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I have a problem in Javascript I want to make a form which have one input text field and one button when I click on the button window.prompt is called.
It will prompt depend upon my array length but I want array length get through input text field when I write 10 it will prompt 10 times when I write 2 it will prompt 2 times.
How can i write this type of query?
I tried this code but its not working.
words = new Array (4);
function a() {
for ( k = 0 ; k < words.length ; k = k + 1 ) {
words[ k ] = window.prompt( "Enter word # " + k, "" ) ;
}
}
Maybe you forgot to call your function a().
Some remarks about your code:
You don't have to specify an initial array size, e.g. words = [] or words = new Array() is enough.
Also k=k+1 is usually written as k++.
A remark about asking questions:
Use punctuation to make sentences! Your whole question is one sentence.
Hopefully it's just the snippet of code but I hope you are using var somewhere to declare all those variables.
Otherwise this should do the trick, however not sure what you are trying to achieve but this sounds like a bad user experience.
Here is the jsffidle http://jsfiddle.net/R2bCz/1/
function Handler(event) {
var count = event.target.value;
var i = 0;
var words = [];
var word;
for (; i < count; i++) {
word = window.prompt("Enter word # " + i, "");
words.push(word);
}
}
$("#multi").on("change", Handler);
I have created a button in JavaScript with the following details:
<td id='2,A,B,C' onclick='enterKey(this.id)'>2</td>
When the JS is passed through the function an array is created:
string = string.split(',')
meaning string[0] is 2, string[1] is A and henceforth....
The question I wanted to ask is how do I get JS to register multiple presses on the button.
So if the user presses the twice - they get A instead of 2. If they press it three times - they get B. But if they press is 5 times - it reverts back to 2.
Any advice on how I can achieve this? Many thanks in advance!
First off, you have an invalid ID:
ID and NAME tokens must begin with a letter ([A-Za-z]) and may be followed by any number of letters, digits ([0-9]), hyphens ("-"), underscores ("_"), colons (":"), and periods (".").
However, assuming you either revise it to use, say, a period or something else, you can track it but just assigning the "click count" to an attribute on the td. For instance:
<script type="text/javascript">
function incCounter(e){
var count = e.getAttribute('data-clicks') || 0,
id = e.getAttribute('data-clickid').split(',');
e.innerHTML = id[++count % id.length];
e.setAttribute('data-clicks', count);
}
</script>
<td data-clickid="2,a,b,c" onclick="incCounter(this);"></td>
Working Demo
Then read the data attribute to determine which element of the "ID array" you need to reference.
A simple solution would be to declare a global variable outside of the method definition, and increment it on each press.
var count = 0;
function enterKey() {
//Split and whatnot here
var myValue = string[count];
count++;
if(count == 5) {
count = 0;
}
}
You would attach it dynamically somehow. So, for example, if you wanted to do this to all <td> elements:
var elements = document.getElementsByTagName('td');
var i, element;
for(i = 0; element = elements[i]; i++) {
(function(element) {
var data = element.getAttribute('data').split(',');
var numClicks = 0;
element.onclick = function() {
enterKey(data[numClicks++ % data.length]);
};
})(element);
}
Note that I used element.getAttribute('data') instead of element.id; #FelixKling is correct, that's an invalid ID.
Something like this?
var count = 0;
function enterKey( string ) {
string = string.split( "," );
return string[(count++) % string.length];
}
I want to display YouTube videos on my website, but I need to be able to add a unique id for each video that's going to be shared by users. So I put this together, and I have run into a little problem. I am trying to get the JavaScript to add a random string for the div id, but it's not working, showing the string:
<script type='text/javascript' src='jwplayer.js'></script>
<script type='text/javascript'>
function randomString(length) {
var chars = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXTZabcdefghiklmnopqrstuvwxyz'.split('');
if (! length) {
length = Math.floor(Math.random() * chars.length);
}
var str = '';
for (var i = 0; i < length; i++) {
str += chars[Math.floor(Math.random() * chars.length)];
}
return str;
}
var div = randomString(8);
</script>
<div id='div()'>This text will be replaced</div>
<script type='text/javascript'>
jwplayer('div()').setup({
'flashplayer': 'player.swf',
'file': 'http://www.youtube.com/watch?v=4AX0bi9GXXY',
'controlbar': 'bottom',
'width': '470',
'height': '320'
});
</script>
I really like this function:
function guidGenerator() {
var S4 = function() {
return (((1+Math.random())*0x10000)|0).toString(16).substring(1);
};
return (S4()+S4()+"-"+S4()+"-"+S4()+"-"+S4()+"-"+S4()+S4()+S4());
}
From Create GUID / UUID in JavaScript?
2018 edit: I think this answer has some interesting info, but for any practical applications you should use Joe's answer instead.
A simple way to create a unique ID in JavaScript is to use the Date object:
var uniqid = Date.now();
That gives you the total milliseconds elapsed since January 1st 1970, which is a unique value every time you call that.
The problem with that value now is that you cannot use it as an element's ID, since in HTML, IDs need to start with an alphabetical character. There is also the problem that two users doing an action at the exact same time might result in the same ID. We could lessen the probability of that, and fix our alphabetical character problem, by appending a random letter before the numerical part of the ID.
var randLetter = String.fromCharCode(65 + Math.floor(Math.random() * 26));
var uniqid = randLetter + Date.now();
This still has a chance, however slim, of colliding though. Your best bet for a unique id is to keep a running count, increment it every time, and do all that in a single place, ie, on the server.
Here is the reusable function to generate the random IDs :
function revisedRandId() {
return Math.random().toString(36).replace(/[^a-z]+/g, '').substr(2, 10);
}
// It will not start with the any number digit so it will be supported by CSS3
I think some folks here haven't really focused on your particular question. It looks like the problem you have is in putting the random number in the page and hooking the player up to it. There are a number of ways to do that. The simplest is with a small change to your existing code like this to document.write() the result into the page. I wouldn't normally recommend document.write(), but since your code is already inline and what you were trying do already was to put the div inline, this is the simplest way to do that. At the point where you have the random number, you just use this to put it and the div into the page:
var randomId = "x" + randomString(8);
document.write('<div id="' + randomId + '">This text will be replaced</div>');
and then, you refer to that in the jwplayer set up code like this:
jwplayer(randomId).setup({
And the whole block of code would look like this:
<script type='text/javascript' src='jwplayer.js'></script>
<script type='text/javascript'>
function randomString(length) {
var chars = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghiklmnopqrstuvwxyz'.split('');
if (! length) {
length = Math.floor(Math.random() * chars.length);
}
var str = '';
for (var i = 0; i < length; i++) {
str += chars[Math.floor(Math.random() * chars.length)];
}
return str;
}
var randomId = "x" + randomString(8);
document.write('<div id="' + randomId + '">This text will be replaced</div>');
jwplayer(randomId).setup({
'flashplayer': 'player.swf',
'file': 'http://www.youtube.com/watch?v=4AX0bi9GXXY',
'controlbar': 'bottom',
'width': '470',
'height': '320'
});
</script>
Another way to do it
I might add here at the end that generating a truly random number just to create a unique div ID is way overkill. You don't need a random number. You just need an ID that won't otherwise exist in the page. Frameworks like YUI have such a function and all they do is have a global variable that gets incremented each time the function is called and then combine that with a unique base string. It can look something like this:
var generateID = (function() {
var globalIdCounter = 0;
return function(baseStr) {
return(baseStr + globalIdCounter++);
}
})();
And, then in practical use, you would do something like this:
var randomId = generateID("myMovieContainer"); // "myMovieContainer1"
document.write('<div id="' + randomId + '">This text will be replaced</div>');
jwplayer(randomId).setup({
i like this simple one:
function randstr(prefix)
{
return Math.random().toString(36).replace('0.',prefix || '');
}
since id should (though not must) start with a letter, i'd use it like this:
let div_id = randstr('youtube_div_');
some example values:
youtube_div_4vvbgs01076
youtube_div_1rofi36hslx
youtube_div_i62wtpptnpo
youtube_div_rl4fc05xahs
youtube_div_jb9bu85go7
youtube_div_etmk8u7a3r9
youtube_div_7jrzty7x4ft
youtube_div_f41t3hxrxy
youtube_div_8822fmp5sc8
youtube_div_bv3a3flv425
I also needed a random id, I went with using base64 encoding:
btoa(Math.random()).substring(0,12)
Pick however many characters you want, the result is usually at least 24 characters.
Based on HTML 4, the id should start from letter:
ID and NAME tokens must begin with a letter ([A-Za-z]) and may be followed by any number of letters, digits ([0-9]), hyphens ("-"), underscores ("_"), colons (":"), and periods (".").
So, one of the solutions could be (alphanumeric):
var length = 9;
var prefix = 'my-awesome-prefix-'; // To be 100% sure id starts with letter
// Convert it to base 36 (numbers + letters), and grab the first 9 characters
// after the decimal.
var id = prefix + Math.random().toString(36).substr(2, length);
Another solution - generate string with letters only:
var length = 9;
var id = Math.random().toString(36).replace(/[^a-z]+/g, '').substr(0, length);
Or you could use Cripto since it's already built in(except in IE11, I swear these guys havent updated in years!)
https://developer.mozilla.org/en-US/docs/Web/API/Crypto/getRandomValues#Examples
var id = new Uint32Array(10);
window.crypto.getRandomValues(id);
I also found this:
https://gist.github.com/6174/6062387#gistcomment-3255605
let length = 32;
let id = crypto.randomBytes(length).toString("base64");
There's a lot of ways to do this, but for most people, there's no reason to reinvent the wheel :)
A edited version of #jfriend000 version:
/**
* Generates a random string
*
* #param int length_
* #return string
*/
function randomString(length_) {
var chars = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghiklmnopqrstuvwxyz'.split('');
if (typeof length_ !== "number") {
length_ = Math.floor(Math.random() * chars.length_);
}
var str = '';
for (var i = 0; i < length_; i++) {
str += chars[Math.floor(Math.random() * chars.length)];
}
return str;
}
For generating random ids, you can also use the standard crypto API with its randomUUID() function which is available in node.js (>=v16.7.0) and all relevant browsers except Safari:
const uuid = crypto.randomUUID()
console.log(uuid)
// prints e.g. "7f3f4512-fcf9-45fe-b726-512bba403426"
I would suggest that you start with some sort of placeholder, you may have this already, but its somewhere to append the div.
<div id="placeholder"></div>
Now, the idea is to dynamically create a new div, with your random id:
var rndId = randomString(8);
var div = document.createElement('div');
div.id = rndId
div.innerHTML = "Whatever you want the content of your div to be";
this can be apended to your placeholder as follows:
document.getElementById('placeholder').appendChild(div);
You can then use that in your jwplayer code:
jwplayer(rndId).setup(...);
Live example: http://jsfiddle.net/pNYZp/
Sidenote: Im pretty sure id's must start with an alpha character (ie, no numbers) - you might want to change your implementation of randomstring to enforce this rule. (ref)
May I an share an intuitive way to generate a randomID ?
const getRandomID = (length: number) => {
let text = '';
const possible = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789';
for (let i = 0; i < length; i++) {
text += possible.charAt(Math.floor(Math.random() * possible.length));
}
return text;
}
Here is an easy one liner:
const generateUniqueID = (idLength) => [...Array(idLength).keys()].map((elem)=>Math.random().toString(36).substr(2, 1)).join("")
Where all you do is enter the idLength and it will return a unique id of that length.
generateUniqueID(23)
>>>'s3y9uebzuo73ih79g0s9p2q' // Id of length 23
First. Assign an id to your div. Like this:
<div id="uniqueid">This text will be replaced</div>
After that, add inside your <script> tag following code:
Document.getElementById("uniqueid").id = randomString(8);
window.btoa(String.fromCharCode(...window.crypto.getRandomValues(new Uint8Array(5))))
Using characters except ASCII letters, digits, '_', '-' and '.' may cause compatibility problems, as they weren't allowed in HTML 4. Though this restriction has been lifted in HTML5, an ID should start with a letter for compatibility.
function id(prefix = '', length = 7) {
let result = prefix;
for(let i = 0; i < length; i++) {
const random = Math.random();
result += String.fromCharCode(Math.floor(random * 26) + (random < .5 ? 65 : 97));
}
return result;
}
a random number between 0 and 25 is generated then added to either 65 or 97. When added to 65 it will give you an ascii code for a capital letter and when added to 97, an ascii code for a small letter.
Just use built-int crypto.randomUUID() which is supportted by all major browsers:
let uuid = crypto.randomUUID();
console.log(uuid);
This should be a quickie, but I'm scratching my head as to why this bit of JavaScript isn't working for me. The goal is to take the value of an input box (string of words separated by spaces), list these words as items in an array, and remove those which are fewer than 3 characters:
var typed = $('input').val();
var query = typed.split(" ");
var i=0;
for (i=0; i<query.length; i++) {
if (query[i].length < 3) {
query.splice(i,1);
}
}
Have this running onkeyup for the input box and it seems to work, but only about 50% of the time (strings of 1 and 2 characters somehow find their way into the array on occasion). Any suggestions would be hugely appreciated.
The problem is that you are iterating while removing the elements. Consider this array:
["he", "l", "lo world"]
Initially your loop starts at index 0 and removes "he" from the array. Now the new array is
["l", "lo world"]
In the next iteration i will be 1, and you will check "lo world"'s length, thus ignoring the "l" string altogether.
Use the filter method in Array to remove the unwanted elements.
var biggerWords = query.filter(function(word) {
return word.length >= 3;
});
Besides the iterating problem, you may also see unexpected entries if you type multiple spaces
try
var query = typed.split(/\s+/);
This way it will split on any number of spaces, instead of each individual one
The problem is that you're slicing the array while counting forward. Think about it...if you take an index point out of the array, thereby shortening it by one, incrementing i and moving on to the next one actually moves one further than you want, completely missing the next index. Increment i--, start at query.length-1, and make the condition that i>=0. For an example of this in action, check it out here:
http://jsfiddle.net/kcwjs/
CSS:
input {
width:300px;
}
HTML:
<input id="textbox" type="text" />
<div id="message"></div>
Javascript:
$(document).ready(function() {
$('#textbox').keyup(checkStrings);
});
function checkStrings(e) {
var typed = $('#textbox').val();
if (typed == "") return false;
var query = typed.split(" ");
var querylen = query.length;
var acceptedWords = '';
var badWords = '';
for (var i = querylen-1; i >= 0; i--) {
if (query[i].length < 3) {
badWords += query[i] + " ";
} else {
acceptedWords += query.splice(i,1) + " ";
}
}
$('#message').html("<div>Bad words are: " + badWords + "</div>" +
"<div>Good words are: " + acceptedWords + "</div>");
}
Try this code, it get's rid of any 3 character words, as well as making sure no empty array elements are created.
typed.replace(/(\b)\w{1,3}\b/g,"$1");
var query = typed.split(/\s+/);
hey i think you should use a new array for the result. since you are removing the element in array. the length is changed. here is my solution
var typed = "dacda cdac cd k foorar";
var query = typed.split(" ");
var i=0;
var result = [];
for (i=0; i<query.length; i++) {
if (query[i].length >= 3) {
result.push(query[i]);
}
}
What I would like is to count the number of lines in a textarea, e.g:
line 1
line 2
line 3
line 4
should count up to 4 lines. Basically pressing enter once would transfer you to the next line
The following code isn't working:
var text = $("#myTextArea").val();
var lines = text.split("\r");
var count = lines.length;
console.log(count);
It always gives '1' no matter how many lines.
The problem with using "\n" or "\r" is it only counts the number of returns, if you have a line that is long it could wrap and then it wouldn't be counted as a new line. This is an alternative way to get the number of lines - so it may not be the best way.
Edit (thanks alex):
Script
$(document).ready(function(){
var lht = parseInt($('textarea').css('lineHeight'),10);
var lines = $('textarea').attr('scrollHeight') / lht;
console.log(lines);
})
Update: There is a much more thorough answer here: https://stackoverflow.com/a/1761203/145346
If you are just wanting to test hard line returns, this will work cross platform:
var text = $("#myTextArea").val();
var lines = text.split(/\r|\r\n|\n/);
var count = lines.length;
console.log(count); // Outputs 4
I have implemented the lines and lineCount methods as String prototypes:
String.prototype.lines = function() { return this.split(/\r*\n/); }
String.prototype.lineCount = function() { return this.lines().length; }
Apparently the split method will not count a carriage return and/or newline character at the end of the string (or the innerText property of a textarea) in IE9, but it will count it in Chrome 22, yielding different results.
So far I have accomodated for this by subtracting 1 from the line count when the browser is other than Internet Explorer:
String.prototype.lineCount = function() { return this.lines().length - navigator.userAgent.indexOf("MSIE") != -1); }
Hopefully someone has a better RegExp or another workaround.
user \n instead of \r
var text = $("#myTextArea").val();
var lines = text.split("\n");
var count = lines.length;
console.log(count);
However this is working if you need use it because it respond to your problem
let text = document.getElementById("myTextarea").value;
let lines = text.split(/\r|\r\n|\n/);
let count = lines.length;
console.log(count);
What about splitting on "\n" instead?
It will also be a problem where one line wrapped to 2 lines in the textarea.
To do it accurately like this, you could use a fixed height font and measure pixels. This could be problematic though.
This function counts the number of lines which have text in a textarea:
function countLine(element) {
var text = $(element).val();
var lines = text.split("\n");
var count = 0;
for (var i = 0; i < lines.length-1; i++) {
if (lines[i].trim()!="" && lines[i].trim()!=null) {
count += 1;
}
}
return count;
}
Counting the newlines is not a reliable way for finding the number of lines, since long text could simply break and still only count as a single line.
What you want to do, is find out the scrollHeight of the textarea and divide it by the height of a single line.
This is answered in detail here:
https://stackoverflow.com/a/1761203/9863305
I've used the original answer of Mottie but some functions were changed in the JQuery API. Here is the working function for the current API v3.1.0:
var lht = parseInt($('#textarea').css('lineHeight'),10);
var lines = $('#textarea').prop('scrollHeight') / lht;
console.log(lines);
All tumbs up for Mottie's answer!
This will aim to consider lines with both hard and soft returns:
//determine what the fontsize will be
let fontsize = 12;
//get number of characters that can fit in a row
let charsperrow = textarea.clientWidth / fontsize;
//get any hard returns
let hardreturns = textarea.textContent.split(/\r|\r\n|\n/);
let rows = hardreturns.length;
//loop through returns and calculate soft returns
for(let i = 0,len = rows; i < len; i++){
let line = hardreturns[i];
let softreturns = Math.round(line.length / charsperrow);
//if softreturns is greater than 0, minus by 1 (hard return already counted)
softreturns = Math.round(softreturns > 0 ? (softreturns - 1) : 0);
rows += softreturns;
}
console.log(Math.round(rows));
The normal newline character is "\n". The convention on some systems is to also have "\r" beforehand, so on these systems "\r\n" is often found to mean a new line. In a browser, unless the user intentionally enters a "\r" by copying it from somewhere else, the newline will probably be expressed as just "\n". In either case splitting by "\n" will count the number of lines.
<html>
<head>
<script>
function countLines(theArea){
var theLines = theArea.value.replace((new RegExp(".{"+theArea.cols+"}","g")),"\n").split("\n");
if(theLines[theLines.length-1]=="") theLines.length--;
theArea.form.lineCount.value = theLines.length;
}
</script>
</head>
<body>
<form>
<textarea name="myText" onKeyUp="countLines(this)" cols="10" rows="10">
</textarea>
<br>
Lines:
<input type=text name="lineCount" size="2" value="0">
</form>
</body>
</html>
Your ans can be done in very simple way.
var text = $("#myTextArea").val();
// will remove the blank lines from the text-area
text = text.replace(/^\s*[\r\n]/gm, "");
//It will split when new lines enter
var lines = text.split(/\r|\r\n|\n/);
var count = lines.length; //now you can count thses lines.
console.log(count);
This code for exact lines filled in the textarea.
and will work for sure.
Instead of textarea you could use a div with the attribute contenteditable="true". On a div with this attribute you can write anything, just like in a textarea, but any new line (except the first) is automatically wrapped inside a div. You can use jQuery or JS to count the div's and add +1, which is the first line.
It's a no brainer, i would use this instead of textarea with every occasion. It has several advantages. It auto resizes, you can easily count blank lines, you can customize every div or add spans with colors or font sizes or anything, you can use any line-height and any font-size, you can add rich text features and more, it's better for SEO and more. Here is a working example with jQuery:
$("#Editor").on("keyup mouseup", function(){
blankSpace = $(this).find("br").length; //count blank lines
urlCounter = $(this).find("div").length + 1 - blankSpace;
$(".lineCounter").text("Number of links: "+ urlCounter);
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="Editor" contenteditable="true" style="color:aqua;width: 100%;height: 100%;background: blue;"></div>
<div class="lineCounter" style="position: absolute;bottom: 0;z-index: 999;left: 0;"></div>
Try calling this function every time you change its value.
textArea.addEventListener('input', function() {
setDynamicHeight();
});
function setDynamicHeight() {
textArea.style.height = 0; // set the height to 0 in case of it has to be shrinked
textArea.style.height = textArea.scrollHeight + 'px'; // set the dynamic height
}
Each line break is defined by '\n'. The goal is to count them. For this, we will have to iterate on this with a loop on each character. See the example below
let count = 0
const a = document.querySelector('textarea')
for (let i = 0; i < a.value.length; i++) {
if (a.value[i] == '\n') {
count++
}
}
console.log(count)
In this live demonstration we can see a concrete case with 3 sentences :
const textareaLineCount = () => {
let count = 0
const a = document.querySelector('textarea')
for (let i = 0; i < a.value.length; i++) {
if (a.value[i] == '\n') {
count++
}
}
return count
}
const displayTotalTextareaLine = (total) => {
document.querySelector('p').innerText = total
}
document.querySelector('button').addEventListener('click', () => {
const total = textareaLineCount()
displayTotalTextareaLine(total)
})
<textarea>
Lorem ipsum dolor sit amet.
Lorem ipsum dolor sit amet.
Lorem ipsum dolor sit amet.
</textarea>
<button>count</button>
<p></p>
⚠️ It's possible that the last phase is not a line break, so I advise you to add 1 to the total result