I am adding a simple toggle button through Javascript. Then I want to add three span tags inside it.
So, I am creating variable of span and trying to append it inside our very own basic FOR loop. Iteration count is 3 times.
Here's my basic code below. Please let me know what has been missing or misplaced that my span tag refuses to append more than once. I checked this in the inspect mode.
Then, I brought up console tab and the value of i was 3. Append is meant to append and NOT replace the element. Right ?
var $navbar_header = $('<div class="navbar-header"></div>');
var $button = $("<button></button>");
var $span = $('<span class="icon-bar"></span>');
for (var i = 0; i < 3; i++) {
$button.append($span);
}
$button.addClass('navbar-toggle');
$navbar_header.append($button);
$("#menu").append($navbar_header);
Here's a link to fiddle.
The DOM is a tree, where any element points to its parent (see parentNode). An element can have only one location. So when you append an element, you're removing it from its precedent location.
The solution here is either to clone the element:
$button.append($span.clone());
or just to create it in the loop:
for (var i = 0; i < 3; i++) {
$button.append('<span class="icon-bar"></span>');
}
Related
First of all I have to find the number of cells with one class, this line works.
var numcells = $('.hidden-td').length
And now I have to find the element with the class .placeholder-style I use this line (only one <tr>have this class):
$(this).find('.placeholder-style')
Now I have to add the same number of var numcellslike <td>inside the <tr>with the clase .hidden-td I think this will be with .addClass('hidden-td').
How can I make this?
Thanks
I'm assuming this is the correct structure you're after... if not, post your HTML so I can amend it but either way, this is how you should do it.
var numcells = $('.hidden-td').length;
var content = $(this).find('.placeholder-style');
for (i = 0; i < numcells; i++) {
content.append('<td class="hidden-td"></td>');
}
I am trying to remove an element based on type of attribute. It isn't working for some reason.
The element in question is this:
<p style="width:250px;font-size:11px;text-align:left;margin-left:1.2ex;margin-top:0px;margin-bottom:0px;line-height:1.15em;">– in Europe<span style="font-size:8px;"><span style="white-space:nowrap;"> </span></span>(<span style="font-size:9px;">green & dark grey</span>)<br>
– in the European Union<span style="font-size:8px;"><span style="white-space:nowrap;"> </span></span>(<span style="font-size:9px;">green</span>)</p>
I am trying to remove it this way - item is a container element.
$(item).find("p").filter("[style]").remove();
There are no other <p> tags with the attribute style, however this doesn't appear to remove it.
Other code, like this, works fine:
$(item).find(".reference").remove();
How do I remove all p tags with the style attribute from the item element?
This is how item is created:
$.get(link, function(response) {
var elements = $.parseHTML(response);
var wiki = $(elements).find('#mw-content-text').find("p");
//var ps = [];
var arrayLength = wiki.length;
for (var i = 0; i < arrayLength; i++) {
if (wiki[i].innerHTML === "") {
break;
}
var item = wiki[i];
The link variable is a link to wikipedia.
Maybe try this:
$.each(item.children('p'), function(index) {
if ($(this).attr('style')) {
$(this).remove();
}
});
item refers to p element itself. you don't have to find p in item:
$(item).filter("[style]").remove();
after re-looking over your question ,
$(item).find("p").filter("[style]").remove();
is perfectly valid , instead of trying to come up with alternative ways to write it , find out what is wrong with item, because it is not what you think it is if above code is not working
I wrote a function to insert divs dynamically into the web page. but then I have to remove these divs. While adding the divs I used a classname to all the divs. So I got all the elements from the dom using getElementsByClassName() and looping through all these elements and deleting the divs. My code is not removing all the divs that were created earlier.
Please find my code snippet:
var elements = document.getElementsByClassName("xxxx");
for (var i = 0; i < elements .length; i++) {
var element = elements[i];
if (element && element.hasChildNodes()) {
var parent_node = element.parentNode;
while(element.firstChild) {
parent_node.insertBefore(element.firstChild, element);
}
parent_node.removeChild(element);
}
elements = document.getElementsByClassName("xxxx");
}
You need to remove the last line "elements = document.getElementsByClassName("xxxx");" - that line will cause you to miss out every other element as you go around the loop.
If all you want is to remove all DIV elements with that class, you can use this code:
var elements = document.getElementsByClassName("xxxx");
while ( elements[0] ) {
elements[0].parentNode.removeChild(elements[0]);
}
It will remove your DIVs and their child nodes as well.
for(var i=0; i<num_cols; i++)
{
//Wrapper for column
$('#cupcake-list').append('<div>');
//end wrapper
col_count++;
num_in_col = rowsInCol(total,num_perCol,col_count);
start = i*num_perCol;
end = start + num_in_col;
for(var d=start; d<end; d++)
{
$('#cupcake-list').append('<p>'+cupcakeData[d].name+'</p>');
}
//Wrapper for column
$('#cupcake-list').append('</div>');
//end wrapper
}
I just want to encapsulate my p tags within div tags to act as rows, however all I get are <div></div><p>ssdfsdf</p><p>sdfsdfdsf</p><div></div>etc....
What's the best way of doing it?
Start with a fragment so that you don't access the DOM more than once, and append it all at the end. You can skip the wrap by starting with your empty fragment, like so:
var $fragment;
for(var i=0; i<num_cols; i++)
{
$fragment = $('<div />');
col_count++;
num_in_col = rowsInCol(total,num_perCol,col_count);
start = i*num_perCol;
end = start + num_in_col;
for(var d=start; d<end; d++)
{
$fragment.append('<p>'+cupcakeData[d].name+'</p>');
}
//Wrapper for column
$('#cupcake-list').append($fragment);
//end wrapper
}
This is a much faster way to do it! Append parts of a string to an array and then you only have to update the DOM once.
var a = [];
for(var i=0; i<num_cols; i++)
{
a.push('<div>');
col_count++;
num_in_col = rowsInCol(total,num_perCol,col_count);
start = i*num_perCol;
end = start + num_in_col;
for(var d=start; d<end; d++)
{
a.push('<p>'+cupcakeData[d].name+'</p>');
}
a.push('</div>');
}
$('#cupcake-list').append(a.join(''));
EDIT:
I'll explain why yours wasn't working. When you were calling $('#cupcake-list').append('<div>'); you thought it would only add the opening div tag, but that is not the case. jQuery won't let you do this is because they want to make sure the html is valid after every function call. If you were to just add the opening div and then do some other stuff, the next closing div (</div>) in the document would close the div you just opened, changing the structure of the document entirely.
In summation:
$('#cupcake-list').append('<div>'); and $('#cupcake-list').append('</div>'); will both append <div></div> to the document. Also, access and update the DOM as if it costs you a million dollars because it is among the slowest things you can do in javascript.
jQuery has a method called .wrap, and some similar ones (.wrapAll).
If you are having the output that you showed, your code is not reaching the inner for, so you have a logic problem. I think your way of doing this is correct. When i need to build some structure on the fly i usually do the same thing.
JQuery append adds DOM nodes, not HTML. So you can accomplish your task like this:
for(var i=0; i<num_cols; i++)
{
col_count++;
num_in_col = rowsInCol(total,num_perCol,col_count);
start = i*num_perCol;
end = start + num_in_col;
for(var d=start; d<end; d++)
{
$('#cupcake-list').append($('<div></div>').append('<p>'+cupcakeData[d].name+'</p>'));
}
}
First, $('<div></div>') creates a new empty div element not yet attached to the page (you can also do $('<div>') as a shorthand if you want). Then .append('<p>...</p>') adds a p element inside the div. Finally, $('#cupcake-list').append(...) adds the whole div to the end of #cupcake-list.
I'm creating 3 dropdowns/select boxes on the fly and insert them in the DOM through .innerHTML.
I don't know the ID's of the dropdowns until I created them in Javascript.
To know which dropdowns have been created, I create an array where I store the ID's of the dropdowns I have created.
for(var i=0; i<course.books.length; i++)
{
output+="<label for='book_"+course.books[i].id+"'>"+ course.books[i].name +"</label>";
output+="<select id='variant"+course.books[i].id+"' name='book_"+course.books[i].id+"'>";
output+="<option value='-'>-- Select one --</option>";
for(var j=0; j<course.books[i].options.length; j++)
{
output+="<option value='"+course.books[i].options[j].id+"'>"+course.books[i].options[j].name+"</option>";
}
output+="</select>";
}
Now I have an array with 3 id's like:
dropdown1
dropdown2
dropdown3
What I want to accomplish with Javascript (without using jQuery or another framework) is to loop over these 3 dropdowns and attach a change event listener to them.
When a user changes the selection in one of these dropdown, I want to call a function called updatePrice for example.
I'm a bit stuck on the dynamic adding of event listeners here.
Now you have added your code its straight forward and you can ignore my verbose answer !!!
output+="<select id='variant"+course.books[i].id+"' name='book_"+course.books[i].id+"'>";
could become :
output+="<select onchange="updatePrice(this)" id='variant"+course.books[i].id+"' name='book_"+course.books[i].id+"'>";
This will call the updatePrice function, passing the select list that changed
However
IMO its far better (from a performance point of view for a start) to create elements in the DOM using the DOM.
var newSelect = document.createElement("select");
newSelect.id = "selectlistid"; //add some attributes
newSelect.onchange = somethingChanged; // call the somethingChanged function when a change is made
newSelect[newSelect.length] = new Option("One", "1", false, false); // add new option
document.getElementById('myDiv').appendChild(newSelect); // myDiv is the container to hold the select list
Working example here -> http://jsfiddle.net/MStgq/2/
You got the array already? Then you can do this:
function updatePrice()
{
alert(this.id + " - " + this.selectedIndex);
}
var list = ["dropdown1", "dropdown2"];
for(var i=0;i<list.length;i++)
{
document.getElementById(list[i]).onchange = updatePrice;
}
Fiddle: http://jsfiddle.net/QkLMT/3/
That won't work across browsers.
You'll want something like
for(var i = 0; i < list.length; i++)
{
$("#"+list[i]).change(updatePrice);
}
in jquery.