How to pass data between 2 different pages using jQuery POST method? - javascript

I have 2 php files named card_process.php and payment.php. I'm trying to pass data from the cart_process page to payment page. The code goes like this:
cart_process.php:
$paynow = "<button type='submit' id='reset' class='btn btn-danger' align='center' disabled>PAY NOW</button> ";
$cart_box_total = '<div class="cart-products-total" id="cart-products-total" name="subtotalsub">.$total.</div>';
?>
<script>
$(document).ready(function() {
$("#reset").click(function() {
var content = $('#cart-products-total').html();
$.post("payment.php", { html: content})
.done(function(data) {
window.location = "payment.php";
});
});
});
</script>
And on payment.php:
<?php echo $_POST['html']; ?>
As the page redirects to payment.php, the $_POST['html'] doesn't echoes anything, but if I use alert(content) in cart_process.php it alerts me with the needed data.
How can I post the whole data to the page?

Replace window.location = "payment.php"; with:
$('body').append( data );
See how that works out. Eventually you may want to designate a destination target element:
<div id="ajax-target"></div>
Then instead of $('body').append( data ) you would have:
$('#ajax-target').html( data );
UPDATE
If you must be redirected, then you do not need ajax. Here is how you can do that:
$(document).ready(function() {
$("#reset").click(function() {
var content = $('#cart-products-total').html();
$('<form action="payments.php" method="POST"/>')
.html( '<textarea name="html">' + content + '</textarea>' )
[0].submit();
});
});

You have some misconceptions of the order of operations taking place here. You're actually invoking payment.php twice. Once as a POST request with the html parameter here:
$.post("payment.php", { html: content})
and then again as a GET request without any parameter here:
window.location = "http://selina.co.il/payment.php";
The client-side code is essentially ignoring the result of the POST request and just sending the user to the GET request, which naturally doesn't echo anything.
It's not entirely clear what you're trying to do here, but if you're using AJAX then you probably don't really want to be redirecting the user to anything anyway. So instead of doing this:
window.location = "http://selina.co.il/payment.php";
Do something in that AJAX callback to modify the current page. Maybe set the data variable to some content on the page? Something like this?:
$('#someDiv').html(data);
It's really up to you what should happen here, we can't tell for certain from the code posted.
If the flow of the application indeed is that the user should be redirected to another page, then you have two options:
1: Expect a GET parameter instead of a POST parameter in the PHP code and include it on the redirect:
window.location = "http://selina.co.il/payment.php?html=" + encodeURIComponent(content);
That will probably be pretty ugly if content is what it implies to be.
2: Don't use AJAX at all and simply have a form which POSTS to payment.php.

Related

JQuery to submit PHP not executing

After hours of playing with this, it hit me that my JQuery simply isn't executing.
I have a page that I am trying to submit to a PHP script without refreshing/leaving the page. If I use a typical form action/method/submit, it inserts into my database just fine. But when I use JQuery, the JQuery will not run at all. The alert does not show. (I'm new to JQuery). I have tried to research this, but nothing is working.
Here is my main page:
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script>
$(document).ready(function(e) {
$('submitpicks').on('submit','#submitpicks',function(e){
e.preventDefault(); //this will prevent reloading page
alert('Form submitted Without Reloading');
});
});
</script>
</head>
<body>
<form name="submitpicks" id="submitpicks" action="" method="post">
<script language="javascript">
var v=0;
function acceptpick(thepick,removepick){
var userPick = confirm("You picked " + thepick + ". Accept this pick?");
//var theid = "finalpick" + v;
var removebtn = "btn" + removepick;
//alert(theid);
if(userPick==1){
document.getElementById("finalpick").value=removepick;
document.getElementById(removebtn).disabled = true;
document.getElementById("submitpicks").submit();
v=v+1;
}
}
</script>
<?php
include "Connections/myconn.php";
//$setid = $_SESSION["gbsid"];
$setid = 11;
$setqry = "Select * from grabBagParticipants where gbsid = $setid order by rand()";
$setresult = mysqli_query($conn, $setqry);
$u=0;
if(mysqli_num_rows($setresult)>0){
while($setrow = mysqli_fetch_array($setresult)){
//shuffle($setrow);
echo '<input type="button" name="' . $setrow["gbpid"] . '" id="btn' . $setrow["gbpid"] . '" value="' . $u . '" onClick=\'acceptpick("' . $setrow["gbpname"] . '", ' . $setrow["gbpid"] . ');\' /><br />';
$u=$u+1;
}
}
?>
<input type="text" name="finalpick" id="finalpick" />
<input type="submit" value="Save" />
</form>
<div id="results"> </div>
</body>
</html>
Here is my PHP:
<?php
include "Connections/myconn.php";
$theGiver = 1;
$theReceiver = $_POST['finalpick'];
$insertsql = "insert into grabBagFinalList(gbflgid, gbflrid) values($theGiver, $theReceiver)";
mysqli_query($conn, $insertsql);
?>
you can use e.preventDefault(); or return false;
<script>
$(document).ready(function(e) {
$('#submitpicks').on('submit',function(e){
e.preventDefault();
$.post('submitpick.php', $(this).serialize(), function(data) {
$('#results').html(data);
});
// return false;
});
});
</script>
Note: in your php you not echo out anything to get it back as a data .. so basic knowledge when you trying to use $.post or $.get or $.ajax .. to check the connection between js and php .. so in php
<?php
echo 'File connected';
?>
and then alert(data) in js .. if everything works fine .. go to next step
Explain each Step..
before everything you should check you install jquery if you use
<script type="text/javascript" src="jquery-1.11.3.min.js"></script>
from w3schools website.. its totally wrong .. you should looking for how to install jquery ... then
1st to submit form with js and prevent reloading.. and you used <script> in your main page
<script>
$(document).ready(function(e) {
$('#submitpicks').on('submit',function(e){
e.preventDefault(); //this will prevent reloading page
alert('Form submitted Without Reloading');
});
});
<script>
output : alert with Form submitted Without Reloading ... if this step is good and you get the alert .. go to next step
2nd add $.post to your code
<script>
$(document).ready(function(e) {
$('#submitpicks').on('submit',function(e){
e.preventDefault(); //this will prevent reloading page
$.post('submitpick.php', $(this).serialize(), function(data){
alert(data);
});
});
});
<script>
and in submitpick.php >>> be sure your mainpage.php and submitpick.php in the same directory
<?php
echo 'File connected';
?>
output: alert with File connected
Have you heard of AJAX(asynchronous javascript and XML). While it may not be something that is easy to learn for someone who is new to JQuery and javascript, it does pretty much what you need. Well, its a bit more complicated than that, but basically AJAX submits information by using HTTP requests (much like normal forms) but without refreshing the page.
Here's a link to a tutorial: http://www.w3schools.com/ajax/ with vanilla javascript.
Here's one with Jquery: http://www.w3schools.com/jquery/jquery_ajax_intro.asp
And here's an example of how you can set it up with Jquery:
$(document).ready(function() {
$.ajax({
method: "POST",
url: "/something.php"
dataType: "JSON",
data: {formData:{formfield1: $('formfield1').val(), formfield2: $('formfield2)'.val()}},
success: function(data){
if (data["somevalue"]) == something {
dosomething;
} else {
dosomethingelse
},
error: function() {
alert("Error message");
}
});
});
This is only a basic example, now what does all this stuff mean anyway. Well, there are several methods, some of them are POST and GET, these are HTTP request methods, which you can use to do several things. I'm no expert on this stuff, but here's what they do:
Method
POST
POST basically works, to submit information to a server, which is then usually inserted to a database to which that server is connected to. I believe most forms utilize POST requests, but don't quote me on that.
GET
GET on the other hand requests data from a server, which then fetches it into the database and sends it back to the client so it can perform an action. For instance, whenever you load a page, GET requests are made to load the various elements of a page. What's important to note here, is that this request is made specifically to retrieve data.
There are other types of HTTP requests you can use such as PUT and DELETE, which I'd say are the most common along with GET and POST. Anyway I'd recommend that you look them up, its useful information.
Url
The url represents the path to which you are making a request, I'm not exactly sure how it works with PHP, I think you just need to call the PHP page in question and it will work properly, but I'm not sure, I haven't used PHP since my last semester, been using Rails and it doesn't work quite the same. Anyway, lets say you have some PHP page called, "Something.php" and lets say that somethihng PHP has the following content:
<?php
$form_data = $_POST['data'];
$array = json_decode(form_data, true);
do something with your data;
$jsonToSendBack = "{status: 1}";
$response = json_encode($jsonToSendBack);
echo $response;
?>
So basically what that file received was a JSON, which was our specified datatype and in turn after we finish interpreting data in the server, we send back a response through echo our echo. Now since our datatype is a JSON, the client is expecting a response with JSON, but we'll get to that later. If you're not familiar with JSON, you should look it up, but in simple terms JSON is a data exchange format that different languages can utilize to pass data to each other, like in this example, where I sent data to PHP through Javascript and vice-versa.
DataType
Data type is basically, the type of information that you want to send to the server, you can specify it through ajax. There are many data types you can send and receive, for instance if you wanted to, you could send XML or Text to the server, and in turn it should return XML or text, depending on what you chose.
Success and Error
Finally, there's the success and error parameters, basically if a request was successful, it returns a status code of 200, though that doesn't mean that other status codes do not indicate success too, nonetheless 200 is probably the one you'd like to see when making HTTP requests. Anyway, success basically specifies that if the request succeeded it should execute that function code I wrote, otherwise if there is an error, it will execute the function within error. Finally, even if you do have a success on your request, that doesn't mean everything went right, it just means that the client was successful in contacting the server and that it received a response. A request might be successful but that doesn't generally mean that your server-side code executed everything perfectly.
Anyway, I hope my explanation is sufficient, and that you can take it from here.

Minor difficulties with Ajax and PHP interaction

I working in CodeIgniter and I am trying to spit out all of the items I have in a table and order them as they should be using the dropdown. I want it to happen without page reload and without submit buttons, so I am using this jQuery function to make immediately react, when it is changed:
$(document).ready(function() {
$(".order-by-select").click(function() {var orderValue = this.value;
$.post("<?php echo base_url() ?>welcome/index", {val: orderValue}, function(data) {
alert(data);
});
});
Inside you can see the $.post method, with wich I am trying to send the data to php script (orderValue).
After that, I am getting an alert (not even sure, why do I need it (Maybe to check if everything is ok there))
In PHP, I am receiving the chosen select option and assigning a variable ($data['people']) to the results of MySQL query (that is placed in the model) to be able to access it withing the view. This - $_POST['val'] represents, how can I order the list (select * from people order by $theorder" ($theother is just a variable inside the query function. It recieves the value of $_POST['val'])).
if(isset($_POST['val'])) {
$data['people'] = $this->database->listPeople($_POST['val']);
exit;
}
After that I recieve this variable in the view and I am running foreach loop to take different parts of the array(name of the person, his age, etc..) and placing it in the way they should be.
The problem is - if I do that without ajax, when I have static order by value - everything works fine. I did not mean that was the problem :D, the problem basically is that is doesn't work with ajax... I was trying to recieve the array in the js callback and create a layout using
$.each(eval(data), function() {
$('#container').text('<div>' + eval(res).name + '</div>');
});
But that was also a failure...
How should I organize and create my code to make everything work properly?
I am kinda new to Ajax, so I hope I'll really learn how to do that from you guys. I already searched through the whole internet and have seen a lot of ajax tutorials and other kind of material (e. g. StackOverflow), but I still can't get, how can I do all of that in my particular situation. I have wasted already about 12 hours trying to solve the problem and couldn't do that, so I hope You will tell me if there is any useful salvation.
Thank you for your consideration.
Hi the skinny is you need 3 parts to make ajax work,
serverside code to generate the page
ajax ( clientside ) to make the call and respond
seperate serverside to receive it.
Also it will be easier to replace the table completely then to pick out elements. But that is up to you.
So say we have the page with our ajax call
<script type="text/javascript" >
$(document).ready(function() {
$(".order-by-select").click(function() {var orderValue = this.value;
$.post("<?php echo base_url() ?>welcome/index", {val: orderValue}, function(data) {
alert(data);
});
});
</script>
Now you seem to have some json response I'll assume you get this from the alert above;
[{"id":"1","name":"Nick","age":"18"},{"id":"2","name":"John","age":"23"}]
I'll also assume that this comes from something like
echo json_encode( array( array('id'=>1, ...), array('id'=>2 ...) .. );
It's important before doing the echo that you tell the server that this is json, you do this using a header, but you cannot output anything before the header, and after the json header all output must be in the json format or it wont work, it's like telling the browser that this is html, or an image etc. what the content is.
Header("Content-Type: application/json");
echo json_encode( ....
You can get away without doing this sometimes, but often you'll need to use eval or something, by telling the browser its json you don't need that. Now doing an alert is great and all but if you see the string data [{"id": .. your header is wrong, you should get something like [object] when you do the alert.
No once we have a factual Json object we can make use of all that wonderful data
<script type="text/javascript" >
$(document).ready(function() {
$(".order-by-select").click(function() {var orderValue = this.value;
$.post("<?php echo base_url() ?>welcome/index", {val: orderValue}, function(data) {
$.each(data, function(i,v){
alert(v.id);
alert(v.name);
});
});
});
</script>
This should loop through all the data and do 2 alerts, first the id then the name, right. Next it's a simple matter of replacing the content using .text() or .append()
<script type="text/javascript" >
$(document).ready(function() {
$(".order-by-select").click(function() {var orderValue = this.value;
$.post("<?php echo base_url() ?>welcome/index", {val: orderValue}, function(data) {
$.each(data, function(i,v){
$('#test').append('<p>'+v.id+'</p>');
});
});
});
</script>
<p id="test" ></p>

post json data to php and echo result

I'm a struggling learner of php and javascript and Have been searching frantically for a solutionbut to no avail. I am trying to send a json object/string from one page to another using php and then echo the results in that new page (eventually to generate a pdf using tcppdf) . So basically some javascript generates an object, pageStructure, in one page, which I then stringify:
var jsonString = JSON.stringify(pageStructure);
alert(jsonString);`
The alert pops up fine.
I now want to send (post) this to another php file getdata.php and then play around with it to construct a pdf.
I have tried posting with forms but updating the value of an input in the form with jsonString won't work.
**ADDITION - EXPLANATION OF MY PROBLEM HERE
I created a form as follows:
<form action="getdata.php" method="post">
<textarea type="hidden" id="printMatter" name="printMatter" value=""></textarea>
<button type="submit"><span class="glyphicon glyphicon-eye-open" ></span></button>
</form>
I have some code after constructing jsonString to set the value of the textarea to that value:
document.getElementById('printMatter').value = jsonString;
alert(document.getElementById('printMatter').value);
A submit button activates the form which opens the getdata.php page but I noticed two things:
(1) before sending the jsonString string is full of escapes () before every quote mark (").
(2) when getdata.php opens, the echoed jsonString has changed to include no \s but instead one of the values ('value') of an object in the json string (a piece of svg code including numerous \s) - for example (truncated because the value is a very long svg string, but this gives the idea):
{"type":"chartSVG","value":"<g transform=\"translate(168.33333333333334,75)\" class=\"arc\">...
has changed to integers - for example:
{"type":"chartSVG","value":"12"}
I don't understand how or why this happens and what to do to get the full svg code to be maintained after the form is posted.
**
I have tried using jquery/ajax as follows:
$.ajax({
url: 'getdata.php',
type: 'post',
data: {printMatter: jsonString},
success: function(){
alert('it worked');
},
error: function(){
alert('it failed')}
})
I'm getting the success response but I end up on the same page instead of getting the new php file to just echo what it is being sent!
The php script contains the following:
<?php
echo $_POST['printMatter'];
?>
But this doesn't work. Nor does trying to add a header to the php page (e.g. header('Content: application/json'). I end up staying on my original page. How do I get this to leave me on the new page (getdata.php) with an echo of the json string?
Can anyone explain what I am doing wrong or how I can get what I want?
Thank you so much.
**ADDITION
This is indicative of how I get the jsonString object:
function item(type,value) {
this.type = type;
this.value = value;
}
for (i=0;i<thePage[0].length;i++) {
pageid = thePage[0][i].id;
var entry = new item("page",pageid);
pageStructure.push(entry);
}
var jsonString = JSON.stringify(pageStructure);
So I end up with a series of pages listed out in the jsonString.
Try changing $_POST to $_GET since your AJAX request is doing a HTTP GET and not a HTTP POST.
UPDATE
This doesn't leave me on the page I want to be on. I don't want to refresh the page but just redirect to a new page that receives the posted json data.
By this is essentially a page "refresh", though perhaps "refresh mislead you because it can imply reloading the current URL. What i meant by refresh was a completely new page load. Which is essentially what you are asking for. There are a few ways to go about this...
If you data is pretty short and will not violate the maximum length for a URI on the webserver then you can jsut use window.location:
// send it as json like you are currently trying to do
window.location = 'getdata.php?printMatter=' + encodeURIComponent(jsonString);
// OR send it with typical url-encoded data and dont use JSON
window.location = 'getdata.php?' + $.serialize(pageStructure);
In this case you would use $_GET['printMatter'] to access the data as opposed to $_POST['printMatter'].
If the data has the potential to produce a long string then you will need to POST it. This gets a bit trickier since if we want to POST we have to use a form. Using JSON and jQuery that is pretty simple:
var form = '<form action="getdata.php" method="post">'
+ '<input type="hidden" name="printMatter" value="%value%" />'
+ '</form>';
form.replace('$value%', jsonString);
// if you have any visual styles on form that might then you may
// need to also position this off screen with something like
// left: -2000em or what have you
$(form).css({position: 'absolute'})
.appendTo('body')
.submit();
If we wanted to just send this as normal formdata then it would get more complex because we would need to recursively loop over pageStructure and create input elements with the proper name attribute... i wouldn't got that route.
So the final way (but i dont think it would work because it seems like youre tryign to generate a file and have the browser download it) would be to send it over AJAX and have ajax return the next url to go to:
JS
$.ajax({
url: 'getdata.php',
type: 'post',
data: {printMatter: jsonString},
type: 'json',
success: function(data){
window.location = data.redirectUrl;
},
error: function(){
alert('it failed')}
});
getdata.php
// do something with the $_POST['printMatter'] data and then...
$response = array(
'redirectUrl' =>$theUrlToGoTo
);
header('Content-Type: application/json');
print json_encode($response);
You are using AJAX. By nature AJAX will not refresh the page for example if you do this:
$.ajax({
url: 'getdata.php',
type: 'post',
data: {printMatter: jsonString},
success: function(data){
alert('it worked');
alert('You sent this json string: ' + data);
},
error: function(){
alert('it failed')}
});
Also note that i changed your type from 'get' to 'post'... The type set here will in part determine where you can access the data you are sending... if you set it to get then in getdata.php you need to use $_GET, if you set it to post then you should use $_POST.
Now if you actually want a full page refresh as you implied then you would need to do this another way. How you would go about it i cant say because you havent provided enough of an idea of what happens to get your jsonString before sending it.

JS variable to PHP variable without buttons or refresh

I've searched for over an hour and tried many examples but none do what I need. From JavaScript I can display the necessary variable in PHP or HTML with <b id="citynm"></b> but I need to make citynm $citynm. I've tried looking in AJAX for the first time but could only get it to work with a button click or page refresh.
I need to run the JavaScript to get citynm and then make it into $citynm for PHP use on any page without running the JS again. The JS is only run once upon entering the site. But the $citynm will be run on several pages in different needs (such as echo "You live in ".$citynm).
The best way is to store the value you want for citynm into a session variable as below:
$_SESSION['citynm'] = $citynm
You have to do this either at page load, or by ajax. Then, you can use $_SESSION['citynm'] in any pages you want since its global.
USECASE 1: via user input
in your html document:
<input type="text" name="citynm" id="citynm" value="Brussels">
inside your javascript file (using jquery here for readability):
(function(){
$('#citynm').on('blur',function(){
// when the input value has changed, post its value to server.
var citynm = $(this).val();
$.post('http://domain.com/path/to/your/php/file.php',{citynm: citynm},function(data){
// if the request is successful, the following script will be executed.
alert("server said: "+data);
});
});
})(jQuery);
And inside the file.php file:
<?php
session_start();
if(isset($_POST['citynm']) && strlen($_POST['citynm'])>0){
$_SESSION['citynm'] = $_POST['citynm'];
}
echo "citynm is ". $_SESSION['citynm'];
?>
USECASE 2: no userinput
var cityname = city.short_name;
if (status == google.maps.GeocoderStatus.OK) { document.getElementById("citynm").innerHTML = cityname; }
(function(){
$.post('http://domain.com/path/to/your/php/file.php',{citynm: cityname},function(data){
// if the request is successful, the following script will be executed.
alert("server said: "+data);
});
})(jQuery);

Redirect after submitting multiple forms

There is a submit button that serializes some forms and submits them correspondingly to different handlers on the server. When the data have been sent, I would like to redirect to another page where the user can see an overview of the results. How can I do it so? Redirecting right away does not work since the page does not have enough time to submit the data (or it looks so).
The following fails:
$(document).ready(function(){
$('#submit_all_button').submit(function(){
var querystring = $('#q1').serialize();
$.get('/change_q1', querystring);
var querystring = $('#q2').serialize();
$.get('/change_q2', querystring);
var querystring = $('#q3').serialize();
$.get('/change_q3', querystring);
window.location.href = "/main";
return false;
});
});
The same problem arises when the submit action is to redirect to /main page.
Use the success function of jQuery get() and keep track whether all your updates are send. So the last success function call finally redirects your page.
I have an other answer in PHP which is interesting: run it as a background job (Other answer is the best way to go but if, for some reason, you can't use it):
set_time_limit(900);
ignore_user_abort(true);
header("Connection: close");
header("Content-Length: " . mb_strlen('ok'));
echo 'ok';
flush();
// Your code follows here
Maybe you can use this logic in your server-side language.

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