
var pos = $("img").map(function(){
var $this = $(this);
return {
el: $this,
top: $this.offset().top
};
}).get();
// provide document scrolling
$(document).on("scroll", function() {
$("img").removeClass("first-in-view");
var scroll = $(this).scrollTop();
var i = 0;
while(pos[i].top < scroll) i++;
pos[i].el.addClass("first-in-view");
}).scroll();
This should be optimised to only toggle class when it needs to. Otherwise we have flickering in every scroll. But it demonstrates how this can be done and you can get going from here.
IMPORTANT
It is utterly important that you attach your image position determining process on document load event and not the usually use DOM ready, because you have to wait for the document to load in order for your images to have final positions.

How to keep jQuery function from moving elements all the way to the left?

I was able to implement the solution posted here ("position: fixed and absolute at the same time. HOW?") to get a div element to move with the rest of the page horizontally, but stay fixed vertically. However, this solution causes the selected element to move ALL the way to the left of the page (with what appears to be a 20px margin). I'm still new to javascript and jQuery, but as I understand it, the following:
$(window).scroll(function(){
var $this = $(this);
$('#homeheader').css('left', 20 - $this.scrollLeft());});
takes the selected element and, upon scrolling by the user, affects the CSS of the element so that its position from the left becomes some function of the current scrollbar position adjusted by the 20px margin. If this is correct? And if so, can anyone think of a way that I could change it so that instead of moving the selected element all the way to the left side of the window, we only move it as far left as my default CSS position for the body elements of the HTML document (shown below)?
body {font-size:100%;
width: 800px;
margin-top: 0px;
margin-bottom: 20px;
margin-left: auto;
margin-right: auto;
padding-left: 20px;
padding-right: 20px;}
EDIT: Here is a jsfiddle (code here) that I made to illustrate the issue. My page is designed so that when it is displayed in full-screen or near full-screen mode, the #homeheader element appears centered horizontally due to its width and the left and right margins being set to auto. As the page gets smaller and smaller the margins do as well, until they disappear altogether and are replaced by the padding-left and padding-right settings of 20px. So at this point (when the window is small enough that the margins disappear altogether), which is what the jsfiddle shows, the code appears to work as intended, but when the window is full-sized the JS overrides the CSS and pushes the div element all the way to the left (getting rid of the margin) upon any scrolling action.
There are two events you need to handle to get this to work correctly. First is the scroll event which you are pretty close on. The only thing you might want to do is to use offset to get the current left position value based on the document.
The other event which is not yet handled is the resize event. If you don't handle this then once a left position is defined your element (header) will be there always regardless of whether or not the user resizes the window.
Basically something like this should work:
var headeroffset;
var header = $('#homeheader');
// handle scroll
$(window).scroll(function() {
// auto when not defined
if (headeroffset === undefined) {
// capture offset for current screen size
headeroffset = header.offset();
}
// calculate offset
var leftOffset = headeroffset.left - $(this).scrollLeft();
// set left offset
header.css('left', leftOffset);
});
// handle resize
$(window).resize(function() {
// remove left setting
// (this stops the element from being stuck after a resize event
if (header.css('left') !== 'auto') {
header.css('left', '');
headeroffset = undefined;
}
});
JSFiddle example: http://jsfiddle.net/infiniteloops/ELCq7/6/
http://jsfiddle.net/infiniteloops/ELCq7/6/show
This type of effect can be done purely in css however, i would suggest taking a look at the full page app series Steve Sanderson did recently.
http://blog.stevensanderson.com/2011/10/05/full-height-app-layouts-a-css-trick-to-make-it-easier/
As an example you could do something like this:
http://jsfiddle.net/infiniteloops/ELCq7/18/
Try this
$('#homeheader').css('left', parseInt($('body').css('margin-left')) - $this.scrollLeft());});
What I did here is just replace 20 with body's left-margin value.

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